Physical Pendulum Problems - Moment of Inertia - Physics

[@TheOrganicChemistryTutor]

Full Video - The Simple Pendulum: www.patreon.com/MathScienceTutor Direct Link to The Full Video: bit.ly/3GEctFc More Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html Physics Final Exam Review: bit.ly/3YZgrQl

[@gp7493]

When I get into the work field as an engineer, I'm paying your patreon hella

[@jagoayomikun2304]

Hell sire, I really appreciate your efforts.. Ur videos helped me to an A in my last semester physics course. I was the best in my class. This semester I have oscillations in my outline which includes simple harmonic motion, physical pendulum, simple pendulum, I've seen those video's and picked up important points. But I wud appreciate if you could make videos on forced oscillations and damped harmonic motion,which I can't seem to find. I would also like you to recommend a good textbook for me.. Tanks in advance sire..

[@canadianhaitian]

This is great I wish my professor would tell us where to get these formulas?! Now that I know I= 1/3 ml it’s easier to plug in

[@Bluebabykitten]

Watch his 2 hour video of simple harmonic motion

[@Yourlocaljp]

Search 'Inertia Moment of Common Bodies' in image search. Sadly in my class I have to memorize them for NO justifiable reason...

[@Bluebabykitten]

+Yourlocaljp same engineering physics

[@mikaelafrias7786]

Hello, is it mgd or mgl for the equation at 2:17? Like are they both correct for me to use?

[@engr.rimarc.liguan1795]

mgd

[@emmanulluakila4302]

I do not know how many times this dude saved my life. thanks

[@ibsangonzalez7351]

@The Organic Chemistry Tutor whats the inertia when the axis of rotation is not at the end of the rod?

[@tamimrahman9749]

Thank you very much.Thanks a lot ♥♥♥

[@shokhrukhmirzozokirov104]

Very nice explonation, thank u so much

[@abdulrakeebalsarori8171]

Brilliant! Thanks a million

[@cialatr]

Excellent video! Thank you! :)

[@iridianramos9083]

Hi! I have a question. I'm doing an experiment based on this showing how the moment of inertia changes based on different distributions of mass. This relationship can be demonstrated by shortening the string length of a simple pendulum and measuring the velocity at the bottom of its swing for each string length. However, I'm confused on why my experimental velocities are all different from each other. I was told this would work by my physics teacher, but I'm confused. If the height to which I'm raising the pendulum doesn't change for each string length and therefore, neither does the potential energy then neither should the kinetic energy for each new string length. But all of my velocities are different. I know the angular velocity should be different but I'm finding the time taken to swing at the bottom of the pendulum (then used to find the velocity and then the angular velocity) changes when it shouldn't. Essentially, experimentally the velocity at the bottom of its swing changes between different string lengths indicating changes in angular velocities but theoretically, the velocity shouldn't change and only the angular velocity should. What is the theory behind these theoretical and experimental differences?

[@PatL_13]

THANK YOU SO MUCH 😘

[@quahntasy]

This video really helped. But I was wondering why the channel name is Chemistry Tutor when this is physics.

[@kriztylkatemacalisang3526]

Thank you so muuuuuch!!!

[@akashtandon3527]

what happens if the axis of rotation passes through the centre of mass?

[@akxyn5010]

T is ∞ It means, it's never gng to oscillate

[@akxyn5010]

Because of 2 reasons 1) denominator becomes 0 2) There is no torque to cause rotation as distance between the perpendicular force and point of rotation is 0 Hence rxF = 0

[@prashanthseethapettai5347]

Thank you!

[@Pedritox0953]

Very complete problem

[@nic741]

1/3ML^2 is the moment of inertia of a rod of length 2l hence isnt L=1.5/2?

[@engr.rimarc.liguan1795]

d is the location of the center of the rod

[@mashanatanzon557]

Hi! If I have a physical pendulum where I vary the height at which I apply the mass on the rod does the same formula work? Thank you.

[@Troeltsch7873]

But a practical moment of inertia is a sum that could hardly get finished and also this youtube formula appears to fit a rod of negligible radius. You can tell from a Serway schoolbook that a FAT rod is going to deserve another formula and if you are also going to attach a big disk to it somewhere then the formula for that is going to be a sum that has both your rod and also your disk in it. Maybe the formulas for making a grandfather clock are up here on the internet somewhere?

[@celestialrainstorm]

If d is the distance from the center of mass then if i drill a hole in between the pivot shown in the first problem and the center of mass then the distance would be 1/4 L and if i start pivoting from there then the period should be greater since d is smaller right?

[@Hongkhamphoumy]

May I want to help you

[@gregschraiber4224]

Does anything in the formulas change if I'm dealing in imperial units (Lbs, inches) ?

[@alphajim9405]

Yes…. Just convert those units to metric

[@Troeltsch7873]

Yes imperial units seem to work just as well in the particular case. Your unit of mass is not going to make any difference but if standard gravity is going to be feet per second per second then your pendulum length must be made out of feet and not inches.

[@duncanram]

A conical pendulum consists of a uniform straight bar (L) long and of mass (M), with a bob of mass (m) at its lower end. it rotates at (N rev/min) about a vertical axis through the upper end of the bar. How would you find the radius of rotation of mass (m)

[@planeloverpilot4802]

radius will be length × cos theta with the horizontal.. its basically the horizontal component of length

[@siphelelenene3359]

what if we are given compound pendulum say, 10 oscilltions in time of 95secs and we are ask to find moment of inertia

[@michaelcharif5818]

I think the moment of inertia of a rod is (1/12)mL^2 not 1/3. Could you please double check this because it's kind of confuesing... other wise nice explanation , tnx

[@tabularasa6581]

It's 1/12 when the axis is in the middle of the rod, and it's 1/3 when the axis is at one end

[@feeargodpz65]

In my school it's I/mgh haha i was a little confused until i realized it, yay slow learner me 😔👍

[@ibsangonzalez7351]

Whats the inertia when the axis of rotation isnt at the end of the rod?

[@tonibalogun4897]

You can use parallel axis theorem to get that

[@sulafamohammad5526]

Does anyone know what is the relationship between the length an period in physical pendulum???!

[@Troeltsch7873]

If you leave out the physical part of it then some pendulum lengths are listed in a book of Physical and Mathematical tables from Yarwood and Castle. Over there you see, that, for example, apparent gravity at Rome is about 9.80347 meters per second square and over there the length of a one second pendulum is about .99329 meters. That is an impractical pendulum, since, so far, the massive part of it has a negligible size and the longer part of it has a negligible mass. Also such a one second pendulum has a period of two seconds and it takes one second to go from one extreme to the other.

[@masseyway5261]

Can someone confirm that 'd' = L/2. It's making me feel weird

[@SpookyRumi]

I dont understand why the block doesn't measure anything, it makes no sense..

[@komandodouane2193]

please i am facing difficulties to become a member in your channel

[@julianaloisetudlong9095]

What if there is no given mass in the problem??

[@Troeltsch7873]

Since you are dividing the moment of inertia by the mass of the pendulum it doesn't make any difference however massive it is and you may as well leave the mass of it entirely out of it. Apart from any consideration for air resistance the one and a half meter long rod should have the same period (at small angular displacements) regardless whether it weights a gram or a ton or anywhere in between.

[@westhompson3573]

big clutch

[@fanadeynbataoil8362]

How did you get the 1/3

[@mz2neat411]

ily

[@yonasmeshesha3023]

Pluuuuuuuuuugggggg

[@adrienm2012]

The ad was long asf

[@jimdarrenacojedo4561]

k

[@impanthering]

i hate this class

[@fanadeynbataoil8362]

How did you get the 1/3

[@diegoarpino2080]

If youre talking about the part at 0:39, that is the formula for the moment of inertia of a rod rotating at its end. Hope this makes sense. Best of luck