A Nice one from the Indian JEE Advance 2023

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Today a wonderful differential equation from the famous Indian jee advance exam 2023. Coming at you with a clever and elegant solution. Enjoy! =D
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[@o_s-24]

7:33 lmao "black magic physics f*ckery." My diff equations professor actually went on to prove why this works in class, but then in the physics we just randomly have dx's and dy's floating around in equations

[@tusharsr2709]

papa flammy finally picked up JEE

[@DaedalusTheInventor]

Wow I wasn't expecting a jee advanced question here lolol But how I would have done it is by dividing by cos²x. Then using the linear differential equation dy/dx + Py = Q method with integrating factor and stuff

[@Sidharth_V_Jain]

that was my first instinct too, i just tried it and i got y = tanx + (C-1)e^-tanx

[@alphastar5626]

When I'm too lazy, I use the variation of the constants method to find the particular solution (linear diff. equations). It always work, it's easy, pretty quick and you never need to "guess" what kind of particular solution may work, thus avoids wasting time. Only exception is if everything is a polynomial or a polynomial of trigonometric functions

[@yahia2601]

I'm curious isn't vop a method for 2nd order odes

[@alphastar5626]

@@yahia2601 works also for 1st order

[@kamarinelson]

@@yahia2601we can solve the associated homogeneous equation, but we typically can’t guess a particular solution if the function is tan(x). That’s where variation of parameters comes in. Use the general solution to solve for the particular solution.

[@kamarinelson]

@@yahia2601it appears we could also have just used and integrating factor on the original DE. Sorry, it’s been a few years 😅.

[@yahia2601]

@@kamarinelson no worres. I thougt there was something I was missing /didn't know. Thanks for the reply

[@Professional-Hater]

Don't pick questions from this exam flam, people would still never be pleased that you tried a creative approach instead of the "short tricks" these kids learn in their Entrance Exam factories.

[@itachu.]

your name is professional hater... you sure you aren't one of "those" kids

[@ThorfinnBus]

Lol you are also one of the reasons to start those fights. Moreover this is one of the standard methods in current day JEE mains itself(in fact from 2021) and also VITEEE. I am not saying the video is bad or literally nothing. You are making it sound like this is an unknown method. That's what I am pointing.

[@Professional-Hater]

@@ThorfinnBus I wouldn't have commented if I hadn't seen a comment calling this question trash and easy because of the existence of IF method

[@subhamtiwari6204]

Bhai chorde isko limits ka problem dege​@@itachu.

[@rakshith9820]

Yes. I personally don't like this exam as they are overrated in india

[@albertrichard3659]

I like this solution. I did something a lot less elegant but still dependent on the derivative of tan. Let t(x) = tan (x). Then the ODE becomes y'/t' + y = t But d/dx (y(t (x)) = y' = dy/dt * t' so dy/dt = y'/t', and thus dy/dt + y = t This is easily solved using the method of linear equations or by a clever substitution.

[@TranquilSeaOfMath]

This is really good. I'm surprised, I saw the thumbnail and title and was expecting a joke video.

[@AlphaCurveMath]

noooooo papa there's no end to pleasing this crowd :(( ( I am as Indian as it can get)

[@monisahmedrizvi1697]

True 😂

[@xinpingdonohoe3978]

The integrating factor method makes this question trivial. Still nice method though.

[@retro_jonny]

Heh I currently taking Diff Eq/Linear Algebra. This pretty cool, this is what we’re soon gonna learn when we return to Diff Eq

[@seventysevensquare]

Papa Flammy doing JEE Advanced? Most unpredictable thing of this year🤡

[@anubhabbhattacharjee476]

I don't think so this is from last year's JEE advance Question it might be from old year question but not from recent year because, all CBSE students can do by using integrating factor. I don't think we need particular solution and homogeneous solution. By showing this question it is a digress for the examination to pick this easy question. I would say pick Q4 from 2023 JEE advance question. Thank you!

[@Bhakti_hai_shakti_hai]

Wtf

[@KazACWizard]

for a question in an exam its quite fair as it isnt particularly lengthy to solve, but the solution is very pretty. prettier than most DE exam questions im used to. although now looking thru comments... What are you up to FLAMMY?

[@gunaysoni6792]

It has been years since I did something like this. My first instinct is to use the integrating factor method.

[@oyomera]

It's a linear differential equation and It's solution will be y = tanx + C

[@holyshit922]

Seems to be linear first order Hint for those who are beginners in differential equations and want to solve it on their own First order linear equation has structure similar to the derivative of product so it is good idea to multiply equation by the unknown function such that LHS indeed would be derivative of product I would solve it as linear and there are two ways which I know variation of parameter and integrating factor Your first idea wasn't so bad t = tan(x) dt/dx = 1/cos^2(x) dy/dx = (1+t^2)dy/dt 1/(1+t^2)*(1+t^2)dy/dt+y=t dy/dt+y=t dy/dt*exp(t)+y*exp(t) = t*exp(t) d(exp(t)y)/dt = t*exp(t)

[@holyshit922]

The only difficulty while solving linear first order equations is calculating integrals

[@theepicman8160]

wow thats very creative, thanks 😍

[@steveshaver4000]

Great work!

[@eevee8856]

Bro finally decided to pick up on side quests 🗣️

[@AmlanSarkar-wr2pr]

Papa Flammy try to take questions from ISI(Indian Statistical Institute) exam and CMI(Chennai Mathematical Institute) entrance exam these institutes are pure math research institutes and it's questions are even higher than Jee Advance.You will surely love them and I guarantee you.

[@PaulJai-v1h]

Nice one !!

[@pandavroomvroom]

this is one way to increase views

[@who-hoo-man]

yeah lol kinda saddened me that papa has to do this :( (its ok papa)

[@PapaFlammy69]

I am very certain that this is a JEE question, this is not supposed to be clickbait.

[@gametimewitharyan6665]

​@@PapaFlammy69 He meant that solving JEE questions on the channel will make the indian audience happier and attract more of them

[@69Gigantosaur]

​@@PapaFlammy69Love your skits with andrew ❤❤

[@abhinandip5642]

This is an example of linear differential equation (y` + P(x)y = Q(x)) use standard solution (y*IF = integral(IF*Q(x) dx) + c) it will give direct answer...This question was very easy There are good questions in Advanced I think you will enjoy solving them

[@jayadeepnayak6582]

Exactly!

[@yasharora6772]

ez views as u mentioned JEE ADVANCED!!!!

[@PremChand-ts1bi]

substituting y = tan(x) + z simplifies the equation and is readily solved.

[@haryr_]

nice DE, I liked this method, I used the integrating factor, but I did a stoopid, and when I was integrating 1/cos^2x, i forgot that tanx differentiates to sec^x, so it took me a while to figure.

[@NXT_LVL_DVL]

Great to see problems I've solved ❤❤❤❤❤. From India .

[@athiest100]

Basic integrqting factor ,,e^tanx

[@mittato2135]

papa flammy is there a way to find a function f such that it satisfies the condition f'(x)=(f^-1)(x) (the derivative is the inverse) and f(1)=1 without an Ansatz? I am getting desperate

[@jameyatesmauriat6116]

I have seen many videos of mathematics but I don’t know how to solve this, what is the method followed up by the instructor in this question?

[@hossainboard86]

I remember solving it in my last year of school

[@navneetsinghr4290]

Cool solution man better than the usual linear de what I'd do

[@depressedguy9467]

Are you doing phd

[@mrityunjaykumar4202]

just use LDE simplest way to solve this

[@arnavthesceintist1149]

We only have 3 minutes per question. Nobody appreciates a creative solution but cheap tricks. I hate our education system..... Deshalb will ich in Deutschland studieren.

[@pradyumnabilagi7661]

I think we can use substitution to highly simplify the the problem. We can use tanx = X and then the equation becomes dy/dX + y = X , and then we can find y(X) and then substitute X with tanx

[@jameyatesmauriat6116]

What about cos^2(x)?

[@pradyumnabilagi7661]

@@jameyatesmauriat6116 yes cos^2(x) dy/dx becomes dy/d(tanx)

[@BaconSpeedrun378]

50 years vid

[@who-hoo-man]

Its kinda unexpected seeing JEE here lol

[@horseios3655]

in the homo solution, why did tan(x) on the right hand Side just disappear to zero

[@Ayush-yj5qv]

Take up 2022 jee advance question one of the finest question

[@varunrmallya5369]

Did that question ,")

[@krushna_prasad]

Wish me luck papa, gonna appear for jee adv 2024

[@honestadministrator]

y' + y sec^2 ( x) = tan ( x) sec^2(x) exp ( tan ( x)) y = Int [exp (tan (x)) tan (x) sec^2(x) dx] + constant of indefinite integration Here in integration ( exp( z) z dz ) = exp(z) z - exp( z) + constant Hereby y = tan ( x) - 1 + A exp ( - tan ( x))

[@Spyro-kt8gy]

Good morning saar.

[@CepheusMappy]

We have Papa Flammy solving JEE before GTA 6

[@germgoblin5313]

This is a weird question but do you have any advice for learning maths as someone with ADHD? I sat the uni entry test and I got a good score but I have such a shit attention span and so many depressing thoughts that focusing and learning maths is hard for me.

[@kls4770]

The equation that i ca't resolve is 353K and 821 views knowing that it is nice viedeo !!!!

[@AnshPathak2005]

Finally , JEE advance 😮

[@midnightgamer4201]

I don't think this question was asked in jee advanced, nevertheless a good way to increase the views 😂😂

[@xa-4246]

Yeah lmao I'm pretty sure this is just an ncert question(the most basic linear D.E question ever). But hey its simple.... I see papa flammy I click.

[@midnightgamer4201]

@@xa-4246 yeah

[@satvik9391]

papa flammy why dont u become a jee teacher lol

[@vinniepeterss]

❤

[@itachu.]

i know you

[@vinniepeterss]

@@itachu. ?

[@itachu.]

@@vinniepeterss yes

[@YoungPhysicistsClub1729]

even with his hatred for india, he still took up a jee question, chad

[@monishrules6580]

Chad indeed

[@i2keepitrealInreseach]

He is running on low views.

[@quantumboii]

that question isnt even of jee advanced 2023

[@ankitbhattacharjee_iitkgp]

He probably picked the easiest question of the 2023 paper. I had scored 126 in this paper in total, with 35 out of 120 in Mathematics. And trust me there were some brutal questions of Maths in Paper 1. Edit: I am already through my first year at IIT Kharagpur, and don't really recall if a question this easy was on the test!

[@nword683]

Branch ? Rank?

[@karthik_nt.]

one of the easiest question of jee adv lol

[@mahigurram1712]

Pls don't complicate the solution just use bernollius ode

[@PaulJai-v1h]

It's not complicated, he's not trying to just solve the question and tick the ans faster than anyone else's, he's trying to think of a new type of creative approach. And that's worth being appreciated for

[@agrajyadav2951]

@@PaulJai-v1h nice cope

[@agrajyadav2951]

hey what happened to the passionate racism and hatred for everything Indian?

[@purvamaheshjoshi9brln.665]

It's Jee advanced not jee advance

[@mandalorian3246]

no one gives a shit pajeet, take shower

[@Bhakti_hai_shakti_hai]

Who cares?

[@vatsalyavashisth828]

smd

[@AGARVRAWAT]

Dude this is JEE MAINS question not JEE ADVANCED, such oral questions are barely asked in jee advanced

[@adityamishra0706]

This isn't jee question