thank you so much profesor from the ones like me who dont have to chance to go to your university and your country. i am watching you from China, i am grateful to you for your lectures you share in KZbin.
@JakeBarnwell-s8j6 ай бұрын
Truly impressive how you were able to give a lecture on this essay and somehow make it as simple as the beginning of his publication “the Phil of logical atomism.” Amazing!
@hereticmorte6664 жыл бұрын
Thank you posting these lectures on youtube for free, good sire.
@SAM-Asura Жыл бұрын
Listening to these lectures helped me understand a lot of connections in Semantics and Pragmatics. Thanks a lot professor!
@1987Isabella5 жыл бұрын
Very engaging and easy to follow. Thank you for sharing!
@MrAlanfalk737 жыл бұрын
You are an awesome teacher 😆 (and a nice human being too) . Thanks for all your lectures 😎
@romeoharold21833 жыл бұрын
i know Im randomly asking but does someone know a method to log back into an instagram account..? I stupidly lost the account password. I would appreciate any assistance you can offer me!
@jacksoncayson92423 жыл бұрын
@Romeo Harold Instablaster =)
@romeoharold21833 жыл бұрын
@Jackson Cayson Thanks so much for your reply. I got to the site through google and im in the hacking process atm. Looks like it's gonna take a while so I will get back to you later with my results.
@romeoharold21833 жыл бұрын
@Jackson Cayson it did the trick and I finally got access to my account again. I am so happy! Thank you so much you saved my ass !
@jacksoncayson92423 жыл бұрын
@Romeo Harold happy to help xD
@intrograted7926 жыл бұрын
I just watched you're first attempt at this and felt for you. I'm so pleased you had another crack at it. Thank-you.
@vincentmutale45627 жыл бұрын
I salute u professor. u are a great professor
@krzysztofciuba2712 жыл бұрын
At 35:52 -"I am confused" and yes, he really messed it up contra original B. Russell's intention in the article!
@whitb62Ай бұрын
If anyone watched this like I did (multiple times) and is still confused, check out the “absolute philosophy” channel. His video on Russell’s “On Denoting” is excellent and he actually goes over the formal logic involved which is necessary to understand this.
@NousProductions6 жыл бұрын
I'm glad he finally erased that partial A on the chalkboard at 33:00 into the lecture.
@repubblesmcglonky89902 жыл бұрын
It's the case that every time he says "everything is awesome" is that everything is awesome
@JakeBarnwell-s8j6 ай бұрын
Stop playing the metaphysician. Wanna see my theorem?
@lola0u4 жыл бұрын
This is an amazing lecture! I want to study more philosophy now😀
@hemalatayaddanapudi7564 Жыл бұрын
Audio is having lor of background noise and disturbance, voice is also not clear
@sebastianuys4253 жыл бұрын
At minute 44, is there not in some sense an analogical relationship between "always" and "everything"
@pengefikseret3 жыл бұрын
That 'its not unnecessary' joke was pretty spot on! Or better: It is not the case that the 'its not unnecessary' joke was not spot on
@Eitankahane4 жыл бұрын
Great teacher! Thanks for the video
@ThePeaceableKingdom7 жыл бұрын
Enjoying your lectures. This is no. 4, I presume?...
@MrFranganito7 жыл бұрын
I think this is the fifth, there's another one on Frege ( "Frege on Thought") uploaded the same day as this one.
@robertstevens12874 жыл бұрын
I've grown acquainted to your face... Your well denoted English face... lol
@renehernandeza.73094 жыл бұрын
Nice! I red the paper, but I missed some stuff.
@markuslepisto78242 жыл бұрын
How can you see the king out of a man?
@DanteHaroun Жыл бұрын
god those students are pretty dim poor guy
@m_monemy5 жыл бұрын
well i think C(nothing) means: "(∀x)¬(x is awesome)"; the student has turned you in a totally wrong way of giving a description of the quantifier: "(∀x)¬¬(x is awesome)" is completely another thing and it's equivalent to the first assertion.
@clockfixer50494 жыл бұрын
Here's the thing, the prof. had to lay down a proposition 'Nothing is not awesome', not 'C(nothing)' by itself which would be exactly what you wrote. In Russel's terminology " 'C(nothing)'means " 'C(nothing) is always false' is always true". And if we abstract from defining 'nothing' by itself, we merely use the language of logic which will even out two negations into one positive proposition. Hope I was clear. محمد صدرا منعمی نودهی