Physics 47.2 The Transformer (1 of 1) Example

[@nisayuksel3440]

if you were my phys lab teacher, phys labs would be so pleasurable :)) thx for everything !

[@MichelvanBiezen]

We do try to have fun in our lab experiments. At least we have the videos. 🙂

[@juank941012]

excellent explanation. Can you make a video explaining the equivalent circuit, refered to the primary, to the secondary, and some examples?. thanks

[@robertpearson8546]

I have never seen a magnetic core shaped like that. Its relative reluctance should be about 1. So throw it away and use fiberglass.

[@MichelvanBiezen]

I have.

[@Pravinsahare]

Dear sir, if you have covered all the topic on 'single phase transformer' kindly send the link...it will be very helpful to me. your videos are so detail informative, your teaching technique and your knowledge is great

[@MichelvanBiezen]

We are currently preparing a playlist in electrical engineering on this topic. The videos should be out this summer.

[@abdel-khalekmahmoud8830]

hello sir: what will happen to the intensity of the current produced in the secondary coil if we (1) increase the frequency of the source. (2) remove the iron core. explain please

[@MichelvanBiezen]

1) Increasing the frequency means that there will be a stronger magnetic field. 2) When you remove the iron, there will be less "coupling" between the 2 coils (the transformer will not work as well and you will need more coils in the secondary to get the same effect).

[@abdel-khalekmahmoud8830]

@@MichelvanBiezenso in case 1 the intensity will increase or decrease?

[@MichelvanBiezen]

A stronger magnetic field does not translate into better power transfer in the transformer. Only 2 will increase/decrease the power transfer.

[@abdel-khalekmahmoud8830]

@@MichelvanBiezen thanks sir

[@pepijn_m]

I only hear it in my left ear

[@MichelvanBiezen]

Yes, our older videos were not recorded in stereo.

[@nijoeli]

Loooool, I only had my left headphone on

[@NotLegato]

why can't the power go up? or rather, why isn't the current on the other side of the winding determined by the resistance, rather than the voltage ratio? it seems strange you'd get a given amperage regardless of resistance.

[@MichelvanBiezen]

Because the current on the output side is caused by mutual inductance and induced voltage.

[@NotLegato]

hmm. that sounds like the math for circuitry on the output side will be different; calculating the current for when resistance of the secondary side ISN'T 0, yet current is finite even with theoretical 0 resistance. well, i guess i'll learn that soon.

[@edharris6452]

Not Legato I’ve always found this to be an interesting question. You’re asking why the output power is voltage dependent, so that if the input is 100W at 50V, and the output has half as many coils, how does nature determine to halve the voltage to 25V rather than halve the current to 2A? Certainly resistance would not be a factor here as you say so yes, this is a good question...

[@j.a.mcbean.4043]

Thanks

[@MichelvanBiezen]

Welcome