Problems on Heat Engine

  Рет қаралды 24,663

Keshav Jadhav

Keshav Jadhav

Күн бұрын

Пікірлер: 15
@gabrielwillie12
@gabrielwillie12 2 жыл бұрын
Thanks sir, also I wanna thank you for presenting your video in English. I really hates few Indian lecturer who used to speak in their own language. Thanks Sir.
@p.pchemistrybyprofessorpra9482
@p.pchemistrybyprofessorpra9482 4 жыл бұрын
Shandaar explanation sir.....
@prachishekhawat1094
@prachishekhawat1094 2 жыл бұрын
Thank you sir. It helped me at the last moment!!
@omerfatih9606
@omerfatih9606 4 жыл бұрын
Thank you so much, teacher.
@nouramohammed275
@nouramohammed275 3 жыл бұрын
Such a great explaining
@FactophilicHindi
@FactophilicHindi 4 жыл бұрын
Good work sir..i appreciates❤
@shivanipal8482
@shivanipal8482 4 жыл бұрын
Sir can you plz plz reply quickly my question answers 1. A piston cylinder system contained air is worked on carnot cycle to do some mechanical work. Initially ,the system contains air at 1bar ,298k and 0.01m3. the system is first compressed until the volume is 0.002m3 (isothermally) .after that, the system undergoes an expansion process (isothermally) to a point where pressure in the system is 5 bar .At that point , the system is subjected to an isothermal expansion process until system reaches the initial state completing a cycle. Calculate the net work done of the cycle and cycle efficiency.
@faicornelius2601
@faicornelius2601 3 жыл бұрын
thank you so much Sir
@safrin3678
@safrin3678 2 жыл бұрын
Tq so much sir ❤
@mjcreation_3366
@mjcreation_3366 2 жыл бұрын
Why we convert in kalvin?
@shreyajaiswal9337
@shreyajaiswal9337 11 ай бұрын
Derive equation for efficiency of heat engine
@KeshavJadhav
@KeshavJadhav 11 ай бұрын
kzbin.info/www/bejne/iGepeH6qd7J9f6ssi=JzwyThCi3ngOpVtM You can watch above video from 09:50minutes onwards for derivation for heat engine efficiency.
@GANESHC-101
@GANESHC-101 3 жыл бұрын
👌
@sonubhat1056
@sonubhat1056 3 жыл бұрын
Derive the value of Q1 and Q2 in a heat engine?
@KeshavJadhav
@KeshavJadhav 3 жыл бұрын
According to first law of thermodynamics, Heat input (Q1)= Work output (W)+ Heat rejected (Q2). So, Q1=W+Q2 and Q2= Q1-W
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