Operational Amplifiers Circuits (Inverting, Non-Inverting, Differentiator and Integrator Op-Amp) 2/2

[@pukaseek]

Great video. Kept talking to a minimum with great efficiency of explanation. I worked years in electronics and this is by far the best explanation video. Thank you sir.

[@lemusgeorge69]

Best explication I have found

[@muwanguzidavid7697]

Brief and contentful 💪👏👏👏🥳

[@kabandajamir9844]

The world's best teacher thanks sir

[@eeapplications]

I'm so glad you think so. Thank you very much ☺️🙏🏻

[@willieriggi]

Really cool and we'll explained. Thanks.

[@rmssantos1314]

Great

[@yousaftoki1599]

Amazing video sir ji

[@eeapplications]

Thank you so much 😊

[@hasantamer9199]

good

[@arashyusefi1889]

Thanks you so much ❤️😊👍🙏💖💘☺️🥰

[@d614gakadoug9]

A differential amplifier and a differentiator are VERY different things! A differential amplifier amplifies the instantaneous magnitude difference between to signals. A differentiator produces an output that proportional to the rate of change of the input signal - the differential of the input signal with respect to time, written as dV/dt (though properly each d is a Greek small delta character), if the input is a voltage.

[@stephenkamanu8258]

Keep it up i like your video

[@eeapplications]

Thank you so much 🙏

[@allanbardon146]

What is name or link of previous video

[@digitalelectronicsacademy5485]

Thanks alot

[@deekondasaikumarsaikumar8564]

Thanks for videos make a more videos plZ and how to work wireless remote control RF circuit plz make a video ..,

[@eeapplications]

Hello. Thank you very much ☺️🙏🏻 Making a video takes a lot of time. Unfortunately, I can't produce more content 😔

[@jancenj2218]

On the inverter, why is the output negative when the supply is DC? What was actually inverted? I know for AC input, the phase was inverted 180 degrees.

[@eeapplications]

Hello. While there is a positive-negative change in DC, it happens in the form of a 180-degrees phase shift in AC.

[@vjnqt27]

what op ampndid you use? lm358?

[@eeapplications]

LM741

[@alexbowman7582]

The moon landings used op amps as analog calculators to work out various scenarios.

[@cjdelphi]

Scary ...

[@nayrbsworld3048]

wow nice. can we convert this to square wave ? how?

[@moh6410]

RECTIFIER CIRCUIT (USING DIODE)

[@memirandawong]

Great video. Well done!! Only one question, two actually. (at 6:23 in the video) 1.) Does it matter that you're not considering the true RMS value for AC inputs when calculating the output value? Or am I still confused as usual??? and, 2.) I think in an earlier video you stated one of the fundamentals is that the voltage at each input is for all practical purposes the same. Is that how you arrived the voltage (2V) to use in the non-inverting example? (4:55 in the video) Or, in the same example how does 2V appear at both input pins 2 and 3?

[@eeapplications]

Thank you so much. I'm glad you liked the video. My preference is to use the effective value in your 1st question. You can also do it over the maximum value if you want. Unfortunately, I couldn't understand your second question. I'm sorry.

[@d614gakadoug9]

old question, but since it didn't get a reply: Yes, arguably THE most important concept in op amps is that there is a "virtual short circuit" between the inverting and non-inverting inputs when the amp is being operated with feedback. There is no current flowing between the inputs, they are just kept at the same voltage by currents flowing in the external circuit.The feedback makes the voltage at the inverting input equal to the voltage at the non-inverting input. That is, the non-inverting input "sets the voltage" for both inputs. There will be some very small difference in voltage between the inputs, but for lots of circuits the difference can be ignored. The other very important thing to remember is that the current into or out of the inputs of the amplifier itself are extremely small. Like the voltage difference between the inputs, these tiny currents can be pretty much ignored for lots of applications, though in some circuits they must be considered and can actually be quite a big issue. In the video, both inputs will be +2 V - the NII made that way directly and the II via the feedback/gain network. If the II is at +2 V, then the current through R1 must be 2 mA by Ohm's Law, flowing from right to left (using "conventional current" which is considered to flow from positive to negative). Since no current goes into or out of the actual input pin, that 2 mA _must_ be coming via the feedback resistor and it must be flowing in the same direction. 2 mA through 4.7 k gives a voltage of 9.4 volts. The II voltage we know will be +2 V, so the output voltage must be (+2 + +9.4) = +11.4 volts. Of course there can be situations where the op amp just can't do what is asked of if. If just a bit more gain were required in the circuit in the video, or the voltage at the NII were just a bit higher, the amp wouldn't be able to do the job because its output voltage would have to be higher than its positive supply voltage. The voltage at the non-inverting input couldn't be driven high enough to match the voltage at the NII. In fact lots of op amps wouldn't even be able to get to 11.4 volts with a +12 volt positive supply.

[@RajibKarmakar-m5j]

Various applications opamps.

[@KartikPatel-nt4ff]

😅😅😅😅😅well information good show you 😅😅

[@MonsterThiv]

👍👍😍👍🇰🇭

[@cleofaspintolimalima1627]

Hey there

[@katrina9512]

"Promosm" 🙌

[@KrishanKumar-hv8fu]

The world's best teacher thanks sir