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Electrical Engineering: Basic Laws (12 of 31) Kirchhoff's Laws: A Harder

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Michel van Biezen

Michel van Biezen

Күн бұрын

Пікірлер: 369
@BentHestad
@BentHestad 7 жыл бұрын
Sir! There should be a Nobel price for excellence in teaching! And You should get the first!
@nicholasjaikeran5041
@nicholasjaikeran5041 6 жыл бұрын
Best mathemati
@joshuacharlery5826
@joshuacharlery5826 4 жыл бұрын
🙂
@chronicsnail6675
@chronicsnail6675 3 жыл бұрын
Feynam gets one and Leonard susskind get ons
@christianjaycanilang1477
@christianjaycanilang1477 3 жыл бұрын
I agree❤❤
@shielalabapis4624
@shielalabapis4624 3 жыл бұрын
Q
@buffysummers1177
@buffysummers1177 3 жыл бұрын
I was stuck on this topic for such a long time and in only 9 minutes I understood it, you really saved me an all-nighter. Thank you so much. Your teaching is phenomenal.
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
Glad it helped!
@ladyvader4358
@ladyvader4358 6 жыл бұрын
Nobel prize for teaching!You are a great teacher, sir!Thanks for all the tutorials!
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
Thank you for the comment.
@ii_ragee752
@ii_ragee752 3 жыл бұрын
this professor saved the day. I spent hours trying to understand this stuff till I watched this thanks PROFESSOR. 9 minutes saved 24 hours.
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
glad it helped.
@philipjohn1338
@philipjohn1338 2 жыл бұрын
You, Sir, are the kind of professor I need.
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Glad you found our videos! 🙂
@melissapardo2688
@melissapardo2688 7 жыл бұрын
You're the best! I wish you were my professor.
@jacobb7379
@jacobb7379 4 жыл бұрын
Bruh this is so beautifully smooth. I was literally melting my brain before but not I can answer these questions in 2 seconds. Also, I’m not at university yet, but I can still understand this because of the really easy method of assuming the direction of current. Thank you so much sir
@enviivalentin9403
@enviivalentin9403 4 жыл бұрын
I just wanted to say THANK YOU! I've watched like 10 videos trying to understand this Law and honestly, you've made it so easy to understand!! In very short steps which I love!
@dewmiranasinghe4039
@dewmiranasinghe4039 Ай бұрын
10 hour lesson in 9 minutes he saved my life god bless sir
@MichelvanBiezen
@MichelvanBiezen Ай бұрын
Thank you. Glad you found the video helpful
@chinny3393
@chinny3393 2 жыл бұрын
I really recommend this proffesor. Ive been struggling to anwer my homework for 3 hours but within just 9 minutes I manage to finish it with the help of this video. THANK YOU VERY MUCH SIR!!
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Thank you. Glad you found our videos. We have covered all topics in physics on this channel.
@zerograv
@zerograv 7 жыл бұрын
thank you ...you saved me because i just couldn't wrap my head around it ... now i only need to find out how to put it in a matrix and i'll be set ^^
@thapedimahapa2564
@thapedimahapa2564 2 жыл бұрын
You out of all the videos I have seen have made me understand kirchoffs rule. Especially when it comes to the direction convention for voltages. Keep it up sir
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Glad you found our videos and you found them helpful. 🙂
@sleeping4cat
@sleeping4cat 2 жыл бұрын
Not gonna lie! I missed some lectures of my Electrical Physics class. And I tried to make it up using Khan Academy and other videos and online resources unfortunately all pf them were crappy except this guy! He made Kricchoff's rule sound so easy now I can easily take nap knowing I'm prepared for my exams! Thanks Man!
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Glad I could help!
@abdussalamadeagbo7441
@abdussalamadeagbo7441 2 жыл бұрын
After watching your videos I actually have confidence for my exams. You are truly a great teacher. Thank you.
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Happy to hear that! Good luck on your exams.
@apangmasan346
@apangmasan346 2 жыл бұрын
I love your precise teaching. Straight and clear. Appreciate your intelligence
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Thank you. Glad you found our videos!
@spartacusferdo1178
@spartacusferdo1178 3 жыл бұрын
Thank you very much..honestly..I went through several videos...but you gave me the enlightenment..even in school, this went terribly wrong! especially the direction of the flow, you mentioned it clearly! just fafded away my doubts! thank you, Sir!
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
You are very welcome
@savahnnacunningham7463
@savahnnacunningham7463 8 жыл бұрын
THANK YOU! You are a gifted teacher and I learn so much from watching your videos.
@flitzert3716
@flitzert3716 3 жыл бұрын
The World need people like you profesor
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
Thank you, we appreciate your comment.
@nicholasjaikeran5041
@nicholasjaikeran5041 6 жыл бұрын
Best mathematics and physics teacher in the world
@sudheerm.s6792
@sudheerm.s6792 2 жыл бұрын
Only this guy in KZbin clearly got an idea about kirchhoff's law.
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Glad you like the videos on Kirchhoff's laws.
@dinusiva3019
@dinusiva3019 6 жыл бұрын
Sir ur a great teacher......u deserve a hatts off......
@mmabathomakhura2381
@mmabathomakhura2381 2 жыл бұрын
After watching multiple videos over a few months , i got even more confused but today i stumbled upon this video and i understand this topic. Thank you sir for the great work
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Glad it helped!
@Lew.6
@Lew.6 7 ай бұрын
Just left this open on my laptop for revision tomorrow. I bet it will help more than any of my dumb lecturers
@MichelvanBiezen
@MichelvanBiezen 7 ай бұрын
Hope it was helpful.
@mrmillmill
@mrmillmill 2 ай бұрын
By far the most excellent online course on basic engineering circuit analysis even compared to the college courses
@TheCeremoniesOfIsrael
@TheCeremoniesOfIsrael 3 жыл бұрын
U are brilliant God has designed u perfectly to help humanity God bless u
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
I am blessed to be able to serve.
@rollandjeffersonmejia5983
@rollandjeffersonmejia5983 7 жыл бұрын
Thank you so much sir. I will recommend you to all of my friends. Keep on making tutorial! By the way you look like Steve Jobs :)
@ricebubbles-v5w
@ricebubbles-v5w 2 ай бұрын
Stuck on this for 2 flipping years....2...and just picked it up in 9mins....the time I've wasted...the time 😢
@RayleenSevua
@RayleenSevua Жыл бұрын
Sir! You are the best professor I need.
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
Thank you. Glad you found our videos. 🙂
@danielgray2280
@danielgray2280 Жыл бұрын
Thanks a lot, I am a senior high student and I have been facing problem but becus of you I now understand it well
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
Great! Glad you found our videos. 🙂
@setenaysimsek4667
@setenaysimsek4667 5 жыл бұрын
I LOVE YOU SO MUCH.You are the best teacher ı have ever seen.I don't have to memorize everthing no longer
@yohanneskebede2323
@yohanneskebede2323 Жыл бұрын
Thank you sir, you are really the best teacher ever.
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
Wow, thanks. We appreciate your comment. 🙂
@Drone360pilot
@Drone360pilot Жыл бұрын
Bravo! Mr. Michel !!! Brilliant and clean explanation ! Deep respect ! 🤓
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
Thank you. Glad you found it helpful. 🙂
@joannabaidoo331
@joannabaidoo331 7 жыл бұрын
THANK YOU SO MUCH ! I WISH I KNEW YOUR ADDRESS TO SEND YOU LOADS OF GIFTS. YOU ARE GIFTED ! PLEASE KEEP DOING WHAT YOU ARE DOING GOD BLESS YOU !
@sunnysun6358
@sunnysun6358 8 жыл бұрын
Hi, is there any other way u could explain the general sign convention when applying KVL? And in the case of loop 2, why is the equation 8 i2+ 6 i3 -4=0 instead of 8 i2+ 6 i3 +4=0. Isn't the current flow opposite to direction of loop for 4V voltage source? Many thanks :)
@MichelvanBiezen
@MichelvanBiezen 8 жыл бұрын
Since you are going around loop 2 in a counterclockwise direction, you cross the battery from the positive end of the battery to the negative end, thus there is a 4V voltage drop. When picking current directions in each branch it doesn't matter if the directions are correct. (The assumed directions could be opposite to the real directions). Then work out the problem as is shown. If you picked the incorrect direction, your answer(s) will come out negative.
@sequii_chan
@sequii_chan 21 күн бұрын
question, in 5:58 how did you get the (3) for multiplying equation 3?
@cosmocelli
@cosmocelli 6 жыл бұрын
Thank you for this! I've learned so much from watching you videos. Kudos to you sir!
@hrithikkhemani3230
@hrithikkhemani3230 3 жыл бұрын
amazing thank you i wish i had him has a teacher.
@jonathana9236
@jonathana9236 Жыл бұрын
I have a problem similar to this except with different numbers and have had trouble with the currents. Major Thank you for this
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
Glad it helped! 🙂
@domfackloic8930
@domfackloic8930 2 жыл бұрын
Sir I just want to say am very happy with the explanation it going to help alot and I also want say keep up
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Glad you found our videos. 🙂
@domfackloic8930
@domfackloic8930 2 жыл бұрын
@@MichelvanBiezen yes sir and hope to see more
@purixlupa1
@purixlupa1 3 жыл бұрын
Sir thank you for always posting helpful videos. 🙏
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
Always welcome
@mathiasgrenacs3680
@mathiasgrenacs3680 8 ай бұрын
3 unknown currents. Use Kirchoff's laws (1st law once, 2nd law twice) and Ohm's law to establish system of 3 algebraic equations. Put that in any math software or any TI, HP pocket calculator and it's done.
@MichelvanBiezen
@MichelvanBiezen 8 ай бұрын
Yes indeed, solving the 3 equations 3 unknowns type of problem can be done with any app or program or calculator which has that programmed. But it is important that we learn how to do that.
@cosmos8366
@cosmos8366 2 жыл бұрын
At 7:50 when you moved 6(-0.308) to the other side you changed te negative sign to a positive which i get but why didn't the positive 6 change to a negative. I'm still learning algebra so I'm still learning all the tricks of moving everything around. Thanks David.
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
- 6 (0.308) = 6 (- 0.308) but that is NOT equal to -6 (- 0.308) = 6 (0.308)
@cosmos8366
@cosmos8366 2 жыл бұрын
@@MichelvanBiezen looking at your answer I couldn't figure out but after doing the calculations now it makes sense. doing it your way gets a positive1.848 which is right. doing it my way would have resulted in a -1.848 which is wrong. As a beginner I would not have known that and would have changed the 6 to a negative. Is that allways the case, if a number is multiplied by a number in brackets you change the sign of the numbers in the brackets but the number outside the bracket you don't change. Isthere some kind of albebra rule that states that. Thanks for your help David
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Yes, you have to be VERY careful with the signs doing these types of problems.
@bobsual3912
@bobsual3912 Жыл бұрын
Thank u helps a lot. Im a grade12 students for the Philippines
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
Great! Glad you found our videos. Welcome to the channel! 🙂
@RowardRowapore
@RowardRowapore 2 ай бұрын
Thanks sir. You are amazing. You pushed me out where i stucked.
@christophersparkes2986
@christophersparkes2986 8 ай бұрын
Thank god for this video. I was about to lose my mind.
@MichelvanBiezen
@MichelvanBiezen 8 ай бұрын
Glad you found it, 🙂
@RickoRiak
@RickoRiak 4 ай бұрын
Finally i understand it, After long time
@ShlomsDaGangSta
@ShlomsDaGangSta 8 жыл бұрын
When you find the other currents, why do you plug in -.0308 Amps for I3. What if i assumed the correct direction for I3 at first, and got a positive value, then my I1 and I2 would be different values
@MichelvanBiezen
@MichelvanBiezen 8 жыл бұрын
+Shlomo No, you would get the same values for I1 and I2, no matter what direction you assume for any of the currents.
@sarah53062
@sarah53062 6 ай бұрын
The loops must be in the same direction? Both clockwise, or both anti-clock. Or can I do ine clock and the other anti-clock?
@MichelvanBiezen
@MichelvanBiezen 6 ай бұрын
They do not need to be in the same direction. You can go around each loop in any direction you like.
@MG-vb6ms
@MG-vb6ms 5 жыл бұрын
Can we apply Ohm's law for 4 ohm resistance and 10 v voltage? In that case current I1 will be equal to 10/4=2.5amp.which does not match with our I1.
@MichelvanBiezen
@MichelvanBiezen 5 жыл бұрын
No, you can't use the simple Ohm's law equation here because you have multiple voltage sources. Each source affects each branch in a way that is difficult to predict, unless you use Kirchhoff's rules.
@MG-vb6ms
@MG-vb6ms 5 жыл бұрын
@@MichelvanBiezen Thanks a million for the fast reply.
@mubarakrikiji6548
@mubarakrikiji6548 2 жыл бұрын
Nice job sir . Indeed i enjoyed the lecture . Keep on making life easy for us
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Glad it was helpful! 🙂
@deadbunnyeyes190
@deadbunnyeyes190 2 жыл бұрын
Is it possible to obtain the currents in a situation exactly like this but with another resistor at the second loop? I reckon it wouldn't be since there'd be 4 unknowns but only 3 equations...
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
You can have any number of resistors in any of the loops and this method will still work. We have examples like that.
@appleship4369
@appleship4369 2 жыл бұрын
Important question, is it wrong if i chose the direction of the current different for each loop? U choose clock wise if i chose anti clockwise for the first loop and clockwise for the second will it still add up corectly? Thx
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
You can choose the direction any way you like, (as long as you remain consistent throughout the problem). If you get a negative answer for the current, the actual direction is opposite to your chosen direction).
@spurti
@spurti 3 жыл бұрын
Hii I have a question about the battery is that inside of the battery you have electrons because of redox rxn's and there are electrons more (8 electrons for example) at the negative terminal and there are less electrons at the positive terminal (3 electrons). And I found out that at the negative terminal the electric potential of 8 electrons is (-8J/C) and the electric potential at the positive terminal, the electric potential of 3 electrons is (-3J/C) and when I take the voltage of the 2 points of electric potential then I got two possible answers that is +5V and -5V and I am not sure which one should I use???
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
The side with the least electrons (let's call it A) is at a higher potential than the side with the greater number of electrons (let's call it B) Then A - B is + 5 V and B - A = - 5 V
@woodychelton5590
@woodychelton5590 Жыл бұрын
is it correct to say that the voltage in that bottom node that I2 passes into via the 8 ohm resistor is 0?
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
Since the node is not connected to ground we don't know. Only if that section of the circtuit is connected to ground do we know that the voltage is zero.
@taiwoonasanya2746
@taiwoonasanya2746 3 жыл бұрын
Thank you sir,I wish you were my professor
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
Happy to help
@biridun9999
@biridun9999 6 ай бұрын
Why I1 and I2 goes down together instead of them splitting some of their currents to the both resistors i did not get that.
@biridun9999
@biridun9999 6 ай бұрын
Oh i get it now, divided the problem into two sections and calculated the currents of each voltages then combined them together and got the same results.
@MichelvanBiezen
@MichelvanBiezen 6 ай бұрын
Great. Glad you figured it out.
@OmarAhmed-sr2bt
@OmarAhmed-sr2bt 5 жыл бұрын
Nice explanation Profesor!
@yeonieee1
@yeonieee1 3 жыл бұрын
Sir, In getting the I2 why 6(-0.308)-4 becomes 4+6(0.308). I'm confused. It should 4-6(0.308), right?
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
We moved the two terms to the other side and therefore the sign changes. A - B - C = 0 becomes A = B + C
@zanebraunstein8366
@zanebraunstein8366 18 күн бұрын
you are an amazing teacher. Thank you.
@chinwubaamadi
@chinwubaamadi 5 ай бұрын
I don't seem to get it. Why are we multiplying it by 2 and 3? Is it because of the equation tag (Equation 2 & Equation 3).
@MichelvanBiezen
@MichelvanBiezen 5 ай бұрын
It is an algebra technique to solve the two equations two unknowns type of problem.
@abioladivine-peaceokikijes1657
@abioladivine-peaceokikijes1657 2 жыл бұрын
Thank you Please will changing the position of any one voltage source change any of the equation
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Not if the voltage source remains oriented the same way and stays on the same branch. Once it is moved to a different branch, it will change the equations.
@abioladivine-peaceokikijes1657
@abioladivine-peaceokikijes1657 2 жыл бұрын
@@MichelvanBiezen you actually replied. I love you Siirrr. Thank you, I understand
@martingregson7136
@martingregson7136 4 жыл бұрын
OK So at 5:34 you have stated that multiplying eq x 2 and eq 3 x 3 both both i1 from Eq1 and Eq2 become equal opposites canceling each other out, but how and why do we need to do this?
@MichelvanBiezen
@MichelvanBiezen 4 жыл бұрын
This is just one of the many methods that can be used to solve simultaneous equations, so we can determine the current in each branch.
@clownbag2173
@clownbag2173 4 жыл бұрын
@@MichelvanBiezen so are the answers suppose to the same in terms of like the 24 for example or can it be different
@successmotivation2997
@successmotivation2997 4 жыл бұрын
Please dont stop teaching your a expert
@Realayyes
@Realayyes 4 жыл бұрын
5:57 how am i suppose to know what number to multiply ?
@MichelvanBiezen
@MichelvanBiezen 4 жыл бұрын
That is a technique we learn in algebra when we use the elimination technique of solving simultaneous equations. What numbers do we multiply with so that the coefficients of one of the variable become the same? We could have used 14 and 8, but that would make the numbers very big.
@Realayyes
@Realayyes 4 жыл бұрын
@@MichelvanBiezen thank you
@NkemkaGentle
@NkemkaGentle 10 ай бұрын
Thanks so much sir for this 💯it made me understand better as beginner, But where my problems lies now is at your final answer in I2 i couldn't understand how you got 0.731A Pls sir can you explain it to me I'm just a beginner 🙏🏾
@MichelvanBiezen
@MichelvanBiezen 10 ай бұрын
Use equation 3 which only contains I2 and I3 and I3 is known. So substitute for I3 and now you have an equation with only 1 variable I2.
@NkemkaGentle
@NkemkaGentle 10 ай бұрын
@@MichelvanBiezen thank you so much sir I've gotten it I really appreciate, you're one in a million teachers 💯
@austinfritzke9305
@austinfritzke9305 4 жыл бұрын
You need a nobel prize for teaching just for that bow tie
@pradipbista607
@pradipbista607 6 жыл бұрын
sir, why did you assume loop2 in a clockwise direction?
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
It doesn't matter. You can assume either direction and it will work.
@christopherwilkins8954
@christopherwilkins8954 Жыл бұрын
Surely there's a better way to do these problems... Been stuck on these Loop and Junction rules all semester. How do you know which variable to solve for first for?
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
This is a very classic example of the use of Kirchhoff's rules. Hopefully after watching a few examples it will make sense. (We have similar examples in the physics playlists as well which is a prerequisite to this course).
@RichardJrEtil
@RichardJrEtil 3 жыл бұрын
In 7:54 the +6 (-0.308), when you move it to the other side it must become -6 (+0.308) am I right? please enlighten me... thanksss
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
No, what is shown in the video is correct. (Note that the 6 and (-0.308) are multiplied, not added)
@RichardJrEtil
@RichardJrEtil 3 жыл бұрын
@@MichelvanBiezen i wish you were my professor thanks sir!!
@treemanfan7718
@treemanfan7718 2 жыл бұрын
Could you correct me? I put i3 as clockwise which created i1 = i2+ i3. I moved the terms to get i1-i2 = i3. I plugged this into resistor 6 creating 6(i1-i2). Doing the system of equations I get an i1 of -0.18 which is different from your answer.
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
The answers in the video are correct. 6(i1 - i2) is not correct as a voltage drop
@anhdo6351
@anhdo6351 5 жыл бұрын
very good and helpful lectures from you. Hope all the best for you.
@wendymari8504
@wendymari8504 2 жыл бұрын
Thanks, this really helped me to understand it easier
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Glad to hear that!
@vinoriawareba9438
@vinoriawareba9438 Жыл бұрын
Thanks for the help sir ☺️.. great explaination 🤌🏼
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
Thank you. You are welcome.
@paulperriman9144
@paulperriman9144 4 жыл бұрын
I had an issue understanding how to do this..well.. not any more great teaching.. still not sure of the math procedure but very good.
@shnurik01
@shnurik01 5 жыл бұрын
why did you multiply the 1st equation by 2, and 2nd equation by 3? is that just random?
@MichelvanBiezen
@MichelvanBiezen 5 жыл бұрын
That is an algebraic method of solving 2 linear equations. (method of elimination)
@chillcloud8904
@chillcloud8904 Ай бұрын
how do you know what factor to multiply the equations by?
@MichelvanBiezen
@MichelvanBiezen Ай бұрын
This is an algebra trick. You multiply one (or both) of the equations in order to eliminate one of the variables, when you add the two equations.
@keldonchase4492
@keldonchase4492 2 ай бұрын
You calculated I1 to be positive, which means the direction you chose for I1 initially was correct. But looking at the diagram, I1 travels from the negative terminal to the positive terminal. Doesn’t this contradict the rule that conventional current is supposed to travel from positive to negative? What am I missing here? I would appreciate any feedback; thanks so much for your help :)
@bangtanedhoe4107
@bangtanedhoe4107 7 ай бұрын
is the process still the same if our teacher has given us the same structure example as yours but the difference is the middle part is an ampere load and we have another resistance on both lower parts of the rectangle. What should I do? please help😢
@MichelvanBiezen
@MichelvanBiezen 7 ай бұрын
Yes the process will be exactly the same, using Kirchhoff's rules.
@bangtanedhoe4107
@bangtanedhoe4107 7 ай бұрын
Should I combine the value of resistors on the upper and lower branch on both sides since it is in series so the structure can be the same as yours or should I just let it be and solve it as it is like you did?
@philipchan5535
@philipchan5535 3 жыл бұрын
If the + - side of that 4V battery is flipped, would the first equation still be i1+i3=i2?
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
The method is to assume the three current directions, regardless how the components are connected. If you guess wrong initially, you will end up with a negative answer, indicating the current is actually in the opposite direction.
@philipchan5535
@philipchan5535 3 жыл бұрын
@@MichelvanBiezen ok thank you.
@yusufmustafa7323
@yusufmustafa7323 2 жыл бұрын
Sir , I have a question What will happen if we take one loop clock wise and the other one anti clockwise Or one of them anti clockwise and the other clockwise.
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
It doesn't matter. You will get the same result. (but you have to keep track of your voltage rises and drops according to the direction you choose. Note by reversing direction, you'll get the negative result of the result you got from your original direction.
@mahlatsesteam3670
@mahlatsesteam3670 5 жыл бұрын
Thank u so much sir for your tutorials..means a lot to me
@AG-cx1ug
@AG-cx1ug 2 жыл бұрын
When we draw the Loop 2 - its in the opposite direction to I3 - I didn't understand this part. Thank you.
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
The arrows in the center of the loops, simply show the direction of "travel" around the loop (which is independent of the current direction) in order to add up all the voltages. KVL
@hirunrashentha1082
@hirunrashentha1082 3 жыл бұрын
Thanks alot sir 😊 Excellence teaching
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
Most welcome
@ngetichvictor-7901
@ngetichvictor-7901 Жыл бұрын
Nice work sir,,,it is understandable sir 🎉
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
Glad you liked it. 🙂
@xilavekonicholasbaloyi3978
@xilavekonicholasbaloyi3978 6 жыл бұрын
so do I have to multiply with 2&3 for all de problems. when want to eliminate .. or to form equation 3
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
It depends on the equation. It will be different for every equation.
@eduardo0796
@eduardo0796 4 жыл бұрын
If I3 has a negative sign, it means we have chosen the incorrect path of the current flow. Does that mean that I3 is actually positive? If so, when you plug in those values to solve for I1, insteaf of adding I2 and I3 (because - times - equals +), shouldn't we be substracting the values and thus we would get a different answer for I1?
@MichelvanBiezen
@MichelvanBiezen 4 жыл бұрын
The answer is no. Remember that we calculated all the currents assuming current directions. If we get a negative answer for one of the currents, it simply means that the current is moving in the opposite direction as assumed. Nothing else changes.
@eduardo0796
@eduardo0796 4 жыл бұрын
@@MichelvanBiezen Thank you so much for taking the time to clarify my doubt. Your videos are much appreciated.
@مفكال
@مفكال 2 жыл бұрын
should I get the same result if I used the mesh analysis method?
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Yes, you should obtain the same result no matter what method you use.
@vigorixx
@vigorixx Жыл бұрын
You have my appreciation.
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
Thank you. Glad you found our videos. 🙂
@sangeethatatineni6214
@sangeethatatineni6214 5 жыл бұрын
Thank you soo much sir, it was soo helpful. Good job !!
@MichelvanBiezen
@MichelvanBiezen 5 жыл бұрын
Thank you for your comment.
@vernaamparo2486
@vernaamparo2486 3 жыл бұрын
this is amazing! but I'vebeen meaning to ask, how about the voltage in that similar diagram?
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
The voltage rises and voltage drops are added on any loop.
@vernaamparo2486
@vernaamparo2486 3 жыл бұрын
@@MichelvanBiezen thank you! I just finished doing a task with similar missing points. hoping for more awesome content!
@carlosmiguelbarros
@carlosmiguelbarros 3 жыл бұрын
6.24 - why do you add the equations instead of subtracting? According to my notes we have been subtracting in class… I’m confused
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
You can do it either way. The algebraic method of elimination can be done either way.
@SinenhlanhlaArnold
@SinenhlanhlaArnold 6 ай бұрын
do you have videos with that involve dependent sources
@MichelvanBiezen
@MichelvanBiezen 6 ай бұрын
We have some.
@vedangisekra9399
@vedangisekra9399 4 жыл бұрын
Sir, do we have any short trick to solve these types of problems? I am preparing for NEET ( medical entrance exam in India ), so we have very little time to solve such problems... It would be great if you can tell a short trick. please
@MichelvanBiezen
@MichelvanBiezen 4 жыл бұрын
For this type of problem there is really no short cut. But that said, it does depend a lot on how the questions are asked on the exam. We are currently making a number of videos on the JEE advanced tests and often you don't have to work out the problem in detail to find the correct answers. We illustrate that in those videos. We haven't looked at the NEET exam yet. But we will and we'll try to determine how to best prepare for that. Our time is very limited, so we don't know when we can get to it.
@vedangisekra9399
@vedangisekra9399 4 жыл бұрын
@@MichelvanBiezen oh ok thank you, sir
@carultch
@carultch Жыл бұрын
@@vedangisekra9399 There is a shortcut. It's the method of superposition. To give an overview, you "turn on" one source at a time, and "turn off" the other sources.. Voltage sources become shorts when "turned off", and current sources become open gaps when "turned off". You then assign a point, or several points at which it is of interest to find the voltage, and would help you solve for everything else you'd like to know. Then you find the voltage at that point, exclusively due to each individual source. Then you add up the partial voltages, to find the total voltage at the waypoint you assigned. You then have the voltage at that point, which you can use to solve for everything else. This turns algebra into plug-and-chug arithmetic.
@yashasvprajapati6851
@yashasvprajapati6851 6 жыл бұрын
Sir, Is if important to take the direction of the loop in the same direction as yours or can We reverse the direction of loop in Loop 2. How do we determine the direction of loop? Could you please explain sir, It would be great. Thanks!
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
The direction is completely arbitrary. (you can pick any direction)
@axelgayondato5110
@axelgayondato5110 5 жыл бұрын
Is it really a must that the direction of the first loop that you assign must be the same for second loop? And also, is it okey if I will assign a counterclockwise direction on loop 2 even if the loop 1 travels in a clockwise direction?
@MichelvanBiezen
@MichelvanBiezen 5 жыл бұрын
Sure you can choose any direction for any of the loops.
@axelgayondato5110
@axelgayondato5110 5 жыл бұрын
@@MichelvanBiezen thank you so much sir. ☺️
@mariecurie465
@mariecurie465 7 ай бұрын
What if if theirs another resistor both left and after on I2 sir ?
@MichelvanBiezen
@MichelvanBiezen 7 ай бұрын
Simply add all the resistors on any branch. It will not change the method of how to solve this type of problem.
@itrstt66
@itrstt66 6 жыл бұрын
Why is direction of loop number 2 against I3 direction?
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
It doesn't matter. The direction you go around the loop is completely arbitrary.
@itrstt66
@itrstt66 6 жыл бұрын
Michel van Biezen thank you
@xcarnage8632
@xcarnage8632 6 жыл бұрын
sir you are god in disguise... thank you
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
Not in the least. Just another person trying to do his little part in the world.
@mercyalegada5811
@mercyalegada5811 3 жыл бұрын
Great sir! But i have a question sir, how about the circuit only have 1 voltage, 1 current entering and 3 current leaving ? There are 3 loops in total now , Thank youu sir ❤️
@MichelvanBiezen
@MichelvanBiezen 3 жыл бұрын
If there is only one voltage source, then it becomes an easy problem and you don't have to use Kirchhoff's rules.
@TheH1TM4NxL3W1
@TheH1TM4NxL3W1 6 жыл бұрын
What do you do if you have two resistors in the middle (i2) and only want current and voltage across one of the resistors in the middle?
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
Since they would be in series, the current through both will be the same and the voltage across each would be (i2) x (R)
@TheH1TM4NxL3W1
@TheH1TM4NxL3W1 6 жыл бұрын
thank you, very much appreciated! great videos
@TheH1TM4NxL3W1
@TheH1TM4NxL3W1 6 жыл бұрын
sorry to be a pain, but does it matter which side of the battery your 4ohm resistor is? as on the circuit im doing my resistor is below where your 10v battery is
@TheH1TM4NxL3W1
@TheH1TM4NxL3W1 6 жыл бұрын
sorry to be a pain, but does it matter which side of the battery your 4ohm resistor is? as on the circuit im doing my resistor is below where your 10v battery is
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
No, as long as the resistor is on the same branch.
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