MOMENT AREA METHOD - NUMERICAL 1 | Moment Area Method for slope and deflection

[@risky_world5692]

A wonderful explanation 🎉

[@abinashkarmakar360]

Well done man... You describe all the thing 😊😊👍👍

[@tanvimodak6121]

Nice video sir..

[@DCBAonline]

Thank you 😘

[@ahmedhyd867]

Thank you very much , you made it very simple finding deflection by this method, I was trying to find deflection between A and D but not able to solve by integration method in finding moment area between point say A and E , as limits are not known of unknown points. Kindly look into this problem if possible.

[@jagathspoojari5805]

Wonderful sir you made the concept so easy

[@consultantskel8374]

Hi ... would you be able to show how to use "Double Integral Method"?

[@c.spandana9083]

Thank you sir

[@ahmetozcan7916]

such a good video. thanks!

[@yangouyannislauryn1328]

Thanks for clarification

[@timothy4247]

Sir, In the BMD for portion B to C, shouldn't the point go upto -120 not -90 at B from point C ,considering the moment of the UDL is 120kN.m? Can you describe please?

[@MJswag2323]

where can i learn more on the table you used for this method. youre the first video ive come across using that

[@DCBAonline]

Which table? At what position in the video can you mention

[@DestroyerWolfFenrir]

Finding area of cubic curve isn't difficult. You can finding area of any degree curve using the genral formula... Area of nth curve: An= b*h/(n+1) So cubic means n=3 so....A= bh/4...where b would be the base(x) and h be the height(y). The CG in x direction in figure....from B X'=b (n+1)/(n+2) In y direction from the base... Y'= h (n+1)/(2n + 1) So for cubic...X= 4/5 b Y=4/7 h Also for parabola n=2 obviously Also if it's outward parabola or any curve...just minus the area from bh So outward cubic is bh-(bh/4) is 3bh/4... i mean the outward and inward together makes a rectangle anyway.

[@haiderrao6362]

Bro you are too good ❤💕

[@Tracks777]

lovely video

[@booksourexistence2153]

Thanks

[@gourihareesh6419]

What is difference between slope ab and slope ba

[@prafulladushing1147]

18:50 to 19:60

[@subhamoysaha4524]

But when i took the t(c/a) the thita a is coming out as (52.5)/EI anticlock wise is it correct plz...clarify

[@souvik.fingtore]

sir i have solved it myself. but not getting your answer. i have checked my paper again and again.

[@vedanshgarg7938]

14:44

[@KajalKumari-wh4oc]

😊

[@jatindhankhar4526]

Bro point B bm is wrong on left

[@binayaprasaddhakal2494]

The region between A and B is hogging as per the moment which means the slope you are calculating for B is opposite in direction. I think your elastic curve is wrong

[@DCBAonline]

Isnt that the hogging elastic curve at 24:41 ? what is wrong in that ?

[@damland1357]

The 30kN force is attempting to make the beam “hog”, however the UDL of 20kN/m * 3m overpowers that load and creates the deflected shape as shown. He is right. :)