I'm loving your lectures. Thank you for making them available. A point of clarification; in this lecture p' is defined as (sig1+sig3)/2, which, I believe, is the MIT definition and we in Australia tend to call s-t plots rather than p-q plots. In your CSSM lectures you have used the Cambridge definition of p', namely (sig1+sig2+sig3)/3 or (sig1+2*sig3)/3. It may be confusing to some that the slope of the fully drained stress path, for example, is 1:1 in this lecture and 1:3 in your CSSM lectures. Great information and very well, and clearly, presented. Your students are a privileged bunch!
@teddychan808 Жыл бұрын
was struggling with understanding the triaxial CU test report, and here comes this video!! Solve my confusion for years, thanks to lecturer for this marvelous course!!!
@B27-o2c5 ай бұрын
Very good video. I’m in a graduate geotech class and a lot of these concepts are bit rusty for me. You explain it all in a very concise and thorough way that is understandable.
@marshmelows4 жыл бұрын
Brilliant and insightful video. The images are on point! I need to think and let my thoughts consolidate for a while so I CONNECT(in my mind) the OC behaviour in clays/dense sands to the peak behaviour in their shear strength TO the existing stress path . Thank you Professor!
@lucascruz15184 жыл бұрын
I really like your lectures. Greetings from Brazil.
@johnhwang4365 Жыл бұрын
Thank you. This lecture is really helpful to me for understanding the p-q diagram.
@pikxoАй бұрын
Gracias, una clase magistral 😊
@hadiasadi31383 жыл бұрын
wonderful lectures of CSSM, thank you Dr. Franke
@jacksonzheng42884 жыл бұрын
Thank you Professor, looking forward more videos about advanced topics to be uploaded. Greeting from Australia!
@reshmarughooputh16095 ай бұрын
Absolutely amazing
@Y2n1233 жыл бұрын
Thank you so much Dr Frankie.
@aymanraouf18204 жыл бұрын
Excellent video! At 19:19 I didnt quite understand why the stress path goes 45 degrees to the right for overconsolidated soils and 45 degrees to the left for normally consolidated soils
@farahbasellinasafira86394 жыл бұрын
Thank you so much Dr.Franke!
@goharalam98702 жыл бұрын
Thank you so much Dr Kevin for your efforts in delivering such productive lectures. You have made this so easy for me to grab these concepts as I really had a hard time getting it.
@sangamacharya57154 жыл бұрын
very brilliant lecture, thank you so much!
@TheAncientColossus15 күн бұрын
41:30 What do you do AFTER getting the correct stress path according to the field condition?
@aadilnabiwani2878 Жыл бұрын
so easily delivered
@muhamadaminalsalamat96084 жыл бұрын
very winderful lecture , I highly appreciated
@khaledmohamedzahran34733 жыл бұрын
Hey Dr. Kevin, Thanks for this course. Its really useful. I can see in the playlist that we are missing from lecture 5 to lecture 10. Are they posted somewhere else?
@masyitahmdnujid47 Жыл бұрын
thanks for the good explanation
@alandiaz57193 ай бұрын
I have a question. If we have two UU test (or two CU with the same isotropic effective stress) in the lab, and I apply two differents path, for example, one increasing sigma 1 and sigma 3 is constant, and the another one decreasing sigma 3 and sigma 1 constant, the value of qf will be the same? I know that it will be in the Kf line, but i have the quetion because i don't know if it posible that two UU test (the same material and effective stress) can have two values of Su (kpa) due to the path. Thank You!
@saiedmohammadi2 жыл бұрын
Very good thank you
@dccopa134 жыл бұрын
Hi professor, i have one question. How does the Mohr-Coulomb failure envelope adjusts to the cases of a axial extension stress path? Are we unable to use the convencional phi and c resistance parameters that we get from the axial compression stress path? Thank you, i really appreciate the effort that you put in your lectures. Greetings from Perú.
@officehours40284 жыл бұрын
Insightful question! Theoretically, you could use the same Mohr-Coulomb strength parameters you get from ANY of the failure modes because Mohr-Coulomb assumes a linear failure surface. The truth is that the failure surface is non-linear, and measured strength parameters will be slightly different for different mechanisms of loading.
@羅拔迪尼路-n8j2 жыл бұрын
Hello Dr. Kevin, Isn't the modified failure envelope plotting apex of max. mohr circle against center of the max mohr circle called s'-t' plot instead of p'-q'? And the p'-q' plot should be plotting the deviator stress (dia. of the circle) and the average stress.
@rickycollins404 жыл бұрын
At the 19:06 time on the video you show A-bar = 0.5 as a vertical line. The notes above this state that a soil is contractive to the left and dilative to the right. The O.C. Clay curve is shown going above the K-f line between the A-bar=0.5 and the A-bar=0 lines. However, in the bottom right hand sector of the graph you indicate that if A-bar is
@nascasa3 жыл бұрын
A 0 contractive. Just that
@wemersonsilvadias43163 жыл бұрын
Hello my name is Wemerson, excellent work, very good analysis, helped me to understand a little more about Geotechnics, path of tensions, work in a Geotechnics laboratory in Brazil, specialization in geotenia, I like to be studying about it. Are you part of the LinkedIn network? Satisfaction. Congratulations.
@Martin-iw1ll2 жыл бұрын
Excellent slides on the whole, very informative and detailed. Good explanations throughout. But unfortunately I do not understand your slide on dilative and contractive soils. I think some of what you say are contradictory while other parts have inadequate explanations. I am quite unsure how the stress path of A bar = 0.5 is obtained and how is it straight upwards. I believe that is an effective stress path but I am not sure how change in pore pressure being half of change in deviatoric pressure, sigma vertical-sigma horizontal will net you a vertical line on the p-q graph, it just feels unrealistic
@shaelmonk-fromont34983 жыл бұрын
Excellent Lecture! Can you make Lectures 5 to 10 and 12 to 13 available?
@kiimiitiruutube25822 жыл бұрын
THANKYU
@aymanraouf18204 жыл бұрын
Also another question @33:02 I always wondered why the stress path for LC is much longer than for AC
@albioncia4 жыл бұрын
thank you very much sir
@JamesDean.4 жыл бұрын
Thank you!
@civilacademic3 жыл бұрын
wow! thanks you so much. ❤️❤️❤️
@lampsgarden Жыл бұрын
Hi Prof. Thank you for your video. I learn a lot from your explanation. May I know which book are you referring to in order to prepare your notes on stress path?
@tiggy77773 жыл бұрын
good guy you
@tanarisley56209 ай бұрын
Slay
@TheAncientColossus15 күн бұрын
41:30 What do you do AFTER getting the correct stress path according to the field condition?