Normal Electric Field Boundary Conditions

  Рет қаралды 36,450

Jordan Louis Edmunds

Jordan Louis Edmunds

Күн бұрын

Пікірлер: 35
@rudylopez6546
@rudylopez6546 3 жыл бұрын
Great explanation!!! My EM professor can't explain boundary conditions as easy as you can. Keep it up Jordan!
@JordanEdmundsEECS
@JordanEdmundsEECS 3 жыл бұрын
EM is a hard subject to explain xD Thank you!
@gerardogutierrez4911
@gerardogutierrez4911 4 жыл бұрын
mMy guy, were in the same Quantum Mechanics II class! Nice video, I always sucked at EM, but your vids make a lot of sense. Good luck on this and the midterm tomorrow lol
@jordanedmunds4460
@jordanedmunds4460 4 жыл бұрын
Ahahahaha that's hilarious xD. Maybe after this semester I'll actually be able to teach QM properly.
@gerardogutierrez4911
@gerardogutierrez4911 4 жыл бұрын
@@jordanedmunds4460 YES I would love to see your explanations in a friendly and straight-foward way lol. Anyways good luck and glad I found your channel.
@andyralph9495
@andyralph9495 3 жыл бұрын
this is good...I'm impressed...I tried watching a lot of videos reading a lot of book to get to the bottom of this but to no vail...Thank you jordan!
@JordanEdmundsEECS
@JordanEdmundsEECS 3 жыл бұрын
You, Andy, are welcome :)
@RamVelagapudi
@RamVelagapudi Жыл бұрын
Thank you edmunds❤ you saved me
@JumbyG
@JumbyG 4 жыл бұрын
Brilliant video! Thank you Mr. Edmunds!
@tarunpurohit6522
@tarunpurohit6522 3 жыл бұрын
Thank you very much, way better than my book 📚
@JordanEdmundsEECS
@JordanEdmundsEECS 3 жыл бұрын
Thank you, Tarun :) I sincerely appreciate the encouragement!
@kingdemon4236
@kingdemon4236 4 жыл бұрын
Well done, amazing video.
@mgx9383
@mgx9383 2 жыл бұрын
8:35 Why did you draw Enorm2 with direction opposite to Enorm1? It doesn't follow from equations.
@bhavsarpriyansh
@bhavsarpriyansh Жыл бұрын
Isn't the direction of Enorm,2 at 9:25 same as Enorm,1?
@damiangierek8047
@damiangierek8047 Жыл бұрын
In 1:58 You didn't mention that Q_encl is the free charge enclosed and not the total charge. Q_total = Q_counfined + Q_free, where Q_confined is the charge that is confinded in diaelectric dipoles.
@aixenlost271
@aixenlost271 Ай бұрын
is there a playlistt ?
@Abcdefghijkl623
@Abcdefghijkl623 2 жыл бұрын
This got you a subscription
@zeeshantahir7825
@zeeshantahir7825 5 жыл бұрын
It helped alot... Thank you
@baghdadiabdellatif1581
@baghdadiabdellatif1581 5 ай бұрын
Thank you
@banajadandasena4142
@banajadandasena4142 5 жыл бұрын
Thank you sir.
@luongdat5196
@luongdat5196 5 жыл бұрын
This is awesome. Thank you sir
@satvikkumarpatel1129
@satvikkumarpatel1129 2 жыл бұрын
HI, 5:50 what do you mean by linear marterial? Linear in what sense? Great video btw
@mgx9383
@mgx9383 2 жыл бұрын
Linear means that epsilon is not a function of E (same thing for µ and H, and for conductivity).
@whoknew3775
@whoknew3775 4 жыл бұрын
Is this process the same regardless of the materials in parallel? So, if you have two conductors, dielectric and a conductor, or two dielectrics?
@andyralph9495
@andyralph9495 3 жыл бұрын
Can I not say the sides of the cylinder have a surface area perpendicular to E so the flux in the curvy side =0?
@dbf72829
@dbf72829 4 жыл бұрын
There are two formulas for boundary condition I saw in book I guess the tangential one they determined with sin theta I guess. I didn't understand that part would you like to explain please
@srideepz9095
@srideepz9095 3 жыл бұрын
Superb
@poly3902
@poly3902 2 жыл бұрын
Hello Mr. Jordan, Thank you very much for your useful videos. I am a little bit confused about one thing that i hope you can make it clear to me. Why we don't follow the same approach as the tangential component, why we didn't use the line integral Maxwell's equation and make the area very small so that ds will equal zero as we did for the tangential components.
@whysoserious0609
@whysoserious0609 2 жыл бұрын
I think we want to keep what we want, if ds goes to zero, then the left-hand side equation containing Enorm1 and 2 are gone, only Qenclosed is left, which seems meaningless since we want the relationship between Enorm1 and 2
@poly3902
@poly3902 2 жыл бұрын
@@whysoserious0609 Thank you :)
@vikaskaushikkarora
@vikaskaushikkarora 4 жыл бұрын
Amazing ...
@vikaskaushikkarora
@vikaskaushikkarora 4 жыл бұрын
Thanks a lot sir ...
@jayjain1033
@jayjain1033 2 жыл бұрын
why does sigma become zero, isnt there still area of the top and bottom of gaussian surface
@luciferinjustice2632
@luciferinjustice2632 2 жыл бұрын
We assume charge free surface
@jacobvandijk6525
@jacobvandijk6525 3 жыл бұрын
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