Projection of Solids_Problem 3 in AUTOCAD

[@ManasPatnaikofficial]

Read this guys....Some of u maybe confused so this may help... .....So be patient and do watch that end part of the video again, Here is the explanation:-Look, in this problem, we are talking about a plane which has an axis and grounded slant edge.....Now this plane is perpendicular to HP.....Just think about this....How would that plane look from the top.....Obviously, it would appear as a line. If this plane is inclined at 45 degrees with the VP, then the axis, as well as the grounded slant edge, would automatically get inclined at 45 degrees.....And hence the top view in step 2 has been recreated in step 3 making sure that grounded slant edge is kept at 45 degrees with xy line..........I hope this will clear your doubt....

[@akhileshyadav9862]

Ty sir ,but what about the axis perpendicular to hp

[@aakashchaudhary165]

Sir in drawing the base hexagon , can we draw it such that edge perpendicular to VP. You drawed with edge parallel to VP

[@thoughtoftheday3253]

@@nithinkavil122 ad kanichathinu enganeyokke parayano.sir Oru nalla karyam Alle cheythath ad kandun karuthi onn shamichoode😉🙄

[@jayapriya6361]

I will be back in the office on Monday and will be able to come in on the day of the day for school assembly in two weeks and then we will be able to come to the meeting on Monday

[@MSuriyaPrakaashJL]

@@aakashchaudhary165 i think you cant do that because when you tilt the figure the entire fave of hexagonal pyramid would lie on the ground which we wouldn't want as we want the slant edge to lie on ground

[@Ed-gd5ec]

Sir, your explanation made me crazy to learn more and more about EG, Unfortunately I have my Final EG today, and I did not prepare well for this. (Since i hated this subject very much from the beginning of the semester and ended up ignoring all class work, not done even a single sheet and missed Mid's Exam.) Hopefully I've prepared around 3 chapter from your videos and finally gonna write paper today. Doesn't care if i failed, i would be ever thankful to you Sir. You are such an amazing person on this planet with sole intension is to help those desperate student who were forced to learn this subject. A big thank from my side.

[@ManasPatnaikofficial]

My best wishes are with u John.... God bless u brother...

[@Ed-gd5ec]

@@ManasPatnaikofficial Thank you Sir. You just made my day. 🥰🥰

[@milindshivdekar8120]

I've recommended this channel to all my friends.. Thank you so much 😀😀😀

[@ndheerajkumar6029]

Lavada tere ko kya pasannd aaya be

[@myself5812]

@@ndheerajkumar6029 chmn chutiye seniors ko respect kar

[@rahulkumarmaddheshiya9864]

That's the real way of teaching these kind of topics. Thank You Sir!

[@prashannkumarshekhar3923]

Awesome Sir,the way you understand the 3-D VISUALIZATION is quite amazing ,It cleared my all doubts.

[@ManasPatnaikofficial]

Thanks for appreciating my work Prashann... All the best man... And do create an awareness amongst your friends and classmates to subscribe to this channel so that al can benefit...

[@ManasPatnaikofficial]

Thanks for appreciating my work Prashann... All the best man... And do create an awareness amongst your friends and classmates to subscribe to this channel so that al can benefit...

[@gibranfahad6876]

sir Im having a doubt regarding the first step on how to assume that we have to consider weather the edge or the corner of the hexagon is facing the reference line

[@sumanth5232]

Best engineering drawing tutor for all NITK students

[@austineetyang1318]

The best channel for technical drawing

[@dhinishkumar9799]

You the only one person explain step by step I really satisfied with ur class I'm very thankful to u sir

[@336atifnoman7]

Sir Your videos are superb. It looks like that our brain is being programmed by your teachings. Tq sir, Great work for Mechanical students👌👌👌👍👍👍👍 Once again. Tq so much sir

[@mantrisathya6638]

Hatsoff to your determination , your helping so many students thanku so mucch sir,keep making videos

[@krishnapuramnagarajan4802]

Thank you Shri Manas Patnaik. What a few Centers of Excellences refused to help me with, you have helped me. I am tending to be an Innovator of a Machine to dedicate to public through NaMo Bharat Mudra Entrepreneurs, employees, Incubators Trust. I have fabricated 99.5% of my proto type machine and I want to study the position of the component when they are assembled. Thank you Mr. Manas Patnaik. K.S.Nagarajan, Chennai. 09.04.2023.

[@ManasPatnaikofficial]

Thank u sir for appreciating my work.....i wish u all the very best in future endeavors.

[@mohammedzubairbaig5288]

ur just awesome sir .. I was unable to understand before now it is very clear. ... Thanx very much keep going

[@ManasPatnaikofficial]

Thanks for appreciating Zubair.... All the best...And do encourage your classmates to subscribe to this channel so that all can learn Engineering Drawing in the best possible way.....

[@chendrakanthpalamakula1622]

I'm weak at drawing but after watching your videos i got confidence that i can clear my engineering graphics

[@ManasPatnaikofficial]

Chandu....Thanks for appreciating my work.... All the best in life And do share and recommend this channel to your friends and classmates so that they can also benefit... Cheers....

[@ritabritabasak5652]

I am so lucky to get this video before my assignment

[@yashmundhe01]

Sir!!! It's too easy to understand you're amazing 😎

[@ManasPatnaikofficial]

Hi Yash...Well Thanks for appreciating my work... All the best in life And if you wanna support my channel visit this link: manaspatnaik.in/?page_id=401 Small contributions can make a Big Difference

[@mrindiagaming7803]

It's amazing sir at last night by seeing n practicing your videos only I passed ed thanks alot Caz it's my golden attempt you r like godfather for me thanks alot again

[@donkeshwarkavyasree8632]

Sir tomorrow is my exam...and i watched your videos before night....my frnd recommended me this on that night..i felt like why i didn't watch his videos before....anyways tq so much sir.Really awesome explanation.

[@nahush6299]

Thank you soo much sir.I understood projection of lines,planes & solids only bcos of u.And ur really gud with AutoCad.

[@ManasPatnaikofficial]

Hi Nahush....... Thanks for appreciating my work.... All the best in life... And do let your friends know about this channel so that they can also benefit....

[@pooja9587]

sir u r way of explanation is excellent.....

[@hrishikeshps9105]

after seeing this class i was able to understand this question very well thank you sir

[@ManasPatnaikofficial]

Thanks Hrishikesh Ps for appreciating my work.... Hope that u enjoyed and learned a lot from this... All the best..... And.Do recommend this channel to your friends also, so that all can learn Engineering Drawing in the best possible way....

[@dharaneshreddy252]

Explanation by a right demonstrater,thank u sir

[@abirami61299]

super sir.now,I'm able to imagine and solve problems myself.thankyou so much.

[@ManasPatnaikofficial]

Hi Abirami......First of all....Thanks for appreciating my work.... I always focus on giving you guys excellent quality free education.... All the best in life and do let your friends know about this channel on drawing and mechanics so that they can also benefit....

[@youme4552]

In previous two vedio of solid when solid edge or face rest on h.p we take f.v for true shape but here you are taking top view for true shape.

[@aaryajogalekar]

Mast video 1 video concept clear ❤️

[@Shivam-sh2qt]

you r really awesome.... i have recommended ur channel to all my classmates......... thankyou for such a good explanation.....

[@ManasPatnaikofficial]

Thanks for commenting shivu... And all the best in life...........

[@srinurocky5407]

Your drawing videos explanation is very well

[@sekhar2391]

U are explaining very excellently sir. Thank u for making videos and getting us educated.

[@rutikbongale440]

Thank you so much sir it helped me alot for preparation towards vtu semister end exam🙏🏽💯god bless you sir

[@poojanageshwarrao944]

Good job sir ... Your way of explanation is so awesome....now am solving so many problems....tysm sir...keep saying like this...keep rocking sir.....😍😍

[@ManasPatnaikofficial]

Thanks Pooja for the appreciation All the best... And do let your friends know about this channel (regarding drawing and mechanics) so that you all can benefit...

[@ritikkarma2544]

Sir you solve my big problem. Because you explain by practicle.thanks sir

[@nehakumari1482]

thanks sir...your way of explanation is really awesome..now, I'm able to solve problems on projection of solids...

[@ManasPatnaikofficial]

thanks neha

[@udayjadav4062]

right Neha

[@premnathkalasua7914]

Gio night and fast dileep garasiya

[@tushargoyaliit]

@@ManasPatnaikofficial OA should be visible in final answer

[@471swetha2]

It was very heplful in my exam thank you so much sir for giving clear explanation

[@joeljoseph2038]

You are amazing sir! i wish u were teaching in my school.xd

[@ManasPatnaikofficial]

Hi Joel... I am sure that these videos are helping u learn... Keep watching and do let your friends know about this channel so that they can also benefit.......

[@gurrammadanmadan2517]

Excellent teaching sir ,now iam very clear in this topic

[@srinurocky5407]

This videos is useful for improvement of drawings

[@samanvithachidella2485]

Fidaa sir...... super ...... Excellent teaching........Thank u very much

[@-Muralivalavala]

Hi

[@sayakmessideb683]

the class was so helpful for me before exam

[@-Sasipriyagoda]

Tqqqqq soooooooooooo much sirrrrrr u r way of teaching is toooooooo good

[@ManasPatnaikofficial]

Hi Priya.......Thanks for appreciating my work…and all the best for your examI am sure this channel is helping you learn…You can support my channel by donating and do watch this video: kzbin.info/www/bejne/jZfchnierc2dkLd8ave a nice day.

[@Omkar_Kaviskar]

A hexagonal prism has one of its rectangular faces parallel to the H.P. It's axis is perpendicular to the V.P. and 3.5cm above the ground. Draw it's projections when the nearer end is 2cm in front of the V.P. side of base 2.5cm long; axis 5cm long.

[@asifali_official3137]

Love u sir what a way of clarifying i really appreciate it.

[@pruthvirajjadhav4049]

My self is a fe cse geca student Thx sir for the making my basic concept best .👌👍

[@venkyreddy1913]

manas sir awesome leature ...... nice leature more than my sir

[@ManasPatnaikofficial]

Hi Venky... I am sure, this channel is helping you learn. All the best and do let your friends know about this channel so that they can also benefit....

[@NKmemers]

A hexagonal pyramid side of base 30 mm and slant edge length 75 mm is resting on one of its base edge in the HP with an apex 50 mm above HP. Draw the projections if axis is 45° inclined to VP and apex is in the VP.

[@thoughtoftheday3253]

U r aweson sir. Easy to understand 🤩thank you sooooooo much😎🙏

[@gundlapallysarala2841]

Ur class is excellent, but I suggest you to label HP and VP also

[@nandhinis8438]

thank you sir, jumped here from the involute video!

[@aks2566]

Here the second statement: A plane containing that edge is perpendicular to the HP. so what about that?

[@deadskull1411]

Same question

[@whaThirukkovalluruSripriya]

Plz some one reply to this question

[@-A-Madhav]

An Imaginary plane i.e.,joining base line and axis is perpendicular to H.P

[@staywithmeforever]

See the diagram correctly after 1 year answer is given

[@anitasubaharan4098]

same doubt

[@GlamBAR]

Thank you thank you sir.. aj ed exm r exm r age apnar video to dakhtei hbe sir☺

[@ManasPatnaikofficial]

Khoob daarun hobe tumar exam...........Tension niyo na....

[@Manja-rd3dr]

Sab doubt clear ho gaya sirr 🥳🥳

[@MrAbhishek0604]

sir you are absolutely brilliant!

[@ManasPatnaikofficial]

Thanks abhishek. Do watch all the stuff on graphics and let your friends know of this, so that they can also benefit......

[@anushavelpula2147]

Soft explanation annaya

[@markzuckerberg3238]

Holy Shit This Guy Is Good!!

[@ManasPatnaikofficial]

Thanks for appreciating my work.... All the best in life I have also started making lectures on engineering mechanics Do check it out on my channel page... Do share and recommend this channel to your friends and classmates so that they can also benefit... Cheers...

[@pavankumarnamburu2925]

Sir you explain very clearly and very nicely thank you so much sir

[@ManasPatnaikofficial]

+Pavan Kumar Namburu Hi pavan.... Keep learning and do let your friends know about this channel so that they can also benefit..... All the best

[@goutamdas838]

sir,,,tq u somch..i m rly appreciate to u...u r grt faculty...in you tube..for that ED

[@madhavwadhwa3509]

Sir the axis is inclined at 45 degrees to vp so we shouldn't have assumed the object to be resting on vp so we have to draw front view first?

[@ManasPatnaikofficial]

Madhav...i would strongly suggest that u watch the video again.... I am sure your doubt will be clear.........

[@akhilsharma7525]

Manas Patnaik please explain answer. to this question sir.. i had seen it 3 times but did not get

[@madhavwadhwa3509]

akki sharma what I have noticed is that the plane is making an angle of 45 degrees to vp not the object so as one of slant edges is lying on hp so we will asumme the object to be lying on hp and not on vp......I can be wrong but this is what I have figured out..hope it clears your doubt.

[@akhilsharma7525]

Madhav Wadhwa yes i do think so and thanks btw for considering to reply and making my concept clear!! :)

[@madhavwadhwa3509]

akki sharma your welcome bro!🙂

[@litegamer2588]

Ur lessons r so helpful , sir

[@prashantnetwork9713]

Sir ... Why had u start making video from the top view first ,whereas we have to make front view first, because the axis is making angle with the vertical plane???? Please reply sir....

[@karthikamohan2701]

Same doubt?

[@shubham6557]

For seeing the true shape of hexagon

[@Saii4202]

awesome sir thank u very much i will pakka share your page to my friends and once again thank u very very much sir!!!!!!

[@bhavyaboppana211]

Awesome explanation

[@JayPatel-pe4wn]

Thank you sir !! very nice tutorial & all doubts & concepts clear after showing this video.

[@ManasPatnaikofficial]

Thanks Jay....Always there for u guys............

[@silentword669]

Sir instead of redrawing we could have even used that auxillary method that od is acting as axis here so we can find beta angle then and measure the distance from xy to top view?? Plzz response

[@ujjwalhiredesai499]

It was very helpful to me in my exams thank you very much for your excellent explaintion

[@souticksamanta2981]

This question has appeared in our diploma second semester question.

[@ManasPatnaikofficial]

Lucky you Soutick.... All the best for ur results

[@randomcontent6002]

Hello sir, My doubt is,,since the plane containing edge and axis making an angle with VP so we should consider that the object is placed with its base on VP, there should be front view in 1st step??

[@ManasPatnaikofficial]

Read the pinned comment pankaj

[@shreyeshyerramilli9723]

Excellent explaination by u sir I learned lot of concepts from u sir

[@imranimu3914]

Super explanation sir

[@akshayakamble3544]

To easy to understand the topic thanks sir

[@ManasPatnaikofficial]

All the best Akshay

[@srikarsribhashyam7218]

sir absolutely brilliant content , thanks a lot sir.

[@karthikeyans6825]

Why is the step1 not done in problem no.1? It also has its faces lying on hp

[@rajeshraju607]

Sir please tell the andhra university basic syllabus problems I need. Your teaching is good use of engineering students

[@ManasPatnaikofficial]

Topic-wise Playlist of Engineering Drawing / Engineering Graphics in English 1. Orthographic Projection: kzbin.info/www/bejne/jXiZeWWmfriIsLM 2. Projection of Point: kzbin.info/www/bejne/nHyXmWidgpxmrZo 3. Projection of Line: OLD: kzbin.info/aero/PLIhUrsYr8yHz_FkG5tGWXaNbIxVcibQvV NEW: kzbin.info/www/bejne/pquoYXdjfs-rmpY 4. Projection of Plane: kzbin.info/aero/PLIhUrsYr8yHx7TVB51jN3HZVyW3R6RiBg 5. Projection of Solid: kzbin.info/aero/PLIhUrsYr8yHxARPzEFz1nXgt8j6xF_tEm 6. Section of Solid: kzbin.info/aero/PLIhUrsYr8yHwAbiCATZUbzd_CpF0EHF3v 7. Development of Surface: kzbin.info/aero/PLIhUrsYr8yHwdB96ft6c0Uwc4SDCLuG1v 8. Auxiliary Plane: kzbin.info/aero/PLIhUrsYr8yHxHWk2TCg1SrphF1vKpHXoB 9. Interpenetration of Solids: kzbin.info/aero/PLIhUrsYr8yHyTGceE1TGhCSxxfHyFpnNM 10. Isometric Drawings: kzbin.info/aero/PLIhUrsYr8yHxVky7bfrnbRcdXcHjT_K83 11. Conic Sections: kzbin.info/aero/PLIhUrsYr8yHx0TuqsY0FUZ7Z24BbKxJoQ 12. Cycloidal Curves: kzbin.info/aero/PLIhUrsYr8yHwwA8eBea78pJW1lw9XAv6z 13. Involute: kzbin.info/aero/PLIhUrsYr8yHzu8pqYvGwQoJKVpuS1Jusa 14. Plain Scale and Diagonal Scale: kzbin.info/aero/PLIhUrsYr8yHwTgo_zu_ELqOC1ypcp5Gr9 15. Complete Engineering Drawing in one single Playlist: kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS Topic-wise Playlist of Engineering Drawing / Engineering Graphics in Hindi 1. Orthographic Projection in Hindi: kzbin.info/aero/PLIhUrsYr8yHy3chHVzYA4BMbY9DbhyYSY 2. Projection of Point in Hindi: kzbin.info/aero/PLIhUrsYr8yHwinNUxVA1NW0xxLRlDfINH 3. Projection of Line in Hindi: kzbin.info/aero/PLIhUrsYr8yHyvWb87YtG3A3jDEnChgzir 4. Projection of Plane in Hindi: kzbin.info/aero/PLIhUrsYr8yHxj9N5e1oZA0x_k5ZVssf3U 5. Projection of Solid in Hindi: kzbin.info/aero/PLIhUrsYr8yHylYPjrulRGm8DSPiimxP3P 6. Scales Hindi-Urdu: kzbin.info/aero/PLIhUrsYr8yHzJA426HjlEmiRqUkJTkozB Topic-wise Playlist of Engineering Mechanics / Applied Mechanics / Fundamentals of Mechanical Engineering in English 1. Forces: kzbin.info/aero/PLIhUrsYr8yHzoyUutEK57JzWy1n-vxIS0 2. Friction: kzbin.info/aero/PLIhUrsYr8yHwY1TDraJpyYkU8Zug-kM4m 3. Shear Force and Bending Moment: kzbin.info/aero/PLIhUrsYr8yHy1lc0hEhbpEAGsGwNmUWt7 4. Trusses: kzbin.info/aero/PLIhUrsYr8yHwIXEt9cqjEsEO8l83xcIf7 5. Centroid and Centre of Gravity: kzbin.info/aero/PLIhUrsYr8yHzZ52dVA3wQ_0IQVl7CKL7p 6. Moment of Inertia: kzbin.info/aero/PLIhUrsYr8yHw8qWxAVOx-5Y2XfGPOmcDy 7. Dynamics: kzbin.info/aero/PLIhUrsYr8yHwOZxmY63A_lURu6c-jNk-z 8. Complete Engineering Mechanics / Applied Mechanics in one single Playlist: kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS

[@ram_2016]

Sir hp se perpendicular bi to he

[@tanaaznd8159]

Sir, do you have any trick for hidden lines? I get confused alot

[@shrutisingh5349]

awsome video sir... it helped me a lot....

[@vanshikasharma6784]

Plane containing axis and edge is inclined to vp. It means axis is also inclined to vp. So we should have made the front view first . Sir everyone has the same doubt here and we are not able to clear this doubt by watching the video repeatedly. So its better that you should make another video explaining this doubt. Or you can also explain by replying me.

[@SharafatAhmadKhan]

Sir u are so much awesome in ED

[@devan9718]

Ur absolutely awesome sir

[@surajpradeep7135]

Very helpful sir, thank you sir ❤️

[@aakashchaudhary165]

Sir in drawing the base hexagon , can we draw it such that edge perpendicular to VP. You drawed with edge parallel to VP

[@vinayjustin8138]

Same doubt bro plz explain

[@karanrakhonde1521]

Why we not assume the object perpendicular to the hp in problem no.1,2?

[@Itsmemeghana26]

thanks manas for helping me nd ur guys even mechanics ha

[@ManasPatnaikofficial]

You are welcome... All the best

[@editorfx9827]

Sir if inclined to VP is said then we have to find out the apparent inclination by line rotation no ?Also how to identify whether we have to do line rotation while drawing the 3rd tilt ?

[@ManasPatnaikofficial]

That is a different case where the true length is inclined Mr. Editor.... 1. Engineering Drawing Playlist: kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS 2. Engineering Mechanics Playlist (OLD): kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS 3. Engineering Mechanics Playlist (NEW 2023-2024): kzbin.info/aero/PLIhUrsYr8yHxeypEyVdWeGNxWHjNxU_JP 4. Mechanics of Solids Playlist: kzbin.info/aero/PLIhUrsYr8yHzft7ygw5THZo4aDcsxEadP 5. Theory of Machines / KOM / DOM Playlist: kzbin.info/aero/PLIhUrsYr8yHx0aFXSQvT7nm6ivJSMKnAU 6. AUTOCAD Playlist: kzbin.info/aero/PLIhUrsYr8yHyLArdiiSDLa0Fmz8YKIy7G 7. Machine Drawing Playlist: kzbin.info/aero/PLIhUrsYr8yHzwT06rv7u3tqdfmmKOCz1w Visit Channel Page(@manaspatnaikmech) for Playlists on specific topics. Download the Manas Patnaik App for Premium content : bit.ly/3wMRxoc

[@divyanshutakey5480]

Why we supposed the initial position as one side of hexagon perpendicular to the xy axis????

[@lakshyasinghthakur4021]

A hexagonal pyramid, base 25 mm side and axis 55 mm long, has one of its slant edges on the ground. A plane containing that edge and the axis is perpendicular to the H.P. and inclined at 45" to the V.P. Draw its projections when the apex is nearer the V.P. than the base.

[@spandanareddym1919]

Superrr sir clear explanation tq sooo much

[@rav.en0426]

Isn't the angle in below xy line shouldn't be clockwise?

[@shahanshajahan1013]

U r super sir. Very good explanation 😊

[@ManasPatnaikofficial]

Thanks Shahan for appreciating my work... Do encourage your friends also to subscribe and learn from this channel..... All the best in life....

[@shahanshajahan1013]

sure sir

[@yash2154]

Sir, how will we get to know when to draw the diagram on top of the xy line and when to draw below it?

[@eitoes]

Same doubt. Did you understood that part?

[@karishmamandal6600]

When you draw top view you draw below xy line. When you draw front view you draw above xy line.

[@nidhichhagnani5825]

I m confused about why the corner is to the left in step 1 top view , .. it could be an edge to the left ???

[@chakrik3520]

The point that you had put at 45 • is that our wish to put the point at any where sir please clarify my doubt as fast you can please it's emergency.

[@tushalnirasoi]

Sir plz understand about hidden line in brief and if it is possible plz make special ..video for hidden line of all solid..

[@dhiraj319]

hexagonal pyramid, base 25 mm side and axis 55 mm long, has one of its slant edges on the ground. A plane containing that edge and the axis is perpendicular to the H.P. and inclined at 45o to the V.P. Draw its projections when the apex is nearer the V.P. than the base. OR

[@prathameshajmire1873]

sir,you are exceptionally good..I just have one doubt..i am able to understand that when to make the solid vertical and when to let it lie on the hp?

[@ManasPatnaikofficial]

kzbin.info/www/bejne/j4eXg42EhpeseJo watch this video prathmesh.....

[@brainhax6758]

sir , i have two questions,1) when do we take two parallel sides of hexagon , perpendicular to x-y line 2) Is it neccessary in step 3 to move the apex towards the observer or its our choice ,when no info regarding apex is given??

[@ManasPatnaikofficial]

1) Suppose you were asked to keep a triangular face grounded (on HP) then u would have made a vertical hexagon in TV (2 sides perpendicular to xy)........just think about this......And let's say we have been asked to keep a slant edge on ground (as in this problem itself) here you will make a horizontal hexagon (2 sides parallel to xy). 2)No its not necessary in step 3 to move the apex towards the observer. If nothing specifically hasn't been mentioned you have the option to keep the apex closer or far away from xy line....

[@pedurinigam8218]

sir,in this drawing where do u used the condition that the "plane containing axis and edge is perpendicular to HP"

[@digvijaysinhsodha3187]

So many ads disturbing me while study time

[@nachiketpatel800]

Hey sir , why we are not using locus method at 45 degree?? Bcoz, axis length not remain same

[@khursheedahmedparah186]

A hexagonal pyramid of Base side 30 mm and axis length 60mm is kept with a side of Base parallel to the v.p and the triangular faces containing that side being vertical .Draw the projection of the solid??? plz upload this question Sir.

[@arsalanmakhdoomi7405]

Sir why we did not follow step 1 here . As axis was inclined to VP, why didn't we take solid resting with base on VP???

[@vasavirouthu7283]

Pls do problems on different types of prisms too

[@ManasPatnaikofficial]

sure....your request noted...