Moment Area Method Example 4 (Part 2/2) - Structural Analysis

[@exilibus]

9 years later and this is the only video I could find that explained this in an intuitive way. This will very likely save my grade on the final today

[@f.tolgasavas9776]

You are born to teach man. I'm studying my exams from your videos. I hope I can get a good point. And I think you should open a website and put your writings in PDF form. That would be so useful to people. :)

[@structurefree]

thank you for the comment and question...i'm also glad to hear the videos are saving the important parts of your body :). Technically, yes, d = L*sin(phi). However, when we calculate beam deflections in a structure (since deflections are so small relative to the size of the structure) we typically use a small angle approximation...sin(theta) ~ theta...which allows for d = L * phi.

[@hudaal-mashta7920]

I wish I knew you 5 years ago, this would have made my structures theory class much easier. I'm taking MSc entrance exam this month, and your videos are saving my every day! BIG LIKE, and BIG THANK YOU

[@randalperfected5644]

i think im in love ❤ i stopped going to my solid mechanics lectures and started using your videos, right now i´m helping the guys in my course understand, and i say it´s your videos that make it so easy So A BIG THANK YOU from me 😊

[@alexhamad9307]

You're the man! More examples would be awesome, thanks!

[@pavstaaaa]

I agree! With numbers :)

[@anubhutialok470]

Thankx a lot. Saved us using a lot of brains. Great help....

[@structurefree]

no problem. i hope you will still continue to use the brains you have. cheers.

[@thoae236]

Thanks for the video. I also used singularity functions to find deflection at point C, which gave me -P(b^2)(a+b)/(3EI), which is different with the result here. Does anyone have the same issue?

[@Ferson101]

I think I am ready to solve some problems now , Thanks !

[@zjyub]

I have a question and I see I am a little late to the game. But How do we know which directions to take our centroids from. It seems like in one example you go left to right and then other examples you go right to left. Things are starting to clear up for me.

[@arrdeep]

Thanks man! Its very easy to understand.

[@HHHPedigrees]

If the two points that you're trying to find has both a postive and negative moment do you take the signs into account? Would the positive moment cancel out the negative moment?

[@Blogdorf]

Great presentation. I'm working back through Structural Analysis by McCormac (1960) to re-learn what we blasted through in engineering school. What software are you using to do the board work? That makes the presentation really cool.

[@Mishu1434]

If load p is in between the supports than what should be the approach? Imean i want to solve a problem by triangle proportion property.(may be in this problem this is not required)

[@hikaru2521]

thanks so much for all the helpful videos, you've certainly saved my grade a few time T.T ;D

[@bhargavajith222]

will the angle at B be "delta C/b"??

[@Kevin_Tembo]

Like how is d equal to and angle times length

[@ammarkareem633]

please what is the rule to choose where the x bar should taken ....

[@structurefree]

Ammar Kareem I think it might help if you watch the explanation .... kzbin.info/www/bejne/aoiXaKWdiapjb68

[@altaazghoor7364]

Not sure if you'll reply to me xD but how do you know where to take your xbar from. Your xbar for tB/A was taken from B and your xbar for tC/A was taken from C, so i would assume the xbar value comes from the first letter in t to the centroid of the particular area?

[@kavishdaya3594]

hi lol have you figured it out by now, I'm curious to know as I'm not not sure as well

[@teresarodriguez9902]

To find DeltaC we use the magnitude of Tc/a, if d was also negative would we also take its magnitude or leave the negative?

[@teresarodriguez9902]

Answered my own question: Take the magnitude because we are using the distances (which are magnitudes) to find DeltaC.

[@patrickwoolery6000]

Very helpful. But I also need to figure out the angle at B! Why the heck are you not my professor for this class?

[@mdsamiullahchowdhury9191]

thanks a lot. u are the boss

[@onursaroglu1737]

Thanx for everything i passed the mechanics of materials class thanks to you and your videoss Helllooo whatsapp welcomee backkk everyone

[@lestervalmores829]

how to solve for the slope at C?

[@bhargavajith222]

+Lester Valmores i guess it is equal to the slope at b and its "delta C/b"

[@Kevin_Tembo]

Sorry to ask but I dont quite understand how the angle is found without using tan

[@mohamedelgendy159]

Since the angle is very small, we assume that the angle and the tan of the angle are equal

[@y.x.782]

Excellent instruction certainly. Just one thing I thought could make it slightly better, personal perspective. That is to keep the sign of tc/a, then the results would be able to tell if the defelection is up or down. But after all, thanks!

[@vijay4560]

Not possible with the tc/a direction he assume.

[@pattanapongkitnongsuang2141]

why don't you just directly calculate Tc/b? (I'm not so good at geometry Thx a lot)

[@structurefree]

Pattanapong Kitnongsuang tc/b would be the vertical distance to c from the tangent line at b.

[@SeckinTankisi]

just wow

[@structurefree]

word.

[@aarontao2353]

thank you so much

[@alvmal]

Why can't we say tc = tc/b + tb... Which means tb is zero... Then solve for tc/b and get an answer of -(Pb^3)/(3EI) ? ... Big thanks for the videos, I've watched them all.

[@jasonaricheta5330]

hrmm, I tried to draw tb/c in a diagram and it doesn't seem to work (it geometrically doesn't make sense). I can see that you used a vector notation in your algebra and it seems to not be able to work in this concept.

[@joseemmanuelnavarro7210]

HAHAHA "Don't judge me judge yourselff" :D

[@structurefree]

the process is still the same.

[@vijay4560]

Hi, I have one doubt

[@mashudurathogwa4731]

don't judge me judge yourself...haha.Thank you so much for the help

[@maryamezz8848]

thaaaaank you...may allah bless u :)

[@marcusbautista97]

Too siiccckkk!!!!

[@structurefree]

+Marcus Bautista i'm illin.

[@slickskillsman]

I think you made a mistake: You said Phi = Pba^2/6EI/a = Pba/6EI Is it not Pba^3/6EI ???

[@structurefree]

It probably would have helped you if I wrote the formula as phi = (1/a) * (tB/A) which makes phi = Pba/6EI. It's also a good idea to check units. phi should be in radians...[Pba] = Force * Length^2 and [EI] = Force * length^2. Thanks for your question. I hope my explanation is clear enough.

[@icyburger]

Structurefree, tell the truth. Are you the re-incarnation of Jesus. Becuase, you just fucking saved me.

[@icwhatudont]

im not a fan of using geometry and assuming we have a table of centroids. it's nice, but just using calculus seems more reliable.

[@michaelflynn3433]

He's demonstrating the Moment-Area method- it's in the title. The other method using double integration may have been easier, but that's not the point.

[@albatus187]

Basit ya

[@lyka37ful]

structurefree i love you please marry me