Problem 1 on Design of Shaft - Design of Shafts, Keys and Couplings - Design of Machine

Subject - DOM
Video Name - Problem 1 on design of Shaft
Chapter - Design of Shafts, Keys and Couplings
Faculty - Prof. Zafar Shaikh
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#whatisproblem1ondesignofshaft
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[@akramfaiz2280]

i bunk class and watch your lectures.....thanks sir

[@pranilpawar6763]

Sir, really liked how u simplified the every problem in your each video. Thanx alot from me and my friends.. 👍

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[@azamjan580]

Amazing. i never had this much good understanding of such problems.

[@Karthimeena1]

Excellent Professional explanation. Thanks.

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You are most welcome.

[@Ekeeda]

Thank you all for your inputs...

[@kurunandanshishaudhiya1159]

answer my question

[@kurunandanshishaudhiya1159]

You can check. ....shaft is not safe at this dia......it will fail due to principle stress. ....

[@kalyanroy6559]

Thank you sir. your class is best class .

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[@rohanchowdhary975]

Great to have a good educational video from our country too.

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+Rohan Chowdhary Thanks

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[@jaisinghmaurya]

Thanks sir superb 🙏 👍

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[@achyuth_rj]

When calculating M, why didnt you consider the moment due to Rb and the pulley force at D?

[@yuktipatil8044]

A transmission shaft is supported on two bearings which are 1m apart. Power is supplied to the shaft by means of a flexible coupling, which is located to the left of left hand bearing. Power is transmitted from the shaft by means of a belt pulley, 250 mm diameter, which is located at a distance of 300 mm from the left hand bearing. The mass of the pulley is 20 kg and the ratio of belt tension on tight and slack sides is 2:1. The belt tensions act vertically downward. The shaft is made of steel with yield stress 300N/mm2 and the factor of safety is 3. Determine the shaft diameter, if it transmits 10 kW power at 360 rpm from the coupling to the pulley.

[@vinodhprasad6050]

Super teaching i learned easily and understand the problem to solve tnk sir...

[@AJ-ti4hy]

Sir aap ek WhatsApp group bnaayei or sab students Ko aad kr diji ye jis sa jyada se jyada log aap k video ka advantage le sake

[@kalesrikant]

Tq sir your class is always better than others classes

[@harishm6067]

It's very useful to me....i learn Clearly for ur videos ...Tq sir...

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[@brianahirekar9167]

U. Explained the problem with such great precession Sir.. Thanks.

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[@ravimetra5310]

Very good sir ...nice

[@akashshet728]

Excellent superb teaching in easy way

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[@AnkitPal-sl4oc]

Nice explanation...thank u so much...

[@chaithanyacolan9184]

Thankyou sir and pls ceep up the good work for students like me

[@mangeshdeshmukh7633]

Nice Tutorial Sanmit , can you elaborate more on T eq ( twisting moment concept ) how it is derived, had it been calculated @ point c only coz u r using value of B'moment @ point c only then what about @ point D ...Please help on that.

[@nathanielajayi5827]

😊 nice 👍🏾

[@darshitshah1499]

some basic concept thnku sir

[@shivansh8763]

Very nice and easy explanation

[@3bdulr7man707]

Thank you very much. This is very helpful

[@PrateekAher]

Thank you sir for this beautifully explained problem. Only one query though. Why did you select 70mm as the approximate answer and not 68, as it is the next even whole number?

[@hasithpereira2451]

very useful thanks a lot ,upload more ,cheers

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[@HappyguyAmazingvideos]

At 9:15 who else got deaf on right ear (headphone users)

[@monicam8139]

Happy guy Amazing videos me

[@triptabhattacharjee7004]

i thought my new headphone have gone out too :v

[@ananyathyagarajan7206]

@@triptabhattacharjee7004 Sameeee i literally opened my music app and checked !!😂😂😂

[@triptabhattacharjee7004]

@@ananyathyagarajan7206 me too. thanks to the comments 😂

[@aayubhardwaj9875]

@@triptabhattacharjee7004 ya literally

[@dheerajsoni7363]

sir plz upload videos on combined loading

[@ajayrohra2920]

ty sir and try to cover problem which difficult rather this types of simple ones....

[@chaituharsha3191]

helpful....thanks for sharing

[@allaryyan6608]

Thank you! your effort is really appreciated

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[@ThePRS66]

Ekeeda is doing a great job. Keep up the good work :-)

[@aswad7368]

Amazing :) Thank you so much

[@achirabdirzak8010]

Amazing

[@aboleejagtap5196]

Sir, I am working on the pellet machine. In that machine has two rollers attached on both side. Due to die rotation the roller rotates and the shaft is place in one place. For the roller, ball bearing is used. so how can I calculate diameter of shaft??

[@kimseng2661]

Thanks Sirnm Can the pulley change to sprocket for lift up of 150kg (1500N) for the same calculation ?

[@akshaypatil.7564]

Nice sir..thank you so much

[@panchalanand927]

nice teaching sir

[@lovelymurugesh4112]

Amazing sir wt.a teaching

[@shaharinbabu689]

such an excellent class sir

[@abhiyendersharma2493]

Sir,You r another best teacher for me, Thank you

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[@dheerajsoni7363]

i liked your videos so much

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[@TaqwiousMuslims]

Appreciative SIR

[@RehanKhan-lx5oi]

Hi sir your performance is very well. But last topic sound recording is not well.

[@dilersing8928]

thanks alot sir.....very helpfull for me .. but sir where are the lecture of clutch and break also

[@sureshchavhan3791]

Nice lecture sir

[@akhila838]

Nyz lecture 😊

[@agentbabu6923]

Nice sir plz upload with different load...

[@rodriguesjohnbaptist]

Thank you so much very helpful

[@ramumaddi8869]

nice video sir

[@ahmadsandhu9843]

how you take moment at C by neglecting force at D and reaction of B ?????

[@Amit-mv5vs]

its wrong plzzzz correct it..

[@sarojsimkhada8476]

I came here to say same thing better calculate bending moments using equilibrium diagram and making sum of moments=0

[@burakkrbas792]

When we draw the bending moment and shear force diagram, the maximum value of bending moment can be easily find which is 1500 Nm

[@MUKESHKUMAR-si2tf]

Sir bahut achha padate h

[@Radhekrishna098-b1]

A Hooke coupling is used to connect two shafts whose axes are inclined at 30°. The driving shaft rotates uniformly at 600 rpm. What are the ... angle where both will occur.

[@Radhekrishna098-b1]

Sir please send this problem solution

[@Hakisingh]

What if the Tau (60Mpa) is not given and all you have provided is the type of material? How would you solve from the last equation i.e. D^3= (Teq. x 10^3 x 16)/ pi x Tau?

[@fazalrahman5138]

superb explanation sir

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+fazal rahman Thank you

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[@AmitKumar-ym8uz]

It is so nice

[@marinerblue2547]

excellent......

[@charleskaruru481]

In this problem why did the lectirer not consider the effect of tension of the belt drives...if the shaft is rotating ot means it is driven by the belt drives therefore the effect of tension in tightside and slack side must be considered

[@Marine_Hunt]

Superb sir

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[@pratikshetty4988]

Just perfect ❤

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[@Adil_shares]

you explained well sir.... but i want some advanced problem

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[@mohdshafi-kc8kx]

really helpfull

[@kaand2232]

give this man a cookie some advanced examples would be better tho

[@rupeshzope4366]

Really thank'sss sirrrrr

[@Sandy-kc3bw]

great sir!!

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[@mohamadimamwicaksono9490]

Thank you so much sir, really helpful! i wanna ask, if we have a shaft and pulley exactly the same with your question but its vertically positioned. how do we solve the problem?

[@sangramsinhajadhav7425]

Good, but did we take FOS in this calculation?

[@emmanueltaiwo17]

What will be the effect on the diameter of the shaft. if a dynamic force (3000 Sin wt) is used to replace the 1500 N force. will appreciate your response.

[@Tadipatriwealthwellness]

sir easy to understand that sir

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[@zelfaloisrodriguez2155]

The kilowatt that can be transmitted safely by a shaft varies directly as the number of revolutions it makes per minute and the cube of its diameter. If a shaft 3 centimeters in diameter making 200 revolutions per minute can safely transmit 60-kilowatt, what kilowatt can be safely transmitted by a 2-centimeter shaft making 300 revolutions per minute

[@rahulmangate1095]

Nice...sir

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[@amanyisyemwalulesa416]

Sir which things should I consider during the design of screw shaft for squeezing tomato..?

[@maheshm6557]

Thanks you sir

[@11111111175890]

Why bending moment at point C was only taken and not from point D , while calculating total bending moment on the shaft ???? Or what happened is u calculated bending moment of point D about point C ? , I m confused

[@Boxerakku]

super

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[@divyaarramshetti110]

thank you so much sir

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[@anilrawal9007]

A V-belt drive is to transmit 10 kW to a compressor. The motor speed is 750 rpm and the compressor pulley runs at 250 rpm. Design the V-belt drive. Clearly state the design decisions taken. Plz solution this question

[@harshitrastogi2150]

Sir approx me 37 ku nhi liya But, awesome explained thanks 👍

[@semmes5342]

do you add a safety factor to your 70mm

[@swamisoundu5225]

Sir can you please explain problem which containing both pulley and gears and inclined angle.

[@Amit-mv5vs]

plz correcr the BM AT C by considering the forces at c and d....

[@g11111ish]

P = (2*pi*N*T) / (60 *1000) kW , N - rpm, T - Nm . And. T=9.55*10^6 * P/ n Nmm, P - kW , n - rpm Can anyone prove that above 2 equations are equal with proper steps and proof?

[@marutidodmani2236]

If pulley takes at 1mtr from left bearing toward left side ,is it right?

[@srunsubbiah]

What if I don't know the safe value of strees? Is it possible to decide based on the material?

[@medication1372]

Thnku sr

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[@confidenceejimkonye2106]

Sir it,s really helpful but if the load causing failure has uncertainty of plus--minus 15% and the maximum load on the structure is plus--minus 20%uncertainty how help solve for the design factor. Thanks for helping

[@sumeetsingh222]

Sir , if shaft in step then daimeter is?

[@prakashgade4835]

Sir do your dme 1 lectures are based on pune University syllabus ? And Do you make lectures of subjects heat transfer, turbo machines, and tom 2 ? Please reply

[@flawns]

I just had an exam on this 80% similar

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[@_Nickel_MdSayfulIslam]

a shaft is designed to carry 50 n load. the maximum stress it can tolerate is 150 mpa. what should be the diameter of the shaft.. Sir how to solve it..

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[@pulkitprabhat6541]

make a video on shaft subjected to two bending at 90°.. vertically and horizontally....

[@Tadipatriwealthwellness]

thanks sir

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[@Alalpog]

Good Sir, may you please help me with my homework? the problem goes like this. The following data apply to a motor and gear drive for a centrifugal pump. The shaft is supported by bearing A and B. A flexible coupling C connects the pump to the shaft. Pump output, 500 gpm Total head, 60 ft Pump speed, 500 rpm Efficiency of pump, 64 percent Motor speed, 1,800 rpm Efficiency of gears, 97 percent Power cost, 3 cents per kwhr Determine the following: (a) maximum horsepower required of motor; (b) horsepower of motor to be recommended, assuming a duty cycle of full load for 15 min and rest 15 min; (c) diametral pitch, pitch diameters, and face width of gears, assuming 14.5o teeth, 20 teeth for pinion, SAE 1045 for pinion and SAE 1030 for gear; (d) loads on bearing A and B; (e) size of shaft to be recommended, assuming allowable stress in shear, ss = 5,500 psi; (f) power cost of operating pump, dollars per day. The electrical efficiency of the motor may be assumed as 87 percent.

[@novendraanon3181]

why pick bending moment at c , how to pick the maximum bending moment ?

[@radhekrishna9313]

If you draw bending moment diagram for this system , you will get it . reply me if didn't get.

[@vikramvickey1648]

Moment about c would be zero when the other two forces and distances are considered

[@brajeshsharma911]

Sir agr safe stress ki value nhi de rkhi ho to kya kre hmare paper main ye hi aa rha tha lekin isme safe strees ki value nhi bta rkhhi thi

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[@VB66699]

Can u add problems....... on desgin on cotter joint, knuckle joint.

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[@laveshkumar9995]

sr I have some problem in shaft in combined loading

[@panchalanand927]

cotter joint and knuckle joint example ke video Upload kro na sir plz