Physics - Nuclear Physics (21 of 22) Find the Decay Rate and Half-Life

[@zuhabuha4766]

I know its long time but u calculated activity with decay/min and t(time) with hours(2 h). Shouldnt you convert both of those in same unit? Like decay/hour

[@MichelvanBiezen]

Yes you can use any unit of time. (off course you will have to adjust the decay constant)

[@cricobug9778]

Sir why radioactive series terminate at lead although we have the iron as the element with maximum binding enregy oer nucleon value (most stable in BE curve)

[@MichelvanBiezen]

Maximum binding energy and nuclear stability are not the same thing. Nuclear stability comes from having the correct balance between protons and neutrons in the nucleus, and instability comes from having too many protons close together in a large nucleus such that the repulsive forces between the protons overpower the nuclear strong force.

[@cricobug9778]

@@MichelvanBiezen thank you sir. What my answer should be then if asked 'Why many radioactive series terminate at lead?"

[@MichelvanBiezen]

Because lead 206 is the first stable isotope, which means that there is the correct ratio of neutrons to protons in the nucleus to make it stable. (The nuclear strong force is strong enough to keep any of the protons of being repelled by the other protons)

[@cricobug9778]

@@MichelvanBiezen thank you sir

[@rabiaazizi1973]

where you got the 0.693 from the lambda you found to be 0.296

[@MichelvanBiezen]

ln(2) = 0.693

[@adil1551]

Thank you so much professor.

[@soliatv1038]

thanxxx Prof Michel van Biezen ....u r great

[@hburger5968]

Hi Mr. Van Biezen, i thought 't' had to be converted to years, not into hours?

[@MichelvanBiezen]

+waynos 77 The decay rate can be calculated in any units of time.Whichever is most convenient.

[@hburger5968]

Thank you.

[@roaasab3499]

thank you so much , you are amazing sir

[@Peddayana]

When you differentiate wrt to time there will be two terms Sir.....u missed the second term?

[@MichelvanBiezen]

We are not actually taking the derivative of both sides of the equation with respect to t, but simply replacing N (the number of atoms ) with the decay rate on each side, since we know that they are proportional. Thus no error was made.

[@zackcarman7845]

This is f*cking easy! Thank you sir!