Moments of a Force | Horizontal beam in equilibrium on 1 support

Here I look at the moments of forces acting on horizontal beams resting on 1 support in equilibrium.
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[@topaussiemezza5715]

Clear & good stuff. Crazy that this is from 2012, already.

[@ExamSolutions_Maths]

Time flies by

[@josephmacklin2773]

Maths is one of the few subjects that often transcends time.

[@ibrahimshafi2064]

@@josephmacklin2773 ok Joseph

[@theintellectualdeath8730]

@@ExamSolutions_Maths Seriously 3 years passed already

[@amrinahmed2279]

Crazy stuff man. Love it. Love from 🇧🇩 Bangladesh

[@Katielizc22]

I'm really struggling with this part of physics but this video is really helpful, so thanks a lot :)

[@jhonnybhai4296]

Thank you Sir...the video is old but it amazing... understood the concept without any probs..(much better than my teacher). Watching in 2019

[@ExamSolutions_Maths]

Thanks for watching despite its age.

[@ExamSolutions_Maths]

Sorry, but I am confused by your question. I did convert all the forces to Newtons and to do that we multiply by g. g being 9.8

[@FatimaZahid00]

Thanks a lot. It really helped me!

[@LondonWalkability]

why is the contact force (R) not factored in for the kids on the bench?

[@ExamSolutions_Maths]

It is. It is the only upward force supporting the downward forces of the weight of the plank and children

[@ExamSolutions_Maths]

You're welcome

[@MinecraftCurios]

Minecraft curios approves!

[@PinkBroBlueRope]

i was afraid this video wasnt legit but thank God it's Minecraft Curios approved

[@eeshairfan5677]

Sir, why do we not take into account the contact force of the children? why do we not include those in the equation as well? thank you so much, your work has helped me loadz!

[@ExamSolutions_Maths]

+Eesha Irfan We are only interested in the forces acting on the plank. The contact forces you mention act on the children not the plank.

[@eeshairfan5677]

+ExamSolutions oh okay, thank you so much!

[@ExamSolutions_Maths]

Difficult to say without seeing your working.

[@584emad]

Sir , can we first convert all the forces to newtons so we don't get confused with g ? also we don't need to multiply it by 9.8 ?

[@PinkBroBlueRope]

I was also confused by the g, I wasn't sure what it meant or why he converted 10kg into 10gN. Have you found an answer for this, 9 years later?

[@Maxoplasm]

@@PinkBroBlueRope Because 10gN is the force (Weight = mass x gravity (g)), while 10kg is just the mass.

[@PinkBroBlueRope]

@@Maxoplasm Thanks for replying. It might be better to just say that g in this context is 9.8

[@584emad]

I got it , thank you , i made a mistake , but thank you anyway :)

[@ssajid40]

Oh sorry, I know now! I done 4g*3, as opposed to 4g*4 !!!

[@ssajid40]

sir, at 19:08, I took moments in a clockwise direction, and I got M= 11 kg, I dont know where I went wrong!

[@bengeary4740]

Shabaz Khan 5 years later this man still doesn't know... someone help him

[@emmanuel73143]

I know it has been 6 years, you have gone through uni, settled in an apartment with the women you love, working a 9-5 you hate. But alas I finally relinquish the burden of this question from your shoulders. M(0)clockwise= 10g(1)+4g(4)-mg(2)=0. Which rearranges to m=13.

[@saharfarzand6684]

You must have input the value for g as 10 N that's the only way your answer can end up being 11kg

[@Riplure]

what program do you use

[@ExamSolutions_Maths]

Hope you don't drop off to sleep!

[@ameena6485]

We'd have to calculate the moment and force of that turning point!

[@olamijiodunlami6851]

what did u divide b 27g to give 264.6N

[@ar0z957]

You dont divide anything ,you multiply 27g by the gravitational field strength because thats what g stands for and the gravitation field strength is 9.8 ,so it would be 27(9.8) which is 264.6 newtons