Rotational Mechanics | Advanced Problem | Accelerations of Beads on a Ring Just After Release

[@Sandeep-xc8fm]

Sir dnt have any words for you u r limt n to infinity (best)^(best)^(best)......n mentor of physics. Thanks sir noo word for you

[@siddhantgupta555]

Thank you sir, this was my doubt . Cleared😊

[@vaibhavkumar5419]

2nd part ki explaination awesome thi sir ................ 👍👍👍

[@mamtamittal3051]

Physics with Akash Goyal (PWAG) Sir in this question when you said that the bead b is performing circular motion so a = r alpha but we can also say that with respect to the hinge the position of bead b on the ring has r alpha in the x direction and to maintain the normal the bead must have r alpha in the same direction henceforth the bead has r alpha in the x direction

[@srslyumang]

Very nice analysis sir 🙂💥

[@ranjinireghunath8692]

Sir,in the second part of the question,while considering the net torque about O,why did you not take into account the torque generated by gravitational force acting on the centre of ring

[@atikshagarwal5147]

Sir why is the normal reaction on B in the horizontal direction? Should it not be along the direction of tangential acceleration?

[@Piyushthote0867]

Sir angular vel zero toh usse a=raplha kyu ye kya karega ang vel zero hai toh Ohh accha mw²r zero hoga isiliye

[@wehtam]

sir do you have any tips on how to choose reference frame? in this problem i think its ok to say that choosing o as frame was the most important step

[@alternative3697]

Sir Since it is given that friction is very small , so I applied energy conservation and from there I got w in terms of Theta and got alpha from wdw/dtheta , at the end I got alpha in terms of theta and applied limits on the expression 'theta tend to 0' and got acceleration √2 g/4 What is my mistake sir ?

[@vilakshangupta380]

Sir you have not considered the moment of inertia of ring, it should be 4mR^2...

[@PhysicswithAkashGoyal]

As given in the problem Ring is light (negligible mass)

[@ujjwaldwivedi5877]

Sir can we use energy conservation to find theta

[@aniketsen6845]

That's what a very basic approach is❤❤❤❤❤❤❤❤❤❤ Just a lovely Problem and an amazing solution sir💚💚

[@raghuchireddy912]

Bro are you 2020 or 2021 aspirant

[@khushantrana4495]

Sir first part main apne hinge ke about B ke mass ka torque consider insliye nahi kiya because wo slide kar raha hai toh rotational equilibrium main hoga ????

[@PhysicswithAkashGoyal]

B is NOT part of the system taken... I have taken A and Ring in the system and whatever force B is exerting will be external for the system

[@khushantrana4495]

OK sir thanks

[@physicsiseverything9138]

Sir can you please make a video on instantaneous axis of rotation and its application.

[@PhysicswithAkashGoyal]

it's already there kzbin.info/aero/PLb2lQ33Kj042LI5nvktN6UuapdEPi8lnx

[@rmishra70]

Sir why we are not considering acceleration due to gravity for bead A ?

[@vaibhavkumar5419]

Wonderful 👌👌👌

[@tnsh8946]

I don't know why sir has disabled likes dislikes.content is amazing

[@itsamankumar403]

One of Sir's subscriber disliked the video just because he was didn't heard a particular word ( he told he was confused ). I guess that made sir disheartened and he disabled this. Although sir maintained zero dislike in almost every video.

[@tnsh8946]

There are only 2-3 channels on KZbin providing this level of content we should respect them

[@ishaanagarwal5547]

Sir, what is the ideal approach for solving such questions. Should I try to my fullest to find the answer (consuming lot of time), or give the problem some thought and then try to understand the solution that you give. I am a 2020 aspirant.

[@PhysicswithAkashGoyal]

You should not give too much time to a single problem. Some of these problems require too much thinking and then right way of calculation.

[@rmishra70]

Sir why we are not taking account for acceleration due to gravity for bead A ?

[@PhysicswithAkashGoyal]

A is fixed on the ring. its not free to move on the ring.so I have taken FBD of ring and A together.

[@rmishra70]

@@PhysicswithAkashGoyal thanks sir

[@sunritroykarmakar4406]

Sir last diagram is not clear

[@PhysicswithAkashGoyal]

What's your doubt ... can you please elaborate

[@sunritroykarmakar4406]

@@PhysicswithAkashGoyal sir second part of the question didn't understand

[@PhysicswithAkashGoyal]

@@sunritroykarmakar4406 since B can slide along the ring it should be at the lowest point such that there is no tangential force due to gravity. CM should be vertically below the hinge so that there is NO torque about hinge.

[@asdfghjkl6506]

Sir please krotov ka block time period question karva do. Qn 96

[@arshsaiyad7547]

Sir I am still confused about the part where you removed bead B.If we remove bead B we are completely neglecting the component of vertical force due to mg of bead B,which is capable of generating torque about point O Please help

[@PhysicswithAkashGoyal]

You are talking about contact forces... It has two components Normal and friction .... Friction is neglected here and hence only normal appears..

[@PhysicswithAkashGoyal]

@@swetankpandey999 There is torque of Normal about hinge

[@ishaanagarwal5547]

@Arsh Saiyad mg of bead B acts on bead B. According to the system Sir has considered, you need to write the forces acting on the ring+A system, so you won't include mg.

[@samardas-zy1vu]

Please come and teach in unacademy sir

[@MdAthar-bv1or]

Sir you miss out of moment of inertia of ring.... 4mR^2

[@physicsdekhovedprakashtiwa5160]

🙏🙏