Properties of Convolution (Part 3)

[@ikramwani5207]

All of the neso academy will be in heaven In Sha ALLah. The founder of neso academy must have been a great soul I owe my results to you

[@moosasaboor1221]

A unit ramp function on integration yields a unit parabolic function r(t+2)*u(t-3)= p(t-1)

[@a-classzone1998]

p(t-(-2+3))=p(t+1)

[@basundharahazra8124]

​@@a-classzone1998bruh 3-2=1 not -1

[@ayanhaider5579]

there's a negative sign outside the parenthesis@@basundharahazra8124

[@maishareddy]

can u tell what happens when we integrate other typesof signals

[@nitecedemon152]

@@basundharahazra8124 no see the ramp signa is r(t+2) so it will be r(t-(-2), so its is -2 and from the second one it is +3 , at the end it will be -2+3=1 so it will be p(t+1)

[@collegetv7986]

H.w. ans = p(t-1)

[@nazirafridi3179]

is this right or not?

[@astakalasuswith6946]

P(t + 1) is correct

[@bojarajan04]

@@astakalasuswith6946 p(t-1) is correct

[@apoorvpandey5058]

@@nazirafridi3179 yes it's correct

[@subhashishbehera2424]

@@bojarajan04 p[t-(-3+2)]=p[t-(-1)]=p(t+1)

[@javariamalik8475]

These videos are truly great, especially the ones on the properties of convolution. I had my quiz and most of the questions were similar, but unfortunately, I hadn't watched this video at that time. Now I realize that I should have watched these videos first.

[@BhavikRaghav14905]

Thanks a lot sir!!! for such to the point yet very very informative video, I can't express how grateful I am to my Parents, Saraswati Mata and teachers like you who have helped me so much in my studies Thank you very much sir Jai Siya Ram

[@saadjamil1198]

(t-1)^2/2 * u(t-1)

[@arshavchand671]

In time scaling, if the scale factor of 1st and 2nd s/g are different.. What will be the answer?

[@masonp5]

Thank you thank you thank you. This is so clear explanation

[@diegor.2366]

HW answer is p(t-1) (t-(-2+3)) = (t-1) therefore, it is p(t-1) if you are still confused look pt.2

[@danielaremo424]

= t^2/2.u(t-1)

[@ajayprakashpandey5335]

In property 8 if the two signals are scaled by different factors like for instance x1 is scaled by a and x2 is scaled by b then what would be the y(t)?

[@srishtikumar5544]

Amazing video as always; I think there is an error at @7:25 though. Shouldn't x2(t) = t, not x2(t) = 3?

[@srishtikumar5544]

Thank you very much for the reply. An honor to speak with you :)

[@aadithyaiyer4514]

what would happen if both functions x1 and x2 have different time scaling??

[@kamleshpancholi6156]

for example 2 homework question : P(t-1) is periodic function

[@TheRedWolf-fo3oy]

At 6:24 example of time scaling, how did the value of a=3 came out? Didn't understood the solution

[@gglollipop407]

The output is giving from the example, as you can see the value of a in the output (1/3) ×y(3t) where you can find the value of a from the coefficient of the independent value which is t, hopefully this is clear to you now 😊

[@arnoldthegreat4138]

at the last example of time scaling you write x2(t)=3 it should be x2(t)=t

[@VikramKumar-st7xs]

P(t-(-2+3)=P(t-1)

[@ton_moy]

Ans of example 2 of property 7 is : t^2/2 *u(t-1)

[@rayhankabir9086]

shouldn't it be (t-1)^2*u(t-1)?

[@Starlight-rt1zr]

Please please please help me...tell me the best book for this subject with ample amount of examples and questions along with crystal clear concept explanation. Please suggest a book having all the above listed things

[@anshuhimanshusuthar5614]

🤣👎

[@entertainmentpro2186]

Oppenheim follow kar bhai

[@HarshKrSingh-wq8yu]

@@entertainmentpro2186 Ab tak to sir ka Btech ki degree complete bhi ho gayi hogi

[@arjun431]

integration of ramp signal ?

[@divyapitla7929]

parabolic

[@sandeepprajapati8718]

1/2 (t-1)^2 *u(t-1).

[@NomanKhan-zr5kp]

Solutions ?!!!!

[@bojarajan04]

Your answer is a parabola signal when you plot it

[@pragyaraj3637]

Wrong

[@gauravkulmethe3628]

Sir x(t-t1) should be the time advance but you are saying it is time delay?though the time is being shifted towards left of axis.

[@082.niketsingla5]

He took a general case bro

[@ParminderKaur-zm4kw]

sir z transform???? u have capabilities of explaining things very well that is y all want u to upload vedios

[@narendarrathod4972]

Sir if time scaling factor 'a' and 'b' then resultant signal will be |ab| or |a+b|

[@sethusri0123]

(A+b)/2

[@debapriyadasgupta6534]

sir if the signals are scaled by different values then how should we approach?

[@nmtbytes]

if x1(at) n x2(bt) then what change will come in y(t)?

[@musshahidd]

Sir Very very thank you

[@uradiajay9202]

Sir if x(3t)*x(4t) is given so how to find out resultant ?? Plz provide solution

[@dishasoni001]

h.w ans =p(t-1)

[@healingmeditation5970]

Is these properties also valid for discerete convolution

[@vishal538]

P(t-1)

[@arunsinghmehra7728]

((t-1)^2)/2 .u(t-1)

[@dhineshkola8691]

sir, t please upload lectures on **REGION OF CONVERGENCE**

[@inaramara2416]

thank you sir ...please is it working for u(t-a)*u(t-a) ??

[@harshit-tx-16]

yes u(t)*u(t)=r(t) then by time delay r(t-(a+a))=r(t-2a)

[@pronojit100]

If scaling factor "a" is unequal for two signals is there any property there? Thanks!

[@lolovadibilal6465]

U r really doing grt work,, thanks a lot sir GOD bless u sirSir pls start communication

[@ytmultiverse8193]

H.W ans.....P(t-1)

[@HardikPatel-wj8wo]

Sir please make video on z transform, After 4 days its my exam..

[@shubham509]

Bro. Did u pass the exam or not?

[@vikasrawat3858]

@@shubham509 bro did you pass the exam or not?

[@madhurgoyal2908]

(t-1)^2/2 × u(t-1)

[@Fantasticsman]

the answer is p(t-1) since t1=-2 and t2=3

[@ismritigupta9126]

@neso academy please reveal the answer of r(t +2)*u(t-3)

[@jitendragupta-gk8ql]

p(t-1) parabolic function

[@-RaagaviM]

@@jitendragupta-gk8ql how???

[@ojhamridul2552]

@@-RaagaviM using property of shifting and property of convolution with unit step.

[@kamleshpancholi6156]

Answer of example 2 : homework question is P(t-1)

[@surendra_c]

Sir when do you a start "communications system"? Plz reply sir.....

[@Cyber_Space660]

yes sir communication system

[@laxmankumarnahak1535]

Prop 8 example.?

[@violet-b2q]

what if x1 is scaled by a and x2 is scaled by b then what is the output signal

[@TemplateTroveNCRax]

P(t+1) or t^2/2*u(t+1)

[@PRIYANSHUKUMAR-rg1xy]

tri(t-1) integration of ramp signal is tri(t)

[@tejasriram1480]

integration of ramp is parabola not triangle because integration of t is t^2(its nature is parabola(y=x^2))

[@tejeshreddy8819]

t^2/2 *u(t-1)

[@tanujkalra7334]

Ans to Homework Problem: r(t) * u(t) = (t*t)/2).(u(t)) therefore r(t+2)*u(t-3) = (((t-1)*(t-1))/2).u(t-1)

[@tejeshreddy8819]

sry (t-1)^2/2 *u(t-1)

[@keshav_c17]

can you please clear my doubt that why it is (t-1)^2 and not t^2

[@rajeshwararaju9865]

r(t)*u(t) = p(t)= t^2 /2 u(t) but there time shifting # t should be replaced with (t+2-3)=(t-1) so now replace t with (t-1) in the above ans. so we get {(t-1)^2 /2 } u(t-1)

[@lolovadibilal6465]

Plz add lecture no.s ...at the start of lecture

[@lolovadibilal6465]

sir they do not remain in order when downloaded. it becomes very difficult to arrange them in order

[@Mehraj_IITKGP]

Since r(t)*u(t)=p(t): r(t-(-2))*u(t-3)=p(t-(-2+3))=p(t-1) p(t-1)

[@Baby12875]

Hi, you write 3 in o/p just as on assumption basis. Because if we write 4 in o/p then our input scaling will be changed as per this. So this problem may have many solutions as solved by you. I am not satisfied by your approach. Or we can say that it only depends on user as by which amount he wants to scale o/p, the I/p will be scaled accordingly. If am am write, give reply

[@DeepakKumar-gf8mz]

Hw solution pls?

[@reficeismail6520]

(t-1)^2*u(t-1)

[@krishnavala9404]

What is the answer if we have x(At)©x(Bt)?????????????????????????????????????????????????????????????????????

[@xstreamrushi5015]

How does 1/3 y(t) comes 😢

[@sreekarbasa574]

Home work problem :- r(t+2) * u(t-3) = y(t) => r[ ( t + 2 ) - 2] * u[ ( t - 3 ) + 3 ] = y( t - (2 + (-3) ) ) = y ( t + 1 ) since , r(t) * u(t) = p(t) ; => p(t) = y(t+1); => y(t) = p( t - 1 )

[@shibamojha6351]

MY ANS IS P(T+1) AS P(T-(2-3))

[@btbaskarthaosen]

The Home work u have given in this video is the answer y(t)=r(t-1)

[@darshitvachhani9790]

What is the solution

[@yacinealiouane8859]

HW ans is: p(t+1)

[@faizulislam1075]

((t-1)^2/2)u(t-1)

[@komalipadala154]

How did u get u(t-1)in the answer🤔

[@bankisendrahighschool8552]

@@komalipadala154 r(t+2)*u(t-3)=y(t+2-3)=y(t-1) As we know r(t)*u(t)= t^2/2*u(t)

[@rajujohn3462]

p(t-1)

[@sairaja6849]

p(t-1) or ((t-1)^2/2*u(t-1)

[@divyanshusaxena1328]

how can you pls. exlain

[@avinashmaurya6087]

r(t-3)

[@akilaby8290]

anyone who can show the solution of homework problem?

[@nabilatasfiharahman4585]

((t-1)^2)/2

[@KirkHammer-fj2of]

First

[@ranadanish7222]

H. W.... t^2/2

[@skashikrahman5526]

Ans : u(t-1)

[@kamleshpancholi6156]

Answe

[@pradeepchaudhary2739]

r(t)

[@shyamallenka6165]

how 3t become as 9^t it supposed to be 3t^2+3t

[@laxmankumarnahak1535]

P(t+2)

[@priyamsaha]

p(t+1)

[@akashkumar1433]

r(t-1)

[@abdulwahoodshaikh7501]

P(t-5)

[@salaarkhan569]

sir what if the time scaling factor is not the same for both?

[@kaavyasameerasajja6730]

P(t-1)

[@shishpal8633]

p(t-1)

[@KristinaDoko]

p(t+1)

[@Raven_T_T_]

p(t-1)

[@nirajjayswal]

u(t-1)

[@kiranjangid9175]

P (t-1)

[@johnology]

p(t-1)

[@aishiksarkar8226]

P(t-1)

[@aakankshanidhi4989]

p(t-1)

[@ashishtiwary7947]

p(t-1)