Normalization of the wavefunction

  Рет қаралды 109,555

Brant Carlson

Brant Carlson

Күн бұрын

The normalization of the wavefunction in the context of probability distributions, normalizable functions, and what time evolution does to normalization. (This lecture is part of a series for a course based on Griffiths' Introduction to Quantum Mechanics. The Full playlist is at www.youtube.com...)

Пікірлер: 66
@biswarup077
@biswarup077 4 жыл бұрын
It would have been very difficult to jump start my my self learning QM using Griffith's book if had not found your videos. Thanks for making these videos.This was just what I needed.
@rashidalali6510
@rashidalali6510 3 жыл бұрын
What a coincidence, I also came here because of Griffith
@Peter_1986
@Peter_1986 3 ай бұрын
A lot of physics books have an irritating tendency to go on forever about a million different things at the same time, so that it takes a very long time to read them. Video tutorials tend to be much more straightforward and to the point.
@riosvm
@riosvm 11 жыл бұрын
Best explanation of wave function normalization on KZbin.
@mikevaldez7684
@mikevaldez7684 5 жыл бұрын
An Excellent exposition of Griffth's much abbreviated proof in chapter 1 of the 2nd ed.
@sphericalchicken
@sphericalchicken 11 жыл бұрын
No real magic there... 1/i is equal to -i. You can see that starting with i^2 = -1. Dividing both sides by i should give you i = -1/i, so multiplying both sides by -1 gives you -i = 1/i. It's handy sometimes to move i to the numerator, so I've made that 1/i --> -i conversion.
@zenojimneuromansah8665
@zenojimneuromansah8665 11 жыл бұрын
You are excellent at explaining your mathematical reasoning. Your mini visual proof of e ^-ix multiplied with it's complex conjugate was very helpful. thanks
@nelsonappiagyei4713
@nelsonappiagyei4713 Жыл бұрын
At 23:08 why did you not integrate from negative infinity to positive one but negative one to positive one?
@vasudevankn575
@vasudevankn575 2 жыл бұрын
soo much thanks mahn, been searching for this for years
@sphericalchicken
@sphericalchicken 11 жыл бұрын
It's worse than that, actually -- Psi(x) can be positive or negative, and can even by complex. The missing piece is that Psi (the wavefunction) is not itself the probability density. Instead, we treat |Psi(x)|^2, the squared absolute magnitude of Psi(x), as the probability density, and |Psi(x)|^2 is always a positive real number.
@genekisayan6564
@genekisayan6564 Жыл бұрын
hey, could you explain why we can factorize with a derivative ? I am about the question left unanswered in the video
@jacquelinebaeza7462
@jacquelinebaeza7462 3 жыл бұрын
I took QMI last semester and aced it. I had no idea what any of the math meant, but thanks to you know I understand what this means!! only took me 2 weeks into QMII to realize I didn't know what I was doing
@goldenchopstick1788
@goldenchopstick1788 11 жыл бұрын
great explanation of probabilistic interpretation! I finally understood the relationship thanks.!
@tommygaa
@tommygaa 10 жыл бұрын
at 14:34 it should be PSI* (psi star) :)
@asifhossain2863
@asifhossain2863 8 жыл бұрын
this will greatly help in my today's exam.... superb!!!!
@FlintPet
@FlintPet 7 ай бұрын
14:48 There is a star missing on the last blue psi for those who are confused :)
@alexfriebe1508
@alexfriebe1508 10 жыл бұрын
would love a video on expectation values and spherical polar coordinates
@goutham94
@goutham94 8 жыл бұрын
dear sir there is a slight mistake in the 1st term of schrodinger equation on the RHS at 6:24 Great video sir.. thank you :D
@dannijunglejim5692
@dannijunglejim5692 11 жыл бұрын
Great explanation! Much appreciated before my exam!
@Andrew6James
@Andrew6James 5 жыл бұрын
@Brant Carlson Could you please expand on the @18:48
@hidden_anonymous
@hidden_anonymous Жыл бұрын
Great lecture. Thank you!
@عبدالرحمنالعصيمي-ي6ظ
@عبدالرحمنالعصيمي-ي6ظ 5 жыл бұрын
Thank billion time for this amazing video , go ahead for such amazing explanations👍🏻😩😩😩
@jonnyyy9716
@jonnyyy9716 Жыл бұрын
If the wave function satisfies the conditions for normalisation does it suffice to differentiate the integral of psi squared dx = 1 wrt time? And then the RHS goes to 0?
@maxmiller5656
@maxmiller5656 9 жыл бұрын
thanks, clear and concise!
@danv8718
@danv8718 4 жыл бұрын
Fantastic series! Thanks a lot for sharing
@StephenRayner
@StephenRayner 10 жыл бұрын
What software are you using?
@richroylance4630
@richroylance4630 6 жыл бұрын
Excellent lecture...thank you.
@deconfinedQPT
@deconfinedQPT 7 жыл бұрын
at 19:08 the reason it is true that because differentiation is a linear transformation hence superposition and homogeneity is preserved, for people who wonders as to why he was able to rewrite the expression
@executorarktanis2323
@executorarktanis2323 4 жыл бұрын
explain more is this not simple common
@universal69
@universal69 2 жыл бұрын
The reason isn't this complex
@stijndhondt9611
@stijndhondt9611 8 жыл бұрын
This is golden. Thanks alot!
@dannijunglejim5692
@dannijunglejim5692 11 жыл бұрын
At around 13:30 You divide the Schrödinger equation by ih, and the way I would have computed that, the i would have stayed next to (2m), however you have placed it as if you were multiplying the equation by i. I also am unsure of what happened to the negative symbol in that step. Could you please explain the reasoning behind these steps?
@weisun184
@weisun184 3 жыл бұрын
This is my mom’s account but I think he multiplied by i on both side. On the left side of the shrodinger eqn you would have i^2 = -1 and hence the signs are flipped.
@gibsonmaglasang
@gibsonmaglasang 8 жыл бұрын
thank you so much prof. carlson. i learned a lot from your lecture videos. do you have lec videos on many particle physics or quantum field? thanks :)
@juanreyes8564
@juanreyes8564 10 жыл бұрын
Hi I am having trouble understanding what you said at 5:35 that it is not posible to have a function that stays non zero or goes to infinity as x goes to infinity and still have to be integrable. If you could explain that will be great thanks.
@juanreyes8564
@juanreyes8564 10 жыл бұрын
I think i understand: The wave function has to be zeros at both ends -infinity and pos infinity because if its not the the integral from -infinity to infinity will not be 1 thefore the wave function is non-normalizable.
@mkminerals12343
@mkminerals12343 8 жыл бұрын
dear,i m confused here,once you said that infinite square amplitudes are not normalizablet,right,as in dirac delta function,/////then you fit this idea to integral(summation) of infinite basis. as we know that square integrable functions converges in hilbert space in h2 space,i.e in infinite basis. so normalizable.
@thewalesj897
@thewalesj897 2 жыл бұрын
Brilliant!
@RI-xt4nh
@RI-xt4nh 8 жыл бұрын
Didn't know Eric Foreman taught quantum mechanics.
@RICHFRVR
@RICHFRVR 4 жыл бұрын
Haha
@sacha7958
@sacha7958 2 жыл бұрын
I'm pretty sure that the normalization constant at the end could also have been MINUS the square root of 15/16.
@lasha97
@lasha97 11 жыл бұрын
I can't get the part when you bring up functions in 02:37 how can probability be negative? sigh represents probability of finding a particle in some point of x right? well how can it be negative?
@magtutorial3606
@magtutorial3606 4 жыл бұрын
That's probability density psi(x) Not probability psi(x)2
@nashtrojan
@nashtrojan 11 жыл бұрын
great video.
@gforcebreakin
@gforcebreakin 10 жыл бұрын
sounds like main guy from that 70s show
@kharonofficial
@kharonofficial 9 жыл бұрын
What calculus you talked when you solved the integral?
@muhammadziaulislamarsalan1392
@muhammadziaulislamarsalan1392 8 жыл бұрын
thank u sir...
@kimyongtan3818
@kimyongtan3818 7 жыл бұрын
Brant Carlson, May I know why 18:48 is true?
@jayvalook
@jayvalook 7 жыл бұрын
late but just take the derivative using product rule, some of the terms cancel out leaving you with the equation Brant left
@Andrew6James
@Andrew6James 5 жыл бұрын
@@jayvalook Can you be more specific please?
@TheBrazilianFury
@TheBrazilianFury 3 жыл бұрын
@@jayvalook thanks!!
@Vector_world2036
@Vector_world2036 6 жыл бұрын
Position density
@compphysgeek
@compphysgeek 5 жыл бұрын
I dont know who the first person was to put arrows on graphs but that person deserves some sort of punishment
@reimalm7191
@reimalm7191 9 жыл бұрын
hi, can the constant be a negative value
@niemandwirklich
@niemandwirklich 6 жыл бұрын
I was asking myself the same question - mathematically yes, but would it make sense for a wave function having a negative sign? I think so, yes, but I could be wrong...
@Dekoherence-ii8pw
@Dekoherence-ii8pw Жыл бұрын
The wave function has a real and an imaginary part. Both of those parts are a wave which oscillate between positive and negative. If you multiply the wave function by -1 you just change the phase of the wave by 180 degrees (pi radians). @@niemandwirklich
@Dekoherence-ii8pw
@Dekoherence-ii8pw Жыл бұрын
If the constant is (for example) -3.5, then positive 3.5 would work just as well. The sign of the constant doesn't make a difference, because we're interested only in the square of the absolute value.
@a1ang0r85
@a1ang0r85 8 жыл бұрын
can anyone show the step for 22:00?
@cellerism
@cellerism 8 жыл бұрын
That is the most simple way of expressing it. u cant get anything more simpler. Its just like x^2=x(x) or u can say x^2+x^2=x(x+x)
@executorarktanis2323
@executorarktanis2323 4 жыл бұрын
@@cellerism pls help is it just that he took partial dx common or something big i missed
@SamsherSinghJoon
@SamsherSinghJoon 11 жыл бұрын
explain ???//
@basilpines2201
@basilpines2201 Жыл бұрын
3:44 am and 6 hours till ny final
@AlchemistOfNirnroot
@AlchemistOfNirnroot 6 жыл бұрын
wrt the derivative of the partial derivative of psi*, why isnt +(iV/h-bar)psi not psi star?
@AlchemistOfNirnroot
@AlchemistOfNirnroot 6 жыл бұрын
1st derivative****
@professionalprocrastinator8103
@professionalprocrastinator8103 5 жыл бұрын
Yeah he forgot
@juliopchile
@juliopchile 8 жыл бұрын
d'fuck??
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