Videos like these make me feel so grateful about youtube.
@PavlosAssimenos8 ай бұрын
You’re such an excellent professor, easy to understand, easy to follow. Keep up the great work, knowledgable sir!
@MichelvanBiezen8 ай бұрын
Thank you. Glad you found our videos.
@christ010119947 жыл бұрын
Your explanations are very explicit and easy to follow... Tremendously helpful
@aramisstavridis64495 жыл бұрын
youre the best prof i've ever had
@يحيىالعراقي-ج1ظ7 жыл бұрын
Thank you so much. You are great engineer
@baigao60626 жыл бұрын
Oh Mr Biezen you saved my life! I am currently a mehcanical engineering student who want to transfer my major to electrical enginneering in Master and doctor! Semicondutor always seems so difficult to me, but it will be not like this anymore because of your video!
@bubududucartoon8 жыл бұрын
ur awesome sir no one can explain very clear like u
@ezeprojects54255 жыл бұрын
Great series of lectures. Appreciate your time.
@duncanmckenzie28157 жыл бұрын
Very clear explanation. Very helpful to anyone like myself studying electronics.
@mykedoes4099 Жыл бұрын
Hey Mike , I studied ITT Tech , just thought to let you know i am subscribed and hope to learn a lot . Good stuff man
@MichelvanBiezen Жыл бұрын
Glad to have you on board. Welcome to the channel! 🙂
@Cheesypockets3 жыл бұрын
I assume the 300 microamps is just for the saturation not for the maximum base current the transistor can take?
@MichelvanBiezen3 жыл бұрын
It is the base current required to produce a 30 mA collector current. Not the maximum available current.
@tupai625 жыл бұрын
what the base resistor calculation formula for BD139 transistor?
@mechanicclemont47995 жыл бұрын
Professor, Can I ask you about mechanical vibration??? MIT uploaded lecture video about mechanical vibration with subtitle and I don't know whether listening that video is a wise time-spending... Is it related to mechanical or electrical engineering???
@AvZNaV9 жыл бұрын
Your title says "NPN Transmitter" instead of "NPN Transistor". Very helpful video, though. Thanks!
@MichelvanBiezen9 жыл бұрын
+AvZ “Astatine” NaV Thank you. We'll correct it.
@anueie3627 жыл бұрын
thank you sir,your great
@cmrr30996 жыл бұрын
thank you sir best
@ianloveservice4 жыл бұрын
i have a question guys, why 30milliAmps divided by 100 is equal to 300 micro Amps??? Please answer me, thank you
@WisdomAndWhisk4 жыл бұрын
Well, in order to better understand. Most calculators ignore trailing zeroes to the right of the number since zero has no end, you just have to imagine they are there. That is why the fancy calculators like a TI-83 has what is called Scientific Notation and Engineering Notation. This allows to see the trailing zeroes but it is specific to the notations being used. In our case, since we are Engineers, we are using Engineering Notation. So if you look at a normal calculator, you would see that 30mA is actually 0.03 in a normal calculator because it is ignoring the trailing zeroes. So the TI-83 sees something more like this 0.0300000000000000=> repeating. Because it is using a function called engineering notation, it knows that in order to look at the number, more clearly it will move the decimal place to the next common engineering notation representation of this number which is in our case milli. So your 0.0300000000 will actually be now 0.030 or 30mA. So in the example shown above in the lecture, if you were to take 0.030/100 it will give you on a normal calculator a value of 0.0003. But you just have to imagine the trailing zeroes so you can see it as 0.000300000=>repeating. So if you can see, the next engineering notation you can move over is in milli, so if you move over the decimal 3 places to the right, the milli representation of that new value is actually 0.3mA. But since he wanted to show it in a nice whole number representation, he move the decimal places another 3 places to the right to put it in the micro engineering notation and thus giving you 300uA. It is more of a visual representation so if you really wanted to go even further, you can even put it in the next 3 decimal places to the right, which would give you nano representation of that value. So it would be 300,000nA. I hope this helps. Clarify it a bit.