Abstract Algebra | The third isomorphism theorem for groups.

[@nik5132]

These types of videos get little recognition, but give some the biggest sigh of relief when found. Thank you!

[@maxdickens9280]

Indeed, I discovered that the quality of these videos matches that of a top university course.

[@leonelcontreras652]

thank you for uploading your videos! spent an entire week trying to prove it on my own and had no idea how to do it. great job, i hope to see more videos from you in the future

[@OvsankaPoutram]

Man, I adore your videos!!!

[@culturecreating]

his physique as well

[@parthajitsarmah5847]

You explain the topics so precisely.. thanks a lot for your efforts ❤️

[@adamwilkshire2]

really enjoyed this series on the isomorphisms. Be aware views, that the definition of well defined can be found in his video on coset equality. In particulalr the crucial step that g1H = g2H => g1g2^-1 belongs to H.

[@zzykrkv8322]

6:35 lmaooo did you just accidentally say "coshit" instead of coset

[@ONUTPEN1]

Just REMARKABLE! Thanks again.

[@madurangaperera4333]

1st isomorphism theorem does it need be onto homomorphism?

[@MuffinsAPlenty]

A homomorphism does not need to be onto/surjective to use the first isomorphism theorem. The first isomorphism theorem gives you an isomorphism with the image/range of the homomorphism. However, if a homomorphism is onto/surjective, then the image/range is the whole codomain. So in practice, to show that a quotient group G/N is isomorphic to another group H, one will take a group homomorphism from G to H with kernel equal to N and which is surjective/onto.

[@rl512]

gN = g’N implies g^-1g’ is in N (not g(g’)^-1)

[@iqramalick1795]

Great job 👍

[@charitylyngdoh8912]

Thank You Sir 🙏🙏

[@ISLAMMOHDKHIREDIES]

Thank you

[@NavidVali]

love you mate

[@ZaBaloch-pl7wn]

Nice