Initial Value and Final Value Theorems

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@aaronfritz6892 2 жыл бұрын

Seriously, its so weird having a college professor jump straight into how to derive these concepts without explaining the concept in terms of what its used for or how it relates to other things. These videos are what fills the gap for me, thanks for making this intuitive for a beginner!

@sanjayprabhu6909 4 жыл бұрын

hello neso i am really happy you are uploading vedios continously thankyou very much

@PunmasterSTP 3 жыл бұрын

Initial value? More like "Incredible; thank you!" These videos really are quite splendid.

@maharjaveed8289 3 жыл бұрын

Good method and easy to understand Again your's work is very Good

@mohammeduzair1276 3 жыл бұрын

I can't believe the fact that such amazing videos have such few likes!

@balasubramaniyans1426 3 жыл бұрын

Excellent explanations sir

@ippalavalasaanusha3672 Ай бұрын

Thanks a lot neso academy for the great explanation

@kaverik.thekodda 2 жыл бұрын

Is the value of u(0) & u(inf.) just equal to "1"? See 01:50 I ask because, we determine the value of the function using only the term with the exponent. (or that's how it seems)

@kaverik.thekodda 2 жыл бұрын

does the question makes sense?

@comment8767 Жыл бұрын

u(t) looks like it might be a step function .... is is not just anything. So is does equal 1 at times later than zero.

@rahulguptha3131 4 жыл бұрын

Nice video thank you we need more videos like this

@gowriv944 4 жыл бұрын

Nice sir.upload more and more vedios about control system.

@hikmathasanov 3 жыл бұрын

For the first condition, I think it is supposed to be s.F(s). That is how it was explained before at Signals and Systems Lecture Series.

@NitinSharma-so9hg Жыл бұрын

Good Lecture . THANKYOU

@sohelansari-dq5kv 4 жыл бұрын

great teacher

@patriciaa4260 Жыл бұрын

Thank you so much! You have helped me!

@sarojinivaradharajan5598 3 жыл бұрын

Great! Thank you very much

@agjhv3835 3 жыл бұрын

5:38 but the example you took is discontinuous at t =0

@PunmasterSTP 3 жыл бұрын

Yeah I was a bit unsure of that part as well. I think the main idea is that the function can't be discontinuous immediately after t = 0, as in, f(0+) is finite and the limit of f as t approaches 0 from the right is f(0+).

@s.m.senses7199 3 жыл бұрын

thanks Sir🙏❤

@serenasavage9842 2 ай бұрын

For final value theorem, how does 1/s+2 = 0 if s=0? I don’t understand what I’m missing

@chidanandadatta4695 4 жыл бұрын

Can we say, result from final value theorem as dc value of the system??

@sudeepshetty4530 3 жыл бұрын

In final value theorem 2nd example, how do you say F(s)=1/(s-2) pole value is 2? No clarity given about direct conclusion of RHS value?? Can you explain more..other than that quality of explanation is super.

@PunmasterSTP 3 жыл бұрын

A pole is a value of the variable that makes the denominator of a function equal to zero. Because the factor (s - 2) is in the denominator of F(s), we can set s - 2 = 0 to see that s = 2 is a pole.

@triposat 4 жыл бұрын

Please upload the lectures of Data Structure as soon as possible. please sir 🙏🙏

@nesoacademy 4 жыл бұрын

Sure 👍

@Muvva_raj 5 ай бұрын

In first example e power zero is one ....but side of that we have u(0) whole will become zero no?

@mohamedabdulraseethma9568 2 ай бұрын

u(t) is an unit step function whose value at t=0 is equal to 1.

@shreyashagrawal2264 2 жыл бұрын

If we do Inverse Laplace Transform of F(s) = 1/(s+2) then it will give us f(t) = e^-2t and therefore f(t) violates the condition 1 i.e. f(t) = 0, t

@ahasnainkhan9622 2 жыл бұрын

f(t)=e^-2t.u(t) for F(s)=1/(s+1) not just e^-2t, hope answered your question.

@Happiestsoul31 3 жыл бұрын

Thank you

@aaqibrashidle6655 3 жыл бұрын

Uh r great sir

@comment8767 Жыл бұрын

The value of u(0) in Example 1 is unclear. If u(0) = infinity, then IV would be infinity, no? Maybe u(t) is a step function at 0? It is not a generalized function?