Torque about ICR for a SLIDING ROD

[@INSP_NITIN]

congratulations sir for 10 K ... millions more to follow . FIZIKA 2021 would be a boom baam .

[@BhautikiGyanamJAISHREERAM]

U recieved 41 hearts and i am on 40 good competition 🤨

[@INSP_NITIN]

@@BhautikiGyanamJAISHREERAM i surrender ha ha :)

[@BhautikiGyanamJAISHREERAM]

@@INSP_NITIN GOOD FOR ALL :)

[@ProTeachers]

Yes, Nitin Sir and Janardhan Sir. You both are great.

[@BhautikiGyanamJAISHREERAM]

@@endlesseducation2845 what 😲😲😲

[@PhysicswithAkashGoyal]

Congratulations for 10k subscribers sir 👏👌

[@vinayaksharma9251]

Arey sir aap 🙏🙏🙏🙏 ....pranaam

[@ShahrukhKhan-hg9jj]

😍op sir

[@neerajchoprarealid3935]

PWAG is best and in my top 3 fav phy channels on YT

[@atikshagarwal5147]

@@neerajchoprarealid3935 bhai sir ke subscriber baad jayenge toh competition bahut tough ho jayega yaar😂..

[@RamizZamanJEEPhysics]

Congratulations for 10K sir. You're an inspiration . Best wishes for you. 🤗🤗

[@KJ-zs7pi]

Hello frand

[@NikhilKumar-ns6zw]

this channel is like treasure of oak island so precious to be channelized or televised. loved the explanation.

[@pranavsalunke9804]

22:44 1)yes 2)no 3) l root w^4+l^2 Direction radial and tangential in circle of radius l

[@GRAMOLY]

Congratulations sir for the 10k family! Honestly, you deserve much more since you deliver such excellent content for free. Your contribution to the Indian physics olympiad community is fathomless. HAIL #FIZIKA2021

[@AdityaScich]

Congo SIR 😍😍 for 10 K subscribers 🥰.

[@ajinkyagohad7206]

This channel is a treasure for Physics aspirants - students and teachers alike! So glad to see you grow! Onwards and upwards!

[@physicsguy6625]

Physics cup 2012 was about this too i believe.. great concept

[@equalcell1555]

Congrats sir for 10k. Your channel has been a lot to me and has increased my interest in physics.

[@dishakayande3997]

bhai same

[@dishakayande3997]

@@vilgax9955 ok

[@manishkhandelwal7734]

Equal cell

[@pranjalrathoreiitkharagpur2201]

27 minutes video took me 1hr+ to get each and every thing cleared😅😅.....felt very confident after this video thank you sir jee , u are really op

[@curiash]

Op means

[@pranjalrathoreiitkharagpur2201]

@@curiash over powered

[@harshiljain2368]

Some golden words sir 17:14 💛💛 22:00 Q1 a) Yes, b) Yes, because even though icor is moving with a non zero acceleration, the magnitude of inertia is constant. c) w²l from A to B along a circle of r=l 24:17 Q2) (B) Not entirely sure, explanation being even though it is slipping, we could say that work done by friction is same in both cases and v and w of disc is greater

[@devashishthakkar6723]

Sir aapne to dil physics physics kar diya. Gajab ke master ho aap to ..salaam hain aapko..God bless 🙌

[@Arvindmerasathi-vd5bz]

loved it sir, thanks a lot....now i got deep understanding of psuedo torque

[@sarthakmaheshwari3813]

i always had problem in such questions, thank you so much sir

[@indiann871]

Wow!what a clarity given by you.Awesome,keep it up. Thanks a lot.☺️

[@beluga8956]

Thank you sir Eagerly waiting for new videos 🙂

[@jaygupta3740]

23:00 iii)a(radial)=w^2l and a tangential=alpha*l

[@AnshPl]

Thanks sir😊 Your videos are treat for us

[@anishtakshak6515]

Thank you sirji☺❤

[@amarsinha866]

Congo for 10k sir ,millions are waiting for you sir 😊🙏

[@sarthakmishra1483]

Can't wait to see what amazing problems u have prepaired for fizika sir 😍

[@agarwalaman123]

What is fizika, everyone talk about this

[@atharvamahajan4949]

@@agarwalaman123 it's an exam in which sir is making problems

[@atharvamahajan4949]

@@agarwalaman123 wtf?

[@aaryansahu2003]

Congo on 10k sir.Hats off to your dedication and presentation in each and every video.

[@JEE-zm3sh]

This confusion I had for a long time.... a constant source of frustration for about an year...thanks a lot sir

[@manishkhandelwal7734]

19:56 The same I thing I tried to explain in the official solution qotd 46 (Mine one) Many people did it but only one got to the last answer Sir have you seen that problem? @PHYSICS SIR JEE - JANARDHAN - IIT JEE and Olympiad

[@PHYSICSSIRJEE]

I think I missed it. Let me check 🙂

[@manishkhandelwal7734]

@@PHYSICSSIRJEE sir today is my birthday I just waked up And seeing ur reply had made my day ❤️❤️

[@PHYSICSSIRJEE]

@@manishkhandelwal7734 many many happy returns 🙂👍🏼

[@manishkhandelwal7734]

@@PHYSICSSIRJEE thank you so much sir😊😊

[@rishikachauhan4490]

Waiting for resolved series 🤗 practice problems so conceptual

[@as.if_0077]

😍😍😎😎amazing Thank you sir

[@visalaj767]

Congrats for 10k sir 💥💥

[@anishdatta698]

23:30 1) yes, 2)yes, 3) L root(alpha^2 + w^4)

[@coolrockerify34]

Everytime I come here, I learn something new and I absolutely love it. ❤️❤️

[@samaryadav5943]

Congratulations for 10k subs, sirjee! 10 k special fizika video ❤️

[@cauchyschwarzkabhai257]

ok

[@jishnudas5698]

Thank you sir for your wonderful explanation . Congratulations for 10K subs. The answers for Practice problem 1 at 21:58 are a)Yes. b)Yes. c) (-Lcosθ ω^2- L sinθ α ) i +(-Lsin θ ω^2+L cosθ α ) j

[@sirjamesjeans7676]

22:23 1) Valid 2) Not valid, as pseudo torque would be non zero 3) L(alpha) perpendicular to CI vector, and w^2(L) along IC vector. The I point would be actually moving in a circle with center as the other point of the rectangle formed by end points of rod and I. 24:17 1. 2) 2. 2) 3. 4) (I felt for the last one it was not possible to decide as Sphere pure rolling doesn't imply anything on the Hoop or disk pure rolling) 25:15 Slips at a height of 2/3 H, irrespective of length of rod Can you please check these sir jee? Thank you!

[@mihirdeshpande4345]

22:23 Pseudo torque would be zero, in fact , because accn of IAR points towards the COM of rod. You could easily prove it by writing acceleration constraints , i.e, y comp of accn of point sliding along floor = 0, and x component accn of point sliding along wall = 0

[@sirjamesjeans7676]

@PHYSICS SIR JEE - JANARDHAN - IIT JEE and Olympiad Can you please check it sir?

[@mihirdeshpande4345]

@@sirjamesjeans7676 did u try to prove the fact that accn of IAR points towards COM of rod?

[@sirjamesjeans7676]

@@mihirdeshpande4345 I feel there will indeed be a pseudo torque if you sit in frame of ICOR. Because ICOR has a acceleration of L(alpha) tangentially. But I have doubts on whether considering ICOR to be this is correct. Because then, the ICOR would have a L(w) velocity too, which doesn't make sense. So I feel this L(w) is just a rate of change of position of ICOR rather than velocity, and same way for acc, though not very sure. Wanted to confirm the same

[@sirjamesjeans7676]

@@mihirdeshpande4345 but this seems wrong to me, as if acc points only radially , that would mean no acc along the tangentisl direction, and they are moving in same speed Everytime in this frame, which doesn't seem to be the case

[@gouharmaquboolnitp]

Congratulations for 10k sir

[@anushkrajbordia1873]

Sir congratulations for 10k subscribers... This is just the beginning... This channel will grow exponentially!

[@rithvikk3754]

Sir u are truly amazing I have been stuck on angular momentum since many days... Amazing pitch and clarity was delivered through this video thanks a lot 👌

[@PHYSICSSIRJEE]

I am glad you liked it. Thank you for your kind and appreciative words 🙂🙏

[@toshiv-y1l]

12:05 Sir you could have mentioned the moment of inertia tensor which resolves the issue and allows us to write torque=I *alpha where I is moi tensor

[@PHYSICSSIRJEE]

I generally avoid mentioning concepts which are "out of the JEE ADV syllabus"... It scares students away from the channel

[@PHYSICSSIRJEE]

I generally avoid mentioning concepts which are "out of the JEE ADV syllabus"... It scares students away from the channel

[@durgasathwik820]

Nice sum sir Tq please make videos on optics part sir

[@jaygupta3740]

23:00 A)yes since the rod moves in circle with respect to I B)no since it is an non inertial frame there must be pseudo torque also

[@PratyushKumar-d9f]

Sir for the practice problem at 22:25, icr 1 and 2 are yes as icr is a point on the massless extension of the body?

[@PratyushKumar-d9f]

Also sir for that instant all the points are maintaining their distance from the icr

[@PHYSICSSIRJEE]

22:25, your reason to 1 is correct but 2 is not... Tau = I alpha is not always valid about ICR, here it's valid because acceleration of ICR is directed towards CM ( so no pseudo torque), like in uniform disc rolling case

[@PratyushKumar-d9f]

@@PHYSICSSIRJEE okay sir understood

[@deveshkumar7288]

Sir how. Acceleration of icr is towards cm there is tengential acc also​@@PHYSICSSIRJEE

[@adityamishra3118]

Thank u sir...i got myself cleared of some of the misconceptions I had in this particular topic 🥺🙂🔥

[@vibhuverma6252]

Sir please made vedio of solution of practice problem

[@jgchaudhary1035]

Congratulations for 10k 😎

[@anishdatta698]

24:20 51) opn(2), 52) opn(2), 53) opn(4)

[@kushjuvekar1080]

Sir can you please make a video on beat frequency of three sources. I can't find and conclusive answer by myself or on the net. Pleaseee🥺

[@PHYSICSSIRJEE]

Solvable only in special cases of AP. For others , the solutions given in internet are wrong. I wanted to do a resolved series video on this in March. It requires a lot of time. Also video will be long. When I saw the channel is not doing well , I kept many such video productions under pause. I may definitely do it in the future

[@kushjuvekar1080]

@@PHYSICSSIRJEE Thank you sirrrrr.

[@Rishabh-se5yo]

Congratulations sir♥️♥️

[@hiteshsonawane77]

Congrats sir for 10k🔥

[@deorasirsphysicschannel4665]

Guest appearance by ICOR...loved it!!😂

[@jeeenthusiast]

22:56 1. Yes 2. No because pseudo torque isn't zero

[@amber1171]

Thank u sir.. Its Very helpful🙏

[@vedarthbhawsar4286]

Congratulations sir jee for 10k subscribers.... Abhi toh party shuru hue h🤩🤩

[@supriya1729]

Congo for 10 K sir 🙂🎉

[@ThakurGovinnSingh]

I love these advanced things to solve

[@nandanamish394]

Rod will loose contact at height = l/sqrt3 , from base.

[@chakradhar5884]

Wonderful sir

[@equalcell1555]

Sir I got a doubt At 7:19 .. the Vcm term is taken in inertial frame but when we take it on the material point wouldn't there be some problem And also would the angular momentum about point B and B' be same?

[@satwik1268]

yes, i have the same doubt.

[@PHYSICSSIRJEE]

Vcm is not in inertial frame when it's taken about material point. L about B and B' are different

[@satwik1268]

@@PHYSICSSIRJEE sir when will the soln video of the practice problem given at end will be released. If video is not possible then please give the correct answers to the practise problem!

[@satwik1268]

@@PHYSICSSIRJEE Also sir, can we conserve momentum about ICR if net torque about it is zero? I think not as it is 'jumping' at every instant (since it's velocity is zero but it's changes position) . What is your though on it?

[@rushikesh_nale07]

Great Problem Sir!💙

[@AyushRajput-xw2ru]

26:14 no sir answer won't changes as it is always 2/3 of vertical height means 6m and so independent of theta

[@jitendrapandey1085]

Practice problem 1 1 yes 2 no 3 acceleration of point ICR = vector sum of acc of point A + acc of point B

[@neerujat1978]

Thank you very much sir

[@RahulKumar-jo1yq]

10k sir 🎉🎉💥💥

[@arpangoswami5760]

22:51 I am getting 1) yes 2) No 3) lwsin^2(theta)

[@vj51]

sir 10k ho gaye moj congratulations

[@indrakumartak9865]

Sir, is the video solution to practice problems starting from 23:29 posted? The solution is not available in your "resolved series" playlist. Kindly reply 🙏

[@PHYSICSSIRJEE]

Not yet prepared. Good idea, added to my list

[@slayerinmakin]

The First Question of this QOTD was amazing, got to learn something new, the third one I wrote the motion of COM as rcos i + rsin j about O and found the velocity as dv/dt unfortunately didnt apply d theta /dt as -omega which yielded me wrong answer while writing orbital angular momentum(m(r*vcm) .Loved it, will watch the question one again to understand the concepts even better, also sir, could you please bring videos on Piston Cylinder arrangement? Thank you.

[@therealsan9949]

thks for using english!! cool explanation

[@rajanihatti]

sir at 13:20 , can you explain how does the pseudo force act in that manner on the rod?

[@PHYSICSSIRJEE]

Since acceleration of A is downward as shown at 13:20 , the pseudo force of every dm element of the rod is (dm a) upward... This uniformly distributed pseudo force can be replaced with a single force of ma at centre of mass (basic concept of 'center of force' taught in rotation)

[@rajanihatti]

Sir if we choose a general point P on the rod, then how can we write the pseudo force pertaining to the observer sitting at P?

[@neerajchoprarealid3935]

Sir aajkal aapke views bahut aa rahe hai..please ese he grow krte raho sir or videos daalte raho.... Aap P with akash goyal sir Ind school of physics are really boon for phy lover

[@yatharthgupta6468]

23:00 1)yes even ass it's a non inertial frame , rod performs pure rotation about this point and has IW is valid and can be proved by L = mr×v + iw 2) no since its a non interial frame 3 w^2l towards o as it moves in a circle of radius l with origin as centre

[@muhammedaslams6065]

23:00.... When IAOR has centripetal Acceleration, we have to consider pseudo torque also... We can write L=I omega.. In IAOR frame, since the body always rotates in this frame. Here the Acceleration of ICOR is centripetal Acceleration towards COM.. Is this right sir?? If not please correct me sir.!

[@shashwatdwivedi8184]

If I don't like your video my fingers feel uncomfortable. I will watch this tomorrow.

[@adnann5232]

OK

[@vj51]

ok

[@ilovemrbeast2380]

Wowww

[@metablaze3523]

Congratulations sir for 10K🥳🥳🥳🥳❤️❤️❤️. 25K next

[@jgchaudhary1035]

25:13 h=6m No change

[@jgchaudhary1035]

Similar to Pathfinder problem

[@jgchaudhary1035]

Correct?

[@rohanyadav3022]

Sir plz solve ray and wave optics check your understanding 1

[@yatharthgupta6468]

Again sir a brilliant problem with exceptional explanation..learnt a lot of new things And congratulations sir again for 10k suscribers 🎉🎉 text target 20k soon And who are these 5 morons who has disliked this video 🤬just jealous of success 🤬🤬🤬

[@ShahrukhKhan-hg9jj]

Replacing senorita with Fizika this time!

[@uttambose2723]

Sir very eager for 5th september btw its like the Morin problem type

[@ayushsahu9916]

Sir i m a regular viewer of your channel i just want to ask u can u make a video on how to calculate work done in spring pistons system in thermodynamics

[@dhirendrakumar3767]

Centre of mass goes in circle of radius L/2 from point O (origin ) , can we say it's in nonuniform circular motion about O so one centripetal acceleration towards o w Square into r , and other tangential acceleration is along tangent to this always , but my doubts is by definition cm is translating frame so it's only acceleration is radial towards O not any tangential component because it is not rotating , so please correct me

[@BhautikiGyanamJAISHREERAM]

30 minutes only !

[@amrutanshumishramishra6056]

sir can u recommend some good books on physcics plz

[@vilakshangupta380]

P1) 23:00 - A) Yes , B) Yes , C) It's moving in a circle centred at the origin , so acceleration is towards origin, and magnitude is given in replies to this comment 😂

[@yatharthgupta6468]

It will be w^2L as icor moves in a circle of radius L with centre as origin and u can verify that coordinates of icor is always (lcostheta,lsintheta) where theta is angle made by rod with horizontal

[@vilakshangupta380]

@@yatharthgupta6468 Yes , you are correct, didn't pay attention

[@jaygupta3740]

What about tangential acceleration

[@jaygupta3740]

I am getting a(radial) as w^2l

[@jaygupta3740]

And a(tangential)as (3gcostheta)/2

[@brokenwings6925]

Sir when are you going to start your comprehensive lecture series for JEE Advanced as stated in your website? Is it going to be before JEE 2022?

[@PHYSICSSIRJEE]

Yes , after JEE advanced . Plan is on . Just a problem of sponsorship

[@brokenwings6925]

@@PHYSICSSIRJEE thank you so much sir 🙏🙏🙏

[@shivisisodiya146]

Sir, B' is defined as the point which is on the ground directly below the poin of contact of rod and ground...so when the point of contact has acceleration in the horizontal direction the point B' must also have horizontal acceleration doesn't it mean that B' is non inertial point???

[@nishantpastor6224]

No need to go to jwellery shop Gold is here ❤

[@jaygupta3740]

Please tell sir if I am correct

[@vaibhavdev974]

👍👍

[@shlokk007]

You sometimes sound like hcv sir

[@krishsharma162]

I have a slight doubt , can we always write L about cm =Icm×w ,even in General planar motion ,,if mass distribution about cm is not symmetrical (pls confirm can it be non symmetrical),then Ixz,Ixy,etc may not be zero then L about cm will have components along x,y axis also other than z component .pls clear Also can u pls come up with concepts of 3d rotation in near future ?

[@krishsharma162]

Respond pls

[@krishsharma162]

Did u get my doubt?

[@sumatisumati4594]

Hello sir, at 18:53 how do you take that point to be ICR?

[@PHYSICSSIRJEE]

Draw perpendicular lines to velocity vectors at the end of rod. If rod is assumed to be purely rotating about ICR , then these perpendicular lines should meet at ICR ....this is the standard rule of locating ICR taught to 11th standard students taking JEE advanced

[@sumatisumati4594]

@@PHYSICSSIRJEE Thankyou Sir!

[@ashwinchakote]

When is 10K special coming sir eagerly waiting 😀

[@PHYSICSSIRJEE]

Didn't plan specifically anything, this video was it . Let me see what else can I do🙂

[@Prodbybah]

Any one please reply is this fizika exam i can apper if i know only mechanics or other thing i should know pls say anyone

[@monalgupta03]

hello. i just wanted to ask where can i find the solutions of the three practice problems at the end of the video. I also have doubts in some other practice problems on another video, but i could not find their solution. pls help

[@PHYSICSSIRJEE]

You can get the correct key from comments I liked below or join the Discord server or telegram group for discussion among students. Or you can wait for me to post video solutions here

[@freefiregaming5284]

#jee advance 2023

[@dhruvilshah7770]

This question is from which book ???

[@PHYSICSSIRJEE]

I have not yet written that book

[@dhruvilshah7770]

@@PHYSICSSIRJEE So you’ll be publishing a book !!!

[@Farm_ai]

🥳🥳🥳🥳10k subs sir !!!

[@hke.4475]

Noice

[@shashwatmishra4342]

I did apply the right concept but while calculating I was lazy and instead thought that L about o would be ICM*w-some number(positive) and L about C is simply ICM*w so L about C should be greater 😭😭😭

[@jeeranker1167]

Same

[@PHYSICSSIRJEE]

I knew this was happening, so added 3rd question 🙂

[@nirmalkrdubey9375]

22:20 1) YES 2)NO 3)ICR MOVES IN A CIRCLE WITH a_r = W^2L, a_t = 3g/2cosx 24:22 51-(2) 24:44 52-(2), 53-(4) 25:25 6,no EDIT: i saw some solutions to the last problem, i think i have a much shorter solution