Projectile motion (10 MARK QUESTION) 😳 | Mechanics | ExamSolutions

[@Ash-en4ul]

You're doing a brilliant job at taking over with the channel bro

[@ExamSolutions_Maths]

Very much appreciated bro.

[@tanneicabenjamin5447]

A job well done with all these videos. Thank you!

[@thomasking684]

"😳" lmao

[@jewelhossain7214]

Thank you so much,your teaching power is just brilliant❤️

[@musyi]

i tried to use range equation R=(u^2sin2theta)/g and got the same answer for the second part. Thank you for giving me another approach for this question

[@dontworry7272]

The last thing I would expect in mechanics is trig identities lol

[@ExamSolutions_Maths]

In A level maths, expect anything :D

[@ElonMusk-ov2xe]

11:15 why not S=-0.02 since it’s going through the hole

[@airmathstuition9]

The hole is at the same level as the point the ball started moving. So since we've modelled the particle to land at the same point it started, displacement = 0

[@ElonMusk-ov2xe]

@@airmathstuition9 ahh I see. Thanks

[@lukasproko3978]

i used a different trig identify 2sinxcosx = sin2x but i lost a value for x. Could you tell me why this is? Thanks

[@citra5431]

Using the identity 2sinxcosx you get that 20sinxcosx = 10sin(2x) which is equal to 2. Now if you solve that you get your first value as 2x = 11.5, but then you can also do 180-11.5 to get the second value (remember the quadrant rule from trig, sin is positive in the first and second quadrants). That gives 168.4 degrees. Dividing both of these by 2 to get x gives you the two solutions.

[@IMadeOfClay]

I haven't visited this channel in a while. I'm curious what happened to the previous fellow? Did he sell up? I hope nothing happened to him. I'm not complaining, this video is very good. Thanks.

[@Nickseeq11]

Look on the channel they made a video about two weeks ago.

[@ExamSolutions_Maths]

You're welcome, yes Thomas is right. We released a video a couple of weeks ago about Stuart (who you're used to hearing) retiring, though his legacy lives on!

[@IMadeOfClay]

@@ExamSolutions_Maths Ah, I've found it. Please tell Stuart thank you. I can't imagine how many hours he put into this channel. He's a wonderful person for making such a gift free. If there were more people like him, the world would be a better place. And good luck to you sir.

[@ExamSolutions_Maths]

@@IMadeOfClay Thanks for your well wishes and message to Stuart. I'll make sure he gets this.

[@scherrouk9391]

Thank you

[@ExamSolutions_Maths]

You're welcome.

[@Nickseeq11]

This is a level, right? Started a level maths in September and so far mechanics has been the most difficult part. Why is it not S = ut + 1/2 at²?

[@ExamSolutions_Maths]

Hi Thomas, yes it's A level. It is S = ut + 1/2 at^2 as in the video.

[@Nickseeq11]

@@ExamSolutions_Maths so for the first bit why did you do s = ut

[@legendlegend4459]

@@Nickseeq11 because the acceleration is 0

[@goldenegg7949]

​@@Nickseeq11 this is year 13 mechanics not 12. You do s=ut because when dealing with projectiles the only acceleration that acts on the particle is acceleration due to gravity which acts in the vertical motion. There's no acceleration in horizontal motion so you can't use suvat equations.

[@Nickseeq11]

@@goldenegg7949 thank you

[@osamaanees8406]

where did the other guy go?

[@legendlegend4459]

how many marks for each section

[@ExamSolutions_Maths]

4 marks for the 1st, 6 marks for the last.

[@maldinduwijayarathna9486]

Why is S=-0.2 ?

[@tees6675]

because the particle decreases in height from 0.2m to 0m at the end of its flight. this is because the ball will eventually hit the ground so s=-0.2 shows thay the ball has hit the ground essentially

[@AkashManick-h6r]

M1 or m2

[@grrizi7910]

This is M2