Norton's Theorem and Thevenin's Theorem - Electrical Circuit Analysis

This electronics video tutorial on electrical circuit analysis provides a basic introduction into Norton's theorem and touches on Thevenin's theorem. It explains how to use Norton's theorem to calculate the current flowing through the load resistor in addition to using KVL nodal circuit analysis.
Schematic Diagrams & Symbols:
• Schematic Diagrams & S...
Resistors In Series:
• Resistors In Series - ...
Resistors In Parallel:
• Resistors In Parallel ...
Series and Parallel Circuits - Light Bulb Brightness:
• Series and Parallel Ci...
Equivalent Resistance of Complex Circuits:
• Equivalent Resistance ...
How To Solve DC Circuits:
• How To Solve Any Resis...
_________________________
Voltage Divider Circuit:
• Voltage Divider Circui...
Current Dividers:
• Current Dividers Expla...
Parallel Circuit Challenge Problem:
• Finding The Current In...
Kirchhoff's Current Law:
• Kirchhoff's Current La...
Kirchhoff's Voltage Law:
• Kirchhoff's Voltage La...
DC Circuits Review:
• Series and Parallel Ci...
____________________________
KCL and KVL Circuit Analysis:
• Kirchhoff's Law, Junct...
Thevenin's Theorem - Circuit Analysis:
• Thevenin's Theorem - C...
Superposition Theorem:
• Superposition Theorem
Maximum Power Transfer:
• Maximum Power Transfer...
Physics PDF Worksheets:
www.video-tuto...

[@TheOrganicChemistryTutor]

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[@Zero-h2f2m]

4:10 why did we substitute Vc from 100? Help pls and why voltage at point B is 0?

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[@benjaminheindl1069]

As they say "A good YT video is worth a thousand lectures". Thanks man!!!

[@HamedAdefuwa]

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[@gululu_jnr18]

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[@buffplums]

Well done sir! That is one of the best demonstration I have seen for a long time. Good use of visual and audible techniques. As a kinaesthetic learner I was able to combine what you drew on the board with your voice description. As an old engineer of 56 this took me way back to a 16 year old who was t that interested in T+N and just wanted to build exciting projects instead…. Anyway you explained it so well I actually remembered the theory and I think I would say I learnt some very useful theory. Thanks again

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[@kayebaron695]

I appreciate your work! It's very intuitive-- the way you often use voltage. It may be good for folks to know how to find "I Norton" without the use of Thevenin. This circuit is actually much easier if you go about shorting points A and B (since it removes a 3 ohm resistor), doing Source Transformation on the voltage source, and adding the current sources via the Superposition Principle. I ended up with a current source of 19.5 A running through two resistors in parallel. Current division yielded "I Norton." Anyway, thanks for your work!

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[@omegacanon]

Helped me review for an on-site interview. Thanks and cheers!

[@PunmasterSTP]

Thevenin? More like “Thanks for filling us in!” Your videos are just the best; keep up the great work.

[@ivancastro365]

Why minus the potential at B at 4:15? Why not Vc-Va?

[@AiCentric001]

Thanks man!!! Such a great teacher 💯 Much love from 🇳🇬

[@GREGGRCO]

Thanks for the refresher ! ENJOYED your videos. Good teacher! Correct me?: You do not need (Vc-0)/6. It's just the total voltage Vc across both resistors to B, Vc/6. How you said it confused me. It's been years. For me, what would have helped me understand quicker, if you'd said, "Total" current of I1, plus "total" current of I2...I lost that back in time somewhere. We all learn and obsess (lol) differently ! Thanks again! Made the gray cells exercise again !! Broke out my pencil and paper and eraser ! Good format. Liked how your computer graphics worked. Good calm voice. And your math gymnastics. I love to see how other people learned. You taught me to see several of the formulas differently than I was taught. Enjoyed it !!

[@mohnazaidi4666]

You became a wizard in that last minute while doing the check - I've never seen someone check their circuit so clearly!

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[@barsilgen120]

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[@Zero-h2f2m]

4:10 why did we substitute Vc from 100? Help pls

[@privak1175]

How come at 2:00 the resistors are in parallel, but in 4:20 they are in series? I am just a little confused since they seem to be exactly the same.

[@ThilebanTheEngineer]

I have the same doubt. 😇

[@mghq-mobilegamerzhq2533]

Same here!

[@arisariss1897]

same here

[@jafarsabbagh7914]

The resistances are in parallel at 2:00 because he was calculating the resistance, but when he started to calculate the current at 4:20 the current would be the same at both positions because at A there is no current going through so the current would just continue down to B. I3 is the same at both resistances. Another way to think about it is through KCL which states that the current that goes into a node is the same amount of current going out of a node. in this case I3= 0+I4, meaning that I3=I4 so they are both basically I3.

[@deveshmeena5798]

at 6:58 Va should be Vc*R2/(R2+R3) not Vc*R3/(R2+R3). Here R2 and R3 are same so we would get the same answer. Thanks for your video

[@shichiya5743]

Actually the video is right by using R3 instead of R2. To put it into a perspective, the amount of voltage entering R3 would be the same voltage entering the Load (RL in this case) since R3 and RL are parallel.

[@deveshmeena5798]

@@shichiya5743 nope you should watch circuit carefully. Here we are talking about R2 and R3 which are in series not in parallel, you should know the formula for the drop of voltage in series. And Rl which is load is parallel with the resultant of R2 and R3

[@rradical4714]

@@deveshmeena5798I noticed the same thing and was wondering if it was a mistake from TOCT, or if I had a poor understanding, but thank you :D!

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[@michaelloguemichael85]

We’re did he get RL

[@wallywhyte9280]

@@michaelloguemichael85 load resistor was given

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Nicely and thoroughly explained, much appreciated.

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[@narayanaswamyprakash7147]

Beautifully explained. Thanks

[@OMNI-Infinity]

The voltage we calculated at point C, was 66.857V (5:55) but when we substitute the values and check it again we get 60V (10:51). Why is that? Please answer before OpenAI releases GPT-4 for free. BTW congrats on 6M subs, well deserved🎉🎉

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[@johnschopp4566]

when you are doing node analysis about node C why is it not (Vc-Va)/3. why did you do Vb instead of Va?

[@PigeonPulverizer]

Might be a bit late, but since I had the same question and figured it out, I thought I would share: He took the two 3ohm resistors in series and added them together, causing node A and node C to be identical. Then, since node B is the designated ground (therefore 0V), Vc/6k is the simplified result.

[@keremhassoy9556]

@@PigeonPulverizer Hi! when you do the calculation it yields two different solutions. (Vb-va)/3 + Va/3 = Vb/3. Not Vb/6

[@kayebaron695]

@@PigeonPulverizer, right! This is possible because while finding V Thevinin, he creates an open circuit between points A and B which results in the two 3 ohm resistors being in series. Happy studying!

[@kayebaron695]

@@keremhassoy9556, I am not sure what you mean by this. Doing (Vb-Va)/3 would be in the incorrect current direction for this solution. Also, the calculation of (Vb-Va)/3 +Va/3 is TECHNICALLY (Vb-Va)/3 +(Va-Vb)/3; which sums to 0 since you are adding the current value across the same resistor from from both directions. Good luck!

[@leafsharp]

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[@maxwellschaphorst8574]

Thanks man you're a great teacher! Excellent explanation.

[@robonkenhout7965]

Question; at one point Vc was 66.8V, then at the end it was 60V. Is this because the load resistors was connected?

[@dovydasvaiksnys3807]

Just an advice for your tutoring from what i personally find confusing. Can you explain where you get point C in your nodal analysis? I understand A and B but does C come from? lets say you have different circuit with things all over the place. How you determine where are you going to put that point C ? Like whats the logical reasoning for it...

[@afif4738]

Nodal analysis deals with node voltages. So place your point C,D,E… on the essential nodes. Search essential nodes if you don’t know what they are. It’s where 3 or more branches meet.

[@desmondlim6160]

note: voltage short circuit, current open circuit. 2. cal rth/zth 3.use kcl find voltage

[@tasty_sugarr]

Thanks for the great explanation

[@kanankanan8120]

Doing A great job Brother. Love from Singapore

[@peterchisangamwamba9100]

thanks a lot.. I like the way you were proving final answers. It made me understand well the division of current and voltage in a circuit

[@amrhelmy5795]

in 1:53, how is the 11 ohms resistor in parrallel with the 3 ohms resistor and its an open circuit??

[@arisariss1897]

not that, the end of the 3ohm is touching with the start of the other 3ohm so they are in series not parallel! Unless i am wrong

[@eggxecution]

nice, or to get straight to norton current, shorten the load and that short loop would turn into In or norton current plus it would also open the parallel resistances. then do a nodal to get the voltage then use ohm's law with In.

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This bro is holding way to my Engineering degree

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[@akumarmalai]

Hi thanks the beautiful explanation. I remembered my university days... By the way, what app or software do u use to show all the working?? I am a high school maths and physics teacher and this would be handy for preparing videos too. Hope u can help.

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Try Microsoft Whiteboard

[@eie_for_you]

Nicely done.

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You are the BEST

[@DarkLord-pm1eg]

I've got a question.... At 2:40, we're supposed to add a short circuit to 6 ohms load, right? As far as I know, we need to add a short circuit on the load, when we use Norton's theorm, and open circuit when we use Thevinin's theorm. Correct me, if I am wrong, please.

[@pawanbhatt1767]

yes

[@zamba4882]

@@pawanbhatt1767 so we shouldn't calculate r3 i think

[@shivanshagarwal866]

Amazing content !

[@patrickbelloameh8808]

Greats and its very simplified

[@AJ-et3vf]

Awesome video! Thank you!

[@deema1737]

bro knows everything

[@pdp_29]

Why did we calculate vc?

[@WHO_Is_2020_IfUKNOW]

how will I know at this node I have to find Thevenin voltage?

[@prezlamen]

Why on 2:00 you calculated as a parallel and on 4:24 as in series? Sorry I dont understand,to me looks the same ,beacuse you removed "Rl" ; I see only one way for current to flow. Your videos is one of the most helpfull!You use better concept than school`s.

[@allyhanaffy2329]

2 years and still no reply:( do you have the answer already by any chance? I want to know

[@rahmaahmed2525]

حسبنا الله في هندسة شبرا و في قسم اتصالات وفيا و شكرا جزيلا لصاحب الفديو

[@youssefellouki8874]

Great methods

[@dillanio9191]

How to identify the Load Resistor? Is it always the one on the far right side of the circuit or is there any other specific method to identify it? Btw, superb explanation, you are really helping me for my exam!

[@sebastianionita8479]

Load Resistor is always the resistor that you define as the output of the circuit. Usually, it is on the far right of a circuit schematic.

[@bartimaeu1]

Usually denoted by RL

[@EnderSpy007]

Usually its on the far right, but if the circuit is decently complex your professor should be telling you what the load resistor is anyways.

[@nigelvanlaethem3860]

Great video! But why not go with (R1.R2) / (R1+R2) for the parallel of 2 resistors? Makes it faster and easier.

[@shahzebsaleem270]

For me plugging in (1 / (1/R2 +1/R3)) into my calculator is much faster, maybe that's why? just preference at the end of the day

[@anthonyokonkwo3493]

How did you get the 24 that you used to solve the Norton's resistance ?

[@Lambo-3-6]

24 is used to get rid of the fractions, 24 is in the table of 6 and 8.

[@raphaelling0663]

Y’all this is basic theorem. Try the one with dependent sources you surely like it

[@jianmingtan1090]

Good explanation tqvm

[@bellzon4086]

Can someone explain how in 2:05 they are parallel they seem to be in series?

[@HansSensei]

there's a node in between, they aren't directly connected

[@bellzon4086]

@@HansSensei but he says in 4:19 that they are in series?

[@leviackerman-ri5rt]

watching this the night before my test help

[@natashab8110]

how do you know which resistor is the RL? is it stated in the question already? genuinely asking :) great video btw

[@joelabraham1021]

Can anyone explain why when calculating R(L) the branch with only 3 ohms is parallel with the branch containing 8 and 3 ohms but when calculating V(C) they are in series ? Thanks

[@bartimaeu1]

If you're talking about at 4:30 then he doesn't take the 8 ohm and 3 ohm as series he is actually just looking at the currents at that point. So due to kirchoffs law you just add the currents

[@Subhrajit033]

Thank you sir 🙏

[@vibes_updates]

Hello, thanks for the explanation, Please I wish to know how we came about 24 while looking for the voltage vc

[@Shrutzy]

bsc 24 comes in both the tables of 6and 8 so its used to make the calculation easy thats all

[@akashgillella]

Very consice video. Thanks a lot- The Organic Chemistry Tutor

[@jerrygodson5094]

Why did you specifically use 24 to multiply everything to get rid of the fractions?

[@WoohSteezy]

Get rid of the denominators and solve the equation

[@ajgguerra0]

I legit had the same question too.. common denominator is 24.

[@hassannasreldin257]

What are the main points I have to focus on ?

[@whathehellooo]

when we calculate the value of R Norton can it be ( 3 ohm in series 3 ohm) and parallel with 8 ohm it'll lead to different answer. So is it wrong ?

[@Smackteo]

Why is the voltage at B 0?

[@alanx4121]

Why is R3 added parallel and not serially to Rn?

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[@panashepanaxe629]

Thank you so much

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God bless you sir

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[@successthruknowledge]

I understood every step of your calculations and circuit simplifications however I am not sure that I understanding the significance of Norton's current or Norton's resistance or Thevenin's current or Thevenin's resistance. Why are these points given special assignations? Also why is Rl the load resistor? What makes it a load resistor?

[@spookytofu2078]

Thank you

[@mercychoka2636]

Thanks indeed

[@GREGGRCO]

Oh yeah, and checking the answer too ! Super! Always did that ! Great ! Thanks. What software are you using?

[@R3mix97]

It's honestly probably Paint or Photoshop with a drawing tablet connected