Probability using permutations and combinations : ExamSolutions

[@ali_zaid__786]

I am shocked literally you post this video 10 years ago..... youtube give you award for the founder of educational content on youtube

[@SomebodyThatIusedtoknow-zr8ci]

Searched this over the whole Indian KZbin only to find a foreigner explain it, Thank you so much

[@anassawas7423]

I would recommend this playlist to anyone struggling with perms and combs. BEST EXPLAINATION EVER

[@kenrock6136]

faxxx

[@ExamSolutions_Maths]

Thank you and all the best for tomorrow.

[@anapecanape]

Thanks! You remind me of Ross from F.R.I.E.N.D.S.

[@ExamSolutions_Maths]

Cheers - that's a new one.

[@sylviachong5988]

I can't unhear his voice now

[@naheenisapoet69]

@Grady Rowen dunno if anyone told u but you are a lifesaver lmaoo

[@aarti7136]

@@ExamSolutions_Maths hey how you make these videos ?

[@the_indomitablespirit]

If he was British

[@justnorth7400]

I have been looking for a good hour now for a clear tutorial on probability with combinations, and I have finally found it here! Thank you so much

[@ExamSolutions_Maths]

No probs, pleased to hear they helped

[@ExamSolutions_Maths]

Hope it goes well for you - Good luck.

[@jamessaphu2163]

1st 11C5 is wrong... It is 77..

[@ZazzlesGS]

I've been struggling with perms and combs since the start my A levels, and finally now, after a year, I understand them, maybe now I'll pass my A level! Thank you so much!

[@internetborn]

I always wonder if you passed ur A levels

[@ZazzlesGS]

@@internetborn I did, I have my bachelor's now

[@aymennimir7464]

@@ZazzlesGS shoutout

[@loliking6628]

could i bag you

[@loliking6628]

youre so cute @@ZazzlesGS

[@encly3881]

Thanks to u I just found the answer to a maths problem I spent the last half hour straining my mind over, thanks!

[@vijaychaurasia9603]

You are great . Many videos do not explain the same thing so well as you do. Thanks a lot.

[@alsoarmani]

very understandable teacher.

[@ExamSolutions_Maths]

Thank you

[@peterodhiambo9423]

well elaborated.... I have got no problem at all... thank you very much🙏

[@niwagabaemmanuel4566]

You guys are good. This kind of explanations makes probability simple. Kudos!

[@lanacassidy9060]

thank you v helpful, million times better than my teacher!

[@gooddeedsleadto7499]

You are one in a million or one in 100 years kind of a teacher. It is hard to find one like you, you deserve special mathematics society honor confirmed upon to teachers like you similar to fields medal. Always stay upbeat, you are blessed. Thanks a million. You should train and produce mathematics teachers like u.

[@ksw2562]

AMAZING now at least I understand how the two are different and when to use them, thank you

[@subhrasmitkar6304]

Thanks a lot. I was really confused about the permutation and combination part. But you cleared it. Thanks!!!❤️

[@ExamSolutions_Maths]

Glad it was helpful!

[@xVeltZ]

Omg thank u soo muchhh i owe u big bits if it werent for i i wouldnt have graduated

[@ExamSolutions_Maths]

Cool. Keep at it and I am sure you will get there.

[@starbeeleung]

Your explaination is great and clear,thank you so much.

[@bryantay862]

You really deserve more subscription. Keep up the hard work! Really understood and would really be blessed if you are my lecturer.

[@ExamSolutions_Maths]

@anglican09 Pleased to hear you found it helpful.

[@MAUSAM_PARIHAR_]

thank you sir for teaching this in easiest way possible

[@ceelocadhays5593]

wow i did not understand even i took days but i understand in 5 minute on this thank u

[@ammarchen8850]

Bro thank you so much. You helped me out so much. I wish i could give you a warm hug. Keep up the great work broo!👍

[@anjaguldemond6234]

you explain so much better than my teacher!! Thank you so much!!

[@Paulineee_v]

thank you so much! it's our finals today and I really needed this I love you!

[@ExamSolutions_Maths]

+pauline valdez I wish you every success.

[@Jordie389]

thanks man! I have an exam today on combinations and permutations and this really helped!

[@akatsukisempai422]

Got stuck with this subject during online classes. TY

[@ExamSolutions_Maths]

Pleased it helped. Best wishes.

[@matthewsmiley7742]

Oh so helpful! Thanks

[@ExamSolutions_Maths]

Good to hear, thank you

[@Mbye-t3c]

Thanks. Well explained 👏

[@ambrishsudhanandan7098]

that was a really awesome series very well explained

[@An_ony_mous]

Thanks alot. I wamted this last one bit to do questions with both P and C and Probability mixed.

[@kuldeeplohe3902]

It is most wonderful series of lectures i have ever seen on Utube for aforesaid topic do u have few more lectures on the same pls do upload the lec for circular permutation & pls do inform me i very much greatful to u for ur lectures

[@RachelZhang]

Thank you for saving my life.

[@swaguilar_]

You are helping me more than my teachers. I finally have a grasp on it! Thank you! :)

[@ExamSolutions_Maths]

Well done.

[@شيماءصلاح-و1خ]

thank you very much from oman. You have helped me a lot

[@badjaeaux]

you are an excellent teacher ... may the King reward you

[@nandinibansal3983]

This was amazing! Thank you so much.. your way of explaining is awesome! :)

[@ExamSolutions_Maths]

Flattery will get you everywhere!

[@aishaalshawafi2599]

Your videos are outstanding! and I really appreciate it, thank you.

[@LogeshVishal]

I'm having my examination on Monday! I was still finding a way to solve this stuff but later when I got into this channel I understood nearly 90% of this Permutations and combinations in Probability

[@aayaanashar9263]

How was your examination bro.....?😄😄

[@sitasma3339]

Omg you're a lifesaver and a really awesome teacher ❤️❤️

[@SarkySk8inGuitarist]

Thank You! Your videos are so clear, and are really helping me get through my AS! Thanks!!! :)

[@alexandrajones8696]

Found this the night before my statistics exam, thank you so much! I may have a chance now!

[@hydershariff5737]

did you pass?

[@shanurathore9515]

Thank you so much 💖

[@f2t2r37]

thank you sir !!!

[@OriaPlay]

A billion thanks

[@ExamSolutions_Maths]

i) 29C6 is correct and (ii) 29C7

[@radaradaitsbob]

Thank you! This helped me out a lot.

[@ExamSolutions_Maths]

Good

[@Aeodn]

Good day sir, I just want to ask quick question, where did you get the 120 and the 48 from? I tried to work it out where you actually get the 120 and 48 from, can you explain on the comment box please!

[@ramanshrivastava1407]

watching from 2024 amazing video really 🫡🫡

[@shamoil4444]

This is the easy stuff........ I need more advanced examples.

[@aryadamle8772]

really helpful series, pls make 1 on geometric and binomial distribution

[@ExamSolutions_Maths]

kzbin.info/www/bejne/hJKni2Owi7msjrM&ab_channel=ExamSolutions Please check out our series on the binomial distribution.

[@guedesofc]

Thanks Gordon

[@MsHeartBreaker16]

Now I understand better! =D Thank you! ^^

[@matinhewing1]

Excellent video! Really helped! Thanks a lot!

[@ExamSolutions_Maths]

Thanks for watching.

[@ExamSolutions_Maths]

Yes it can be

[@DisguisedEnzo]

saw this questions on a cambridg statistics as level past paper, very usefull thanks!

[@oneinabillion654]

Rly? I wished Im gonna have questions like this this coming OCT NOV AS test

[@antoinepoisson4791]

thanks a LOT

[@thehrchannel8983]

You explain better than my professor. I can't even read half my professor's handwriting.

[@stupermanana]

can u use the notation (permutation) for the ABCDE question, as in 4 permute 2 (eg) because I dont understand how to show it.

[@tbilisi45]

I didn't quite follow you on the ABCDE problem. How exactly did you come up with 4! ways of A and B being together? There are only 5 places for an A; out of those 5 places, for 2 of them - first and last, there's only one place a 'B' can be put, to be next to A, and out of remaining 3 middle places for 'A', there are only two neighboring places for 'B' to be next to 'A'. Which gives us total of 1+1+2+2+2 = 8 combinations for A and B to be next to each other. thanks.

[@elijahprice5174]

thanks man that was awesome

[@ExamSolutions_Maths]

Thanks

[@yoyoyoc3po]

Thanks a lot mate.

[@DarkDungeon-ux6rz]

In the second example, when finding the no of arrangements where A and B are together, shouldn't we divide by 2! instead of multiplying? Also, thank you very much your videos explain the concepts very well!

[@0mfgitzramzi]

no you should multiply. since a and b can swapped and still be grouped together (b before a), that effectively doubles the number of possible arrangements that have a and b being beside each other which is why you multiply the 4! by 2.

[@shozebkohari9593]

october exams are close and thank god your videos are so damn helpful keeo up the good work

[@ExamSolutions_Maths]

Thanks and good luck.

[@kathleenolivier1588]

@@ExamSolutions_Maths Hi sir can you tell me the answer for this question. A coach has 16 players and can pick from 11 players for a match. it consist of 7 specialist batsmen, 4 fast bowlers, 3 spinner and 2 wicketkeeper. how many different teams can be formed if it must comprised of 6 specialist batsmen, 3 fast bowlers , 1 spinner and a wicketkeeper.

[@isi6402]

@@kathleenolivier1588 7C6 * 4C3 * 3C1 * 2C1 Dude use combinations.

[@suryamanjunathang4947]

@@isi6402 divided by 16C11

[@klaus9687]

so why are you keeping the rearrangmenet in denominator in 1st example and multiplying it in 2nd example

[@SilentEagle2029]

@ExamSolutions hey im in 7th grade and learning this and this was helpful a lot but how did u know wether or not it was combination or permutation? If u have a trick with this it would help a lot and i am now going to use these videos for future reference all of the time get it or not. Thanks for being such a smart person and being able to do this stuff. To me this is difficult

[@rajdipshah9225]

if the quesrion is asking to arrange, then permutation, if ir's asking to SELECT/CHOOSE, it's combination

[@kayte5804]

@@rajdipshah9225a bit late, this person is probably working a 9 to 5 now

[@ExamSolutions_Maths]

Good luck

[@ashrafibrahim4934]

A multiple-choice question on an economics quiz contains 10 questions with five possible answers each. Compute the probability of randomly guessing the answers and getting exactly 9 questions correct. I figured the answer should be 10C9*((1/5)^9)*(4/5). But a website says it is 9*4/(5^10). I will be grateful if you can clear the confusion.

[@billiondollarbeast]

thanks super helpful

[@Sh4wnTzy]

thank you sir 😊

[@kreinsch100]

Amazing Thank You !!!!!

[@jamesivan24]

In how many ways can seven students from a class of 30 be chosen for a field trip if Jack must go on the field trip. I'm assuming this is the same equation as 6 out of 29 students being chosen (29 nCr 6 on a graphing calculator). Is that correct? I'm assuming on the next question (what if Jack can't go on the trip) is the same formula. I just want to make sure I'm doing it right. Thanks, guys! You rock!

[@sea5205]

This was a great video thanks a lot!

[@ExamSolutions_Maths]

Cheers - thanks for watching

[@jameslucas6754]

how come for the second video the nPr=n!/(n-r)! wasn't used?

[@biski800]

Thank you! I don’t live in an English speaking country, but your videos make much more sense than my professor (˃̵ᴗ˂̵)

[@TheBlazefire33]

this is an easy question....do one where the letters of a word have to be in an order and we need that probability

[@realdragon]

If I roll 2 dice and the only thing I care about is sum of these dice should I use permutation or combination?

[@ayamgorengspicy3x]

Im actually dont understand how and when I gonna use P and C. Thanks, now Im understand. Tomorrow I have quiz about Statistics. zzz

[@ExamSolutions_Maths]

+NurFarrah Soda Good Luck - I hope it goes well for you.

[@ayamgorengspicy3x]

+ExamSolutions Thanks again. 😊

[@KeijiJohnLibadisos]

me too

[@dontbeserious5153]

Sir may you clarify? In the second example did you mean 4!/2! Or 4! × 4! ?

[@ExamSolutions_Maths]

Neither. 4! x 2!

[@Sergiopt96]

thank you very much for the video :)

[@bumboy8736]

7 years later, thank you

[@sean_tristan31]

Why do we multiply the combinations instead of adding them up? Can someone explain?

[@Sh4wnTzy]

Sean Tristan Francisco principles of counting...multiplication rule

[@shafiahmed8103]

Sean Tristan Francisco

[@ninanime21]

Sean Tristan Francisco...because there are different sets... So we have to use the multiplication operation. However, if we have the same set then we can use adition.

[@movischoy3388]

Thank you very much!!!:)

[@SilentEagle2029]

@stupermanana thanks I passed it....with a 65...now I'm in 8th grade so yea thanks again only 2 months too late tho...

[@jainikajeda3448]

is this for o level add math?

[@gran7773]

what if by any chance cards with letter A and B refuses to be together what would the solution be?

[@omyyer]

thank you, friend :D

[@sirhc1999]

is it OCR?

[@ExamSolutions_Maths]

@MsHeartBreaker16 cool

[@stupermanana]

dont worry ur stil in grade 7^^ permutations: order matters (how many ways can 5 books be arranged on a shelf) the way you order the books. Combinations: order doesn't matter. eg (how many ways can 3 groups be formed from 7 ppl, the order doesn't matter)

[@bonchasilark]

good luck on fri guys

[@donicesneed8514]

Okay you multiplied 11*10*9*8*7 why didn't you multiply 6 also when multiplying the number of committees?

[@dealwiththebob3877]

Donice Sneed because the committee needed 5 people out of 11. Once 1 person is picked, they can't be re-picked. So the 'pool' to choose from goes from 11 to 10. And goes down 5 times. So it's 11x10x9x8x7

[@selenaferrerart]

You Made this EASY - awesome teacher. you are SAVING my ass right now!

[@ExamSolutions_Maths]

Saving ass's is what I do.

[@ExamSolutions_Maths]

There were 5 gaps to fill not 6

[@tbilisi45]

Care to elaborate any further?

[@samkelly8908]

how is 5! 120??

[@realpeoplesmusic]

5!=5x4x3x2x1. 5x4=20, 20x3=60, 60x2=120

[@darrenmafemba3881]

Sam Kelly...5x4x3x2x1