Be Careful How You Approach This | Cambridge Final Year Math Problem | Where To Start From.

[@pierrickroger4431]

Why not use the natural logarithm right at the first step ? I got to the same conclusion within 4 steps

[@ogbonnaemmanuel5340]

I don't know why he stretched the solution

[@WorldwideBibleClass-qr9jk]

This explanation is so explicit. You are the best man. Love you dearly....❤❤❤

[@kateknowles8055]

This is so nice and clear. Thank you.

[@anderson11884]

😊wow!! Nice!!

[@Cardpoints]

Well done, my friend. Posters challenging the calculation at the end (splitting hairs) or providing briefer solutions are missing the point of the exercise: to show in practice the laws of logarithms. Carry on, sir (and to those posters pointed out: stop showing off!). j

[@robfrohwein2986]

Nice challenge again!! I'm happy i could solve this one 🙂

[@richshuttleworth8121]

Hmm? Cambridge final year.....I teach this (well the quick method of taking logs of both sides then collecting like terms) to year 12 students. It's a challenge to them, but not particularly difficult to master.

[@antonyqueen6512]

You got it wrong. It’s x=0.81884 not 0.8168 It too simple to use log straight away and x= [4Ln(3)-3Ln(4)]/[Ln(4)-Ln(3)]

[@dukassis4906]

2. log (8/9) na base 3/4, para ser mais exato

[@ChavoMysterio]

3^(n+4)-4^(n+3)=0 3^(n+4)=4^(n+3) 81(3ⁿ)=64(4ⁿ) (¾)ⁿ=64/81 (¾)ⁿ=(8/9)² n=2[log_¾(8/9)] ❤

[@musicsubicandcebu1774]

I think it would be more helpful to first list the steps. 1) Simplify by putting the x terms on one side and the constant on the other. 2) Take logs both sides using appropriate base (i.e. the number you're logging). No need to break down the logs, just check the answer with calculator.

[@benyasir423]

passez au logarithme decimal dés la première ligne

[@Bertin-q3y]

X=3 +(ln3)/(ln(3/4)

[@pspprabhat]

3/4)^×=4^3/3^4 =>×.log(3/4)=3log4 -4log3) =>×=(3log4-4log3)// (Log3-log4) 10:57

[@اسماعیلخسروی-خ6ظ]

Easy ❤😊

[@oseven524]

Another person complicating and easy question took me 4 lines

[@ppvshenoy]

Use logarithmic function to solve this in 3 steps after your step 2. Ex: 3 to the power x is x log 3. 😊

[@abdellahaitouahmane1593]

Methmthode longue et compliquer utilset log depuis le debut. Pourqoui ne pas Laisser le Mr parler

[@ManojkantSamal]

^=read as to the power *=read as square root As per question 3^(x+4) - 4^(x+3)=0 So, 3^(x+4)=4^(x+3) (3^x). (3^4)=(4^x). (4^3) (3^x)/(4^x) =(4^3)/(3^4) (3/4)^x ={4^3/3^3}×(1/3) (3/4)^x={(4/3)^3}×(1/3) {(3/4)^x}/{(3/4)^-3}=(1/3) (3/4)^(x+3)=1/3 Take the log log{(3/4)^(x+3)}=log(1/3) (X+3)×log(3/4)=log(1/3) X+3=log(3/4)/log(1/3) X=(-3)+{log(3/4)/log(1/3)} X=(-3)+{(log3-log4)/(log1-log3)} =(-3)+{(log3-log4)/(0-log3) =(-3)+{(log3-log4)/(-log3)} =(-3)+{(log3/-log3)+(log4/log3)} =(-3-1)+(log4/log3) =(-4)+(log4/log3) =(-4)+{log4 of base 3)....May be

[@ralphtrucksess7008]

The path was right but the result is false: you made a mistake in line 11: (X+3)×log(3/4)=log(1/3) is not equivalent to X+3=log(3/4)/log(1/3) but this does: (X+3)×log(3/4)=log(1/3) X+3=log(1/3)/log(3/4) and I prefer your way :) No bases of 3/4 and no conversions from base 3/4 to base 10

[@स्वामीविवेकानंद-थ1ह]

X= 0.7586....

[@HalilSer505]

👏

[@nadjibhaddoud9109]

Trop lent et trop confus !

[@sandortimar6686]

X=1 !??? Logarithm and so on @#£=)("" Brackets and no brackets What about whitout all the accepted mathematics rules.??? Maybe I'm so wrong. Teach me if 1 no good. Please

[@簡欽慧]

糊塗

[@gerardomr8231]

No, desde el inicio se pudo aplicar logaritmos y de una manera más fácil, directa y sin tantos pasos, se hubiera llegado al resultado !!

[@torstenbroeer1797]

This was the way I did it and I got the right answer x=0.8188… within two minutes. Not 0.8168 as this idiot. And I call him an idiot because he is making calculations for nearly a1/4 hour that don't bring him any closer to the result, not because he pressed the wrong key at one instance.

[@cristan9582]

This is math for last year? Lmfao.