Parallel Diode Configurations

[@ramseyshehadeh2914]

Your small details in your illustrations make a huge difference in describing the process! (i.e. when you seperated the two currents using that drawn green wire) Keep it up!

[@warrior100girl]

the best. Thanx. Without you, i couldn´t make it through my university course Technical Principles of Computer Science. Now i need to make it through "Computer Organization and Design" and "Microprocessor Systems". :D

[@adammoe537]

All the calculated current values are in the Amps range not milliamps

[@cristi95cip]

I was looking for this comment

[@fladomiciano]

@@cristi95cip Me too!

[@krrish.pawar819]

Me too...2024

[@abdurrahmanyakar3040]

I think current is not mA, because of R=0,33 ohms. Am I right?

[@arpitaarpi7015]

Yes

[@ndoumga]

Thanks a lot dude. If I pass my course "Electronics" it'll be thanks to you.

[@94D33M]

Did you pass?

[@mohammadimtiyazuddin2065]

did u pass?

[@barrackobama7553]

did u pass?

[@thedirector6297]

Did u pass?

[@krupaallll]

Did you pass

[@AnjaliSingh-ko7ze]

what happens if one of the diode is of Ge and the other one is Si?

[@chinmayakar240]

I think jee main 2019 january ka question ke liye tum yahan aye ho 😁😁 Sahi bola na??

[@TahaElAmineHaddouche]

good question , we need answers

[@045akashmaurya7]

Then there must be a resistance with their respective diode(or we will use linear piecewise diode)

[@treaciajumuad1103]

You will just replace the value of Si which is 0.7 the value for Ge is O.3

[@Rehan_LogicLab]

Then only Germanium diode will ON because of low voltage of 0.3V and Silicon diode will OFF

[@angelafrancisco3580]

At 2:37 shouldn't it be just A not mA? since you just use Ohms and not kOhms at 0.33?

[@Fotosepken]

that should be A, i agree your point

[@Rehan_LogicLab]

Yes that's Amps

[@csabamolnar5674]

9.3V/0.33ohm = 28.18A not mA.

[@alterguy4327]

Csaba Molnar Probably its 0.33k ohms

[@alterguy4327]

0.33 ohms will burn the diode😂😂😂

[@utsabchatterjee5584]

yes, you r right. but I think 0.33kohm is the actual value

[@sumitchoudhary9143]

Yeah this is the point where I was stucked

[@krrish.pawar819]

2:46 How mili amos came, Would it not be only Amps??...

[@someone2879]

What if we have 2 different types of parallel diode, where the equivalent model (the polarity) are not the same for both of them?

[@SiddharthSingh-rx5ie]

If the diode is placed in reversed direction then it simply will act as an open circuit causing the parallel configuration to act like a normal configuration.

[@PallaviKumari-en2bx]

why ID1 and ID2 current same please explain??

[@romainedixon4560]

Since they are the same type of diode ( silicon in this instance ) they have the same voltage drop across them and hence draw the same current

[@rajinder250987]

Hi Gentleman, How to calculate the Id1 and Id2 in the case, if diode 1 is silicon diode and diode 2 is Germanium diode? Thanks

[@gamingplus8908]

and output voltage Vo too.

[@alterguy4327]

Rajinder Bhagat Vo will be 0.7V

[@shubhamnayak9369]

Rajinder Bhagat :if ge diode is used along with si in parallel then ge will conduct therefore output will be 0.3. si diode will never conduct as it requires 0.7 volt to conduct.

[@fariborzmomtazzadeh4497]

@@shubhamnayak9369 can u explain more pls ?

[@shubhamnayak9369]

@@fariborzmomtazzadeh4497 see both Ge and Si diode are in parallel..ok now input voltage increases slowly.. 0,0.1,...etc as soon as it reaches 0.3V ,Ge diode conducts...so voltage across Ge will be 0.3V and since voltage across parallel combination remains same so voltage across Si diode will also be 0.3V but Si diode will conduct only when 0.7V is across it.. but we know it is 0.3 V so Si diode will never conduct as loong as Ge is conducting

[@enjoyingyourself]

Concept is correct to learn this equation

[@TheFreezingTuberJosh]

Very well explained

[@mowafagnazar3979]

You are a Legend!

[@alterguy4327]

Thanks a Lot☺☺

[@alterguy4327]

Sir 0.33ohms will burn the diode

[@Abdurrehman-ee7nw]

Presented Nicely (y)

[@srikanthreddy549]

At 02:22 , is barrier potential +ve?

[@Kattar_Awaam]

i like your all video sir

[@sahabulhoque1255]

sir, pls tell me, how i can find a equivalent diode. my required diode is SB5150 which is unavailable at market. its for led tv power supply pcb.

[@waterfuel]

Question - How do I measure on multimeter the output voltage from circuit seen from 2007, that was secondary side of Inverter of 120VAC connected on each output line single diodes that are opposite polarity each facing, going to resistor load? Is this still a portion of 120V AC output ,or approx 40 volt half wave DC plus and minus DC? The writer may have been thinking about back flow protection. This is not print error, or about clipping circuit. Please advise.

[@mahjabinsalim3030]

Current is not in mA, it will be only amphere

[@baitywahidiah8077]

how to calculate if i put another resistor in the middle of the diodes? should i use node voltage?

[@SefaOralz]

Why you didn't point out the risk of thermal runaway in case of negative thermal coefficient of Si diode. Its risky to parallel two Si diode without any snubber or protection/current balancing circuit.

[@allahnawaz8265]

Nyc explain sr

[@saumypandey2184]

Y r u taking current I1 through only one. Battry...it will b e I/2 so to get I we hve to consider both diode battry ???

[@sudiptaproggaislam7321]

if D1 is Ge which have 0.3V, then what will be the result?

[@ramtripathi1621]

the overall voltage drop across the combination of germanium and silicon diode remains the same as that of the germanium diode so that silicon diode wont even be activated. And we can have voltage drops in each case as 0.3V.

[@wb19newgate34]

Hello prof. Why is the unit for I1 is ma?? Even for id1 and id2? Since it is 9.3V/0.33ohms. Should it be Amperes

[@chrisoca958]

Thank you!!!

[@vicente6110]

damn. that hp ad was deep

[@manisharan5713]

sir please upload problems on how to find weather the diode is forward bias or reverse bias when the circuit is given , thanking you sir

[@saymasarwarela4785]

@Mushahid Intesum hi

[@harshithm6937]

Excuse me 9.3/0.33 is 28.18 Amps not mA.

[@AbhishekRaj-vv7dr]

what if the diode is a zener diode,I have this problem with zener I cannot solve

[@skeltongamingstudios]

9.3 volts/ 0.33 ohm = 28.18 A... not m A

[@stefano.a]

In the real case the voltage drop accross diodes in palallel is lower than the one in a single diode. The simplified model of diodes i this circuit is not adequate

[@Koryteq]

Why ID1 is equal to ID2??

[@user-cf4iw2tr4i]

I think because the have same voltage??

[@AKSHAYCARIAPPAPN]

why is Id1= Id2?

[@hadiaamin1466]

Akshay Cariappa because both are silicon diodes

[@vishalmehra794]

Why the two currents are equal in the two diodes

[@ranjithKumar-eg7ln]

Because two diodes are silicon diodes.

[@FerNam-q1r]

Why we replaced the diode by a generator and not a generator and a resistance? if someone knows the answer pls write it in the comment section 🙏

[@nozomi_senpai]

did you find it?

[@hariomgupta3891]

Why Vo =0.7 v... Plzz explain it

[@joanwambura]

Voltage required by silicon diode

[@anshumandey.0472]

you explain very nicely but make many mistakes while taking the units

[@shreyxnsh.14]

questions mein aise current ki direction thodi na given hoti hai

[@lpsoldier8627]

what if there were two different diodes?

[@richardmatjeane9004]

Then the currents wouldn't be the same.

[@94D33M]

@@richardmatjeane9004 Only one would be on,the one that requires smaller Vb

[@shivendradwivedi3070]

Not well explained 😑😑😑

[@sharathchandra6349]

❤

[@hariharan-yi8tf]

How u knew 28.18 is milli amps?