Physics 49 RCL Circuits (9 of 13) Impedance and (3) Parallel Branches

[@mlivshiz]

I have been watching your videos for three days now. You are an excellent teacher. You explain everything very well. In upcoming lectures of my current EE course, I am going to sit in the back and watch your videos instead of listening to my professor who, unfortunately, jumbles his thoughts a bit too much.

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[@MichelvanBiezen]

We are glad to be able to help. Welcome to the channel

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I'm from GREAT INDIA 🇮🇳 pranamm 🙏🙏gurudev Fantastic solution , I've learn many things from this vedio

[@MichelvanBiezen]

Welcome to the channel. We are glad you found us. There are over 9000 videos on the channel if you are interested

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@@MichelvanBiezen i will see. Ofcourse!

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You're a good teacher, thank you for these lectures.

[@atakan716]

You're doing a great job, dear Professor!

[@kieronbadenhorst5911]

Awesome. I needed this explanation

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You are a great teacher, thank you so much.

[@MichelvanBiezen]

Thank you! 😃

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You ar doing a great job It was very helpfull to me☺☺☺🤗

[@MichelvanBiezen]

Thank you and we are glad these videos are helpful

[@MrPabloguida]

Excellent content.

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Thank you. Glad you liked it. 🙂

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[@MichelvanBiezen]

Thank you

[@jackalinthebush]

Thank you so much for these videos!

[@MichelvanBiezen]

Glad you like them!

[@ahmedal-ebrashy3691]

I thought of doing the samething in exponential form, what do you think Sir?

[@MichelvanBiezen]

It becomes a matter of preference. Either method is fine.

[@ajj7794]

would it make a difference if one of the Z's was a resistor, because i have the exact same problem but simply with a 50Ω resistor, a 50mH inductor and a 50μF capacitor, i found the total impedence to equal -2.52j+50. which is wrong. i have been given a input voltage of 200sin(50t) thank you

[@MichelvanBiezen]

R = 500 ohms with a phase angle of 0, XL = 2.5 ohms with a phase angle of + 90 XC = 400 ohms with a phase angle of - 90 (assuming that w = 50 rad/sec)

[@ajj7794]

thank you for the quick reply, firstly is it not 50Ω(0)?, i got every thing else the same but how to add them in parallel? i.e. 1/Z=1/Z1+1/Z2.... so i got 1/50 + 1/J2.5 + 1/-J400 = 0.02-0.4J+0.0025j Thus 1/Z = 0.2-0.3975j thus 1/Z=0.44(-63.29) thus Z=1/(0.44(-63.29)) Z=2.27(63.29) Which is incorrect the correct Answer Z=2.5(87.) Which was found by stating that the Voltage in parallel is that same thus Vrms = 200/(2^.5) = 141.42 Then the total current is i = 141.42/50 + 141.42/J2.5 + 141.42/-J400 i = 2.83 - J 56.57 + J 0.35 = 2.83 - 56.21 J i = 56.28(-87) Z = V/i = 141.42 (0) / 56.28 (-87) = 2.5 (87) I hope this has clearly shown my working and as to why i am confused. To clarify i can not get the same answer for Z using the 1/Z = 1/Z1 + 1/Z2 + 1/Z3 ... formula

[@MichelvanBiezen]

When using the method shown in the video and using the numbers you presented z = 2.51ohms / 87.1 degrees

[@ajj7794]

Michel van Biezen thank you for the reply, I will retry until I get the correct answers.

[@Jptoutant]

I didn't even realize those rectangular forms are complex numbers, quite a reveal

[@MichelvanBiezen]

Yes, and the contents can be expressed in terms of the magnitude and the phase angle

[@_Angelus-eh8xi]

thx sir, im from indonesia

[@matthewsmith7979]

top stuff

[@MichelvanBiezen]

Thank you. 🙂

[@gnandhini4298]

In a four branch parallel circuit, 10mA of current flows in each branch . If one of the branch is opens, the current in each of the other branches.. ? A) decrease B) increase C) remaining unaffected D) doubles Please say the answer sir

[@MichelvanBiezen]

The answer is "C" the current in each branch remains unaffected.

[@gnandhini4298]

images.app.goo.gl/oq7FXf8jW7hCEuLRA find potential difference between P and Q

[@ugursoydan8187]

why we subtract the angle in denominator from the angle in numerator?

[@MichelvanBiezen]

Watch video 4 and video 7 in this playlist: Physics - E&M: RCL Circuits (7 of 13) Operations With Impedance Physics - E&M: RCL Circuits (4 of 13) Complex Numbers Review PHYSICS 49 RCL CIRCUITS They will explain that.

[@charafeddine6693]

thnx

[@mrgoodvibs3742]

why did my teacher give Zt = [sqrt((1/R)^2 + ((1/XL)-(1/Xc))^2]^-1, which gives me the incorrect answer?1?!