Newton's 2nd Law (9 of 21) Calculate Acceleration with Friction; Inclined Plane, One Mass

[@justinviasus3833]

I wish you were my honors physics teacher! My teacher rushes, doesn't explain, and is so messy that I can't understand what he does! Thank you so much you're a life saver!

[@stepbystepscience]

+Justin Viasus Glad that I could help. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@andreablignaut2333]

More useful than my Physics class.

[@stepbystepscience]

Thanks, You can see a listing of all my videos at my website, www.stepbystepscience.com

[@seankrkovich2869]

It's well explained and concise.

[@LoGiNfromFIN]

Started a course in physics after a ten year break from maths. This helped TREMENDOUSLY :D Hardly anything beats the feeling of learning something. Thank you so much!

[@stepbystepscience]

Glad to hear it, best wishes to you.

[@Aer01614]

Bravo you are one of the few that actually explained the breaking of the vector into components and you made it so simple. Your an excellent teacher and thank you for your time !

[@stepbystepscience]

Thanks for the great comment. You can see a listing of all my videos at www.stepbystepscience.com

[@gabrielmaghokmathiang5447]

The way you explain it here makes me feel good again after I almost gave up on applied math. Thank you so much

[@stepbystepscience]

Great that you found the videos helpful and thanks for commenting. Don't give up!

[@zackabramson134]

my physics teacher gave us one of these problems for HW and is expects us to not get this problem right due to the fact that he did not directly teach us how to deal with friction and wants to see the equations we come up with to try and deal with this new variable. this helped a lot. i had the general idea down on how it would work without friction but had no idea when it came into play in the equation. thanks to this now i do!

[@stepbystepscience]

Great, thanks for watching and commenting.

[@amirhaabisse9060]

You are the best at teaching physics on this platform. I’ve watched countless of videos and non are as good.

[@stepbystepscience]

Glad you like them and thanks for the great comment.

[@caribbean32]

So much help, my physics teacher tends to rush through the entire unit. Understood everything so far in class except for this one type of question but now I get it! Thank you!!

[@stepbystepscience]

+Braeden .Lav You are very welcome, I try to go over everything step by step. In fact you can see all of my videos at my website, www.stepbystepscience.com.

[@huntershub344]

fantastic, couldn't understand this, reading from the book and you explained it perfectly xx so much love

[@someicedtea1479]

a decade later and your video is still incredibly useful 🎉

[@stepbystepscience]

Happy to hear that, thanks!

[@void7839]

WHY COULDNT I FIND YOU BEFORE!?!? YOU'RE BEYOND AMAZING!!

[@stepbystepscience]

Thank you very much, You can see a listing of all my videos at my website, www.stepbystepscience.com

[@aedenparenteau713]

Had trouble and you made my life so much easier thank you so much! Not only did you help me with this particular situation but helped me look at physics questions in a whole new light.

[@stepbystepscience]

That is really great to hear. Glad I could help!

[@siddarthbatchu9978]

Omg this saved me so much. My physics teacher didn't explain anything. Wish you were my physics teacher

[@stepbystepscience]

so nice of you, thanks!

[@ferc3604]

Oh wow! You don’t have any idea of how much you helped me. Thank you!!!!

[@stepbystepscience]

That's wonderful. Glad I could help!

[@berlynpanabe3370]

Thank you so much. 🤟 You enlightened me. I really can't understand what my instructor is explaining until I watched your vid.

[@stepbystepscience]

you are very welcome, thanks for commenting.

[@jorriesmith3152]

I learned more from this 7 min video than i did in a 3 hr lab ... thank you sooo much

[@stepbystepscience]

Most things are pretty straight forward, but I suppose the lab should give you a better conceptual understanding. Thanks for the comment.

[@moonlitwalks-n2y]

This was so helpful because everything seems so complicated, but you do a wonderful job explaining it! (Saving me for the physics finalll)

[@stepbystepscience]

Glad it was helpful! Good luck on the final!

[@SPIDERMAN-kq1go]

You're a genius. Thanks for your help, now I could solve past paper questions for A-levels

[@stepbystepscience]

+SPIDERMAN Great, thanks for commenting. You can a listing of all my videos from my website, www.stepbystepscience.com

[@bma6469]

Superb clarity on a step-by-step approach.

[@stepbystepscience]

Glad you think so, thanks for the nice comment!

[@lochlanndunn843]

thank you that helps so much in class the teacher goes too fast but you break it down beautifully :)

[@stepbystepscience]

Step by step, thanks for commenting.

[@Asiahkye]

This helped me A LOT! I've been watching video after video. Thank you !

[@stepbystepscience]

Great, thanks for commenting and letting know.

[@mediocregamer2484]

I'm gonna cry, thank you so much

[@stepbystepscience]

You are very welcome. You can a listing of all my videos from my website, www.stepbystepscience.com

[@mediocregamer2484]

one question, what if there is no mass given

[@lesternygaard842]

it does not depend on the mass anyway

[@hassanulger7167]

you dont need mass to get the acc just plug the numbers youll get the acc

[@princekerkula75]

Thank you for the video. But I am not understanding how u sum up the forces in the x direction. Taking the friction force that is going in the positive x direction and minusing it from the x component of mg. I am not understanding please help me out.

[@stepbystepscience]

I decided to make down the ramp the positive direction. (You can decide which direction is the positive.) The x component of the gravity points down the ramp to it is positive and the friction force points in the opposite direction, up the ramp, so it negative. Does that help?

[@GhaidaMmajed]

I wish if I can like this video more than once.... U R LIFESAVER

[@stepbystepscience]

One time is great

[@mlndz111]

If you had a block with an initial velocity moving down a ramp how would you figure out whether the friction coefficient is enough to hold the block from moving at that speed or not?

[@stepbystepscience]

If the coefficient of friction results in a friction force that is great then the component of the gravitational force that is parallel to the ramp, then the block will not move down the ramp.

[@mlndz111]

@@stepbystepscience Thank you for your answer. I am facing a problem where a cart with a block on top are moving down an incline at a certain velocity. If the cart suddenly stops, all the momentum from the block plus the gravitational force would need to overcome the frictional force. My issue is how to find this momentum force. My end goal is to find if friction would be enough to hold the block in place or if I need to add securing pins.

[@Himanshu-ws3vl]

Great step by step amen to this may god bless you sir

[@stepbystepscience]

So nice of you, thank you and warm wishes to you

[@hassanulger7167]

Thank you Mr. step-by-step Science

[@stepbystepscience]

You are very welcome! You can see a listing of all my videos at my website, www.stepbystepscience.com

[@Hunter-qn9vn]

I understood everything else but how the triangles were similar (3:28)

[@kevinroxursocks]

Thank you so much :) need more people like you, keep making these videos!

[@CeresSky]

Good Video. Very useful for an AP Student.

[@stepbystepscience]

great

[@ibrahimbadereddien6324]

Thanks alot alot alot.. very clean explanation great teacher ♥️♥️

[@stepbystepscience]

You are very welcome!

[@Jenko022]

Thank you for another excellent video. Could you possibly do a video series on digital logic and Boolean algebra?

[@stepbystepscience]

Thanks for commenting. I ams still working on physics so I guess digital logic will have to wait.

[@harrywalsh830]

Thanks so much, I'm doing a physics assignment and that was so useful !

[@stepbystepscience]

Great and thanks for commenting

[@AustinFern3rdDegree]

Excellent explanation, easy to follow and great diagrams!

[@smokeylowkey5575]

how do i find the Minimum force F that must be applied perpendicular to the incline, for the object to stop moving?

[@margarethmba7404]

pls sir i would like to know wat is meant by force due to engine?.i have gotten a question and need to calculate it .pls reply i don't really understand

[@fritz411]

As the video progresses, you sound more and more like Vince Vaughn. Haha!

[@stepbystepscience]

Funny how that happens. I do have a bit more hair then he does. Thanks for the comment. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@joeombres1915]

First video I immediately thought that! I cannot ever see his face, because I'm envisioning Vince Vaughn teaching me physics! lol

[@darkrising8280]

I swear the worst class to have a bad teacher in is physics. Thanks so much for the help

[@stepbystepscience]

My pleasure, glad to be of help.

[@ksp1571]

how can i find the acceleration on the incline plane when i got the distance and time? is the answer the same when use (a=x/t²)

[@stepbystepscience]

+Sophot Ky I am not sure that you can…acceleration is a change in velocity…But I would need to see the problem to be sure. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@joeombres1915]

I had a similar question. I am not given the friction coefficient and supposed to find it. "A 3.00-kg block starts from rest at the top of a 30.0° incline and slides a distance of 2.00 m down the incline in 1.50 s. Find acceleration, coefficient of kinetic friction, friction force, and speed of the block at the end of the 2m." I cannot find any examples online anywhere where the coefficient isn't given. I've spent probably close to 10 hours on this one four-part problem alone.

[@josevela9018]

Joe Ombres use a motion equation.

[@MrJuandahero]

If you added hyperlinks for guided problems and solutions for each individual chapter this would be a 5/5 star worthy tutorial, never the less it's amazing thank you +1

[@stepbystepscience]

I have considered doing that but it would be a lot of time and work. Thanks for the comment. You can see a listing of all my videos a my website, www.stepbystepscience.com

[@joannacollins9980]

can someone please explain why the applied force on the x -axis is sine.

[@chikenuget3841]

how did you know the opposite and hypotenuse for sin and con

[@stepbystepscience]

That is the definition of the sine and the cosine. Sine = opposite over hypotenuse and the cosine = adjacent over the hypotenuse.

[@yasserghuloom3525]

It was really a beneficial video Thanx man

[@1018blm]

what if the problem doesnt give a mass and coefficient of friction, but only gives the angle

[@oliviahoying]

Would the acceleration be negative since it’s going in the negative direction? A=-.87m/s^2?

[@vedantmehta2560]

Love the video thank u for clearing my doubt..

[@stepbystepscience]

My pleasure, thanks for the nice comment

[@Al_rock18]

Thanks this helped a lot but I thought you used sin for the vertical and cos for the horizontal don’t you?

[@shrevackado8418]

what if you were to push the block down, with lets say... 10 N of force, how would the equation change?

[@stepbystepscience]

You would have to add a term for the pushing force.

[@annettemolina]

Thanks this helped me with my physics IA soo much

[@stepbystepscience]

Great to hear, you're very welcome!

[@alexandrataylor1111]

I don't understand why we can't solve for Fn in for u*(N) and plug Ff into my x direction acceleration?

[@moonlightgraham1089]

very helpful reminder

[@bananasarefriends1471]

I'm really glad I saw this❤❤❤❤

[@stepbystepscience]

Me too, thanks for watching!

[@AbbieJr]

Thanks sir. I understand stand you better than my class teacher 😉

[@stepbystepscience]

You're welcome. Glad to be of help.

[@KAROLsBlue]

Sir where is the applied force?

[@himalupreti8173]

it was smart and good i liked it thanks i ressolved all my confusions which were in my brain thanks again

[@stepbystepscience]

+himal upreti That is great, hopefully your brain will not get confused anymore. You can see a listing of all my videos from my website, www.stepbystepscience.com

[@ces9180]

Does anyone know how to find the acceleration if you don't have the coefficient of friction? Is it possible to find acceleration of the net force with only using the mass of the object and the angle of the inclined plane?

[@brookeplifts]

the force of friction or the coefficient HAVE to be given if you're dealing with a problem that includes a non-frictionless surface or else it would be a frictionless surface. if you're given the force of friction but need to find the coefficient, it's just that multiplied by the normal force. if you're given the coefficient but you need to solve for the magnitude of the frictional force, it would be the coefficient of the friction force divided by mgcostheta however, if you need to find the magnitude of KINETIC friction of an object on an incline and acceleration IS given, then it's fk = (ma) + (mgsinetheta)

[@ces9180]

@@brookeplifts Thank you for your response!

[@mathewsmbewe]

This is great stuff, physics made simple...

[@gracehamilton2874]

you are simply amazing!!! Thank you so much for being an awesome teacher!!!!!!

[@enochaustin2532]

this saved my life

[@stepbystepscience]

Great that you found it helpful! Thank for the comment.

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bro you saved my grade from a 30% to a 100% and to that I owe you big timeeee

[@stepbystepscience]

I am very happy for you that your grade went up so much. Thanks for letting me know.

[@jewellab1003]

How would you solve this without knowing mass, but knowing velocity?

[@SumdiLumdi]

Cheers dude really helpful.

[@jameslake8117]

Currently studying an engineering HNC in the UK. Great video thanks! One question, what is the difference between Acceleration and an acceleration force? I'm confused as to what my lecture has taught

[@stepbystepscience]

I would say there is no such thing as an "acceleration force". Acceleration is a change in velocity over time and unbalanced forces cause objects to accelerate.

[@jameslake8117]

Step-by-Step Science many thanks for your response. My lecture gave me the formula for 'acceleration force' as = m.g.(sin(x) - u.cos(x)). Is that right, I'm still confused!

[@jameslake8117]

After thinking long and hard I think I've got it! The formula my lecture gave me is the formula for 'Force' on an inclined plane. So that formula I posted previously is the formula for working out the force that the mass would have on the inclined plane...am I right? As force = mass x acceleration

[@vanitha7786]

Thank You . That was an awesome explanation! Cheers :-)

[@stepbystepscience]

Glad it was helpful!

[@نائلنعمان]

thanks a lot excellent video

[@stepbystepscience]

+‫نائل نعمان‬‎ You are very welcome…..You can link to all my videos at my website: www.stepbystepscience.com

[@jnrgunner]

Hey sir should it not be sin19+0.25*cos19 since the friction force is in the positive direction ? thats how my teacher had it ?

[@stepbystepscience]

I decided that to the left (down the ramp) is positve. Therefore the friction force is in the negative direction, it points in the opposite direction, up the ramp. You could make to the right positive (up the ramp) then mg*sin theta would be negative. Either way one of the forces is positive and one would have to be negative. Does that help??? You can see a listing of all my videos at my website, www.stepbystepscience.com

[@jnrgunner]

Thankyou very much that makes sense now. therefore if you were to make the friction force in the positive direction will the final equation look like this -9.8*sintheta + 0.25 *costheta or will it be 9.8*-sintheta +0.25*costheta just not sure were i would put the negative sign infront of gravity or the sin theta thankyou love your videos you the best!! love from canada

[@stepbystepscience]

Put the negative sign in front of the whole thing.

[@jnrgunner]

thankyou so much! your amazing, is it possible if you can show me how the equation will look ? just so i make sure ive written it right

[@andresduarte9347]

Good explanation

[@stepbystepscience]

Thank you.

[@dexterbarnes5249]

This video is so much help

[@stepbystepscience]

Thanks for the comments. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@MillionMovieClips]

If you do components of Mg and then equate normal force you gets N = Mg cos theta , But if you do components of N then you gets N cos theta = Mg. This confusion is eating me, Please Clarify if you can, and if you didn't understand my problem reply to me I will send photo of equations and diagrams on gmail.

[@MillionMovieClips]

Please clear my doubt you reply to everyone.

[@stepbystepscience]

I am not really sure what your point is??? WE do not need the components of N.

[@yungmsa]

thank you so much really I need this so bad it's the might before my paper 😭

[@stepbystepscience]

Glad I could help, good luck!

[@yungmsa]

@@stepbystepscience thank you thank you thank you, I got full marks for the physics component of my paper 🙏🙏🙏🙏

[@isabelbozo8170]

very helpful! you saved me!

[@stepbystepscience]

+Isabel Bozo You are very welcome. You can a listing of all my videos from my website, www.stepbystepscience.com

[@tavo8882]

bro!! i love you...wish you were my physics teacher!!! apply for the job at concordia university- montreal!!

[@marcuschua3688]

Great explanation but if u could talk slower itd be great so that some people who cant catch up with what u are saying dont have to pull back and rewatch the same parts again but overall great much thanks!:)

[@stepbystepscience]

It is always a bit of a balance between too fast or too slow....

[@asmaabulleil8789]

Thank you so much that was very helpful. I'd like to ask though, why didn't you consider the acceleration due to gravity negative?

[@stepbystepscience]

Because I am just getting the magnitude of the forces. Then I account for the sign of the forces when I put them in the acceleration equation. Does that help? You can a listing of all my videos from my website at www.stepbystepscience.com

[@matildachileshe6580]

My God you are so good wish you were my lecturer

[@stepbystepscience]

Thanks for the very nice comments. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@gaelzarzar3393]

thkx man amazing help

[@stepbystepscience]

Any time, thanks for watching!

[@danielay714]

Thanks👍

[@stepbystepscience]

Welcome 👍

[@jasonromo6020]

Thanks soo much!

[@sayedarifhabibi7082]

Very useful

[@stepbystepscience]

Glad you think so, thanks!

[@precioussullivan8533]

Thank you so much !

[@muaazjassat8369]

I'd hate to burst your bubble but your answer is incorrect. First of all, how can you cancel across a minus sign? You've cancelled the mass of the object am I right? According to my calculations where instead of cancelling out the mass of the object, I kept it in my equation and instead got an answer of 0.085 meters per second squared

[@muaazjassat8369]

Sorry I made a mistake, the answer is 0.089

[@stepbystepscience]

It is not cancelling "across" the minus sign but it is basic algebra....the masses cancel.

[@dexterbarnes5249]

This is great

[@alsinakiria]

There was one part I just couldn't get. The teacher was not helpful since he "doesn't want to give away the answer to the assignment". Yeah, whole lot of good that is, how can I do it if he won't explain it? Now I can finally finish my assignment.

[@stepbystepscience]

Great and thanks for the comment.

[@muaazjassat8369]

Please if I'm wrong, correct as I am human, I do make mistakes. I'm not trying to prove that I am smarter than you or if I'm smart at all. I'm just curious that is all

[@nhlahlampungose4599]

Thanks its a nice axample

[@stepbystepscience]

You are very welcome. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@estesclimbbum]

you are a god man. i get it now

[@TheLlamaCannon]

i wish you were my physics teacher!

[@TheLlamaCannon]

thanks a bunch btw great job with the video

[@stepbystepscience]

That is a very nice thing to say, thank you. You can see a listing of all my videos at www.stepbystepscience.com

[@TheLlamaCannon]

i actually cant come up with your answer even when i use the same numbers as you 9.8(sin19 - .25 * cos19) i have the degree signs after the 19's and im not sure what the x you have in your equation is

[@randomnessy12]

thank you!

[@stepbystepscience]

You are welcome. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@simonwalton7412]

i keep getting 0.09729894488 and have no clue as to why

[@richarc2307]

This kinda makes it more confusing is better if you plug all the numbers in first

[@stepbystepscience]

Depends what make more sense for you.

[@thesqaush286]

3:10

[@stepbystepscience]

What about it?

[@thesqaush286]

could you do a quick video explaining the similar triangles lol

[@stepbystepscience]

Same size angles but different size triangle....is that quick enough? lol!

[@thesqaush286]

I KNOW WHAT I SIMILAR TRIANGLE IS but its not adding up as to why its similar

[@stepbystepscience]

Because the angles are the same size........What is your favorite kind of squash?

[@JessicaSanchez-wz2fj]

beautiful :D

[@stepbystepscience]

Thank you, You can see a listing of all my videos at my website, www.stepbystepscience.com

[@siddharthniranjan6539]

You should explain the theory first then example.

[@sistemsylar]

no

[@seanpawelczyk370]

i love you so much

[@stepbystepscience]

Aww, thanks!

[@12stormy13]

cos would be your Y.

[@manhalbakka5780]

i love you

[@stepbystepscience]

If you really love me then you would subscribe! ;-) Thanks for watching!

[@chikenuget3841]

I got -9.bla bla bla

[@KAROLsBlue]

Sir where is the applied force?

[@stepbystepscience]

There really isn't an "applied" force. The force that makes the object move down the ramp is the x-component go the gravitational force. Does that help?

[@MrSocialish]

5:15