Dr. Strang really wants each student to understand linear algebra in all phases from top to bottom and from left to right. After the lectures are over he wants you to retain this information forever. These lectures really tell you the student the passion DR. Strang has for teaching.
@AmandaSMaria7 жыл бұрын
the best teacher in the world!! Thank you professor Strang!!
@galolgedi93146 жыл бұрын
Amanda Maria
@yujing75447 жыл бұрын
“the best teacher in the world!! Thank you professor Strang!! ”, the same words from my heart.
@ffvgdsg55845 жыл бұрын
as a student of international university, which is not in US i've witnessed that most professors are using prof Strang's lectures as a pattern and the book particularly we use is intro to linear algebra G.Strang. That is another evidence of that he is currently the best professor in the world
@dengdengkenya5 жыл бұрын
Fantastic! I'm really enlightened by this lecture, though I can't say Professor Strang always gave such a clear explanation on each linear algebra subject.
@Jeshtroy7 жыл бұрын
He teaches in a way that a 3rd grader could understand!
@paulchan6818 Жыл бұрын
A good lecturer that connects to his students.
@jimnewton45343 жыл бұрын
To compute the nth power of a square matrix A requires at most log(n) matrix multiplications, i.e. n^3 log n. (assuming cubic time matrix multiplication) Why? because if n is even I can simply square A^{n/2}, and if n is odd I can multiply A by A^{n-1}. If I have the Eigen decomposition then raising to the nth power is n^3 (just compute the powers along the diagonal of the diagonal matrix) and multiple on left and right by V and V^{-1}.
@edwardhartz10294 жыл бұрын
That was superb, I love how thorough you are. Now I understand why pii^(n)=a*(lambda1)^n+b*(lambda2)^n+... (For some a,b,c.. which can be determined using simultaneous equations.)
@arvindvishwakarma42576 жыл бұрын
Best teacher in the world
@jonahansen6 жыл бұрын
What a great teacher!
@saeida.alghamdi16714 жыл бұрын
Quite Interesting implication of the presentation!
@jesusglez093 жыл бұрын
i love this Thank you Prof. Thank you MIT
@devrimturker4 жыл бұрын
Excellent explanations
@dengdengkenya5 жыл бұрын
What if all eigenvalues were less than one in the case of Markov Matrix example? Or is there any theorem that proves at least one lambda is greater than one here?
@jordanhansen66494 жыл бұрын
There is always an Eigen value that equals 1 in the case of a Markov Matrix
@tgx35293 жыл бұрын
Time 12:24, is it realy Markov matrix from Markov proces?? 0,8+0,31 and 0,2+0,71
@sauravnagar17456 жыл бұрын
How does he write the values of eigenvectors so easily? I mean he doesn't even perform any mental calculations. Does anyone has any clue?
@checkout83525 жыл бұрын
Thank you vey much
@wuoshiwzm0017 жыл бұрын
professor Strang is getting old.... but always giant to me..
@videofountain7 жыл бұрын
Everyone is getting older or the other alternative. Including you.
@yohanshailu56203 жыл бұрын
make it 1.75x
@engineershmily6 жыл бұрын
please anyone can guide me how if U(k+1)=AU(K) then U(k)=A^k U(0) at time 3:25
@jancirani27486 жыл бұрын
Start with u(1). 1. U(1)= A.U(0). --> eq.1 2. U(2)= A.U(1) = A.A.U(0) (from eq.1) U(2)= A^2.U(0) Proceeding like this, It gives U(k) = A^k.U(0). Hope, it's clear
@shrinivasiyengar57996 жыл бұрын
@@jancirani2748 can this be said to be similar to how in the continuous time system X' = AX gives a solution X(t) = (e^At)X(0)
@WolfixDwell4 жыл бұрын
@@shrinivasiyengar5799 Hi, prolly little bit late but: Solution to differential equation as your system dynamic is equal to x(t)= (e^At)x(0), so this solution coresponds to differential equation. And solving the e^At corresponds to e^\lambda_1 t + e^\lambda_2 t ... bcs of equality of characteristic polynomial equation