Operational Amplifier: Inverting Op Amp and The Concept of Virtual Ground in Op Amp

[@ALLABOUTELECTRONICS]

Time stamps for the different topics covered in the video: 0:34 Why do we need the feedback in Op-Amp (Negative Feedback) 3:08 Inverting Op-Amp configuration 3:47 Concept of Virtual Ground in Op-Amp (What is virtual Short) 6:38 Derivation of Inverting Op-Amp Configuration

[@mr.amp0076]

Next video kab ayega?? Vi... Jaldi lana...

[@ALLABOUTELECTRONICS]

very soon.

[@irock2382]

Bohot mast Sir!!

[@symbionictitan4074]

Thank you sir I finally understood 👍

[@tomc642]

Like all your excellent videos. I have seen this explanation of virtual ground many times, but it is always lacking something. Here the opamp is drawn with a feedback loop, but the huge gain of the open loop opamp is used to explain that the inputs are at virtual ground. Then it turns out that the gain of the opamp with feedback is by several factors smaller than the open loop gain. This would then mean that the inputs are not at virtual ground? Am I missing something in this explanaton. I like to look at it as a differential amplifier with equal bias currents in each branch, so that both inputs have the same voltage.

[@MatheusSilva-dragon]

Wow, now THIS is teaching! You presented all of this so crystal clear! My teacher could learn a thing or two (or three) with you!

[@garnett657]

This vid helped me out a million but lol why you guys always speaking down on the Professors tho….the learning experience is always different went learning at your own pace and time.. Like watching youtube tutorials in the comfort of Your home Versus some huge lecture room with a lecture session that cant be paused or rewind.

[@asamoah-danquahstanislaw2002]

yea, my teacher really needs to see this video

[@vprashamshi6705]

My teacher learns from this and teaches 🤣. He himself told about that

[@primevigilante7259]

this man right here is saving lives with these videos.

[@goyaldeekshant]

Too good. I will refer it to all my classmates.

[@aanikethghosh2343]

DON'T!!! Keep it to yu and surprise them 😉

[@kushagraacharya4629]

Hehe....you had probably lost trust in most of your friends for keeping this channel as a secret to themselves😂....

[@NerdyCatCoffeeee]

Found my Indian guy from youtube. Thank you, dude. A lot of detail is always awesome to see

[@priyanshigupta1117]

Sir u explained the concept pretty well in brief period of time. In my college we had lecture of 45 min on this which u made me understood in 10 min

[@anjalisinghchauhan5360]

you had a lecture.*crying in corner*

[@strangerguy7248]

@@anjalisinghchauhan5360 You had a feminist attitude *crying in side*

[@anjalisinghchauhan5360]

@@strangerguy7248 dude try to understand... I'm saying we were never taught this topic in class at least they had a lecture... *crying in paris*

[@himanshushekhardas1730]

I can't find words to say how good your lectures are sir !!!

[@srivatsaa.r.9936]

sir yr video on INVERTING OP_AMP IS EXCELLENT AND CLEAR. Yr special aptitude in teaching Is praise worthy. In life many will try to teach but only very few will succeed and you are no.1 amongst them. thanks s.vatsa

[@akkahshhagarwaal2056]

Explained in a very lucid and interesting manner. Thank you very much sir! You have uplifted the desire of learning electronics in me.

[@Rahul_Raju]

the best tutorial on op amps ,presented in a lucid and down to earth manner.loved it. at my age of 61, i have learnt the basics in just one lesson.KEEP it up.

[@footballinshorts2711]

Pardon me if I sound rude ,but why did you wanna learn this at 61 years of age?

[@srivatsaa.r.9936]

yr video on OP_AMPLIFYER Is WELL thought and executed. the person delivering the lecture/teaching performance Is praise worthy. very clear. s.vatsa

[@sharvilb2420]

3yrs ago video, helping me and my bois 3days bfore the exam!🙏 Hope you were our online class lecturer!👀😶❤️

[@mayankmathur4667]

bro i am repeating the same feat as urs let's see how it goes

[@ramamurthy7937]

Tq very much sir please make more videos like this and help more students to have clear concept and get succeed in life tq so much

[@happytulip1451]

The way of your explanation is too good sir.....thank you so much....

[@ramlenka7063]

Life-saving channel, Thanks a lot

[@tqaquotes9379]

03:47 I was watching this video for the virtual ground concept, and I must say this part is especially good.

[@amruthas6974]

I see that the concepts are explained in the description too.. thank u so much sir.. i am a btech student graduating in 2020.. i am preparing for campus placements from your video. Plz do more videos .. hats off👌

[@circuitsanalytica4348]

Hello Amrutha, he had explained this topic in an excellent way....

[@upadyaruwanpura2]

Sir, You are a life-saver.😍 I don't know why my lecturers can't explain like this.😣

[@gena8414]

I really understood it pretty well. Though you shouldn't have used the word "feedback" before defining it. Thanks!

[@asamoah-danquahstanislaw2002]

thank you soo soo much you are really becoming one of my favorite youtube teachers.

[@siddhantv1]

I can't see how college professors with so many degrees can't explain the same concept as easily as you do

[@ayush7800]

It's because we don't listen to the professors during class, but are very attentive while watching on yt ( as most of us are here just before exams ).

[@AnjaneyaParashar]

@@ayush7800 ++

[@rupeshr936]

@@ayush7800 spot on reply👌

[@RiddhiGupta-bc3mv]

Sahi hai

[@leadnitrate2194]

​@@ayush7800as someone who listens to the prof, I can confirm this guy teaches better

[@直江狀]

Very good KZbin. You are much better than my professor. You make me understand the electronic, my professor just confuses me, maybe it is his job to confuse me

[@amulyasuryateja9701]

Very much much much better than my college lectures💯💯💯 Thank you so much❤

[@sais.here.5869]

god bless u brother for providing free lectures

[@saikatsRhythmicRiffs]

My concept is now totally clear. Thank you sir. Please release more video .

[@ronjoybhowmik9535]

SAIKAT DAS hope you dont get a backlog

[@rahulranjan7899]

@@ronjoybhowmik9535 haha

[@hasanxnv]

you have an amazing gift of explanation. I love that

[@Vaijuuuuu]

Thank you so much sir... it's really amazing...I will refer it to my classmates too..we are really lucky to have you

[@mabdulla3105]

Thank you Sir, I just started in Electronic lab assistant job. It is very informative

[@akshayaraja1180]

Answered all my doubts without asking .tqsm …tat too one day before exam😃

[@anupamchatterjee1820]

kya bat sir....dhansu padhate ho app....maza a gaya

[@vanhoangtran8783]

Thank you very much, it helps me many things. I learned this at school ( and I forgot this) but thanks to your videos, I can understand this better.

[@Pr3kashSingh]

No video can be better than yours.. 😘

[@priyankag4065]

No boring,easy understanding 👍👍👍

[@haritharamachandran2961]

This was really helpful. I understood the concept clearly.

[@bahaatamer1245]

SIMPLY AMAZING! - Please keep up the amazing work!

[@md.mamunurrashid466]

Innovative video. It is very much helpful to understand the op-amp.

[@kingjibaieaieaie2279]

I love you so much for explain this like a profesional !

[@ashjaahmedkhan3254]

Bhai badiya batata he yr tu meko bhi tere jesa banna he ek no.👌✋

[@gkspeednetinternet9160]

my all doubts are gone away......excellent sir...thanku so much...

[@melvinsaji2805]

SUCH A CLEAR EXPLANATION THANK YOU VERY MUCH SIR GOD BLESS 🙏 YOU

[@akshatchoudhary895]

Tomorrow is my ec end semester exam and i learn so much from this video

[@pratiksingh5022]

Amazingly explained sir...... thankyou 🙏🏻...keep making such videos for us

[@gondukarteek1714]

Superb way of teaching.. I just loved it ❤❤

[@itsak4235]

Awesome.... crystal clear explanation

[@Roger49-x71]

Thanks for this very well presented & explained analysis.

[@sumathiuppari7178]

Simply amazing explanation....the total concept is in simply easy way .thank you so much.....but bhaiah "I request you to explain a little bit slow"...

[@saswatapatra5919]

BEAUTIFUL!!! AAH maza aa gaya bhaisaab.. now how often do you see people making such types of comments on study related videos?

[@rajshukla5663]

You teach better than my profs here at iit

[@rohithss7738]

U were teaching excellently sir😍

[@debabratarouth1235]

Amazingly explained sir, so helpful. Thank u so much.

[@acandmishra]

Excellent explanation , really very helpful

[@psrisaiteja5047]

Thanks for giving clarity on inverting amplifier

[@yashwantkumar1951]

Very well explained... And presentation is also really good. Keep the good work continue 🤘

[@kychemclass5850]

My Op-amp fog is lifting. Thank you so much!!!!!

[@mayankgautam6527]

Very well Explained. Topic become simple and interesting .

[@yadugirin2564]

this is so dman good it fells like some iit teacher has taught this

[@shreeyashrasal8574]

Awsm explanation sir👌👌 Crystal clear concept

[@adrishbhattacharya508]

Great lecture. Understood the concepts well

[@bharammr5130]

Awesome explanation sir thaks a lot.

[@hasnainali7897]

Excellent vedio with concepts please write the theory in background what you are speaking 🗣️ it will help alot to make notes

[@monicaarputharaj59]

Suprb explanation sir...thank you👏👏

[@arjuno195]

Make more videos learning never stops🙏

[@phucnguyenhuu804]

thank you very much..the video helped me understand the theory better

[@amitsubhash1586]

Thank you for the consice and clear answers, it helped me so i hope this comment helps you in the algorithm game)

[@rohitht8720]

Thank u sir Ur teaching is superb

[@eshaghazali2482]

Amazing video tho! Helped me a lot. Thankyou so much for this. 💪

[@ashishrout5265]

awesome video , good explanation and very helpfull.thank you

[@tpsicmin]

Thanks Sir Amazing Explanation

[@damithaliyanage8226]

Thank god u saved me! Great content!

[@nishantpancholi8768]

Very good job sir..!

[@shkumse7943]

Very good for techno managers who hv no time to open books and read pg to pg.

[@samarpreetsingh5318]

Excellent video!👌

[@sgcreations5638]

Really helpful and explained very well without any confusion

[@Brutishh]

I ‘ve seen ur 2 basic videos of Operational amplifier ..They r really good and I request you to explain by taking some problems asked in competitive exams...Plz

[@ALLABOUTELECTRONICS]

Yes, if you have seen my last videos on op-amp (Integrator and Differentiator), I have taken some examples. And anyway I am going to make a dedicated video on problems based on the op-amp. But before I make that video, I will cover few topics like the gain-bandwidth product, slew rate, CMRR and offset voltages in Op-amp. So, that I can cover a variety of questions based on the op-amp.

[@Abhisheksharma-lk4ll]

Bhaiya mazza aa Gaya aap sae padh kae

[@kshitizrana9544]

During derivation of virtual short why we are taking open loop gain (at 4:05)since negative feedback is already connected ,is this not a closed loop gain ??

[@ALLABOUTELECTRONICS]

Just to explain the effect of the closed-loop circuit. The op-amp itself has the open-loop gain. But with external resistors, the overall gain of the entire circuit (Inverting amplifier) is reduced. I hope it will clear your doubt. If you still have any doubt, then let me know here.

[@Hiyori___]

Thank you so much. so well structured explanation

[@abuanas8569]

Very fine explanation.Thank you so much

[@kushagrapunia]

Amazingly explained

[@dinushachathuranga7657]

amazing explanation. Thanks a lot.❤

[@yaminabatool3793]

Really helpful description.. Thanks 👍

[@machirajusaicharan4995]

I didn't understand that at 3:11 Why the polarities of op amp are changed i.e. inverting terminal came up and non inverting terminal went down. Please clarify

[@ALLABOUTELECTRONICS]

It's just for representation. While drawing the opamp symbol, you can represent either inverting or non inverting at the top and the other one at the bottom. It will not change the functionality of the circuit.

[@machirajusaicharan4995]

@@ALLABOUTELECTRONICS I also have a doubt sir, somewhere I have seen the symbol of op Amp in another way, inverting terminal and positive supply at top, non inverting terminal and negative supply at bottom Which is right I am totally confused at this terminals and power supplies positions Please solve my doubt

[@tomc642]

Like all your videos. I have seen this explanation of virtual ground many times, but it is always lacking something. Here the opamp is drawn with a feedback loop, but the huge gain of the open loop opamp is used to explain that the inputs are at virtual ground. Then it turns out that the gain of the opamp with feedback is by several factors smaller than the open loop gain. This would then mean that the inputs are not at virtual ground? Probably a good explanation that would include a differential amplifier with matching, and equal branch currents is too advanced.

[@SreenikethanI]

same doubt!!

[@muneerghure2933]

That's a nice video ☺

[@abunaser4522]

I think being 180 degree out of phase and being negative is really different thing. The effect of 180 degree phase shift is the same as negative signal only for sinusidal and some symmetric signals. not all of them.

[@ALLABOUTELECTRONICS]

Yes, that's true.

[@nikshepbangera5416]

amazing stuff bu ti have a doubt.. at 4:28 .. u use the the open loop gain equation Vout = Av*Vd to prove that virtual ground is in feedback ..so it is confusing because that equation is for open loop without feedback

[@bhavishnagubandi328]

I have a question, For proving the virtual ground concept we consider gain very high e.g 10^6. But by choosing different values of Ri and Rf we got gain as 2. Will this not contradict our virtual ground concept?? Please explain!!!!!!!!!!!!!!!!!!!!

[@SreenikethanI]

same doubt!!

[@Poorvikss]

Hi But to attain desired oscillation the op amp is tunes with R1 and Rf so that it's gain is silgithy more than 1 Please tell if it's correct or not?

[@rajanbhandari5484]

More than good ❤️

[@blatogh1277]

Gosh that really helps a lot for my class!

[@GR3G1987]

8:55 The gain isn't 2, but -2 and the output is -2v, not 2v. Am I wrong ?

[@circuitsanalytica4348]

No, you are right, as the amplifier is inverting amplifier, gain is negative....

[@AhamedKabeer-wn1jb]

Superb explanation

[@som9428]

u r Awesome bro 😃😊😊

[@radhey04ec]

Nice..... explanation

[@vishnu7245]

good explanation💜

[@ksp4619]

Very well explained....

[@nikshepbangera5416]

beautiful teaching

[@shiprabhanu9562]

How can we assume the input terminals as short circuited when op_amp is having high input impedance???🤔

[@shiprabhanu9562]

That should be open circuited because of high input impedance

[@ALLABOUTELECTRONICS]

It's virtual short. It's not actual short. Because of the very high gain of the op-amp, the difference between the two input signal is very low. Even if op-amp has very high input impedance, it is possible to have both terminals are at almost same potential, because of very high gain of op-amp. Of, course ideally current will not flow between the two terminals. So, we can assume that there is virtual short between the two terminal. It's not actual short between the terminal. I hope it will clear your doubt.

[@PropheticNomad]

It's only when you have negative feedback that the virtual ground presents itself. The circuitry inside will try to drive the node to equal the other. Often, it is very good at doing this. So good that you can say there is not a potential difference between inputs. They are "virtually" the same

[@mohdaqibminai5975]

@@ALLABOUTELECTRONICS sir they are virtualy open can you plz explain as their is no potential difference between terminals so no current therefore open circuit and you said short i not get it can you plz explain

[@ritikbhagat8456]

@@mohdaqibminai5975 here they are virtually shorted which means that they have same potential without being actually connected, as the derivation done for Vd in the video, it is obtained that Vd is so small that it can be assumed to be zero so when the difference in voltages between two points is zero then it means they are at the same potential.

[@manupriya280]

Great video sir

[@babaisaha4160]

Thank you so much.🙏🙏🏻

[@naveenpunnam7942]

Sir Is feedback current will flow same direction or reverse direction?

[@ALLABOUTELECTRONICS]

It depends on the output voltage. If the output voltage is positive, then it will flow in the opposite direction. From Vout to ground ( From higher potential to lower potential). If Vout is negative, then feedback current will flow from node X to Vout (From 0 to Vout) I hope it will clear your doubt.

[@naveenpunnam7942]

@@ALLABOUTELECTRONICS It is clear thank you sir