your really fast and very easy to understand great videos keep up the good work
@Inefprag8 жыл бұрын
My mind was blown because I didn't know the equation E = 1/2 *k* x^2 could be also obtained simply by substituting F. It makes a lot of sense.
@ALevelPhysicsOnlineYear138 жыл бұрын
+Inefprag Glad it helped.
@Heaven77k11 ай бұрын
Hello
@sanjaysojan43419 жыл бұрын
@A Level Physics Online! Thanks mate! Great help. Honestly your better than my teacher....
@PhysicsOnline9 жыл бұрын
+Sanjay Sojan Thanks
@mohammedd24839 жыл бұрын
Thanks a lot for all these videos. Really helpful!
@cubekaraja6844 Жыл бұрын
You are genius man taught fast and easily!! Understandable 💕
@johntindell95917 жыл бұрын
what your doing is beyond applaud
@cherlynharyono7 жыл бұрын
i love love love your channel. thank you! 🙏🏼
@lykzjrmaf35098 жыл бұрын
Thanks very much from Papua New Guinea.. :-)
@thectheb10 ай бұрын
Why is the area under the graph equal to the energy stored??
@abdurrasheedsadiq75497 жыл бұрын
This only applies for the period where the material is obeying Hooke's Law, right? If so, does that mean that using the area under the graph to calculate energy is only applicable before the limit of proportionality?
@PhysicsOnline7 жыл бұрын
AbdurRasheed Sadiq You're correct
@abdurrasheedsadiq75497 жыл бұрын
Cool. Thank you :)
@MonkOrMan2 жыл бұрын
I'm watching this out of interest not for a-level. I'm slightly confused by the notation of _F_ and _x_. I will also refer to _x_ as _d_ from now on because it is distance. We know that _E = Fd_. The area under a graph is the _x axis * the y axis_. For example on a speed-time graph where the _y_ is speed and the _x_ is time, the area under the graph is distance which is _speed * time_. It seems to me that the area under the graph in your video is also _the x * the y_ because the area underneath is _E = Fd_. However you said that _E = Fd/2_ because by _F_ you mean the FINAL force applied over the distance rather than the AVERAGE force applied over the distance. You have now ended up with the equation _E = Fd/2_ even though _E = Fd_ because your definition of _F_ was different. How does this work in physics with the different possible meanings of F and contradictory equations? Is there a way to notate this difference (between final and average force)? By the way I have never learnt calculus and I know this has something to do with integrals so that may be where my confusion is. To me my way seems more correct because it is done the same way as in a distance time graph, it works for any shape of a graph, and you end up with the correct _E = Fd_ equation. Thanks for any help!
@lemonadepie96316 жыл бұрын
you need a pair of forces to stretch a spring. one is the gravitational force, what about the other one? is it the reaction force or a frictional force? where on the spring does the other force act?
@YesIlikebananasSo3 жыл бұрын
Tension
@MrMas97 жыл бұрын
Hello; can you please explain why the work done by the spring is not W=Fs? I don't understand why this doesn't apply here.
@PhysicsOnline7 жыл бұрын
MrMas9 because the force increases as the spring extends.
@the_hasnat4 жыл бұрын
is the energy stored only up to where they are proportional?
@nevanmasterson464 жыл бұрын
Would there be a case where they *aren't* proportional?
@the_hasnat4 жыл бұрын
@@nevanmasterson46 things like chewing gum. ALthough they too are proportional to a really small limt.
@YesIlikebananasSo3 жыл бұрын
@@nevanmasterson46 after the elastic limit? When it’s not obeying Hookes law?
@afiazaman66224 жыл бұрын
honestly I love your video but I hate the intro sound its like someones tearing my eardrums apart
@PhysicsOnline4 жыл бұрын
Don’t worry, o my videos from the last few years I’ve used a different intro.