Node Voltage Method Circuit Analysis With Current Sources

[@TheOrganicChemistryTutor]

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HELP but 4vb=2vc-80 no? And 80 - 2vc - 11vc = 100 13vc=180 right? Edit: forgot to say 26:00

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[@liamcay238]

I absolutely love his videos, and this is well done, but he does it a bit differently then what we are being taught, and I do not like it as much, we do it so at each node that we are looking at, we assume current is flowing away in all directions, even though it may be obvious that it isn't right because its more important to stay consistent, and everything should work out in the end.

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[@175griffin]

Rather than going through all the trouble of trying to guess the correct direction of current in a node branch, just pick one. If the current goes the other way, it'll just give you a negative value. Flip the sign, flip the arrow.

[@jealouseggs5619]

i just tried what you said and it was way easier and quicker! but im more prone to making mistakes this way compared to his method so pick and choose i guess

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[@phuongnguyen-kc8hi]

He is the teacher of course he knows we can pick any direction but breaking it down like split the circuit in half is really cool way to analyze which side has more potential.

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[@fisforfriendship6093]

@@jealouseggs5619 i knew before hand current likes to travel through least resistance so when i saw the parralel circuit i seperate it into a series circuit and added the ohms up in series and knew the current would flow towards the smaller ohm's direction

[@edb452]

at 14:00, you can do it either way, if you get a negative current for R3 then that will mean it goes the other way from what you chose. Still so amazing and useful going in-depth

[@mrdave1413]

17:18. He added the resistors in Vc in series to find the current of the whole sub-circuit, that enabled him to find Vc. In the first sub-circuit the current is already known, so finding Vb was easier.

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[@T-She-Go]

Thank you 😭 Its been a while since I have done circuits and this was a really good recap

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[@pspmaster2071]

You do not have to try and find out the direction of current. You can make up your own direction from the get go as long as you are consistent. In KVL you choose counterclockwise or clockwise for all loops and remain consistent. In KCL you choose all currents to leave a node or all currents to go into a node and you will get the right answer. Think of it like scaling an equation by a constant of -1 depending on which convention you choose. You will get the same value when solving. Trying to find the direction of every current is inefficient and will lead to errors if you are not careful. After you find the node voltages you can find any current for any given direction with simple Ohms law.This video was more standard KCL than node voltage. Node voltage is supposed to make KCL even easier by choosing one defined direction. You are less likely to miss signs doing it this way.

[@SuperG3FR]

That's good analogy

[@shehzadkhan7570]

Yes if in R3 we use the reversed direction, it will give -2, which means we have used the wrong direction. then change it

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Gracias he aprendido mucho de circuitos eléctricos con ustedes

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[@destinyobamwonyi8865]

Correct me if am wrong , I attempted it before looking at you approach(17:00), I used the understanding that current will always flow through an easier path which means current from R5 would rather take R4 path than that of R3 as R4 has less resistance than R3 so R3 most there fore be coming from 8amps.

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[@achintsingh4552]

13:57 , I appreciate your method to decide whether Vb is greater or Vc. But I don't think we will get a wrong answer if we just assume one direction of current through BC, i.e. red or blue. If we assume the wrong direction suppose, from C to B, in writing the KCL at node B, (19:16), we will do i1-i2+i3=0, (instead of i1-i2-i3) and i3=(Vc-Vb)/5, (instead of (Vb-Vc)/5) which ultimately will adjust the sign and we will get the correct equation. Correct me if I am wrong somewhere. Thankyou!

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You are correct idk why he made it seem like such a big deal all u do is change the sign if your wrong

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[@BarelyEditingX]

Attention! For anyone watching this video, there is a better way to solve this type of problems without needing to make so many assumptions, the trick is to treat all currents as if these are going into the node even when the signs tells you otherwise, by assuming all currents to go into the node you'll get the same answer regardless I've tested it and it works 100% of the time. My current professor tought me this technique and instead of substituting you can also use cramers rule which makes this type of problems 60% easier than they seem. Trust me it saves a lot of time.

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yes, but you'll need to arrange the (v1-v2) and (v2-v1) by a lot. It won't make the problems easier nor harder.

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