Non uniform circular motion

[@AlePreludioFinal]

Thank you for this videos, are very helpful. You are making a very effective way of teaching! You had already helped to guide the path to thousands of future scientists. Wish you well, Matt.

[@amoghap.8231]

Mr. A doesn't get that much love for the content he creates... I'm studying this because my teacher can't teach and we have a quiz tomorrow!

[@कैलाससपकाळ-ख2न]

Hii

[@AmazonFiesta]

im more impressed of how he writes the opposite direction just so the students can read , or there might be something with that glass.. idk great video though, thanks.

[@yoprofmatt]

Secrets revealed here: kzbin.info/www/bejne/eYirfqeJg7Crj6M Cheers, Dr. A

[@RobbyBoy167]

It's magic bro. Magic

[@yoprofmatt]

Thanks. But it's not magic, bro. Just a bit of optical trickery. Check us out here: www.learning.glass Cheers, Dr. A

[@John3_17-21]

I figured you weren't wrong-handed.

[@Happy-cm7uo]

ikr

[@rajnandininirwal3291]

the way he writes is really cool . awesome . his way of explanation and derivations is great too .

[@yoprofmatt]

Thank you. Keep up with the physics. Cheers, Dr. A

[@wealthpass902]

You just earned a new subscriber. Keep up the great work!

[@kelseywong7337]

Hey Professor A, I'm a little confused uniform circular motion and nonuniform circular motion (just went through your videos on those two topics). Perhaps I'm not making the connections between some fundamental concepts and circular motion. In uniform circular motion, velocity -- though changing direction, has a constant speed. So if I were to plot an acceleration vs. time graph, wouldn't a=0? So how is there acceleration during uniform circular motion? But let's just assume that I totally understand that uniform circular motion does have acceleration. So now I'm wondering, how does this differ from nonuniform circular motion? In nonuniform circular motion, since velocity is changing speed, acceleration is present. In both cases -- uniform and nonuniform -- we have a change in velocity, and therefore a change in acceleration. Why are they different? How does a change in direction for velocity differ from a change in speed? Thanks so much for your time, and for these videos. They are super helpful!

[@yoprofmatt]

Kelsey, Good question. Since acceleration = change in velocity, there are a few possibilities: Speed changes but velocity direction = constant ( -> linear motion), Speed = constant but velocity direction changes (-> uniform circular motion), speed changes and velocity direction changes (-> non-uniform circular motion). Hope this helps. Cheers, Dr. A

[@kelseywong7337]

Thanks Professor A!

[@breatog4192]

I got a question on this. For non-uniform circular motion is the centripetal acceleration not constant because the speed changes because of the translational acceleration so when you put the speed in the formula v^2/R, you will yield a different centripetal acceleration because v is not constant. Thank you very much.

[@Princekumar-oy6dy]

what a concept . thank you so much sir

[@brendondube9967]

thank you professor i had a simliar question on my home work and the video really help me thanks alot for you work

[@yoprofmatt]

Excellent. Thanks for the feedback. Cheers, Dr. A

[@poemsschoolandcompetitions2895]

can you sir also upload angular frequency vs angular velocity.

[@labinatasfia624]

For non unifrom vertical circular motion of an object tied to a string, would the tensino force only depend on the centipetal force?

[@yoprofmatt]

The centripetal force is the net force that keeps it moving in a circle. For a vertical loop, at the bottom the centripetal force = T - mg. At the top the centripetal force = T + mg. Cheers, Dr. A

[@labinatasfia624]

@@yoprofmatt Thank you so much :)

[@siyarilhan219]

Konuyu çalışmayı bıraktım, tersten nasıl yazabiliyor onu düşünmeye başladım

[@farouk8012]

kzbin.info/www/bejne/eYirfqeJg7Crj6M sunu izle kanka

[@ganeshk.ganesh1176]

Good derivation . i like it

[@yoprofmatt]

Thanks. Keep up with the physics. Cheers, Dr. A

[@victormaxwellpeters9771]

From were did ' V ' poped out???

[@yoprofmatt]

Victor Maxwell Peters, v is the speed. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A

[@mohfa1806]

are you guys aware that we have homework?...... lol

[@raghavgiri4071]

lol🤣🤣