PATHFINDER SOLUTIONS - RING WITH A GAP IN E | WRONG ANSWER CORRECTED

[@PHYSICSSIRJEE]

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[@ambarishphysics]

Very fine point Sir and very easy to overlook... enjoyed the video. Cutting analysis... 🙂❤👏👌

[@PHYSICSSIRJEE]

Thank you Sir 🙏🙂

[@bbsir]

👏👏👏 Such a good point discussed Sir! Keep sharing these anecdotes. Thanks.

[@ponbapanda2935]

Just saw that you re-passed 13K subs. Congrats again!

[@PHYSICSSIRJEE]

Yeah , thank you 🙂

[@babyelon1959]

@@PHYSICSSIRJEE I hope you don't re-pass 13k subs again in 2022 xD

[@punamdeviextremefitnessach5087]

XD

[@rahuljha932]

Thank You Sir for reminding me how superficially I look at problems 🙇

[@AnjuSingh-ks5hc]

Sir you are doing very good for advanced level problem solving. I am regularly following you. Sir please also make some advance theory lectures for chapters like electro magnetic rbd and thermo. It will be a great help for us thank you sir for your support..

[@PHYSICSSIRJEE]

Lectures are out of time bound schedule. I can't promise anything that I can't deliver with quality. Keep watching, you never know, I might surprise you 😁

[@sohansingh2022]

Diwali gifts sir 💕

[@AnjuSingh-ks5hc]

@@PHYSICSSIRJEE surprise us with a beautiful diwali gift😅😅 thank you sir for your support..

[@tushteegupta5916]

One of most fantastic physics teachers I have ever come across

[@rms6519]

Thankyou, never though this while solving the first time! I guess it was incorrect to apply torque=i alpha about a non inertial point (the centre of ring) that isnt the COM.

[@bitandutta2191]

op analysis sir .Thank you for sharing such a great approach..

[@agrimmittal]

Thank you for the amazing video.

[@JEEAspirant-ub3id]

sooooo amazing point sir, pure eye opener🙏🙏

[@simisimi9362]

Wow this one is just op. Thank you sir 🙌🙌

[@abz7946]

Thanks sir for always refreshing concepts regarding theory before question.

[@ankitsoni9275]

Thanku ❤️

[@satyamkumarmal7783]

Nice video sir .🙏🙏🙏🙏

[@revolutionmusica]

thank you sir 🙏🏼

[@roam2explore588]

I think we can also correct it by saying if the same ring given in question is attached at the periphery of a light disc and that is hinged at its center

[@a.gabriel1253]

Sir pls do questions from thermal physics some more sir pls. I mean from pathfinder sir

[@shivendraahuja7481]

Sir after solving the corrected version, we get the ans at the back. since l was

[@pritamroy4649]

Bhaiya are you getting a factor of pi in denominator as I'm getting a factor 2pi ?

[@sohansingh2022]

At 12:32 part (a) i am totally blank but part (b) if I assume that the charge distribution is uniform then we know that charge density is inversly proportional to radius of curvature so could have solved it. Part (c) i am totally blank 😅

[@LostZoro798]

Gawd💪

[@entropy1322]

Thank you so much sir!!

[@simi8858]

Sir honestly very helpful video thnx ❤️🎁💐

[@piyushkrsingh]

Sir, is there any good resource for more understanding on differentiating these two points??

[@PHYSICSSIRJEE]

Many good books are there . Beer and Johnston springs to my mind for "center of force" concept

[@chiragatreya530]

Amazing concept Thanks sir 🙏👍👍

[@armansingh3111]

sir can please make a video for explaining step pully

[@Fighter_Believer_Achiever]

Thank you very much sir🥳🥳🥳🥳

[@supriya1729]

Amazing,op,pro,orz,omg😳🙂🎉

[@adityatiwari363]

ohh damn

[@AdityaGupta-xq8ud]

sir for the second part , assuming charge density of bulge and remaining part to be equal, q=Qr^2/2R^2 given that r

[@pranavreddy80]

Sir Which series playlist contain relatively easy questions in ur channel?

[@PHYSICSSIRJEE]

You can try AITS select series and JEE advanced solutions .

[@pranavreddy80]

@@PHYSICSSIRJEE thank you sir

[@parthlambe375]

Sir till which level narayana packages question are really relevant ???

[@princerxj]

First view sir🤟🔥

[@Fighter_Believer_Achiever]

Revised it, though i should be doing it later😁 @1 electro

[@Fighter_Believer_Achiever]

Just came here to take a look, though i should be doing thermodynamics now😂 Getting distracted by electrostatics😅

[@zebra-er6xc]

can someone tell which software is sir using? for writing notes

[@PHYSICSSIRJEE]

PDF annotator or open board

[@zebra-er6xc]

@@PHYSICSSIRJEE thanks sir

[@Shivanshuvermamedico-b7p]

sir in this particular question the counterpart of the lost part is in form of arc so force will act act diff location then threby produce diffwrent torque .is this rhinking correct sir?

[@PHYSICSSIRJEE]

Small arc is a straight line

[@Shivanshuvermamedico-b7p]

but sir if the condition given in the question(l very less than r ) then my observation will be correct or not?

[@PHYSICSSIRJEE]

@@Shivanshuvermamedico-b7p torque will be zero as explained in the video

[@Shivanshuvermamedico-b7p]

@@PHYSICSSIRJEE sorry sir i want to say if l very very leass than r condition is not valid then arc will not be considered as straight line and then my point will be valid or not?

[@PHYSICSSIRJEE]

@@Shivanshuvermamedico-b7p irrespective of the condition , ring won't rotate . I mentioned that in the video clearly , even for semicircle , it won't rotate. Answer would be zero

[@ravi3503]

Sir plze tell which website or app you use Plze chepandi sir

[@PHYSICSSIRJEE]

I use zoom to record videos

[@ravi3503]

@@PHYSICSSIRJEE in which website you write the points sir

[@hardikkansal6479]

Sir please take nlm check your understanding que 6 Pathfinder...

[@mathspoint7246]

Sir it will be very helpful for us if you bring videos in Hindi also pls sir

[@PHYSICSSIRJEE]

I will try 🙂👍🏼. One genuine doubt : What about students who don't understand Hindi ?

[@nihanth9145]

@@PHYSICSSIRJEE actually I think , even Hindi preferring students read many books and papers which are always in English . I don’t think there will be problem in understanding these beautiful concepts in videos.

[@amit3239]

@@PHYSICSSIRJEE sir eventually its hindi dominated country . Its simple if you want masses on this channel then please the masses otherwise wait and watch if you getting enough support and good subscriber base from english speaking community.. work for 4-5 year in shade without much expectations and then its a next big thing... but if you want exponential growth then one has to please the numbers otherwise be satisfied with whatever one achieves with wave of time----- Simple rule of youtube world and the easiest option is to quit.. which a teacher of your calibre won't do i guess

[@janhavikhandelwal734]

The real source from which arvind sir took this problem also contains a fixed vertical axis given in the question. Sir missed it in pathfinder 🙂🙂

[@physicsguy6625]

Can you name the source?

[@janhavikhandelwal734]

@@physicsguy6625 not here

[@aamitabh69]

​@@janhavikhandelwal734SBT?

[@nimitjain8163]

thanks for clearing the concept sir.

[@a.gabriel1253]

Can anyone help me with chapter 4 check ur understanding problem no 24 pls.in pathfinder

[@shounaktikotekar6968]

Even in the corrected question there is a uniform field so why aren't the centre of force any com coinciding?

[@shounaktikotekar6968]

And*

[@sumitkumar-fb5op]

sir olympiad ke lie special batch h jisme aap sirf path finder solve krwaate h?

[@PHYSICSSIRJEE]

I , right now, don't teach online

[@aarnavaakash]

Sir plz reply very few questions I am able to solve but I want to solve what should I do??

[@PHYSICSSIRJEE]

Please watch the videos and note down important points. Watch them again during last few months before the exam

[@promaxsavior9791]

Sir the actually those who calculated didn't took swift in com in consideration

[@chiragatreya530]

Sir what is the link of telegram group??

[@PHYSICSSIRJEE]

It's in "about me" section of channel as explained in the video

[@chiragatreya530]

@@PHYSICSSIRJEE thank you sir I found the link

[@manishkhandelwal7734]

Smash the like button too hard😁😁

[@shubhamjha6418]

Sir please please explain this question its an request the question is *A satellite of mass m is launched vertically upwards with an initial speed u from the surface of the earth. After it reaches height R(R= radius of the earth), it ejects a rocket of mass m/10 so that subsequently the satellite moves in a circular orbit. The kinetic energy of the rocket is (G is the gravitational constant; M is the mass of the earth* Sir please also give 2 to 3 question similar to above question and question concept so i can practice and sir if you can't make video due to your busy schedule so just send me the similar practice question in the comment itself please sir its an urgent request thank you

[@PHYSICSSIRJEE]

Please post the question in our telegram and discord server . Or you can use Google 👇 byjus.com/jee-questions/a-satellite-of-mass-m-is-launched-vertically-upward/

[@princerxj]

🔥🔥🔥

[@tokaisehaiaap_log]

💦💦

[@PHYSICSSIRJEE]

@@tokaisehaiaap_log 😂

[@yeetmeet]

a free body always tries to rotate about com because moment of inertia about com is least

[@ramanverma6835]

Mera bhi book wala ans aaya pehle

[@taran7954]

Poor elephant suffered for the sake of physics!

[@shresthjha8109]

sir although the calculation done here is correct but the conclusion drawn is not that correct because here torque about com is zero but the torque about geometric center is non zero this means that omega relative about com is zero this condition is actually signifying that the com and the ring are rotating with same omega and hence torque is coming out to be zero .

[@PHYSICSSIRJEE]

Geometric centre is accelerating , so please consider pseudo torque and rethink

[@shikharkunal2276]

RIP elephant 😞😓

[@PHYSICSSIRJEE]

😛

[@PHYSICSSIRJEE]

@@Unknown-vl8eh if you can do 1000 problems per day then you are not human

[@PHYSICSSIRJEE]

@@Unknown-vl8eh Even 500

[@beluga8956]

poor elephant 🙁

[@PHYSICSSIRJEE]

Yep , collateral damage 🧠😋

[@BheemChandGoyal]

Clicked