Probability of Snow and/or Car Accident

[@DixieGeezer]

You are a great Instructor. All of us, (OLD GUYS, I'm 80) wish we had teachers like you and "on your level" when we were in school.

[@elsalchemy]

I am in my late 30's and trust me no one has ever taught me probability like the way you did... I understand this much better.. great work👍

[@TeacherLisaHello]

Thank you for your vids Professor! They are a god-send!! I am revising everything to help my son get a Maths foundation that his school will not be able to provide. A million blessings!!!

[@mrhtutoring]

All the best with your son's studies. 👍

[@retired5218]

Depends on the amount of ice mixed with snow on the road and how old your tires are plus if you are used to driving on roads with snow. Real world considerations.

[@xflr-6659]

Always a pleasure to listen to you 🙂

[@mrhtutoring]

Thank you

[@junfon7097]

I like this type of content, exploring all possible questions in a given problem. It makes me think laterally and find my own way to the solution.❤

[@jacobgoldman5780]

Would be more interesting and realistic to make snow and car accidents dependent events (like probability of car accident depends on if it is snowing and then questions like given there was a car accident what is the probability it was snowing) but good video and glad you mentioned at start that they need to be independent events.

[@morganasplund7929]

Thanx for what you are doing sens the society is us people and not a pile of home electronics you are a part of the evolution of the sosiety :)

[@joliettraveler]

I am also 80 and really like your videos. I wish you had online math classes. Exercise for the mind.

[@orobleh77]

Great and simple explanation

[@josephmalone253]

Very good. Im going to watch all of these.

[@peacefulgarden-j1o]

Great explanation!

[@nickcellino1503]

For the first problem, easier is 20/100 x 10/100 = 200/10,000. Cancel out 00 from numerator and denominator to reach 2/100 or 2%.

[@蔡木章]

Very good,have a great day!

[@elektorix]

Thank you for your great explanation.

[@mrhtutoring]

You are welcome!

[@MohamedElmessoudi-l8e]

Aren't car accidents more common in snowy weather? The two events wouldn't be really independent, would they?

[@jeffreyfoster8413]

How would the fact that the probability of car accidents increase in snow affect the calculation?

[@jamesharmon4994]

The thing is... these are NOT actually independent variables. If it snows, the probability of a car accident increases. 😅

[@PilgrimOfEden]

When it says snow or car accident, the reason we subtract the probability of snow and car accident is because snow or car accident means only snow or only car accident. Did I get that right?

[@brownfamily1892]

I think so

[@timmysiu]

No, if you draw a Venn Diagram, you will see that if you do P(A)+P(B) you will count P(A and B) twice, so you need to subtract P(A and B) once.

[@brownfamily1892]

I think that's what they said in other words, they said "only snow or only car accident" meaning double counted A and B must mean both snow and car accident, or the opposite of only snow or only car? Sorry if it doesn't make sense but I swear it made sense in my head 😭@@timmysiu

[@bartsimpson9047]

sir, what if the they aren't independent events..... car accidents only if snow

[@arcaltoby5772]

Can you please do a video on Worldly Cardinals and Inaccessible Cardinals? I'm kinda stuck on them in math.

[@Chlorate299]

Note that this differs slightly from boolean logic, in this case OR is an exclusive OR, hence why we subtract the probability of the AND condition.

[@Adhuko]

The OR is not exclusive. However, when calculating the probability of "A or B", P(A) will be the probability of all instances of A happening, including those where B happens as well (in other words, P(A) is the probability of A happening but not B plus A happening alongside B: P(A) = P(A ∩ B') + P(A ∩ B)). Same for P(B): P(B) = P(B ∩ A') + P(B ∩ A) = P(B ∩ A') + P(A ∩ B). So if you're looking for "A or B", you cannot simply add P(A) and P(B) together because both of them account for instances where A AND B happen together : P(A) + P(B) = P(A ∩ B') + P(B ∩ A') + 2•P(A ∩ B). This means you get "all instances where A happens but not B, and all instances where B happens but not A, and all instances where A and B happen at the same time twice". This is why you need to substract "all instances where A and B happen at the same time" once: P(A or B) = P(A) + P(B) - P(A and B).

[@Areadien]

I did not know this. Is there a formula for 3+ situations? I'm going to use this formula during hurricane season when I want to figure out the likelihood of two or more storms forming in the same basin. I may end up Googling this formula; unfortunately, I do not currently have the time to.

[@babanpal1]

Nice I m from India

[@HINtheKNIGHT]

I wish you were the teacher in my school

[@masewoods8337]

Mr H, I was #1 in My discrete mathematics class at Polytech and I am all alone here. I need some math help. Please respond. These are simple questions. I need a math teacher to grade and repeat my conclusions. I am nobody and no one will help me. Will you tell me I am nuts or that I got this stuff pretty close. I need to know. Please.

[@masewoods8337]

There is more than one way to send 100 million people to polls: 1: As individuals 2: In groups Either 100 million individuals could visit multiple pairs each, of 435+x pairs of people and 9 out of every 10 times, select the one with more money than the other, or we are going to the polls in discrete objects, in groups. Individuals vote. Groups buy pots and pans in predictable amounts. Groups pick the one with more money 9 out of 10 times. The one with more money could not a 'who got more money contest at a .9 clip. If the money were on the ballot next to each name. Right? Does this polynomial disprove democracy. Did I just disprove democracy in America?

[@jiteshsharma8507]

I never enjoy this much in maths...

[@William-Ae-Cha]

Can you please do a video on trigonometry, I'm about to be put in an early grave trying to understand it😅

[@mrhtutoring]

Will do!

[@Ziaphy]

Kind of a weird example cause these are clearly not independent

[@gauravkumarlecture4182]

May you help me sir?

[@JamesPOATE]

Sir i'm from Papua New Guinea , i like your teachings i wish you would be my math teacher😅

[@mrhtutoring]

Thank you for watching my channel.

[@gauravkumarlecture4182]

Sir, I am a teacher of village from India, I want to teach American students.I am appearing in graduation.this is the final year of my. What should I have do?

[@edmondlau511]

I’m an absolute idiot when it comes to math so forgive me. Can probability ever be more than 100%?

[@mrhtutoring]

Absolutely no. Super good question.

[@ruthenianthruth]

I do not understand why we subtract 2% here. Situation when both events happen still fits into OR scenario. Now it looks like that day none of events happened, when in reality they both occurred. So 28% is misleading answer. Correct is 30%.

[@ruthenianthruth]

If you disagree with me, imagine you are an insurance company and my words will immediately make total sense.

[@masewoods8337]

There are 535 people in our capitol building. How likely is it that one group of 535 people, out of 330 million people could, as a matter of probability, govern our stuff into their own bank accounts. How many ways are the to make ALL the groups of 535 people in unordered sets? We can easily measure the rate our stuff ends in in the one groups bank accounts, the group who publishes the words what moves our stuff. Right? This is intentional. Right? One group can't do both, move the stuff so each group has a fair probability and also it ends up in their bank accounts accidentally? Right? The odds congress could accidentally govern our stuff at themselves once is 330m choose 535, right? That number is too big. Flat question, can we rule out "accidental" wealth accumulation form within the capitol building? Isn't this probability hacking? If congress is governing our chances at themselves, as a group, they are not practicing capitalism. Since it's the same money pie for all the groups, did I not just disprove capitalism in America? Does this binomial disprove capitalism?

[@freddiechen5015]

hmmm i used 1-(1-0.2)x(1-0.1) and got the same answer. couldn't remember why but this is more straightforward? 😅 not really...

[@dreamsim71]

Nur richtig, wenn beide Wahrscheinlichkeiten unabhängig voneinander sind. Das ist in diesem Beispiel nicht zutreffend.

[@AnandSaraswat-b4x]

Sir,I am from India but your teaching is so amazing

[@Teams-ex7rd]

0.02=2%

[@Teams-ex7rd]

And=multiply Or=add then subtract

[@ccmplayer87]

Math vocabulary 👍

[@Deejaynerate]

You could also calculate the probability of (a or b) by doing 100% - (100%-a)(100%-b) As for why this works, you basically calculate the probability that both a and b don't happen, then get the difference of that percentage with 100% to get the probability when both a and b not happening doesn't happen, which should be (a or b)

[@masewoods8337]

Abortion: A pregnant animal is a set of beings. A host and some dependent elements. The host acquired her individual rights the instant she became an individual. A string does not become a boson or a quark until it becomes one. A fetus does not become an individual, until it becomes one. The fetuses will acquire theirs when they become an individual. They all have group rights, but only the host has individual rights. Correct?

[@masewoods8337]

There are 535 people in our capitol building. How likely is it that one group of 535 people, out of 330 million people could, as a matter of probability, govern our stuff into their own bank accounts. How many ways are the to make ALL the groups of 535 people in unordered sets? We can easily measure the rate our stuff ends in in the one groups bank accounts, the group who publishes the words what moves our stuff. Right? This is intentional. Right? One group can't do both, move the stuff so each group has a fair probability and also it ends up in their bank accounts accidentally? Right? The odds congress could accidentally govern our stuff at themselves once is 330m choose 535, right? That number is too big. Flat question, can we rule out "accidental" wealth accumulation form within the capitol building? Isn't this probability hacking? If congress is governing our chances at themselves, as a group, they are not practicing capitalism. Since it's the same money pie for all the groups, did I not just disprove capitalism in America? Does this binomial disprove capitalism?