Visit ilectureonline.com for more math and science lectures! In this video I will explain what happens in a L-C circuit with a capacitor and inductor. Next video in series: • Physics 47 Inductance...
Пікірлер: 22
@RiaziMohandesi5 жыл бұрын
Thanx God for creating humans like you, so much time and energy you consumed to draw these beautiful circuits, i hope one day i can come to USA to see you💚💚💚
@valeriereid2337 Жыл бұрын
Excellent explanation. When I read this in the textbook today where the assumption was made that there were no resistance in an L-C circuit I wondered if that was possible in the real world. Thanks for answering my question. There will always be some resistance in the circuit. This certainly helps.
@MichelvanBiezen Жыл бұрын
You are spending a lot of time watching many videos. Glad you find these helpful. Keep up the good work. 🙂
@nellvincervantes62333 жыл бұрын
In phasor diagram, voltages of inductor and capacitor are equal in magnitude but opposite in direction so that total voltage on closed circuit is zero. And then, the current (since it is series, they have equal current) is 90° out of phase from voltages. Am I right sir?
@MichelvanBiezen3 жыл бұрын
The voltage across each component is 90 degrees out of phase with the current, but in opposite directions for each component. Yes.
@agumonkey6 жыл бұрын
Good diagram sequence. Thanks
@TheSalto669 жыл бұрын
circuit RC is the atom model ...energy can oscillate from current to voltage or between E and B field inside a torus ... Than an atom can exist only a specific frequency (resonance frequency)
@dalenassar91525 жыл бұрын
You state that the current NEVER completely stops, BUT, since it REVERSES at certain points and starts flowing in the opposite direction, doesn't it HAVE TO completely stop at those reversal points? Just like a mass on a spring traveling in a sinusoidal fashion BUT in a linear path? In particular at the very top and bottom as it changes direction?
@MrAlbashiri8 жыл бұрын
Thank you so much for the amazing video
@mahamnaveed26606 жыл бұрын
good teaching method...
@AETHERscience7 жыл бұрын
Hi, thanks for the nice video. In diagram 5, how can you say that the capacitor is completely discharged when the charges are still moving (current in the coil is maximum) and so they have not reached the other plate to neutralize the charge there ? More specifically, if you talk in terms of electron flow, electrons moving from the negative plate through the coil produce maximum current in the coil and so they have not reached the other plate (which is positive) to neutralize the charge there. Any idea how do we explain this situation ?
@MichelvanBiezen7 жыл бұрын
The diagram is correct. At #5 there is no charge in the capacitor, At that moment the current is moving in a counterclockwise direction.
@AETHERscience7 жыл бұрын
The conventional current is in counterclockwise direction, but the electron current is in clockwise direction. In a wire, positive charges do not move, only negative charges (electrons) move. So the electric current is the movement of negative charges (electrons) from the negative plate to the positive plate. In diagram 5, the electrons are moving in the coil producing maximum current, so they have not reached the opposite plate to neutralize the positive charges there. Then my question is how come the plates are already discharged when the electrons are still on their way to the positive plate which they are supposed to neutralize ?
@ezxd51923 ай бұрын
From diagram 5 to 6, how do you know the current will flow in that direction?
@mystic75792 жыл бұрын
It would be more practical to start with a fully charged capacitor!!! Also easier to understand……at least a capacitor can bring its own charge to the circuit. Where does the inductor gets its initial magnetic field??!!
@MichelvanBiezen2 жыл бұрын
During the oscillating cycle you can set t = 0 at any point in the cycle.
@IrakleiosTheGreat8 жыл бұрын
Sir. Since now I understand that the energy within the circuit will oscillate between those two components, it leads me to the immediate question: how can this circuit be utilized since its energy is theoretically constant?
@MichelvanBiezen8 жыл бұрын
This circuit is used for demonstration, and doesn't have any practical purpose. It can be used as an oscillator.
@IrakleiosTheGreat8 жыл бұрын
So in order to utilize it, there has to be additional components, right?
@MichelvanBiezen8 жыл бұрын
Yes, you will need other components such as resistors, diodes, op amps, etc. to make useful circuits.