Operational Amplifier: Non-Inverting Op-Amp and Op-Amp as Buffer (Op-Amp as Voltage Follower)

[@tirthadas5767]

3hr 30 min away from exam and u cleared everything.. thanks

[@abhishekranjan4170]

Story of every engineer...

[@balajidasar396]

@@abhishekranjan4170 soo true.. 😂

[@vigneshsambari1733]

The mere truth of any btech guy!!!

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[@abhishekranjan4170]

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[@Physicsbyshalu]

I'm preparing for NET exam online because my classes are dismissed due to corona virus impacts....but your classes help me a lot.. thanku so much...

[@goyaldeekshant]

All the best.

[@ALLABOUTELECTRONICS]

The timestamps for the different topics covered in the video is given below: 0:52 Non-Inverting O-Amp Configuration 1:51 Derivation of Closed Loop Voltage gain for Non-Inverting Op-Amp Configuration 5:00 Advantage of Non-Inverting Op-Amp configuration over Inverting Op-Amp configuration 6:09 Input Impedance of Inverting Op-Amp 7:25 Input Impedance of Non-Inverting Op-Amp 9:28 Op-Amp as Buffer (or Op-Amp as Voltage Follower)

[@anujkondhalkar9776]

ALL ABOUT ELECTRONICS 🤘 You Just Rocked.

[@rajkishornishad1055]

Good

[@vinaykumarm9211]

what an explanation!!U have done a great job.Timestamps concept in the description is very useful.

[@badcaptain1089]

why you considered negative feedback for both inverting and non inverting configuration and not the positive feedback ?Is virtual ground concept applicable for positive feedback? if no why?

[@Mubarak47]

@@badcaptain1089 Positive feedback makes the circuit unstable that's why it is avoided.

[@gianmarcogriffo3460]

Exam lifesaver, providing a complete description of each operation case and a straightforward understanding method. Thank you so much again!

[@ashishverma8740]

Far better and interesting than NPTEL.. keep doing such work.. :D

[@pranayverma9984]

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[@jamielannister509]

Can we have a tutorial based on complicated circuits which include a few of the operational amplifier circuits combined with each other? 12hrs away from a crucial basic electronics exam and you're a lifesaver. Thanks!

[@divyagupta2358]

If these teacher teach in school or colleges then there is bright future of india. 👍🏻

[@teerthraj_verma]

Tomorrow I have semester exam And my last resort is watching you I am watching this for first time and An best part is that i understood most of it

[@noelsmaison685]

Easiest explanation ever. I've always hated electronics but now I understand something! I'm in TYBsc graduating through physics. Thank you for helping us. :D

[@AdityaKushwaha-r5l]

Best playlist for opamp! Loved the video.

[@technicalpsc6441]

best classes i ever watched...

[@pierre-olivier7523]

Wow, honestly this is amazing! I truly hope you are proud of the content you put out its just beyond anything given in class at my university. Short, clear and concise! Keep up the good work mate!

[@shresthshukla3061]

00:18 Non-inverting op-amp configuration and using op-amp as a voltage follower. 01:39 Op-Amp in Negative Feedback Configuration 03:10 The non-inverting op-amp configuration allows control over the gain by adjusting the values of RF and R1. 04:43 Non-inverting op-amp configuration provides amplified AC signal with same phase as input. 05:59 The input impedance of the inverting op-amp configuration is equal to R1. 07:24 In the non-inverting op-amp configuration, the input impedance is infinite. 08:55 The non-inverting op-amp configuration has a high input impedance, allowing the entire applied voltage to appear across the circuit. 10:27 The non-inverting op-amp circuit can be used as a voltage follower or buffer circuit.

[@tharindumaduwantha1023]

very useful video series for my studies . .thankyou very much for making videos about electronics

[@jinusiret]

Super Video, Now i understand a little, if my faculty following this method then i will pass easily.

[@pujithakaricheti8170]

Gud job listening hours and hours is not a matter getting sub with in 15 min really it's very helpful thank you so much

[@nhatson3619]

thanks a lot for your dedication to free but high-quality education for everyone!

[@Tejas.Lipare]

Nice... It is helping me right now while studying Electronics 12th std. Good job.... I will complete all OpAmp videos...👌👌👌

[@rajeshsubramanyam6669]

Very Simple & Clear explanation I ever seen

[@thesilentvampire]

It Helps me with my studies, thanks Yeah just that.

[@aiyshafayaz6682]

Concepts get clear in a very little tym . Thanks

[@jinusiret]

Expecting more on electronics from this channel

[@amanisdreaming3914]

tomorrow I have a presentation on Op-amp, yet today Iknow nothing. Thankyou for this.

[@andya8623]

Thank you sir..... Thank you so much Clear all OPM because of you

[@divyanshverma4148]

Machadiyaa sir jii... So great video lectures

[@happytulip1451]

No word's sir... I Subscribed your channel....

[@miraada7979]

you are one of the best instructors regarding electronics. I am watching your videos but l wish you care a little bit about your sound. you make tired but still, l couldn't find better one and l am listening to you, but your voice is super tiring. Please do something you are a smart person and you can make quadruple your likes only by smoother your voice or anything. The only problem is that.

[@shubhamdesai7749]

Voice me Kya rakha he?

[@invinciblegirl4386]

Thanks a lottt sir..! We have exam tomorrow and I was so scared because I didn't understand op amp.! But after watching your videos, now I understood everything. Thanks a lot sir.!😍😍 SIR IF POSSIBLE PLEASE UPLOAD A VIDEO ON THE APPLICATIONS OF JEFET AND MOSFET AND ALSO PHOTO ELECTRIC DEVICES..PLESE SIR..WE HAVE EXAM TOMORROW

[@saumadeepsen8029]

Vaiya many many many thnxx😘😘 keep going..... We need full semester 1 topics....

[@rssings8540]

Listening to this in the exam hall thanks

[@dharunkumar8461]

U have something beautiful in terms of explanation.Develop them

[@inhdungho9509]

thank you very much Sir ! as everyone did comment, I dont know what I should say more, just Thank you

[@cadcamdesigntutorials]

What a great explaination it is! Thank you so much 🙏🙏

[@sangachidam3219]

All your videos are excellent. Good job guys keep it up.

[@sriiisriii795]

super...................... no words................... only all about electronics.................

[@RaviShankar-xc9fu]

Sir greatly explained ... Sir please complete....

[@eonang9751]

It a great videos! Im new with electronic circuit, not really know about the impedance you had mentioned. How is an infinite/high impedance op-amp will benefit a low impedance circuit?

[@rashmibajaj1396]

Exceptional explanation, thank you so much

[@n4v33nkum4r7]

At 2:00, how was the voltage divider rule applied to get that formula? I can't seem to derive that... Also, how did we alter the connection of R1 like that?

[@AnkitSharma-jf9fg]

you should hold some live question sessions although good videos man I appreciate your work

[@sidcreator2132]

You did it very easily 😍. Nice Explainations. Maja aa gaya. It would be better if you provide notes..✨✨✨✨✨✨

[@ALLABOUTELECTRONICS]

For notes, please check the website. www.allaboutelectronics.org

[@sais.here.5869]

bhai engg colleges should recommend your lectures

[@apekshaphadte4443]

6:12 isn't input impedance present inside the triangle symbol of the op amp instead of being at Vin?

[@ALLABOUTELECTRONICS]

Here we are finding the input impedance of inverting and non inverting configuration. ( instead of input impedance of the op-amp alone). In this configuration we are also connecting external resistors to the opamp. In general for any circuit, the input impedance of the circuit is the impedance seen by the input voltage source. That’s why here we are looking at the impedance seen by Vin. If you want to know more about input and output impedance, you can refer the following video: kzbin.info/www/bejne/bZvaY5Kubcmsh5o

[@apekshaphadte4443]

@@ALLABOUTELECTRONICS thank you so much! Ur reply means a lot! Gbu

[@berenedain8427]

Woah what the hell?! That just clicked in my head now, thank you

[@deepak1952]

I am amazed that i understand this in a minute

[@KotanaPhaniSriRahulAP]

Thanks borther! your videos have been helping me a lot

[@uiticus]

In video timeline 5:53 you stated that the input impedance of the negative terminal of the op amp is equal to R1. But isn't it more correct to state that the input impedance seen into the negative terminal should be R1//Rf?

[@ALLABOUTELECTRONICS]

The more appropriate would be, for the inverting configuration, the input impedance seen through the input (applied at the inverting terminal) is R1.

[@tpsicmin]

Amazing Explanation Thank You Sir

[@sammetakarthik1476]

tq sir your lectures are very much useful

[@debasishbhowmik1005]

Can I know What are possible variety of questions regarding the whole opam chapter it will be helpful for me Anyway ur videos helped me a lot luv ur videos❤️❤️💯

[@ALLABOUTELECTRONICS]

I have made couple of videos on solved examples on op- amp ( please go through the op-amp playlist). Moreover, for more questions please check the second channel ALL ABOUT ELECTRONICS - Quiz.

[@Abhisheksharma-lk4ll]

Sir you said in your previous video(on inverting opamp) that virtual ground cocept can only be used in inverting configuration but here we have non-inverted configuration than how you applied virtual ground concept at 2:25

[@ALLABOUTELECTRONICS]

What I mean to say was, it can only be applied with the negative feedback. ( When the op-amp is operating in the linear region).

[@Abhisheksharma-lk4ll]

@@ALLABOUTELECTRONICS ok Sir thank you very much :) i got it now

[@damlacanatc2949]

simple and perfect explanation

[@ojaspatil2084]

At 4:25 you are giving the sinusoidal input of 1V to opam and getting the output of 3V sinusoidal signal. So, her 1 and 3 V are Vmax or Vrms??

[@chenthanar895]

Super sir if u teach me i will be the topper of my university.

[@ogbuddha7835]

At 1:23 : Inverting input (-) is grounded and non inverting input have input voltage = Vin Doubt : since its a negative feedback opamp and one terminal is grounded then why other terminal i.e Vin isn't 0 ? Both the terminals have equal voltage isn't it?

[@aparnatrivedi1497]

There is due to virtual ground both the input has same input voltage and we know that opam has a out put voltage is equal to =A×(v2-v1) whare v1=v2 and the out should be zero

[@christophersekaran3848]

Excellent video! Was really helpful!

[@manogyurka969]

I really like your videos! The videos are so helpful, thanks! Now I have a question about the "buffer configuration". I try to imagine the situation with an example: 1st, before switching on Vin, Vin = 0V Vout = 0V 2nd, then I switch on Vin: Vin = 5V => Vout = Vin-Vout = 5V - 0V = 5V 3rd, but then this Vout will be substracted from Vin, so: 5V (= Vin) - 5V (Vout) = 0V Then Vout = 0V. 4, And it runs in a circle like this: Vout is = 0V => Vin - Vout = 5V-0V = 5V Vout: 0V >> 5V >> 0V >> 5V... This example has something wrong in it, because the output is not switching between ZERO and 5Volt in real life. What point do I miss from the example? Thank you for your help! Mark

[@taravanova]

I suspect the answer to this question is that the voltage source and op-amp don't respond instantaneously. op-amps have a frequency response, which means the op-amp does not respond well to changes that occur faster than some time constant.

[@mbukee]

I want to ask something. At 11:11, there is a figure which shows the connections between circuit 1, opamp and circuit 2. In this configuration, we use opamp to transfer the signal from circuit 1 to the circuit 2 with gain=1. Why don't we connect the output of the circuit 1 to the input of the circuit 2? Why do we need to buffer the signal? What is the logic behind the opamp? Thanks

[@ALLABOUTELECTRONICS]

When there is impedance mismatch and when the second circuit has low input impedance then to avoid loading, it's advisable to use buffer. That's why the output of circuit is not directly connected to second Circuit. I hope, it will clear your doubt.

[@PavanKumar-lo1nr]

RESPECTED ALL ABOUT ELECTRONICS GROUP: AT 1:25 In the blue diagram, when the voltage is supplied to the non-inverting point and to the ground, how can one say that the Vin as a whole is applied to the non-inverting point?? Please do reply as soon as possible ....

[@ALLABOUTELECTRONICS]

Because if you measure the voltage between the non-inverting input terminal and ground it will be equal to Vin. So, entire voltage is applied at the non-inverting input terminal.

[@Hari-kk7my]

thank you sir ,you are a saviour

[@curious_enough1288]

In your previous video, you added voltage source at the inverting end with a resistance R1. Now, in this video, while modifying the circuit you shifted the voltage source to the non-inverting side but R1 was kept at the same place. Why is it so?

[@ALLABOUTELECTRONICS]

Its because, using the feedback resistor and R1, the feedback voltage is provided back to the input. At 2:10, as I have mentioned, the feedback voltage is R1*Vo/ (R1 + Rf). So, in short, due to the feedback configuration, there is a Resistor R1 at the inverting terminal. The voltage across R1 is the feedback voltage at the inverting terminal.

[@harpalSingh-ql9no]

Virtual ground ka concept lgana kha he inverting m ki non inverting m....?? Input impedance of non invertong opam m ideal opam kyu lgaya.... Input impedance of inverting opam m bhi ideal opam consider ker skte the...??

[@ALLABOUTELECTRONICS]

The input impedance which we are measuring over here is the input impedance of the configuration (and not op-amp). The input impedance of inverting or non-inverting configuration or in general for any circuit, is the ration of input voltage to input current. (Vin / Iin). In case of non-inverting op-amp configuration, assuming ideal op-amp, no current is flowing into op-amp terminal. So, Input current Iin which is sourced from the source Vin is 0. And therefore, input impedance is 0. But that is not the case in Inverting configuration. The current if flowing through R1 and Rf. That is why both configurations have different input impedance. I hope, it will clear your doubt.

[@priyankag4065]

Thank you 😊👍, really awesome ❤

[@ARUNKUMAR-bu6jd]

Very interesting... Sir!!!

[@kontiimanalatit8987]

Hello sir. Thank you very much for these videos, they are extremely helpful. I wanted to ask you, if you have any videos on feedback analysis (shunt-shunt/series-shunt/shunt-series/series-series), on how to find the feedback factor, input feedback resistance etc. Once more, thank you very much.

[@ALLABOUTELECTRONICS]

It is yet to be covered on the channel. Soon, it will be covered.

[@karandev9316]

At 5:44 you mention that non inverting op has high impedance while deriving Acl for inverting opAmp you told us that it has high impedance. Which is why Ir = If...can someone please explain that part?

[@ALLABOUTELECTRONICS]

For, non-inverting op-amp, I was referring to the input impedance of the entire non-inverting circuit. (op-amp with external resistors). Of course, the input impedance of the op-amp is very high. But when we connect external resistors, then it changes the characteristics of the circuit. In case of the inverting op-amp the input impedance is equal to R1. (it is input impedance of the entire inverting circuit ). While I was referring to the Ir = If, I was referring to the input impedance of the op-amp. (That's why it can be assumed that, no current is entering into the op-amp terminal) I hope, it will clear your doubt.

[@samarpreetsingh5318]

Excellent video!👌

[@rameshmadhuranga7429]

best teacher

[@GSPmediaO28]

Asum explanation sir👍 tqsm

[@Conceptuallearning16]

11:18 Sir then why Don't we connect both the circuit with just a simple wire.....then?? Why i have to use buffer instead of just a simple wire?? Thank you sir

[@uiticus]

That is because you want to isolate the input circuit from the output circuit.

[@thisisKaushik]

Sir there is a problem due to subtitles. Sometimes it hides the equations

[@rimjhimghawry1344]

Thank you for your help ✨💜

[@SACHINKUMAR-qo5cg]

sir !! u re best...Thanks

[@nandindwandwe1821]

This helps thanks. You explain this well but you talk too fast sometimes.

[@sejalvinodwasule8868]

Then decrease speed

[@AJ-et3vf]

Great video sir! Thank you!

[@dalenassar9152]

THANK YOU FOR ALL OF YOUR GREAT VIDEOS ON OP AMPS!!! I have a simple requirement that I can't seem to find the answer for: I need an op amp in which I control the GAIN and OFFSET independently!!!!! If I set up a simple inverting amp where I can control the gain with Rf.....then will a variable +/-DC voltage at the "+" input simply move the waveform 'up and down' WITHOUT changing the signal gain??? IOW I need to shift the signal (a 50% duty cycle square wave) without effecting it's shape. THANKS MUCH AGAIN!!!!!

[@abdullatifomar111]

Thanks you very much for your lecture

Sir, thank you so much. 😊

[@omwmakingprogress]

In the non-inverting op-amp, the input impedance is infinite, so if the voltage applied to circuit, it will appear across this circuit. Could anyone pls explain it

[@binarysaiyan9389]

Your I and Z looks similar. I was having a tough time figuring out which was what

[@sionmarak1916]

You sir are a god for me.

[@SlugterraHD]

Watching this 1 hour before exam

[@9780495642]

Slow bolo thoda bro so that ik baar me smjh aa jaaye but good work 👍

[@lukaskunc2869]

Something is missing in your explanation, I think, regarding the input impedance. If you realize, that the 2 grounds in both the inverting and non-inverting op-amps are on the same potential (i.e. connected by a wire), then non-inverting op-amp circuit is exactly the same as the inverting op-amp circuit. I understand, that this is a simplified explanation for students, but I have a feeling, that somebody is cheating on me here. But thanks for your videos anyways, I have learnt a lot from them.

[@ravisanju1629]

In previous vedio the input impedance of inverting op amp is infinite and in this vedio you said input impedance is equal to R1.

[@ALLABOUTELECTRONICS]

I think you misunderstood that. The input impedance of the ideal op-amp is infinite. In the previous video, when I was saying Rin is infinite, it is from node X. (The input impedance of the op-amp is infinite, but not of inverting amplifier configuration). For the inverting amplifier, if you look from the source side (from where the input is applied), the input impedance is R1. I hope, it will clear your doubt.

[@sejalvinodwasule8868]

Sir please upload videos about transducers, Integrated circuits, U will cover 12th syllabus

[@islamicfact3010]

Video is very good and clearing many doubt but I didn't understood one point, how Vx=(R1/R1+Rf)Vo ?

[@AnkitSharma-jf9fg]

how to isolation work if voltage input of one circuit changes then voltage of input of second circuit will also change

[@tusharbehl199]

Sir you have used input impedance = infinity for derivation of inverting input op-amp configuration . But in this video Input impedance is depending on R1 how??

[@ALLABOUTELECTRONICS]

Would you please tell me where exactly in the video you are referring to ( timestamp). So, it will be easy for me to answer.

[@prabhakardas4261]

Please upload the remaining lecture of opam soon if possible, Atleast one video per day

[@rohan8758]

You are doing good but keep voice speed is less than the present speed..

[@hrishie3757]

Then it will be easier to watch them at a faster speed

[@sahilsingh9661]

How does the 180 phase shift in the output voltage of inverting is a disadvantage?

[@amitghosh3938]

Sir in the buffer circuit output of circuit 1 will appear in the vout Sir but what if the input resistance of circuit 2 is low, it would still get fractions of vout. So what is the point of using buffer?

[@ALLABOUTELECTRONICS]

Let's say the input resistance of source signal is 200 ohm. And the input impedance of the second circuit is 50 ohm. Input signal is 1V. In such case, the actual input appearing at the second circuit is 50x 1V /250= 0.2V. But the op-amp has low output impedance. Typically few ohms for some op-amps. Ideal op-amp as zero output impedance. But lets say our op-amp has 10 ohm output impedance. In such case, the input appearing at the second stage is 50*1V / 60 = 5/6V. So, buffer does make a difference. For very low input impedance it won't make difference. But input impedance of most of the practical circuit is more than 10s of ohm. So, buffer does make a difference. I hope it will clear your doubt.

[@amitghosh3938]

@@ALLABOUTELECTRONICS thankyou sir very much it has cleared my all doubts 🤩

[@binarysaiyan9389]

If iI get it correctly, the potential difference between the 2 terminals of the circuit is Vs/2. But you're saying that the entire potential (Vs) appears between the terminal. Why?

[@ALLABOUTELECTRONICS]

Would you please mention, where you are referring to in the video?

[@UaBsoNofficial]

If I connect that Rf with non inverting terminal than how can you say that input resistance of non inverting terminal will be infinite, after that connection current will have e a path nah?

[@ALLABOUTELECTRONICS]

Yes, but here I am referring specifically to the non-inverting configuration of the op amp, where there is a feedback between inverting terminal and output.

[@UaBsoNofficial]

@@ALLABOUTELECTRONICS Sir is it a standard connection, If a question comes about input impedance of inverting and non inverting amplifier , what should i write... THank you Sir for your reply

[@UaBsoNofficial]

@@ALLABOUTELECTRONICS Sir is there any particular rule that we can connect feedback resistance onlyy with the inverting terminal

[@futurefarming3394]

जब घर पर बना बनाया खाना टाइम पर मिलता है तो उसकी कद्र नहीं होती है | वही खाना जब रेस्टॉरेंट पर मिलता है तो बड़ा अच्छा लगता है क्योंकि रेस्टॉरेंट हम केवल भूख लगने पर ही जाते हैं | ठीक वही हाल यूट्यूब वीडियो का है | जब आप ये वीडियो देख रहे हैं | इसका मतलब ही है की आप पढ़ना चाहते हैं | इतने ही ध्यान से क्लास अटेंड करेंगे तो क्लास टीचर का पढ़ाया हुआ भी अच्छा लगेगा | और एक और चीज टीचर को रोज पढ़ाना पड़ता है | HOD कोई भी सब्जेक्ट पढ़ाने को दे देता है कभी भी | टीचर के पास पढ़ाने के अलावा बहुत सरे काम होते हैं | अगर विश्वास नहीं होता है तो पता कर लेना | NBA Accredation, NAAC Accredation से लेकर बहुत कुछ |

[@SadnanSanim00071]

i didn't understand why we are taking the R1 fraction instead of Rf

[@mnada72]

Are you going to discuss the internal structure of the op-amp

[@ALLABOUTELECTRONICS]

Yes, someday I will make a video on it.