Visit ilectureonline.com for more math and science lectures! In this video I will calculate the magnitude and direction of the acceleration of a charged particle in a magnetic field.
Пікірлер: 72
@sharrysingh42438 жыл бұрын
Thank You so much Mr. Biezen! Because of you, I got 93 on my physics exam! Love your video and you do such a great job explaining the problems and the concepts.
@MichelvanBiezen8 жыл бұрын
+Rice Spice Great job! Keep up the good work.
@austinhaider1055 жыл бұрын
Love the breakdown of the units from Tesla’s to the answer.. it seems like so many professors overlook the benefit that an intuition of units can give. Your one of the best physics lecturers I’ve seen and certainly the best one on KZbin. Thank you for your edification!
@MichelvanBiezen8 жыл бұрын
The Weirdologist, But we are not doing X x Y. The direction of the force is determined by v x B Therefore it is in the negative z direction
@Jc1235 жыл бұрын
For anyone confused on the direction of the Magnetic force. You can always check your work by taking the cross product of the direction (Unit) vectors Being that i hat = j hat = and k hat = < 0,0,1> j X i = -k Or in other words the direction of the Magnetic force. is in the negative z axis
@oqhr7 жыл бұрын
thank you for the effort. your lessons are really helpful and clear
@ThousandGigs10 жыл бұрын
without you I wouldn't sand a chance against my physics exams. Thanks from south africa
@MichelvanBiezen10 жыл бұрын
Great that these videos are helping. Keep up the hard work.
@Paperman2995 жыл бұрын
This has been commented so many times but you are legit amazing
@iammoonjooyoung6 жыл бұрын
Better than my professor.
@emiliaborjavelarde7214 жыл бұрын
thank you so much!!! your videos are truly amazing, you help me a lot
@vidaflowmotion4 жыл бұрын
Why is the angle 90 degrees? The magnetic field is slanting downwards, thus shouldn't the angle between V and B be less than 90 degrees?
@valeriereid2337 Жыл бұрын
Thanks so much for explaining the units at the end and not missing any step. I needed this!
@MichelvanBiezen Жыл бұрын
Glad it was helpful!
@MichelvanBiezen Жыл бұрын
Glad you found our videos. 🙂
@LoVeToPMTeTo6 жыл бұрын
he's the best
@chillinandconflictin7 жыл бұрын
Why was the y component not included in the Magnetic Field calculation? If you're crossing it, shouldn't it be x?
@MichelvanBiezen7 жыл бұрын
You only need the perpendicular component.
@izhakbar9 жыл бұрын
thank you so much. REALLY.
@kaylachoi47919 жыл бұрын
can you explain how to use the right hand rule in getting the direction for the acceleration? So the x direction would be where your fingers point and the positive y direction where your fingers curl, and the thumb would be the acceleration?
@ridwan74103 жыл бұрын
Thanks for the class. It was very helpful. One little confusion I had been having. From where are you using the formula F=q(v*B)..I mean is there any proof of the derivation of that formula? Is it included in this segment? I would be very much obliged to get some heads up about the problems I had been having. Thanks once again.
@bonnieandersona.brandao26777 жыл бұрын
I love you!!!! for sure = DD
@carolinek10394 жыл бұрын
Hello Mr. Biezen, I hope you're doing well. When I solved the problem, I found the magnitude of the vector B and said that the angle between V and B is (90+26.56) and I got the same result as yours, is this method accurate?
@MichelvanBiezen4 жыл бұрын
Yes, you will get the correct magnitude that way.
@alvarozerkowski37069 жыл бұрын
I didnt know the units for T. Cool.
@chibingwei7616 жыл бұрын
sir,what rule you use?can use Fleming left hand rule or not?
@MichelvanBiezen6 жыл бұрын
You can use the Fleming left hand rule. You will get the same result.
@chibingwei7616 жыл бұрын
Michel van Biezen sir use what method?
@MichelvanBiezen6 жыл бұрын
If you go to the beginning of the playlist (the first videos) you can see how the technique works.
@joel.1038 жыл бұрын
Hi prof. I was wondering, isn't the magnitude of the Force supposed to be calculated with the angle between v and the B? You considered the angle between v and the X axis...
@MichelvanBiezen8 жыл бұрын
+JLion ofZion We multiplied v with the x-component of the B-field. (which is the perpendicular component to v)
@norhidayah76548 жыл бұрын
It is stated that v parallel to y axis so there's no force and thats why we only consider x axis
@hasibullahmahmood74576 жыл бұрын
darkbrown _ You make it more clear, thank you
@bit91033 жыл бұрын
Why did you draw the magnetic field lines as if they are going down , in the question they did not mention anything about the way we should draw the magnetic field so what made you decide to draw it in that way ? and what is that sign that you draw on top of vector F and the others ?
@MichelvanBiezen3 жыл бұрын
The direction of the magnetic field was given in the problem as a vector field. The symbol on top of the letter representing vectors is an arrow.
@bit91033 жыл бұрын
@@MichelvanBiezen A vector field always points down the same way you drew it and at that angle as well ? and thank you for replying !
@iLavaRF7 жыл бұрын
Is the acceleration that you calculated, the radial acceleration?
@MichelvanBiezen7 жыл бұрын
That is the tangential acceleration (along the curve of the path).
@mrclutch55008 жыл бұрын
So is z basically the opposite of whether the charge is into or out of the board?
@MichelvanBiezen8 жыл бұрын
+Mr Clutch Yes, positive z is out of the board and negative z is into the board.
@mrclutch55008 жыл бұрын
ok thanks for the help
@shahwali42916 жыл бұрын
sir how you assume the magnetic field in a direction as shown above?
@MichelvanBiezen6 жыл бұрын
The direction of the magnetic field is a "given" in the problem for the purpose of illustration. (we didn't have to figure it out).
@shahwali42916 жыл бұрын
Michel van Biezen sir i am asking about the way you draw the B field lines.
@MichelvanBiezen6 жыл бұрын
Once you know the direction of the field you simply draw arrows. If the field goes into the board we draw "crosses". If the field comes out of the board, we draw dots.
@TheWeirdologist8 жыл бұрын
Shouldn't the force be in the positive z-axis (+k)? X x Y is Z, isn't it?
@lorieannalmandres46633 жыл бұрын
yes, same question...
@TheWeirdologist3 жыл бұрын
@@lorieannalmandres4663 this was Michel's comment on my post: "But we are not doing X x Y. The direction of the force is determined by v x B Therefore it is in the negative z direction"
@4draven4183 жыл бұрын
Hello, Michel van Biezen. Why is there no sound just on these 1-6 videos? video 7 onward...no problem. I had watched them a while back and recommended them to a friend who wanted refreshers on the subject. He said that there was no sound.
@MichelvanBiezen3 жыл бұрын
Our older videos were recorded in mono sound (before we figured out what we were doing). Sound will come out on one side.
@4draven4183 жыл бұрын
@@MichelvanBiezen Thank you for your reply. Re setting sound out put doesn't work. But never mind, my friend said he will use the subtitle after all, is is only 1 to 6 that are affect. Thank you again.
@asaadalalawi35615 жыл бұрын
this a centripetal acceleration right?, so the actual speed does't change but direction?
@MichelvanBiezen5 жыл бұрын
The force and acceleration found here is the instantaneous force and acceleration (magnitude and direction). Since the motion of the charge is not perpendicular to the magnetic field, the eventual motion will not be circular (initially) and therefore the motion is not strictly centripetal. Once the motion of the charge is perpendicular to the magnetic field the charge will move in a circular path.
@asaadalalawi35615 жыл бұрын
@@MichelvanBiezen Thank you professor.
@hythe49364 ай бұрын
How do you know the direction is into the board
@MichelvanBiezen4 ай бұрын
Using the right hand rule. We have a video on that (I believe it is the first one in the playlist)
@user-rb3ww3yl5d8 жыл бұрын
I have a question. 1.5*10^-3 kg^2*9.8m/s^2 is a very big number compared with 2*10^-3 N,then why is the force of gravity negligible in this case?
@MichelvanBiezen8 жыл бұрын
In this problem we chose to ignore gravity. If we take the x-y plane to be horizontal, gravity would not be a factor in the x-y direction.
@user-rb3ww3yl5d8 жыл бұрын
Michel van Biezen Thank you very much for answering my question!
@hamzahazzam6684 жыл бұрын
Why -10Tj, is not be written in formula?
@emiliobascary47938 жыл бұрын
the force should be in the positive z-axis direction
@MichelvanBiezen8 жыл бұрын
The force on the moving charge is drawn correctly as drawn "into the board". Thanks for checking.
@emiliobascary47938 жыл бұрын
I´m confused, the force shouldn´t not be popping out the board?
@MichelvanBiezen8 жыл бұрын
The way to check is to take your right hand (since it is a positive charge), point your finger in the direction of motion of the charge (up) and then curl your fingers in the direction of the magnetic field (to the right). Your thumb will point in the direction of the force.
@markjaypar56223 жыл бұрын
My brain be like:🤔whatttttttttt!!!!!!!!
@lorieannalmandres46633 жыл бұрын
isn't X x Y or the +z direction into the page? thank youu
@MichelvanBiezen3 жыл бұрын
As indicated in the video, the direction of the force is in the negative z-direction. (v x B) Not that the positive charge is moving in the positive y direction
@lorieannalmandres46633 жыл бұрын
@@MichelvanBiezen Thank you for your response :) but I'm quite confused in the 5:14 timestamp when you said that the +z direction is out of the page. May I ask what variables did you cross each other with?
@MichelvanBiezen3 жыл бұрын
X x Y is indeed a vector that points in the positive z direction. But in this problem the motion of the positive charge in in the y -direction and the horizontal component of the B-field is in the positive x - direction. Therefore Y x X is a vector in the negative z-direction.
@lorieannalmandres46633 жыл бұрын
@@MichelvanBiezen ohh! that is why! you're the best prof out there, mr. biezen! I have been relying on your physics lectures this semester because i think your videos are the most comprehensive and easy to understand. I owe my grades to you 😁 Cheers to helping more people like me 🥺 I wish you the best and please stay safe!! 💟
@MichelvanBiezen3 жыл бұрын
Thank you and glad we are able to help.
@wawanhitam2 жыл бұрын
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