Physics, Torque (11 of 13) Static Equilibrium, Hanging Sign No. 5

Shows how to use static equilibrium to determine the tension in the cable supporting a hanging sign and the force on the beam from the hinge. The sum of the forces in the x-direction, the sum of the forces in the y-direction and the sum of the torque are set equal to zero.
Torque is a rotating force. It is a measure of how much force is acting on an object that causes the object to rotate. The object will rotate about an axis, which is called the pivot point. It is labeled with the letter P or O. The distance from the pivot point to the point where the force acts is called the moment arm or the lever arm. This distance is labeled with the letter r. This distance r is also a vector, and points from the axis of rotation to the point where the force acts. The force is labeled with the letter F.
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[@danzul1849]

My lecturer suggested two of your videos for our upcoming quiz ! She said the video was very comprehensible as well as my class, good job !

[@stepbystepscience]

Awesome, tell her I said thanks and thank you for watching and commenting.

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[@stepbystepscience]

Thanks for the great comment and that is a good combination. You can see a listing of all my videos at my website, www.stepbystepscience.com

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Good stuff. You are one of the few people who use printed notes as opposed to handwritten notes successfully. thanks!

[@stepbystepscience]

Thanks for the comment, It takes a while to put them together, space is usually and issue. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@Northumbriaosrs]

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[@stepbystepscience]

There are several steps to get through. Hope you get it figured out.

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[@stepbystepscience]

Happy to help and best wishes for your full recovery!

[@SamvitAgarwal]

Hey, great video! Can you please explain how you know the direction of the force from the hinge though? Is there any intuitive way to figure that out?

[@vismutti1656]

If anyone is struggling with this one, I think it's a combination of normal force since the shelf doesn't go through the wall and some upward force supporting the shelf on that end/frictional force since 2 surfaces are touching

[@luigianchondo7241]

I suck at physics and struggle with physics class, until I took engineering mechanics class (statics and dynamics combined). After going back to this video, I used the engineering mechanics method instead of traditional physics method and my answers match yours. I’m glad that I understand this topic now

[@stepbystepscience]

I'm glad too!

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[@stepbystepscience]

Thanks for taking the time to let me know that my videos have helped you. I wish you all the best in your studies.

[@abebesamuel8931]

Thank you, sir. A thorough explanation.

[@stepbystepscience]

So nice of you, thanks for your comment

[@BruceWayne-us3kw]

this torque stuff is killing me. I'm glad I came across this channel.

[@stepbystepscience]

Glad you found me!

[@Flynn1411]

Thanks for the review!!! I have a physics final tomorrow and I needed to review this!!!

[@stepbystepscience]

You are very welcome, hope the final goes/went well.

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Thank you very much for the lesson. With the current pandemic, I'm forced to self-study and this is really helpful!

[@stepbystepscience]

The pandemic has motivated me to keep making videos. Thanks for your comment.

[@Shackled]

Excellent. Def need to go over episode 10-13 again to make sur eI have this foundation down. Thank you!

[@stepbystepscience]

Please do! And thanks for the great comment.

[@christopherthomas7262]

This really helped me understand. Just wanted to say you put the forces of tension as force of tension times cos(35) for both of them. But I still understood it so all good. Thanks.

[@stepbystepscience]

I'll check that, thanks!

[@G109938]

Thank You! The step by step was really helpful.

[@stepbystepscience]

Thanks for watching and commenting.

[@kylebinondo5251]

Thanks to this video it really helps me a lot!

[@stepbystepscience]

You're welcome. Glad to hear that!

[@KJKP]

Note for newbies: At 3:20, when he says the forces do not create a moment "because they are at 90 degree", he could have been more descriptive to say that those two vectors pass through the chosen center of rotation (the hinge.) This basically means the distance part of F*d is zero, and the moment is therefore also zero. This is why you want to chose a point of rotation strategically so that more components zero out. Peace.

[@samanthalora3453]

you explained this better than my professor…thank you

[@stepbystepscience]

Glad to hear that, my pleasure!

[@ordinarythings9864]

This really helped. AP Physics test today!

[@stepbystepscience]

Hope it went well!

[@franciscorosario2709]

Great explanation; I wasn't getting this, but this video explained it all very well. Thanks!

[@stepbystepscience]

You are very welcome and thanks for commenting.

[@Kennamorphosis]

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[@stepbystepscience]

Happy to be help out. You can see a listing of all my videos at my website, www.stepbystepscience.com

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[@sandovstv6515]

How do you know that the value of angle from FT and FTy is 35 also ? when the FTx and FTy is Perpendicular that should be 90 , and the angle between FTx and FT is 35, and the angle between FT and FTY is 35 also ? or the angle between FT and FTy should be 55 ? pls enlighten me ?

[@eugenechoi9146]

Why is the force of the hinge pointed diagonally?

[@samuelkelly3863]

Brilliant video, very easy to understand and follow!

[@stitchwitch70]

This was incredibly helpful - thank you very much!

[@stepbystepscience]

You're very welcome!

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[@stepbystepscience]

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[@stepbystepscience]

I'm so glad the video was helpful. Thanks for your comment.

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[@stepbystepscience]

Glad it was helpful and thanks for the positive comment.

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may god bless you soul IM BEYOND THANKFUL

[@stepbystepscience]

You are very welcome and thanks for commenting.

[@polarbearanne]

I don't know who you are or why you made this video, but I'd like to thank you! I really needed this breakdown of the forces to understand this concept. Also I like your notation a lot better than my textbook's. In my textbook instead of Fhy, they had Fv. I was staring at it at least 15 minutes just thinking WTH is Fv!?! THANK YOU!!

[@stepbystepscience]

+polarbearanne You are very welcome. I am just a teacher trying to help others be successful in school. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@paulinjosepha2336]

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[@stepbystepscience]

It's my pleasure and thank for commenting.

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Learned more in 11 minutes than I have in 3 weeks

[@stepbystepscience]

Glad you're learning, thanks for watching!

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Lmao same my physics teachers fucking shit

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Best professor!!!

[@stepbystepscience]

Best comment, thanks.

[@GuruR97]

This video is amazing. Thank you. Taught me in 10 min what my physics teacher couldn't do in a week. However, I did notice one mistake. Starting from 6:57, you set both FTx and FTy as cos35FT, but FTy is equal to sin35FT.

[@GuruR97]

I just noticed that you noticed this mistake. Annotations don't appear on mobile, so I didn't know. My apologies.

[@stepbystepscience]

+GuruR97 Thanks for the comment. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@jimmyharkin9169]

Helped me a lot, thanks! But please slow down, you already understand how it's solved but the people watching this dont. We need time to absorb the info!

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[@stepbystepscience]

You're welcome!

[@anilsharma-ev2my]

Changes it into gravitational battery by using spring and load swings and yatch types system

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thank you really, thank you

[@stepbystepscience]

My pleasure, thanks for watching!

[@zecchinoroni]

Thank you so much! I have a physics final tomorrow and this helps a lot.

[@stepbystepscience]

+Groovy Satan Hope the final went well, thanks for commenting.

[@zecchinoroni]

@Luckylucc lol no fucking idea. probably ok tho i got A's in all my classes

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Awesome stuff! Thanks, liked and subscribed.

[@stepbystepscience]

Great and thank you very much!

[@davidmojica4520]

I was solving a very similar problem but I got stuck because of this doubt: isn't the hinge supposed to produce an added torque to the system? Therefore, the sum of torque would be: Th+Tty-Tb-Ts=0, where Th is the torque added by the hinge. Could you please explain me why that hinge related torque is not considered in the sum?

[@stepbystepscience]

If I understand your question correctly......if you take the hinge to be the pivot point then the lever arm at that point is zero and therefore the torque would also be zero at that point. Does that help?

[@brunodavide92]

Thank you so much, that was a great lesson. Cheers

[@stepbystepscience]

+brunodavide92 Thank you for the great comment. You can see a listing of all my videos from my website at www.stepbystepscience.com

[@teeclozpt.2483]

thank you very much 😊

[@stepbystepscience]

You're welcome 😊

[@michaelzavala7871]

thank you very much, very helpful

[@farissaamanda2295]

It was indeed very helpful 👍👍

[@StuffWriter]

I would have thought it would have been easier to solve for Tbeam & Tsign as you showed and, then, plug the total of those two into T = rFsinΘ, solving for Fcable. Then, finding the individual components through simple trig.

[@stepbystepscience]

Yes, there is more then one way to solve this problem. I like doing it this way.

[@s_eliza]

Thank you, this was really helpful! My question here though also says to "find the tension in the cable when it has been shortened so that the beam makes an angle of 60 degrees to the horizontal." There's also no hanging mass. Do you know what to do? I'm stuck.

[@ronaldpuran4271]

Thanks for the explanation in this video. Only if you can change from cos to sin of FTy in 6:56 it would be great. Besides this, thanks once again for the video and God Bless.

[@excellinkus]

What would be the tension along the cable and the the beam if the mass of the beam was zero?

[@joshuac9142]

amazing

[@stepbystepscience]

Thank you! Cheers!

[@alexanderconiff8909]

I could kiss you.. thank you for a really helpful video! Saved my life.... you sir have a new subscriber!

[@GodsOfMW2]

at 2:54, don't you mean 0 degrees? Since the tension and hinge force in the x direction are both parallel to the axis of rotation? If it were 90 degrees, i.e perpendicular, then there would be torque no?

[@scrappydoo69]

Thank you

[@stepbystepscience]

Welcome!

[@windthorpe9628]

Why does the x component of the hinge force act away from the wall? Isn't it holding the beam against the wall and should therefore be acting into the wall (be in the negative x direction given your coordinate system)?

[@esthercinzah]

Thank you for your videos, but I have a question regarding FHx - FTx, I can not understand how could FHx be positive direction and FTx be negative direction. because FHx is CW and FTx is CCw.

[@matthewissac7963]

I know i'm a couple years late but at 7:00 shouldn't those torques be measured in Newton Meters, because you end up solving for Fty you end up getting N/m. Regardless thank you so much for this video you did a great job explaining this otherwise convoluted problem.

[@steffanokorafor1543]

I think there's a mistake in your video. At 6:57 you wrote that Fty = cos35Ft when it should be sin, if I'm not mistaken

[@stepbystepscience]

Thank you.

[@tommiecommie6863]

Thanks a lot, but what if the sign is centered on the beam and not off to the side?

[@deeps474]

U are awesomely smart!!! Head off

[@stepbystepscience]

Thanks

[@ali92m]

Many Thanks you are a star

[@tabz6778]

why does the hinge produce a force in that direction (perpendicular to the cable)

[@myaps1859]

I got FTx and FTy using the Component method of Vectors

[@ikevolley5137]

What if there’s no force of sign given with the same problem

[@binyammamo707]

how could we solve the same problem if the sign was hang up on two points of the beam?

[@wozzere1]

warren leighfieldThanks for the video . How would you do a sdf and a bmd for this . Any help would be much appreciated

[@stepbystepscience]

What is sdf and bmd?

[@yarakitty2738]

Excuse me sir, isn’t there any contact force from the beam ?

[@angieazurill]

is there a way to find an estimate of the angle of Fh with no specific known values?

[@user-ul9oj2ni4r]

Hello, thanks for your great video! Great way of teaching. But I have a question does the hinge always exert a force? And if yes how can we tell its direction?

[@stepbystepscience]

No, it could be zero, but if there is a force the angle has to calculated based on the other forces.

[@user-ul9oj2ni4r]

@@stepbystepscience so can we say that the direction of the hinge force is in the same direction that keeps the object in static equilibrium?

[@emmanuelmakubabha5109]

thank you so much

[@Freedomboy006]

way harder.. just do torque total=0.... and use trig to find distance of the rope to the pivot

[@aff4869]

Same opinion , it's still good tho

[@faisal8815]

for the angel. why didn't you use tan^-1(Fy/Fx)? pls help I got confused.

[@fishertech]

Why would the hinge force not be 35 degrees as well?

[@xexpo]

Please use Nm for moments.

[@florencehashaka4339]

If you use Acceleration due to gravity of 9.81, T = 521.4 N and F = 444.5 N

[@michaeldoherty5086]

This is very nicely done and put across extremely well. But I guess your background is in engineering like me, as you have made a few errors regarding intermediate units. We tech types can be sloppy regarding units. (By the way, I fear mechanics, which is why I'm here.). N/m does not equal newtons. The units of torques are newton metres, so if you write the m like that then the forces will cancel to units of N. The maths, the logic, and the result is perfect as well as being a timely bit of tuition for me, but the unit error threw me - for a bit. Having said that, you know your stuff and sure know how to put it across. You can be my tutor any day. Regards, M.

[@michaeldoherty5086]

Oops, if you write the torque (Nm) like that, then the forces will cancel to newtons, N. This is no criticism. I love your instruction and will happily follow you anywhere in mechanics.

[@peace7784]

you can actually solve this problem without the beam lenght since it cancels out in the torque expression.

[@stepbystepscience]

I don't think so.

[@davidxguitar]

Way to go video rocks

[@stepbystepscience]

You are very welcome, thank you very much for watching and commenting.

[@ivyagustin4337]

Where did you get the 9.8 m/s^2?

[@davidstevens9025]

Could please just explain the method of converting your initial tangent value of 0.286 to 16 degrees? The rest was great, Thank you!

[@thehoff37]

You take the inverse tangent of .286 to cancel out the tangent and just be left with theta, the angle.

[@trieudope]

wonderful bruv

[@nurbalqishezlynibrahim5363]

Thank youuuuuu!!!! 💖💘

[@stepbystepscience]

You are very welcome.

[@Shridhar_Thorat]

hey, why is the force from the hinge diagonal; at 1:15 ?

[@stepbystepscience]

Actually at first we really don't know the angle, but it depends on how the cable pulls on the bar.

[@Shridhar_Thorat]

@@stepbystepscience Ahh, I see. Thanks mate :D

[@dawneabdulal-bari9313]

Awesome! Thanks ~ Shared ;->

[@zhenwei4584]

Great

[@stepbystepscience]

Excellent

[@jeffbrigatee9368]

THANK YOU

[@adellafi8173]

Hello Sir , Can I add you on facebook because I have a question about equilibrium , but i cant put it here because it has a photo???

[@stepbystepscience]

Probably not.

[@saitmag]

@@stepbystepscience lmao

[@haicamichung6477]

About FTx=cos35°FT and FTy=sin35°FT Is it really not used? 🤔

[@matinkeivanloo]

For torque, I got 521, T= (mbg/2 + msg) / sin35* this is how my teacher told us to do. Which one is correct?? Thank you

[@nitaware3398]

This video stressed me out, made me feel even dumber, and i cried a little

[@stepbystepscience]

Sorry, just try to break it down into smaller steps.

[@danielbrantley6158]

Pick yourself up from your bootstraps!

[@enelesnsamila7626]

what ever will be will be

[@stepbystepscience]

+Eneles Nsamila Good question. You can see a listing of all my videos at my website,www.stepbystepscience.com

[@enelesnsamila7626]

+Eneles Nsamila ;ok

[@gelyvergeaily5547]

thank u !!!

[@dawitteferatefera3256]

Why counter clockwise torque =FTyLsin teta

[@hetroscodra9210]

Struggling with making the shear body diagram with similar task.