Phase Lead-Lag || How to Calculate Phase Angle between Two Signals || Example 9.2 || ENA 9.2(8)

[@surendrakverma555]

Thanks a lot Sir for useful information 🙏🙏🙏🙏🙏

[@sadiqyusuf4584]

Well explained , don't speak hindi but I understood. Many thank sir

[@ElectricalEngineeringAcademy]

Thanks dear. Here is a slightly detailed on in English kzbin.info/www/bejne/rInCfX-EoZKNprcsi=BD0IYUhAS83YZvyP

[@TanjilAl-Nayeef]

Love from Bangladesh 🇧🇩 and love from #CSTU (#Chandpur_Science_and_Technology_University)

[@ElectricalEngineeringAcademy]

Thanks dear. Best wishes.

[@MDRISHAD-qz9zn]

Wow ❤️

[@Bollywood_Expose]

Bilkul fayada hua sir

[@ElectricalEngineeringAcademy]

Thanks dear.

[@manishabodda2317]

thank u so much sir for this video..

[@ElectricalEngineeringAcademy]

Welcome dear. Best wishes.

[@20tejas]

Prof if you convert both to sin then it gives answer 210 I think it is correct 210 and not 151

[@ElectricalEngineeringAcademy]

Firstly it is not 151 rather 150 degree. As I mentioned that we can add or subtract 360 degree with any angle, the net value will remain same.

[@20tejas]

@@ElectricalEngineeringAcademy thank you your lecture helped me a lot.

[@LEGEND-ok6kw]

angle cannot be greater than 180 degree so the first one is valid in my pov.

[@ElectricalEngineeringAcademy]

You are a legend so I can't challenge you, but angle can have any value.

[@LEGEND-ok6kw]

@@ElectricalEngineeringAcademy No Sir don't take me wrong it's just what I previously learned and you justified that in your lecture that your fellow colleagues were stuck on this. So, when we consider two polar forms with their subsequent trigonometric function the angle should be less than 180 and if it does we add or subtract by 360 degree.