Physics 15 Torque Fundamentals (4 of 13) How to Calculate a Torque (Method 1)

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In this video I will method 1 of 3 of calculating torque = (force) x (distance).
Next video can be seen at:
• Physics 15 Torque Fun...

[@mathieubuisson8873]

you deserve an award for everything you have done on this channel

[@kmbstar]

Your ability to anticipate any questions that may arise in the thought process of learning the information you are presenting is absolutely phenomenal. Second to none!!! Makes it a lot easier for a 40 year old with a BS in Business Administration like me to go back to school and study to obtain a BS in Electrical Engineering. Thank you again for all that you do!

[@MichelvanBiezen]

Keep working hard and enjoy the journey. Hats off to you for meeting the challenge!

[@or-L-E]

Thank you, your videos are very clear and helpful as always

[@motorvehicle1330]

you are saving my life. Thank you so much for your videos. I can't begin to explain how grateful I am to you

[@MichelvanBiezen]

Happy to help! Glad you found our videos. 🙂

[@shorouk9452]

You're brilliant .. thank you so much.

[@KakarotM99]

awesome, thank you sir

[@ayayron9452]

Hi professor, thank you for these videos. wish you would've had them about 3 weeks ago (finished physics 1 final last week, tuesday). when is it appropriate to use rFsinθ compared to rFcosθ. thank you.

[@futurestig17]

Fsin(theta) is dot product shortcut while Fcos(theta) would be fundamentally simplifying the cross product process

[@futurestig17]

And mult. By length

[@younique9710]

Could you please explain why we must use cosine or sine depending on the angle between the vertical line and the force direction; the angle between the position of rotation and the force direction?

[@MichelvanBiezen]

Think of it this way: Torque will be a maximum when the direction of the force is perpendicular to the moment arm (the object you are pulling or pushing to make it go around). When you consider the angle relative to the perpendicular than 0 degrees gives you a maximum torque (cos(0) = 1). When you consider the angle with respect to the moment arm (the object) then an angle of 90 degrees gives you a maximum torque (sin(90) = 1)

[@younique9710]

@@MichelvanBiezen what if we just try to find out the toque at the specific position, rather than maximal torque? we use sine instead of cosine?

[@pietervan356]

You are just awesome sir.... but why didn't you include the torque that is due to gravity??

[@MichelvanBiezen]

The force of gravity on the beams is ignored here as it is assumed to be small compared to the load.

[@pietervan356]

@@MichelvanBiezen thank you so much!

[@omarel9865]

sometimes they do not use gravity in some problems can i please understand why ?

[@omarel9865]

Nevermind the problem said weights which means g was already included

[@arnoutis2938]

Lol he said 69 😆🤣😂😹😆🤣😂😹😆🤣😂😹😆

[@viditdeshpande3259]

Immature

[@ChernobieffPiano]

LOL, He can't say perpindicular!

[@chemlovert6126]

and you can't spell perpendicular :)

[@ChernobieffPiano]

I don't think you comprehended that I was phonetically spelling it to imitate the way he was saying it.

[@ChernobieffPiano]

How about this purpin- dick- ler

[@fayeduddin3229]

@@ChernobieffPiano Lol good one

[@maben15]

OMG, you have a great attention to detail!