Physics 4 Newton's Laws of Motion (19 of 20) Statics: Example 2

[@valerypaul8994]

Hi , I'm french , i'm 59 .. I understand evrything .. It seem so easy when you explain ..Thank you very much ....

[@MichelvanBiezen]

Glad you like the videos. Welcome to the channel!

[@HamachiD]

physics explained right learned a 2 hour lecture in less than 10 minutes

[@historyisthebest5831]

Straight to the point and each video is meant for a specific topic or a kind of problem.

[@masone.6850]

Hades Qamar exactly

[@MichelvanBiezen]

Aung. Tension is a vector. Vectors have magnitude and direction. The magnitude of a vector cannot be negative.

[@kalkidantekle4575]

How can I get you to ask questions

[@Smile_youreoncamera]

Hello, I am an IB student in HL physics, and my physics teacher sucks at explaining concepts, so thank you so much for your videos :)

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so relatable

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OMG IM A HL STUDENT TOO

[@may21st1]

This video helps a lot. Actually all of your videos. I thank you a lot for uploading the videos. I have been learning physics (I got nothing during my high school) at your web and somehow it is hard to find exercise to test my understanding. The way you explain sir is perfectly clear and easy to follow. It would have been great if you could also include some exercises about the topic you just explain. I hope you would consider my advice. Once again thank you very much and keep on uploading videos

[@MichelvanBiezen]

Good advice. We do show a number of examples with the intent that the viewer tries to work them on his/her own. In the future we plan on showing how to take certain exams around the world with examples but again that is for the future. We are still developing a lot of the base material for the channel.

[@microwaves2107]

5:32 why did you take the cos of 45?

[@MichelvanBiezen]

We take the cos and sin of the 2 angles to find the horizontal and vertical components of the two tensions.

[@microwaves2107]

@@MichelvanBiezen thanks for replying! :) Follow up question is, why did you put sin 45 there?

[@MichelvanBiezen]

cos and sin for the x and y components of the tension

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dear sir we wouldn't exist without you

[@MichelvanBiezen]

The world would go on just fine without me. Glad we were able to play a small role in it. 🙂

[@Jonathan-vx7xi]

you are a specimen professor...saw this problem last week and couldn't figure it out...you showed the solution succinctly, this one goes in the notebook...thanks

[@MichelvanBiezen]

You are welcome!

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You are a fantastic teacher and have helped me so much, I am sincerely very happy to have found your videos. My online professor needs to take a hint and provide some lecture videos since physics is not the easiest of topics especially if you are taking it online. Thank You!!!!

[@muhammadabubakar639]

do you have a video in which angle and t1 and t2 are calculated?

[@uzairarshad9976]

Sir, why we took the T3=mg to be negative and acting downward. Does the tension not always act upward??

[@MichelvanBiezen]

Tension and force are vectors. The magnitude of vectors are always positive. The sign determines which way that are directed in. So when we compare the magnitude of vectors, the must be positive.

[@ayeshafayyaz1683]

when you plug in the value of mg, in the second equation, won't the value of g be negative (-9.8) cuz the direction is downward?

[@MichelvanBiezen]

When using g for static problems like these, you use the magnitude of g (always positive) and use the sign to indicate the direction of the force (vector).

[@albertgeller]

The example 1 of this subject isnt added to your mechanics playlist.

[@sanguine9031]

Why does T3 point downwards, shouldnt the tension be upwards?

[@SomethingCool51]

wow this guy is efficient. great info and I didn't have to sit through an unnecessarily long video

[@jerrysmith9780]

I have watched so many of your videos and my understanding of physics has improved 10x what it was even during the time I was in university, but I'm still confused on something. A mass falling from 10 metres above ground will more easily bend a piece of steel than the same mass dropped from 1 metre, yet both induce the same force. Would you help me understand what I'm missing?

[@MichelvanBiezen]

Actually they don't impart the same force. To understand that better we have to use momentum and impulse. (see the videos on impulse and momentum). Since impulse (during a collision) is equal to the force x time spent during the collision and since impulse is also equal to the change in momentum, if we let the time be the same, then the increased force is caused by the increased change in momentum.

[@jerrysmith9780]

@@MichelvanBiezen I will begin watching those this evening. Thank you again. I'll be sure to donate again.

[@faizasikandar6050]

Why we subtitute t of cos in sin equation

[@victoriaaguilar361]

do you have a video that works a problem that finds the mass and the givens are t1 & t2 and and two angles ?

[@MichelvanBiezen]

+Victoria Aguilar The approach is exactly the same. The sum of the forces in the x-direction add up to zero and the sum of the forces in the y-direction add up to zero. Find the x and y components of T1 and T2 and then add them up. You'll find the unknown mass.

[@briankylegarsuta1190]

then how to get the tension of t3?

[@MichelvanBiezen]

T3 = the weight of the hanging object = mg

[@briankylegarsuta1190]

Thankyou!

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Just stopping by to say THANK YOU! Your videos are very helpful

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You are a godsend thank you!

[@TheBetito123]

i know this is a dumb question but when replacing the variable with the equation why i need to use the Fx=0 equation one? can i solve for the variable using the Fy=0 equation?

[@TheBetito123]

Example i have this equation: Fy=0 Mg-sine40*T1-Sine50*T2=0 now i solve for T2 T2=Mg-sine40T1 --------------------- Sine 50 can i plug that equation for T2 instead of using the one from Fx=0?

[@MichelvanBiezen]

In any static situation, both the sum of the forces in the x-direction add up to zero, AND all the forces in the y-direction add up to zero. You can use either equation to solve the problem (and sometimes you need to use both).

[@Arespostale]

Your videos are amazing! It's very detailed and very helpful. Thanks to you, I now understand how to do these Physics problems! :)

[@PolkadOfficial]

end of 2020 here. Thanks for your help. Greetings from South America:)

[@MichelvanBiezen]

Welcome to the channel!

[@jehraldlansang5767]

Thanks a lot sir :) The best online teacher.

[@erikm5753]

What if the mass was on a pulley at the T1/T2 junction? Assume angles stay different because T1 or T2 is not attached at same height

[@pk-dz3fk]

how would i go about this if i was given the tension of one string and an angle of the same one?

[@MichelvanBiezen]

What is given and what is asked?

[@rajivhardeo1193]

god bless my friend this was very very helpful

[@vuongngo2181]

You are the best sir!

[@jezzanabong9428]

why is g not negative

[@MichelvanBiezen]

g is a vector quantity which means that it has both magnitude and direction. The magnitude of a vector cannot be negative. So if we use the magnitude of g it will be positive. if we use g as a vector it will have a negative direction.

[@jezzanabong9428]

@@MichelvanBiezen thank you!

[@johannagerhardsen5102]

Thank you for this! You made this so much easier to grasp!

[@yashtomar6225]

It is 8 years old and still helping me.😊

[@MichelvanBiezen]

good to know. Thanks

[@moe4983]

why did you take the Cosine of T2 sine 45 when you got (0.707) ???

[@MichelvanBiezen]

Moe, Not sure what you are asking....

[@Virxo182]

During the video he says cos but means sin. If you follow the work it is correct

[@petereziagor4604]

Thank you prof. Easy now

[@MichelvanBiezen]

Great. Glad you got the concept.

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The best teacher

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[@MichelvanBiezen]

Glad you found our videos. (Pass the word). 🙂

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helped a lot.thanks a bunch mister!

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[@TheSureBlock]

Amazing! Thank you so much for your help!

[@arleighjanpangatungan953]

Thank you so much sir for helping me with my homework

[@MichelvanBiezen]

Glad to be of help.

[@unikumet]

I get another result by solving it the following way, please correct me if I'm wrong: (-)1 = 30* and (-)2 = 45* T1 = T2Cos(-)2 /Cos (-)1 => plug it into the Y-formula => Solving T2 as: T2= mg / (1+ (Cos(-)2 / Cos(-)1)*Sin(-)2) By doing this I get that T2 = 12.438 N and T1 = 10.156N Can anyone relate to this? Edit: Have no idea why KZbin puts a ----- line across some of the writing. Ignore the line.

[@michaelbarbee8960]

you took the cos of 45 why? it clearly states you take the sine of 45

[@MichelvanBiezen]

Michael, Remember the definition of sin (theta) = OPPOSITE SIDE/Hypothenuse cos (theta) = ADJACENT SIDE / Hypothenuse and cos(45) = sin(45)

[@josephsaab6727]

dude, that is true what you said. He might mistakenly said cosine instead of sin, or he may calculated cosine instead of sin. However, he is lucky :), sin and cos of 45 degrees are the same (square root of two over two or 0.707). The question is why you are that frustrated? chill :) .

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[@mido-tl4vx]

sin rule is gonna save a lot of time

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Great...Thank you so much...

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That bow tie tho

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