Packed Bed Reactor (PBR) Molar Balance Equation // Reactor Engineering - Class 10

[@Ibrahim-mz2dn]

Sir This lecture is 8 years old but It is giving a lot of worth. You are legend your lectures are very helpful . Thankyou sir for making this. God bless you

[@ChemicalEngineeringGuy]

thanks mate! actually, Im working on an updated, more refreshed course, stay tuned!

[@alejandrodelabarra2838]

Muy bueno!! ¡¡Muy buen Nivel!!

[@ChemicalEngineeringGuy]

thnx!

[@richardaversa7128]

3:26 Perhaps a poisoned catalyst is indeed literally "poisoned". After all, if an animal is poisoned, doesn't that usually mean a chemical is binding to the animal's catalysts (enzymes) and causing them to malfunction, and isn't that exactly what is happening here?

[@ChemicalEngineeringGuy]

Yeah, technically its correct. Either way its just industrial "jargon"

[@nylepentik2696]

Legend mate.

[@ChemicalEngineeringGuy]

thanks XD

[@aleynakaya2166]

In 7:26, I think you wrote the f inlet and outlet part wrong after reversing the equation. By the way, your lecture is very clear and understandable, thank you for this useful and good content. 🙏

[@ChemicalEngineeringGuy]

Hey Aleyna, thanks for letting us know! Im glad you like the lectures! Course comin soon XD

[@panoskb9405]

The PFR is used only for homogeneous reactions or also for heterogeneous?

[@marcelinevenus1709]

Sir, is FBR (Fixed bed reactor) and PBR the same? If not, do we still use the same formulas for calculations?

[@ChemicalEngineeringGuy]

Yeah! Packed Bec Reactor and Fixed Bed Reactor are the same

[@folaolojo5245]

when given equation for rA and a value is gotten. how do I calculate rB. they are both reactants

[@ChemicalEngineeringGuy]

since they are related stoichiometrically, you can do so with stoichiometry factors, i.e. if 2 mol of A are reacting for every 1 mol of B, this means that the rate of reaction of A is 2x faster than the rate of reaction of B

[@chemoxyjunior7194]

great work

[@ChemicalEngineeringGuy]

thanks there!

[@mousumidas5051]

thank yu so much..

[@ChemicalEngineeringGuy]

Im glad it worked for you!