Because of your videos, I feel 100 times more confident going into my Physics exam today! Thanks so much!
@TheWhiskeyZone10 жыл бұрын
my left ear learned a lot today
@charlieGEE229410 жыл бұрын
lmao
@MiXDuDeZzTvSubhanZainBilal6 жыл бұрын
lmfaooooo
@TarousDT5 жыл бұрын
Holy shit I laughed so hard
@ignaciovega4465 жыл бұрын
I was wondering why I couldn’t hear it. Thanks!
@yufengyoung55315 жыл бұрын
ooh,I thought there is something wrong with my airpods...
@MichelvanBiezen10 жыл бұрын
Anne To find the horizontal force on the hinge, you must sum all the forces in the x-direction. Therefore Fx = T cos (30 degrees) To find the vertical force at the hinge, you must use the sum of the torques with the pivot point at the right end of the horizontal beam.
@piusksuh10 жыл бұрын
Sir do you have lectures on calculus 3...multi variables
@MichelvanBiezen10 жыл бұрын
Pius Suh Pius, Only a few so far. More will be coming later this year.
@WebGuy10008 жыл бұрын
Bent jij toevallig Nederlands? Bij de naam van je kanaal is een Nederlands lijkende naam te zien.
@MichelvanBiezen8 жыл бұрын
Tijdens mijn jeugd woonde ik in Antwerpen
@anilsharma-ev2my4 жыл бұрын
By using this relationship can we make an easy-to-use hand pumping system for hand pump Now we have to make much effort to pullout the water from Borewell ?
@PilotW652 жыл бұрын
Hi Michael, been taking physics since grade 11 (I'm 25 now and am in first year engineering, sad I know) and for the first time I actually am feeling like I got what it takes to get good at this. I try to do these problems by myself before watching through and thanks to your excellent teaching methods I am finding at least half of the time I am on the right track... much better than before!
@MichelvanBiezen2 жыл бұрын
Don't worry about the "late" start on your engineering studies. (I didn't complete my bachelor degree until I was 27 years old, before I started graduate school). Life happens and we have to live it as it comes. We are glad the videos are helpful.
@PilotW652 жыл бұрын
@@MichelvanBiezen yeah I wound up working trades for five-ish years before I decided I wanted to be an engineer, I didn't try my best in high school so I had to upgrade practically all my grade 12 credits to even qualify. But now that I'm here I don't wanna give up! Happy to report that I did pass my Physics Mechanics course, I imagine you're a big part of that! So thank you for your encouragement, here's hoping Waves and Fields will go well.
@Travisw1359 жыл бұрын
As a physics student, I just wanted to say thanks for all your videos! Even if they are not exactly what I'm looking for, they are quick and to the point which is perfect and helps me solve the problem at hand! Thanks again!
@chichiokoro163911 жыл бұрын
You are born to teach. Thank you for the videos.
@MichelvanBiezen11 жыл бұрын
Stephy, Thank you for your input. Much appreciated.
@cryptid19255 жыл бұрын
@@MichelvanBiezen haha. You reminded me of Sherlock's "yes Anderson, thanks for you input"
@raena35326 жыл бұрын
I cannot thank you enough. You are by far the greatest teacher EVER
@heathertruelove7575 жыл бұрын
Thank You for simplifying it and writing out the equations step by step. I've really been struggling with this but you are an excellent teacher and have helped me so much!
@MichelvanBiezen5 жыл бұрын
We are glad to be able to help. Thanks for writing.
@Rose-yt7qp7 жыл бұрын
Bless your brain and your ability to teach. Literally, your videos are the only reason I'm passing physics 1 lol
@meganmurphy64597 жыл бұрын
You taught me in 8 and a half minutes what I've been struggling for weeks to understand. Thank you, thank you, thank you!
@ariakim18685 жыл бұрын
WOW this is amazing!! Thank you so much! You made this so simple!!! I wish all physics professors taught like you everything makes sense now !! Subscribed :)
@MichelvanBiezen10 жыл бұрын
Nick. Great! Thanks for sharing and good luck on your exam!
@matthewyoungsoonam8 жыл бұрын
Thank you so much!! I was able to cram 12 chapters of physics in 3 days and get an A on the final by watching your videos.
@MichelvanBiezen8 жыл бұрын
Congraduation!!! You still had to do the work.
@tsoojbaterdeneharvard31874 жыл бұрын
I have heard that you are the best teacher in the world.My grattitude toward you is immeasurable.Thank you very much😍😀🤗 Young forever 2022🙏🙏
@MichelvanBiezen4 жыл бұрын
There are many great teachers in the world. I hope to be one of them. Thank you for the comment
@MichelvanBiezen10 жыл бұрын
Nick, Good luck with your exam.
@blackjack-ks8zn5 жыл бұрын
You are a dedicated teacher....
@danielsebola42389 жыл бұрын
Wow!, thank you so much, your explanation is so straight forward and understandable, you're super cool. My prof never explain where he got anything that he writes, he just flows while we are not flowing with him.thank you so much!!!!!!
@megtakara25913 жыл бұрын
why did i learn more from this 8 min video than a week of lectures
@thabisombingo96492 жыл бұрын
Shout out to this channel you do proper examples
@MichelvanBiezen2 жыл бұрын
Thank you. Glad you find these useful.
@joeyGalileoHotto6 жыл бұрын
Static Equilibrium is frustrating because of the idea to relate Transnational Forces to Rotational Forces in an equilibrium system.
@GursimranBedi10 жыл бұрын
I have a physics test tomorrow and this helped me so much! Thanks :D
@rorymax3 жыл бұрын
damn 6 year difference but im in the same boat
@Anya-ef5gj9 жыл бұрын
I'm studying for my AP physics torque quiz and this helped so much. You are a really great teacher
@122KingTulip4 жыл бұрын
Same
@LouieMcConnell269 жыл бұрын
I GET IT! Finally, I see how it is nothing more than vector decomposition! Thank you!
@juanelias945311 жыл бұрын
Thanks Mr. Michel, I learned it much easier from you than my professor.
@muhammadosama83086 жыл бұрын
Thanks alot even tough you made this video long time ago.I was struggling to understand the concept and thanks to you i am able to solve my questions.
@kohisnegere49357 жыл бұрын
your are the best teacher ever!..thank you sir...
@krishnasivakumar24796 жыл бұрын
You just made the concept really simple, thanks.
@shawnrusselld8 жыл бұрын
You did such an excellent job of explaining this
@Camillelele697 жыл бұрын
youre the best ever! i understood everything completely :D
@walbani8 жыл бұрын
First of all: thank you. But I have to point out Two important things. The teacher drew (min. 0:50) the pivot...well. But he explained us that putting this pivot he eliminates the two unknown forces (reactions X and Y). Sorry it only eliminates another torque. The reactions stay or remain. Please just note that this force doesn't (or pair of forces Rx and Ry don't) produce moment or torque because its line of action passes through the fulcrum or pivot axis. . . Sorry about my English.
@MichelvanBiezen8 жыл бұрын
+walbani Very good point. I meant to say that it eliminated those two forces from CONTRIBUTING to the total torque.
@walbani8 жыл бұрын
O. K. thank you for your answer. I've been studied your videos. Thank you again.
@lemniskate_ayd5 жыл бұрын
Thank you very much for this video! I’m french so I’m training static and English at the same time ;) the perfect deal
@MichelvanBiezen5 жыл бұрын
C'est mon plaisir. Welcome to the channel.
@radiahmad72357 жыл бұрын
يسعد قلبك يا زلمة ❤️❤️ Big Respect ❤️❤️
@mahmoudelrefaey41956 жыл бұрын
kos
@1pierreandremercier9 жыл бұрын
very good explanation
@muxaffarally90427 жыл бұрын
stay blessed ....u r such a wonderfull teacher!!!!
@polarchips6 жыл бұрын
Alright I'm one step closer to passing PHYS 106. Thanks!
@jameserayburn10 жыл бұрын
That was an awesome example of how to find torque.
@samerrihani30517 жыл бұрын
At 3:41, you mention how turning clockwise gives you a positive torque, but using the Right hand rule, doesn't it state that a positive torque comes from Counterclockwise rotation giving you a negative value rather than positive?
@MichelvanBiezen7 жыл бұрын
If you consider them as vector quantities then yes.
@David-vo6wr5 жыл бұрын
I have my first year physics final tomorrow. Because of these videos I'm going to pass. Thank you
@MichelvanBiezen5 жыл бұрын
Good luck on your final
@jackiehall67599 жыл бұрын
This video made everything so clear! Thank you!
@pondoyobrigittemyrrhs.32552 жыл бұрын
Thank you so sir.. this is so helpful ❤️ have a good life❤️
@MichelvanBiezen2 жыл бұрын
Thank you. Glad you find these videos helpful.
@FreQuese8 жыл бұрын
This is so useful and helpful for my final tomorrow! Thank you so much.
@gokublack90803 жыл бұрын
how did it go
@FreQuese3 жыл бұрын
@@gokublack9080 if i remember four years ago, it went decent lol. this material was on the test and i was able to get it right, but i suck at physics. thank god i dont have to use it for my job
@sayedaulia2 жыл бұрын
Your video has been very helpful to me, by the way, can you make a series that involves a the dynamic of a rotating rod?
@MichelvanBiezen2 жыл бұрын
Since we plan on filming today, we will add this if we get a chance. It will be some more days after that to make it through production.
@dylanthornsberry87786 жыл бұрын
Legend. So Helpful
@frankrobinson76486 жыл бұрын
There are 4 forces acting on the beam (not 3 as stated). Weight of beam, weight at end, tension and normal force at hinge.
@nicholusopincaijercilio67534 жыл бұрын
Im learning a lot from the videos
@genieyas51865 жыл бұрын
i m frommorocco, my english is not good, but i learned that before applaying static equlibrium we must extact our system.
@laboratory-ob5np7 жыл бұрын
thank you sooo much for this video!!!! i was so lost in physics and now i finally know what's going on lol...
@jasonbirch11825 жыл бұрын
What if the beam is not level and the big force is actually on a ramp connected to the end of the beam? I have a bus with a foldimg rear door(5ft.) that is part of the ramp. The ramp extends another 7 ft to the ground. The pivot is 40" high. The door would need to be lowered to 25" to make the ramp accessible to the car, then lifted once the car is pulled into the ramp to straighten the door and ramp combination.
@reverie96573 жыл бұрын
in the beginning of the video, is it possible for the stick to stay in balence if there is no string to support it? and lets say that the stick is fixed to the wall
@MichelvanBiezen3 жыл бұрын
We can make the assumption that the vertical pole is anchored to the ground.
@halladaas99154 жыл бұрын
What if (for the CCW moment), we multiplied the component of T (Tcos30) with the perp distance (Tsin30 OR 4tan30)? I tried but I got a different answer and I do not know whether it's due to a calculation error or a logical error. Could you help me verify the kind of the error by double-checking my method?
@theprofessor25803 жыл бұрын
for correction (+) counterclockwise (-) clockwise
@MichelvanBiezen3 жыл бұрын
Yes, when used as vectors you are correct.
@celinekisimba44936 жыл бұрын
This video is so helpful! Thank you so much
@raghurajtawargeri35023 жыл бұрын
What is material and diameter of cable to withstand the tension, also length and height of the wall and mounting of the cable is going to matter in the above example
@MichelvanBiezen3 жыл бұрын
Those concepts are explained in a different playlist. Here we are only considerting the concept of torque
@raghurajtawargeri35023 жыл бұрын
@@MichelvanBiezen Will you please me the concerned link
@xxuexx9 жыл бұрын
Wow, you are such a great teacher! You put this wayyy better than my professor. Are you a Professor at a University? Because you should be!! Saw your Cal videos and your Physics tutorials are great as well, so far the best on KZbin in breaking down these concepts. Very clear and straightforward. Do you do Chemistry tutorials as well?
@MichelvanBiezen9 жыл бұрын
shawawong Thank you for the compliment. Yes we also have chemistry and astronomy videos.
@estebanlopez17014 жыл бұрын
I wonder why you did not consider the horizontal force at the joint of the cable with the wall
@jamescorbitt47678 жыл бұрын
Awesome Videos! You are a Physics lifesaver! THANK YOU SO MUCH
@JenAnistonfan18 жыл бұрын
Sounds like I'm taking a physics class from Michael Scott... awesome!
@raikiri62517 жыл бұрын
You rock man! I never thought I would understand this :-). Thankyou!! a lot!
@kslidzorous9 жыл бұрын
anyone else only hear sound from left side?
@MichelvanBiezen9 жыл бұрын
+kslidzorous We had sound problems with our early videos.
@hyunseongpark73306 жыл бұрын
That must be 2 Channel or more. U can set 1 channel therefore sounds will come out from any speaker
@lpsoldier86277 жыл бұрын
sir, did i mension you are awesome!!!
@RMTube8 жыл бұрын
u r a great teacher ..i wish to study with u for real
@genieyas51865 жыл бұрын
could you pls distinguish between the tow cases: calculating resultant and applaying static equilibruim.
@donreynolds52336 жыл бұрын
thanks for the concise explanation, very helpful
@TrueArmenianBoss12345 жыл бұрын
Quick question: can we just draw the d3 along the bar? The only component of tension that causes torque is the y component anyway, and this component is normal to the bar. I find it easier to conceptualize this way.
@MichelvanBiezen5 жыл бұрын
There are multiple ways to approach this problem.
@georgesadler78303 жыл бұрын
Professor Biezen, these lecture are fantastic, however what point did you take the torque about?
@MichelvanBiezen3 жыл бұрын
The point about which we find the torque is where the horizontal beam is connected to the vertical post.
@soreachsang924410 жыл бұрын
Thank You!!! Thank You!!! Thank You!!! Thank You!!! Thank You!!! Thank You!!! Thank You!!! Thank You!!! Thank You!!! Thank You!!! I'm very appreciate for you time!!!
@aizawa22224 жыл бұрын
Hello, I wanted to know why we don't consider any y forces, X forces, or torque from the supporting cube touching the ground. It seems to make sense to me that the whole structure would topple over if there are no forces? Thanks
@MichelvanBiezen4 жыл бұрын
There are x and y forces where the post in embedded in the ground, but those forces would not add torque, since the distance from the point of rotation are considered "zero".
@thehaytch9 жыл бұрын
Thanks for a great video. Your explanation was easy to follow and replicate. Also using an example that is real helped as well We have a couple of swing arm tool balances at work, I am going to do some calcs tomorrow...
@themilkman71273 жыл бұрын
Thanks I really struggle with these exact types of problems
@gwynethstephens31337 жыл бұрын
Please explain d3. Making d3 to the centre of the cable? Where there's no contact at all? Not clear. Thanks.
@MichelvanBiezen7 жыл бұрын
By definition, the moment arm has to be the perpendicular distance from the point of rotation to the line of action of the force.
@utkarshnanivadekar39907 жыл бұрын
this video helped me a lot .thanx sir
@JovialJolaChip3 ай бұрын
Why was the tension in the string to which m was hung not included in the equation?
@Nasiersoulo7 жыл бұрын
WOW THIS NOW SEEMED EASY THANKS
@petervermilyea64905 жыл бұрын
Thanks! You are a great teacher!!!!
@genieyas51865 жыл бұрын
I think to be clear, you chould say: We extract the beam and we will make static equlibrium of it. so we konw wha is interior to the system and what is exterior. what do you think about this.
@ryanbutton87188 жыл бұрын
I solved this problem using the vertical projection of T multipied by d1 as the torque as the horizontal component of T is pointing along the beam and seems to not contribute to the torque of the beam and got a different answer? Could you please clear up how the tension force is acting at distance of d3? How would this make sense in terms of vectors?
@howtodo24479 жыл бұрын
how to assume the forces direction acting on the pin ,thanks
@parthraut17865 жыл бұрын
Sir what's the hinge force at A when it is vertical and horizontal
@jadbazian93368 ай бұрын
Is it not Tcos(theta) since that would be the perpendicular force exerted.
@MichelvanBiezen8 ай бұрын
It depends on the angle used. In this example, since we are using theta, we must use the sin,
@anilsharma-ev2my4 жыл бұрын
Use more contrast by using some filters so more Sharp picture are embossed 🙏🙏🙏🙏👀🕵🕵🕵
@MichelvanBiezen4 жыл бұрын
Yes, our older videos were not as good in several aspects. We have improved upon them over time.
@anilsharma-ev2my4 жыл бұрын
@@MichelvanBiezen it's so simple You just use a video software and all your video are become Sharp in a month or two
@dicksononyango18127 жыл бұрын
Can the tension on the cable be resolved in the vertical direction then use the resolved force in calculating the torque about the same point you chose? Thank you.
@MichelvanBiezen7 жыл бұрын
If you are asking if we can use the components of the tension to find the torque, the answer is yes. Give it a try and see if you get the same answer (best way to check).
@lukeorlando44397 жыл бұрын
why did you draw d3 from the pivot to the center of the cable? Isnt it acting on the end of the beam? why wouldnt d3 just equal d1?
@MichelvanBiezen7 жыл бұрын
By definition, d3 is the perpendicular distance from the line of action of the tension to the point of rotation (pivot point). It is drawn correctly.
@stevenlee24328 жыл бұрын
Learn a lot from this video. Thx for guiding! xD
@alisaguadarroma8296 жыл бұрын
thank god for you
@Beanzybeez7 жыл бұрын
My professor did a similar problem to this one and he multiplied the w(L/2) + Wload(L)/ Sin theta and the result was a smaller value. I'm really confused as to when to use length and when not to.
@MichelvanBiezen7 жыл бұрын
What was the factor he multiplied the equation with and what was the equation?
@ivanchristopherrizo17435 жыл бұрын
I believe that it should be positive when the direction is counterclockwise and negative when clockwise? I think what he is saying is the opposite
@MichelvanBiezen5 жыл бұрын
It doesn't matter unless you consider them to be vector quantities.
@MAliK-ox2lz6 жыл бұрын
In previous video you said clockwise is the negative direction, why you chose the directions reverse ?
@MichelvanBiezen6 жыл бұрын
Unless we consider these as vectors, the direction is not important if we remain consistent. However due to the possible confusion, I tend to hold to the vector definition of positive and negative in more current videos.
@MAliK-ox2lz6 жыл бұрын
@@MichelvanBiezen the best teacher in the world ☺ thank youu
@wozzere17 жыл бұрын
warren leighfieldThanks for the video . How would you do a sdf and a bmd for this . Any help would be much appreciated
@MichelvanBiezen7 жыл бұрын
sdf = ? bmd = ?
@James-gg8xb5 жыл бұрын
why was it multiplied by 9.8?
@MichelvanBiezen5 жыл бұрын
Because you need to calculate the weight. w = mg
@diatribeeverything7 жыл бұрын
I love all your videos, but can you tell me why "d3" was really necessary? Isn't everything just acting at the full radial length or at half the radial length? I understand the need for the angle (sin 30), but couldn't all the torques just be set up quicker/easier as +mgr +MGr/2 and -Trsinϴ from the FBD without d3 since the cable provides torque at the full radial distance anyway?
@MichelvanBiezen7 жыл бұрын
Yes, you can do it that way. The use of d1, d2, and d3 is to make it easier to initially get the concept and set up the initial equation correctly.
@diatribeeverything7 жыл бұрын
Thanks for the prompt reply! Keep up the good work!
@hyunseongpark73306 жыл бұрын
Is it better to put values in each d1 d2 d3 if i have d1 d2 d3 value? Not changing into cos sin
@tworks24346 жыл бұрын
Why do you not account for the Torque at the base of the structure?
@MichelvanBiezen6 жыл бұрын
That toque does not affect the beam.
@andrei6429 жыл бұрын
GOOD JOB PROFESSOR
@Peter_19869 жыл бұрын
I always thought that defining positive rotation to be clockwise seemed more logical and intuitive - after all, that's the "natural" rotation since the sun rotates that way, and we tend to stick to positive values as much as possible since most people prefer positive values.
@MichelvanBiezen9 жыл бұрын
+Laurelindo It only matters when when computing vector products, then the direction of the torque matters and should be taken to be positive in the counter-clockwise direction. Otherwise it doesn't matter as long as you stay consistent.
@SofiaSkywalker6 жыл бұрын
This was great, thanks!
@howtox-plane8852 Жыл бұрын
OMG THANKYOU SO MUCH I ACTUALLY UNDERSTAND AHHHH
@MichelvanBiezen Жыл бұрын
Great! Glad you found our videos. 🙂
@mscourt10110 жыл бұрын
Awesome! thanks so much! this was very clear and I learned a lot.
@marcochimio3 жыл бұрын
Wonderful presentation. QUESTION: Why is the CONVENTION to calculate the length-perpendicular (i.e., L x sin of theta) and multiply by the applied force RATHER THAN calculate the perpendicular force component (i.e., F x sin of theta) and multiply by the full length at the point of application of the force? Is there something inherently wrong with this mode of thinking? Are there exceptional problems where this way will NOT work in a torque problem? I ask because it is so much easier for me to conceptualize decomposing forces into orthogonal component vectors instead of doing that to a LENGTH vector at the point of action.
@MichelvanBiezen3 жыл бұрын
Both methods are perfectly fine. We have videos showing both methods.
@marcochimio3 жыл бұрын
@@MichelvanBiezen Excellent. Thanks. Can you tell me why most presentations (not just yours) use the length-perpendicular method rather than the force-perpendicular method. It seems to quite prevalent, but I'm having a hard time understanding why. It just seems more intuitive to use the force-perpendicular perspective.
@MichelvanBiezen3 жыл бұрын
It becomes a matter of personal preference, no method is better than the other.
@marcochimio3 жыл бұрын
@@MichelvanBiezen Thanks again. I don’t mean to beat a dead horse, but I’m trying to understand why the vast majority of physics instructors seem to take the route you took, while I find the force method much more intuitive. Why do you personally prefer breaking down the length term instead?
@ShirishChavan3335 жыл бұрын
Excellent.
@arnurmakenov43508 жыл бұрын
Dear, why the center of mass of rod is at its center? We also have mass at right side thus CM shall be to the right...
@MichelvanBiezen8 жыл бұрын
Each mass is taken separately. Thus the center of mass of the beam is at the center.