pH of a Weak Acid (0.1 M Acetic Acid) EXAMPLE

[@phuckerization]

If my professor were as entertaining as you while he teaches, maybe I would be doing better in Chem! Thank you sir. You're videos are much appreciated.

[@labelproduct]

Best chem teacher ever hands down

[@chemistNATE]

You'll only get the same answer if 1) There's no A- or H+ in the solution before you dissolve your acid ("common ion effect") 2) Your acid has only one H+ on it (ie it works for HCN but not for H2C2O4 or H3PO4)

[@chemistNATE]

Every teacher has some different rule. I hate that. When I teach, I use 100. When I'm doing real chemistry, I just always assume I can make the assumption, and then once I'm done if the value of "x" that I get is too close to the initial concentration, I redo the calculation with quadratic formula.

[@pimpgrad1080]

You are doing gods work.

[@claudiasmith8690]

"Piece of cake son!" hahah Oh you are gold! Thank you !!!

[@oxyhax1033]

you sound like deadpool

[@pludo645]

Holy crap I literally thought the exact same thing! The comparison is uncanny!

[@1pk155]

Here's a simpler method we were taught in school. We use this formula: √(Ka X C) So, √(Ka X C) = √(1.8 X 10^-5 X 0.1) = √(0.0000018) = 0.001342 Find -log. So, -log 0.001342 = 2.87. Thus pH of a 0.1M solution of Acetic acid with Ka of 1.8 X 10^-5 = 2.87. Finito! :)

[@onlyfabbs]

You are a legend. (Y)

[@radhhpatel]

"Whatever your problem not mine" 😂

[@deependraverma4382]

Dude!!! You're nuts, Cause if you can't understand chemistry, That's your problem, Not his.

[@TheAwesomePikachu]

Entertaining and informative. You explain chemistry like no other! Truly the best!

[@jamesmatthewcastillo2540]

I love you man! You've tremendously helped me finish my lab on time

[@MAhmad-uj8wx]

For weak acids we can get the value of pH by using the equation pH=1/2 {pKa - log C} Here C=concentration in terms of Molarity. Hope it Helps.👍✌️🙂

[@chemistNATE]

Great effort but I think you made a typo. pH=-log [ C * Ka ]^(1/2) pH=-1/2 (log C + log Ka) pH=1/2(-log C - log Ka) Final form: pH=1/2(pKa - log C)

[@MAhmad-uj8wx]

@@chemistNATE oh ! typing Mistake.... Edited:-I have set it correct now.

[@kimlll2981]

I wish you had explained how to do the quadratic equation.

[@Jojo-hy8dm]

Same

[@Palomino0813]

chemistNATE is my favorite superhero.

[@brandonmutyasira6201]

you the best man...my chemistry has become so much better ever since i started watchin your videos..

[@merhawitesfay2333]

you are best of the best ,, its eating good english breakfast in the morning ,, hats off for you sir...

[@ilyadelaco1672]

Your video answered every single question I had about solving these equations, thank you!

[@danmitch8970]

literally you are 10x better than my CHEM 104 prof, thank you so much and thanks for the laughs!

[@321lmn]

God Bless you sir and your abundant wisdom and kindness to share this information... no but seriously thank you.

[@courtnie1783]

My teacher advised us to only spend time trying the assumption rule if the exponent on the equilibrium constant is 10^-5 or smaller bc those numbers are more likely to be insignificant enough to omit the x in the denominator. :)

[@Victoria-vj3wv]

"If your teacher is all extra about it" ;) Love your vids and explanations. You are making this a tad bit easier for me to comprehend!

[@santosibalasahoo9957]

Thank you thank you thank you Thank you thank you thank you Thank you thank you thank you Thank you thank you thank you Thank you thank you thank you

[@erminaburgaj5073]

you're great at teaching.

[@LCDqBqA]

You do it a lot different to how we do it in England We assume [H⁺] = [A⁻] when water dissociated So we can rewrite the equation as Kw = [H⁺]² / [HA] Then if you rearrange you get [H⁺] = SQRT(Kw*[HA]) Seems a lot easier and it skips out steps like the 100 rule and use of ICE tables Am I missing something? You still get the same answer, is there any cases where this method will not work?

[@tizjoanne]

I love your enthusiasm!

[@DedicatedtoErik]

You have saved my lifeeeee!! Thanks

[@lisasun7055]

just the exact problem I was searching for. thanks

[@vedantwate4105]

Thanks for saving my class 10.

[@jimexsha]

Very clear explanation

[@gabrielalopez2512]

"Plug THAT into ur calculator and press enter" AHAHAHA WHY AM I FINDING THESE SO FUNNY.

[@catherinedawson2721]

Thanks, awesomely explained! (both theoretically and theatrically) :)

[@liyaayalew8592]

thanks so much ❤❤❤❤❤

[@tamaht.7581]

what if there is a different volume but 0.1 M is given. Do I just use 0.1 M for the ICE Table?

[@radiatelove21]

You make Chem fun! :)

[@ninacollins7088]

can u show us how to calculate the same if u have 5mL of .10M of acetic acid?

[@mercyobiozor6278]

Your video is really helpful.Thanks

[@LarsTheHonest]

This is a great video. Thanks a bunch.

[@Fatso97]

I'm an idiot waye out my depth. How do I input the equation into my calculator? Because for me the line is divide

[@MeegoHeebo]

Great video! Very helpful. Thank You!

[@PastaSenpai]

1:20 is how easy this guy makes it

[@Bripirate]

Why not just solve the quadratic. It wouldn't take anymore time and you don't have to make any "assumptions".

[@courtnie1783]

You could, but once you practice the assumption method enough, taking the extra few seconds to do it and see if it'll work will be much quicker than the time it takes to type the quadratic into your calculator. It really can make a difference, and it's good to show flexibility and cognitive understanding of multiple methods in chemistry (as well as other fields) anyway.

[@courtnie1783]

Yes, concentrations are positive.

[@jatarokemuri4549]

It's better if you have a calculator program for quadratic

[@mohammeddhakbi3861]

amazing video thanks for helping in my homework much love

[@cardiacmyxoma4073]

You're awesome, thank you so much!

[@chloesizemore9933]

thank you for saving my life

[@fishyfishr]

What a great video!! Explained very well !! Maybe next time blow your nose before recording lol, great video none the less

[@michellesad429]

Thank you!! I have a question, you only use this formula.. finding Ka, and then PH for only weak acids? What do you use for strong acids? Thank You

[@Arjay416]

What if the assumption is not below 0.05

[@wasmiaha1750]

Thank you so much. It is really great and helpful.

[@dinnudevarapalli2382]

Absolute legend!

[@domliger622]

Not a word on H+ resulting from water molecule dissociation?

[@roshanrs6725]

How to calculate when Ka is not given ....plz anyone reply

[@hoimebanerjee1066]

Thank you sir for the solution....

[@LSI_MGA]

Why do you assume it's in water though?

[@ScraperCross]

Helped me out so much! Thank you.

[@angeluomo]

Great job!

[@swordmas7544]

Great VIDEO

[@Oreonis]

I thought the equation for PH was PH= pKa + Log(A/HA)

[@anoushkasingh2636]

Yes its good. But can somebody tell me that how is Acetic acid desolvable in water being a covalent compound? Well I know that acids do that, but the fact is that covalent compounds dont.

[@longshot1710]

The oxygen atoms in the carbonyl and the hydroxy group are more electronegative than the methyl group attached to the central carbon. This creates a dipole moment. Anything with a dipole moment is polar and will be dissolved in water because water is polar. Remember, like dissolves like!

[@1RetroMetro1]

isn't rule of the 1000? or 100? I'm lost...

[@matthew_cramer]

What if I'm not given ka?

[@MrTTbam]

life saver thank you!

[@annryan1056]

Thank you - really helped

[@sanaajennings6285]

awesome video son!

[@deji_ace]

Thanks!

[@mariamjaafardk2671]

THANK YOU

[@allanah2cute]

LOL this was so funny and helpful!

[@eaglesem7877]

Bruh where do you teach! I hate my chem teacher now!!

[@markrancy5804]

i'm falling in love with you. you are so good :)

[@adixtya7736]

Amazing 🔥

[@MoonLonerkid]

THANK YOU SO MUCH

[@vaibhavpandey9009]

Thanks sir!!!! 😊😊😇😇

[@idreesiqbal561]

thanks dude perfect

[@snehamohan7758]

is the Ka common knowledge or did you work that out

[@noraali5856]

Thank you

[@daz2084]

Thank you sir!!

[@kuldeepsahu2460]

weak base and weak acid questions

[@yadumishra7613]

Thanks

[@chrissmithers1313]

thank you!

[@PallyIRL]

Why can't you be my teacher lol

[@surat8591]

Thank you!!!!!!

[@dorukanylmazkulas1538]

God bless you

[@CaptnCameron]

piece o' cake son!

[@ruthlessastrid6681]

TOO NICE

[@morsmb1]

ty

[@axalate4572]

"i got 2.87 just also the answer the textbook i stole this question ..... from.........got same answer in the textbook thats what im sayin " LOL

[@plsjustnathan1]

This video is now property of Ernie Gang

[@beninatorskater]

You da man.

[@Sergio12.01]

And helpful

[@99ninjanun]

Thanks crazy Canadian :p

[@soloxfury1612]

Turn this on 1.5x and he sounds like he's on coke.

[@cristysuarez]

Gracias :)

[@muhammadolim6959]

👍👍👍

[@drjaiswals]

Thank you uncle... Aap ke wajah se kal izzat ban gyi, kal class m boss bnenge.... 😂 😂 😂 😂 😎😎😎😎😎😎😘😘😘😘😘😘

[@flowstardash]

Marry me hahaha!!!

[@Martando7]

cheeky bastard

[@gerrita.v.8422]

is this guy sick in every video

[@daneshkiki9716]

is it just me or is this deadpool teaching us?

[@Sergio12.01]

Hahaha you are hilarious.

[@LaurenBurdick]

LOL your commentary doe.

[@liibaanmohamedahmed5801]

this is agood explanation