Power Electronics Boost Converter Part 1

[@SagaD888]

You are great sir, appreciate your effort to deliver this Buck Boost topologies.

[@durragas4671]

What a great video! I ended up doing Power project even though I studied signals... so this helps.

[@powerelectronicswithdr.k1017]

Glad it helped. I started out in communications and have since switched over to power electronics. Having a good base of fundamental skills will help you navigate a successful career. Best wishes on your project. -Dr. K

[@antipoti]

Life saver video! What a blessing 😇

[@crankshaft30]

Thank you sir.

[@vaibhavpatil-mj5zj]

Thank you sir

[@powerelectronicswithdr.k1017]

Vaibhav, you are welcome. Thank you for watching and best wishes on your designs. -Dr. K

[@chrisranes7964]

I’ve been watching this video, and I’m trying to figure out the calculations to size components needed for a joule thief circuit. I want to be able to use a 12V LED bulb in an extended power outage. Am I looking at the correct video?

[@powerelectronicswithdr.k1017]

It sounds like you require 12VDC for you application. What is the input voltage? I'm assuming less than 12VDC. Please note that this boost topology is somewhat limited in the amount of voltage gain. Much of it really depends on the power requirements too. There are more efficient ways to boost the voltage such as using an LLC resonant DC-DC converter. Hope this helps and best wishes on your design. -Dr. K

[@chrisranes7964]

Yes sir, I would require 12VDC. The input voltage could be as low as one-volt or less, especially if I am using an older AA battery. I will look into the LLC converter circuit you mentioned. Thank you!

[@aviandragon1390]

I know that this is an old post, but for anyone reading this in the future, this is just wishful thinking. If you want to do this, keep a deep cycle battery handy, or possibly two lantern cell batteries. Increasing voltage via any means requires having the extra current to make that possible. Even if the amount of energy required to perform certain work is technically contained within a battery, the internal resistance of small cell batteries is rather high. That means that in the best case, the circuit will not function. In the worst case, your battery will get so hot it will start a fire.

[@theky2234]

Dr.K, why don't we solve: - DxVi = (1-D)x(Vi-Vo) to get D = (Vo-Vi)/Vo ? Thanks!

[@aamir99204]

Hello sir I have been following your power electronics series for a while now. However I have one confusion. In the current equation you mentioned that the voltage across the inductor is constant. However isn’t it swinging between Vi and Vi -Vo. So can u please explain how it will be constant?

[@powerelectronicswithdr.k1017]

Hi Aamir, great observation. Yes, the voltage is swinging between Vi and Vi-Vo. The current through the inductor comes from the equation v(t) = L di/dt. We solve this via piece-wise integration. We integrate to find i(t) over the interval when the voltage is Vi and that voltage is constant. Then we integrate when the voltage is Vi-Vo and this voltage is constant. Therefore we will see the current ramp up and ramp down as the voltage is swinging between these values. Hope this helps and best wishes on your design. -Dr. K

[@aamir99204]

Thankyou sir. Yes I have now understood the statement of the voltage being constant. Thankyou for your quick response!!

[@MrNarasimha214]

Hello sir can you upload about RE Boost converter and it's difference from boost converter plz

[@pinkinegi5935]

Hello sir,please upload a video for closed loop design as well

[@powerelectronicswithdr.k1017]

Hi pinki, thank you for the suggestion. I'll place that on the list. -Dr. K

[@ranganathanrajaram2121]

Dear sir please upload the video for rc diac firing design in books only explained working and also the emi filter design

[@powerelectronicswithdr.k1017]

Hi Ranganthan, you must be looking at a light dimmer design. The classic RC/diac/triac design is often used to control the firing angle of an AC power wave to a load. Timing permitting, I'll see what I can do. Thanks for asking. -Dr. K.

[@ranganathanrajaram2121]

@@powerelectronicswithdr.k1017 yes thank you sir also how to design emi filter

[@khairulislam8683]

what is the meaning of Ts ,can you please tell me?

[@powerelectronicswithdr.k1017]

Ts is the total switching period. For example, if the switching frequency is 10kHz, then Ts = 0.10ms. The switches are only activated for a portion of that period (i.e. the duty cycle D) and we can control the voltage by adjusting the duty cycle. Hope this helps and best wishes on your design. -Dr. K

[@aravind.a123]

How can we get the value for ∆IL in the inductor equation

[@powerelectronicswithdr.k1017]

Hi Aravind, the ripple current through the inductor is a design parameter based on the rated output load for the converter. A good rule of thumb is to start with 40% of rated. Therefore, delta-Il/Il = 0.4. This all assumes continuous conduction mode (CCM). Hope this helps. -Dr. K

[@aravind.a123]

@@powerelectronicswithdr.k1017 thank you

[@shilpaauti9428]

Hello Sir, Can you please share design example of boost convertor similar to buck convertor.

[@AA-je1qm]

How can I design boost converter without inductor

[@powerelectronicswithdr.k1017]

Hi, yes you can. It's called a charge-pump or switching capacitor. Here's a link to a good White Paper from TI www.ti.com/lit/pdf/SLPY005

[@vaibhavpatil-mj5zj]

In boost converter at switch on can i write Ic = - Io

[@powerelectronicswithdr.k1017]

Yes, when the switch is on all the current is supplied by the capacitor.

[@MrSummitville]

The intro music was annoying, at best ...

[@powerelectronicswithdr.k1017]

Lol... You do know you can skip past the introduction. Have a great day MrSummitville and best wishes on your designs. - Dr. K

[@MrSummitville]

@@powerelectronicswithdr.k1017 LOL - You do know, that adding crap noise to your video does not make it better? Have a nice day...