Much better explanation than my professor, thank you!
@wormiestspoon94892 жыл бұрын
this man is a life saver, I've got an assignment due tonight and id be doomed without this absolute legend.
@santoshpal86122 жыл бұрын
U would had asked from friend and copied it 😅😅
@sugoi9680 Жыл бұрын
@@santoshpal8612 He doesn't have any friends lol
@irenee6064 Жыл бұрын
@@sugoi9680😂😂💀
@xijinping3543 Жыл бұрын
@@sugoi9680literally me🤣🤣😔😔😔
@sabirabi879516 күн бұрын
what calculations are we talking about in the last segment of the video? is it about the power dissipation?
@theprophetspath99292 жыл бұрын
On timing 5:30 why current not flow through 10ohm resistor
@sabirabi879516 күн бұрын
because the loop currents have to return to their original starting point. if the currents 4A and 5A flow through the 10ohm resistor they won't find the way of coming back to the starting point (the currents will conflict in the resistor too)
@ashutoshgupta5494 жыл бұрын
Sir you have not made video lectures on operational amplifier it is very important topic for gate and ese exam . Sir i'm dependent on your lectures because signal and system, digital electronics and network theory you have teached very well Please sir respond and make video lectures on operational amplifier , multivibrator and feedback amplifier
@aminashahzadkhan6966 Жыл бұрын
How do we know that there is zero current in 10 ohm resister ??
@ritabratabhattacharjee74402 ай бұрын
Apply kirchoff voltage law in the 10 ohm 5 ohm and 4 ohm loop you'll get current as zero
@PriyaGupta-qt4kh4 жыл бұрын
Well explained 👍
@anandkumartiwari58643 жыл бұрын
If you apply nodal analysis at principal node 1 &2 you will get same potential of 20 volt so there will not be any current through 10 ohm resistor
@soudip87702 жыл бұрын
Ek q m help krdo mera koi
@aryantyagi94265 ай бұрын
@@soudip8770 haa
@BharathKumar-rp5sg4 жыл бұрын
Sir, in that example why the 4A and 5A currents from independent current sources won't enter into the branch consisting of 10 ohm resistance ? Please say sir..
@solaimanabdullah46114 жыл бұрын
@NesoAcademy please answer this question. Why 5&4A current didn’t enter into 10ohms registance?
@SasawataDG4 жыл бұрын
@@solaimanabdullah4611 and @Bharath Kumar, if you assign nodes A and B at the left and the right end of the 10 Ohms resistor terminal respectively and apply KCL at both of them, you will get two equations as follows: 3Va - Vb = 40 ---------------- (i) 3.5Vb - Va = 50 --------------(ii) If you solve these equations you'll get Va = Vb = 20V So, the current through the 10 Ohms resistor would be (Va - Vb)/10 = (20 - 20)/10 = 0A. I hope this clears the confusion. Alternately, you can see that when the source is transformed, you get 20V on each end. making the potential difference to be zero, subsequently, making the current through the resistance = 0A. But as the lecturer mentioned, you must not take this into account for power calculation because it will involve the current through the actual circuit and not the transformed one. Thank you and happy learning!
@solaimanabdullah46114 жыл бұрын
@@SasawataDG thanks ❤
@Varun-zd8vm2 жыл бұрын
@@SasawataDG thanks sir
@RSA_Shock2 жыл бұрын
@@SasawataDG thanks so much
@elonmusksake91414 жыл бұрын
Please upload power system
@somanathsahoo56684 жыл бұрын
Maza aa Gaya bidu
@tıbhendese4 жыл бұрын
5:30 how the current is not entering ? how its 0 ? I dont understand that , please anyone clearify that
@meghanakrishna3094 жыл бұрын
Current always chooses the path with lower resistance and also apply kcl at two nodes you will get the current zero passing through that resistor
@academicstuff548 Жыл бұрын
5:07 but applying node voltage analysis here gives different results.
@AdithyaSanthosh-d5g3 ай бұрын
Nah, same result, I got potential left of 10 ohm and right of 10 ohm as 20, so current=0
@Pixcel252 ай бұрын
Thank you
@121219212 жыл бұрын
Very clear
@Crusader24 жыл бұрын
sir,please do make a video on ldic
@wolffang39862 жыл бұрын
Why when transforming the Nortons eq does the resistance need to be in parallel with the current rather than in series?
@ProVideoEditor_Upwork9 ай бұрын
The last part isn't clear. It needs to be more clear.
@ankurkar79854 жыл бұрын
sir if we r asked to determine the power dissipation of 5 ohm resistor what would be the ans?? And sir how could u take 0A current via 10 ohm resistor from both side at "case no-1"??
@adityaoberoi2664 жыл бұрын
How did 0A come through 10 ohm resistor?
@ankurkar79854 жыл бұрын
@@adityaoberoi266 that's what i was asking for..
@HarshSharma-hl9xg3 жыл бұрын
The points between which 10 ohm resistor is are at equal potential that's why no current flows through it.
@Anonymous011-K3 ай бұрын
Without neso acad, i'd be cooked
@assamesetrader94 жыл бұрын
Sir what about machines.. Its very important for us..
@piyushkumarsingh0694 Жыл бұрын
I am confused about why the power through the 5 and 4 ohm resistors is zero even though the current is flowing through it. Shouldn't it be P = i^2 x R so P(5 ohm) = 4^2x5 = 80 W?
@mohsin007 Жыл бұрын
Current isn't flowing as the 20-volt EMF source on each side is canceling each other.
@Arjun-oh9ob10 ай бұрын
simply apply kvl you willl get I as 0 A
@arunajyothi31042 жыл бұрын
Sir please upload lectures on dc machines and motors!????????
@akashsk64782 жыл бұрын
Sir your teaching is very Nice. One suggestion from me that i feel subtitles are not required below video steaming, what you speak that everyone can understand easily so, not need to show subtitles, because of subtitles are covering other entries that you will be writing /explaining to the next steps. So we are facing the problem for assume that next entries are not able to see properly so, little bit tough to understanding..
@SIbnat-ge4uf2 жыл бұрын
Turn of closed captions then
@krishnendukundu01 Жыл бұрын
Abe kon hai be tuu Cc of kar dene se subtitles off ho jata hai Itna v pata nehi🤣🤣🤣
@edgbaston1493 жыл бұрын
Thanks sir
@MeH75M3 жыл бұрын
How to do source transformation for dependent sources??
@NikhilKumarNiraj3 ай бұрын
better then iits
@hamster491 Жыл бұрын
i just want to know the direction of current from source after converting a voltage source...!.!.!.! anyone...??