Types of Relations (Part 1)

[@Abdul-BazeetBalogun]

From Nigeria, FUTA, this tutorial and that of Algorithm saved a whole faculty😅😅. Nice one really!!!

[@anderichardayomide4163]

😂😂 we gather Dey

[@User0_0-y5c]

He's Indian

[@toby818]

same LASU

[@asmarbaghirova]

Much more short and straighforward explanation. Appreciated🌸

[@shresth3878]

Gm

[@xiaoqingtian6542]

Your video is best one for relation examination

[@kainaatmakhani6550]

Concise and to the point. Thanks

[@saniyaGaikwad-zs7my]

Your voice is so soothing 💝 and teaching is very very good 👍🏻😊

[@robotgameing4522]

Clear and easy to understand . thanks sir

[@alimonzer809]

SAVED MY LIFEEEEEEEEEEEEEEEEEEEEE

[@officialshotoniphonememe6218]

Century complete re baba Thanks neso academy and specially Jaspreet sir 🙏

[@yaduvanshi_jitin_yadav]

Thanks sir , your way of explaining is fantastic

[@piyushkumar-wg8cv]

You have just ruined professor's one hour lecture in 6 minutes

[@Thugzic]

*2 hour

[@glenmarksandigan7066]

*5 hours

[@mdpeealislam7821]

whole semester

[@kobbariraja]

Whole career

[@maamiddithota3689]

Whole life😂

[@yannysan-edits7502]

Thank u, ur saving my college life

[@leo-ki9ye]

thank you so much for these videos, i should have skipped my 2 hour long professor lecture where i understood nothing and just watched this instead

[@Thugzic]

FR

[@ShikongoEster-ww2ug]

This is very helpful

[@d.sarayureddy783]

Much needed video 🎉

[@qwcryy]

In example 5 @4:44, Relation R6 should be ANTI-SYMMETRIC and not NOT-SYMMETRIC as the ordered pair (1,1) exists in the relation, which follows the rule that if (a,b) and (b,a) exist in the relation a must = b (for it to be anti-symmetric). Please correct me if im wrong.

[@tharushisakuntala6540]

yours vedios are well explained,, so please give vedios for functions in maths

[@MuhammadAqibJaved-kj3sm]

Great 👍

[@mdpeealislam7821]

damn i was about to fail the class agter watching your video i am the one who wish to get A on the exam damn what a transition..You really explain good..

[@learninginstudentscafe7284]

Topic explaination is very good

[@orangeinfotainment620]

thank you!!!!

[@chandhansaisuryarajupambal761]

Super smooth

[@jankialoney8681]

Very good explanation 😊

[@RashidSiddiqui]

When you say "as simple as that", it hits me lol🤣, doubting if i am supposed to be that intelligent in first go 😇

[@necreiP]

explained it better than my prof lol 10/10

[@sanjayakash781]

really nice sir thank you

[@elangorramalingam5677]

Thanks

[@TinasheMunjeri]

Great work appreciated

[@JaneDoe-fm9jj]

question: why isn't there (1;3)??

[@dprssdcat]

Thanks, very informative! But I wanna ask if r = {(1,1), (2,2), (3,3), (4,4)} considered symmetric? if yes, please explain because I can't wrap my head around it

[@joeantsaphia3446]

Yes it i s symmetry

[@noone713]

Bro tysm

[@shrashtipandey5398]

Itna acha itna smoothly 👌 Thank you for the video

[@Arseni-e4n]

good so good👍👍👍🍀

[@_Luffy_018]

4:06 ....... Why we need not to check for (1, 1), (2, 2)

[@joeantsaphia3446]

(1,1) is relexive of(1,1) simillarly for (2,2)

[@Mirza_Muhammad_Ali_Jahlmi_sab]

Tomorrow is my paper and i complete whole syllabus in just 6 min video🤣 Love you sir God bless you🎉🎉🎉

[@yagga_mr.idiot.1242]

Thanks bro

[@varunsood7899]

Sir please upload more videos. They are helping me too much

[@collegecoder6301]

Sir please upload videos on DBMS

[@ross9263]

Holy shit I love you. My brain finally understands symmetric vs antisymmetric

[@zanelemileyshandu4876]

Hi I am not understanding the example on Antisymmetric, shouldn't it be that THAT example is NOT Antisymmetric?

[@MatthewViterbo0017]

This helped me alot. Thank You~

[@zazatjijombo174]

Very helpful sir thank you sm

[@AbhishekThakur-fk7px]

Thank you so much sir.

[@sidharthpg3900]

How is anti-symmetric different from non-symmetric?

[@Siva_Shyam]

Consider a relation R = { (1,1) , (1,2) , (3,1) , (1,3) } Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and Hence, Antisymmetric is not always equal to (not symmetric) I hope you got it!

[@tabassumahmed2898]

Hats off

[@Harsita-v8y]

The first ex given for irreflexive relation is not irreflexive but is it reflexive or not

[@YfAsm17]

Is there any relation which is not reflexive, not irreflexive and not antisymmetric

[@gayathrik7673]

So a=b means it is not symmetric but anti symmetric?

[@Siva_Shyam]

No you cannot because , Consider a relation R = { (1,1) , (1,2) , (3,1) , (1,3) } Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and Hence, Antisymmetric is not always equal to (not symmetric) I hope you got it!

[@anveshatagore542]

Data structures... Please upload and complete DS Course.

[@learninginstudentscafe7284]

Excellent

[@kanthareddy7943]

Because if we change 1,1 and2,2 answer is 1,1and2,2

[@shankdgaf]

omg bro ur so smart

[@shankdgaf]

blud will def clear iit

[@shankdgaf]

bro is smarter than einstein himself

[@shankdgaf]

16 missed calls from harvard

[@farhanah5990]

Sir can I conclude that antisymmetric is equal to not symmetric

[@Siva_Shyam]

No you cannot because , Consider a relation R = { (1,1) , (1,2) , (3,1) , (1,3) } Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and Hence, Antisymmetric is not always equal to (not symmetric) I hope you got it!

[@collegecoder6301]

Plz regularly upload videos on DBMS series ✌️✌️🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@drg9807]

Do u mean dms?

[@Lea-mj8qu]

​@@drg9807 Database management system is a engineering sub

[@saifabbasi3114]

Thank you so much sir ❣️❣️☺️💗

[@andriimakarov5781]

You're gods

[@rishabhsundaram6121]

"gods" 💀

[@old_mines]

I am from India

[@zazatjijombo174]

“Let me tell you”❤

[@ハチだよ]

Thank you sir

[@QingqiYang]

awesome

[@gsivarani6747]

Please start teaching CO SUBJECT as soon as possible

[@phamngoctrung678]

Character In the video It's great, I like it a lot $$

[@hanzanthonycahilog2923]

When will part 2 be released?

[@uniqueravi1451]

Tomorrow is the test and I'm studying tonight ,🤫🤫🤫🤫

[@Siva_Shyam]

Yesterday was my test I'm studying today 🤫🤫🤫🤫

[@AbidRao-wf9tc]

👍🏻

[@saad879]

Sir PLz...thora jldi videos Upload kia krein hmara uni waly sir achy nhi hain.....ham aap se idhr hi parhaty hain..

[@gamers_guild978]

Arigato gozaimasu sensei

[@prodiptamondal1758]

Dbms and ds pls

[@collegecoder6301]

DBMS

[@goutham7822]

Sir what happened to the gate aptitude series ? plzz sir upload the continuation videos

[@AmitYadav-cx9ww]

if a relation is not irreflective .is reflective????

[@amberjha5974]

Not necessary, if some elements in a set are {a,a} and some are {a,b}, then its not reflective as {a,b} exists but it isn't irreflective either since {a,a} exists. It has to be all elements following the requirement.

[@natesr5373]

❤❤

[@Tech4QuickHindi]

Yor boss

[@5redage5]

Oke)

[@DeepakKumar-nk3cv]

Same here plzz complete data structure playlist....🙏🙏🙏🙏

[@bilal8247]

Nice

[@coryanders6328]

This explanation is illogical. How is something irreflexive because the numbers are not in the set when they are clearly in the set?

[@gamingxd4902]

My brain is not braining

[@subhanullahdanish8680]

i haven't understand which you have explained its not clearly explain

[@Siva_Shyam]

Let me explain you, Antisymmetric = { (1,1) , (1,2) , (2,3) } Here if 1,2 ( say a,b ) exists then 2,1 ( that is b,a ) is not allowed , however if 1,1 ( say a,a ) exists then 1,1 ( agai a,a ) is allowed Assymetric = { (1,2) , (2,3) , (3,1) } Here if (a,b) exists then (b,a) is not allowed, also (a,a) is not allowed Consider a relation R = { (1,1) , (1,2) , (3,1) , (1,3) } Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and Hence, Antisymmetric is not always equal to (not symmetric) I hope you got it!

[@nithishnagendra]

Antisymmetric? never heard of that when i was studying PU i thought the last one was Transitive relations

[@Siva_Shyam]

Let me explain you, Antisymmetric = { (1,1) , (1,2) , (2,3) } Here if 1,2 ( say a,b ) exists then 2,1 ( that is b,a ) is not allowed , however if 1,1 ( say a,a ) exists then 1,1 ( agai a,a ) is allowed Assymetric = { (1,2) , (2,3) , (3,1) } Here if (a,b) exists then (b,a) is not allowed, also (a,a) for a

[@Rahul-yu3ro]

2:10

[@zaifansari3044]

❤️

[@farooqhusain5534]

anti symmetric is not clearly explained makes no sense or logic

[@Siva_Shyam]

Let me explain you, Antisymmetric = { (1,1) , (1,2) , (2,3) } Here if 1,2 ( say a,b ) exists then 2,1 ( that is b,a ) is not allowed , however if 1,1 ( say a,a ) exists then 1,1 ( agai a,a ) is allowed Assymetric = { (1,2) , (2,3) , (3,1) } Here if (a,b) exists then (b,a) is not allowed, also (a,a) is not allowed Consider a relation R = { (1,1) , (1,2) , (3,1) , (1,3) } Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and Hence, Antisymmetric is not always equal to (not symmetric) I hope you got it!

[@headyshotta5777]

you shouldve had images to represent the relations in this video. all the formal notation is brain melting. no thanks

[@mixtapes5022]

Bro said ir🔫🔫🔫reflexive

[@nitinnegi4663]

Bhai hindi me smjhi diya kro yl

[@JRS541]

Sir hindi me asani hoti😢😢

[@Siva_Shyam]

Lekhin Hindi asan nahi hoti 😅

[@anarosearo9351]

So fast

[@moatazelhmamy9034]

خخخخخخخخخ انت بتقول اي

[@bhaben806]

it is super fast for me 😭😭

[@Hs-nd8fg]

👍👍👍👍

[@jamesmelendez4321]

You talk too fast

[@trangvu2107]

Character In the video It's great, I like it a lot $$

[@gayathrik7673]

So a=b means it is not symmetric but anti symmetric?

[@old_mines]

Thanku so much sir

[@viralshortsgadgets567]

❤

[@ashokversez]

❤