Projection of Solids_Problem 4 in Powerpoint

[@kasanadevesh]

Brilliantly explained. This is how our professors shoul be.

[@shivanshbaurai5747]

Even my teacher recommend your videos for reference. Great Work

[@ManasPatnaikofficial]

Hi Shivansh....Well Thanks for appreciating my work... All the best in life And if you wanna support my channel visit this link: manaspatnaik.in/?page_id=401 Small contributions can make a Big Difference

[@sumanghosh4725]

My teacher should learn from you . excellenct of excellence understanding

[@minishot476]

🤣🤣😛

[@om-ni3dm]

Ur fantastic i grabbed 75% of knowledge of caed from ur videos which i cannot in college

[@sayershaik1027]

Excellent brother you've nailed it Finally I understood Your teaching skills are marvelous Thank you bro

[@spk86]

Are you a human being or god... Your welcome teaching is like a god level... Every eg teacher should beg you.... No one got knowledge like you and your teaching like even a kindergarten can understand engineering graphics concepts clearly... Thanking from bottom of my heart...

[@king_ajeesh]

Super. Now I learned projection of solid better than my college staff thank you.

[@ManasPatnaikofficial]

Engineering Drawing | Engineering Graphics |: kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS

[@satyaneerukonda133]

Legend for legendary department of Engg graphics superb sir 👍👍👍🙏

[@RaushanKumar-fw9sf]

thank u so much sir for loading these type of videos bcoz this is important for better understanding

[@ManasPatnaikofficial]

Thanks for appreciating my work Raushan... All the best man... And do create an awareness amongst your friends and classmates to subscribe to this channel so that al can benefit...

[@SiddharthDandotiya_YT]

The best explanation ever I have seen . Thank you sir 😊

[@arshifatima5536]

Amazing video.You made everything crystal-clear!!!!

[@sayakhalder1239]

thank u alot sir dis video solved my doubts ! about placement of hexagon !

[@ManasPatnaikofficial]

Thanks for appreciating brother...... All the best...And do encourage your classmates to subscribe to this channel so that all can learn Engineering Drawing in the best possible way.....

[@IITlifestyle]

On Projection of Solids: 3. Draw projections of the hexagonal pyramid you made, with base on HP, and a side of the base parallel to and 25 mm in front of VP. 1:32 1:32 1:32 1:32 1:32 1:32 1:32 1:32

[@gowthamsanjeevi1248]

Very very thanks for manas patnaik i followed ur vedios on solids planes lines etc all topics and i cleared my engineering drawing subject which i failed for 4 times this time i clear the exam thanks for ur vedios

[@ManasPatnaikofficial]

Gowtham....What can i say!!! All the best in life Go ahead with confidence...

[@tahreemfatima8363]

Thank you so much sir for uploading such videos👌👌 You teach us in the best possible way.I understand every concept of ED with the help of you only.I like you so much sir..........plz help us in the same way forever.Thank you so much sir..........😘😘😘

[@ManasPatnaikofficial]

Thanks Tahreem....... All the best in life

[@vishnuvardhan9764]

Really something like learning from a scholar of drawing!!!!!!!!!!!!!!

[@sejalbisen8600]

Really helped mee a day before my exam can't thk u enough in words

[@jonyasirvadam83]

Sir!!!!!!! U've made my day xcllnt stuff thank you sir

[@ManasPatnaikofficial]

Hi Jony.... Thabks for appreciating man......

[@balamurali2987]

Sir really it's very very easy to understand......u explained it in a simple way and also catchy

[@mounikavarma1176]

It's helps me a lot for my Tmrw paper

[@thavamayyarsamy9720]

Me too sir

[@Adhithya2003]

same lol

[@SaurabhSingh-ch6nc]

Nice sir its too easy for understand..

[@ManasPatnaikofficial]

Thanks Bharat Do watch all the content on drawing and mechanics..... And do tell your friends about this channel so that they can also benefit..... All the best

[@raj_tricks_and_tips]

hexagonal pyramid of base side 40 mm and axis length 55 mm is resting on H.P. with one of its base corners. The two adjacent base edges containing the corner are equally inclined to H.P. the axis is inclined at 35o to V.P. and parallel to H.P. draw its projections.

[@madhukarneerati6554]

Sir your teaching methodology is completely different and superb

[@ManasPatnaikofficial]

Thanks Madhukar...

[@hadiyaebrahim6285]

Video is really helpful.... waiting for more and more uploads...of different types....your lectures are very far better than my sir

[@GuruPrasad-kx4zt]

Hmm yes

[@harshmewada4213]

Thanks a lot sir u are really great , this type of explanation we really need in our education system by which we understand it by real condition.

[@lokeshkms3839]

Fantastic sir...Keep posting many advanced problems sir

[@ManasPatnaikofficial]

+LOKESH KMS Hi lokesh.... Thanks for appreciating the content.... All the best and do let your friends know about this channel so that they can also benefit...

[@lokeshkms3839]

Sir can you pls post projection of solid without inclinations..Thanks in advance sir

[@parthkulkarni276]

A pentagonal pyramid, 50 mm side of base and 80 mm height, rests on one of its corner of the base on the H.R.P. with axis making an angle of 30° to the HP. The side of the base, opposite to the corner on the H.R.P., is parallel to the VP. Draw the projection of pyramid

[@himanshuvarma8290]

A great learning from you sir a best way you choossed to teach us thank you sir from the core of my 💞 heart

[@ManasPatnaikofficial]

Keep learning And all the best

[@himanshuvarma8290]

Thanks a lot lot sir i appreciate with you sir

[@Civilian-IITB]

thanks sir you are the best teacher. sir me and my all friends sees your video which are very helpful for stdy sir pls upload more videos of different kinds

[@ManasPatnaikofficial]

sure shubham i will....GOD BLess u...

[@devendrathombal3702]

What a teacher 👍 Thanks sir

[@walkwithgod8981]

Hi bro the question is : a hexagonal pyramid of side 30 mm at height 65 mm is resting on its base is in Hp.one of its base lights is parallel to VP it is cut by the cutting plane which is parallel to HP and perpendicular to VP and passing at a height of 45 mm from its bottom and rather development of the surface.

[@walkwithgod8981]

Solve this question please

[@DaveKumar.]

hexagonal pyramid of base edge 30mm and axis height 70 mm has one of its triangular faces, making an angle of 450 to V.P. Draw its projections when the base edge o f the triangular face is inclined to 500 to the H.P and parallel to V.P.

[@piyushsharnagat83]

Thank you sir!! You are doing a such a great job

[@bitturajkumar4227]

I can't explain how thanks to you for these videos

[@abdulkalam9826]

My dear manas you helped me a lot.

[@rudra_sanyal1679]

Sir,your video is very helpful for me

[@sairanjanmuni8698]

hexagonal pyramid is resting on a side of its base on the ground having its axis inclined at 45° to the H.P. and the vertical plane containing that axis is inclined at 30° to the V.P. Draw its projections. Base 30 mm side; height 60 mm.

[@lildax5390]

Nice one bro You cleared my concept easily Thanks!

[@ManasPatnaikofficial]

Engineering Drawing | Engineering Graphics |: kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS

[@kaustubhhavanur8000]

your all the videos are really awesome

[@rayavarapuyaswanth2683]

Sir super ..it help me for my examinations . thank a lot

[@LALA65465]

great content sir....very helpful

[@ManasPatnaikofficial]

Thanks for appreciating my work Saransh... Do watch more videos on projection of solids... All the best man And do encourage and recommend this channel to your friends...

[@shaikabdulkhadeer2368]

Excellent explaination 🤗

[@nipunraj494]

Thank u so much I understood it very well Excellent explanation 😊

[@anumukitha9807]

I wish u can be my teacher !pls do more videos like this . Thank you sir !

[@piyushsharnagat83]

It is so helpful to me to understand it by easily way🙂🙂

[@sandhyavelpula2726]

nice sir this method is easy to understand problems

[@ChandramouliHaldar]

6} a hexagonal piramid side of base 25mm annd axis 50mm long rest with 1 of the adge of the space of hp and is axis is incliend at 30' to hp and parpenducular to vp draw the projection

[@abilash8098]

legendry eg teacher

[@anonymous34683]

You are my new superhero🙂

[@ManasPatnaikofficial]

All the best. 1. Engineering Drawing (English) : kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS 2. Engineering Drawing (Hindi) : kzbin.info/aero/PLIhUrsYr8yHx0C3ebAW-FQxTP8ig8-QxU 3. Engineering Mechanics: kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS 4. Mechanics of Solids: kzbin.info/aero/PLIhUrsYr8yHzft7ygw5THZo4aDcsxEadP 5. Theory of Machines: kzbin.info/aero/PLIhUrsYr8yHx0aFXSQvT7nm6ivJSMKnAU 6. Machine Drawing: kzbin.info/aero/PLIhUrsYr8yHzwT06rv7u3tqdfmmKOCz1w 7. Engineering Services Examination_Engineering Drawing_Prelims: kzbin.info/aero/PLIhUrsYr8yHwFTNav_k3EEIvztQEQHilU 8. Physics for Class 11: kzbin.info/aero/PLknJ2c9H1euEwtFJLUGZvkjG35OoVvemM 9. Manas Speaks Series: kzbin.info/aero/PLIhUrsYr8yHz9g5V7Lw_BA5UXbAbgVyf0 10. Physics Channel Link: kzbin.info/door/_aqx41HWeOebfL6FqBYU6Q My AMAZON Store - For all you students. www.amazon.in/shop/manaspatnaik

[@anamikajayaprakash3341]

Great work sir

[@bhaviktelisara253]

Best video..all my doubts were cleared...

[@ManasPatnaikofficial]

Enjoy.....all the best

[@mohanrao2607]

Tq very much sir i learn alot from u sir

[@shabarish2727]

Very nice sir

[@ManasPatnaikofficial]

Engineering Drawing | Engineering Graphics |: kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS

[@shabarish2727]

@@ManasPatnaikofficial Thank you sir , i have also informed my friends about your channel . Thumbs up from me for quality content you have provided.

[@arunkumarray9023]

It was very to understand, Thanks sir 🙏

[@RameshSahu]

Q5. A pentagonal pyramid, edge of base 30 mm and height 50 mm, stands on its base on the HP with an edge of base parallel to the VP. A section plane cuts the pyramid at point 30 mm along the axis and above the base and makes an angle of 50_ with the axis. Draw the development of the truncated pyramid.

[@sowmyaburgula5359]

your videos are really helpful sir thankyou.

[@haifamohammed6573]

I don't understand when we should do 90deg -30deg n when we shouldn't

[@saisampath787]

Thank you very much sir. Really the explanation was 👌

[@abhijaysaraswat83]

Great video.

[@sreelakshmip736]

Thanks sir. You have done something great

[@TRAPSOULGAMINGISLIVE]

Thank you so much sir, It is very easy to understand this type of questions

[@goutamdas838]

sir in dis lecture u taech with a xcitmnt ....its rly gd ...anywy its rly nice...i lyk ur spokn styl

[@ManasPatnaikofficial]

Thanks goutam and all the best

[@JSP_1518]

Thank you very much for the explanation, it helped alot.

[@silentlyplaying8426]

Thanks u save my semester.

[@lavakumar1020]

U cleared all my doubts...

[@shardulkarhe4975]

Sir can you please upload some more and some tricky or tough questions becoz they are frequently asked in exams .if you do so dont show how to draw becoz we have learned it in previous lectures just question with answer and how that answer came.so that in a single video no of questions will be covered which will be helpful.thank you

[@tejasdobariya7350]

sir, can we draw 2nd step(F.V) to opposite side??(FROM LEFT TO RIGHT)

[@DubsmashAdda]

axis inclined at 30° to v.p means..why u have written in condition inclined 30° to h.p..sir..please answer me sir

[@user4454]

We can make directly if if it is given 60 degree then we can make or not without doing minus from 90 minus theta

[@nitinmahobiya9620]

Thanks sir college is a best teaching you solid plens

[@ManasPatnaikofficial]

1. Engineering Drawing (English) : kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS 2. Engineering Drawing (Hindi) : kzbin.info/aero/PLIhUrsYr8yHx0C3ebAW-FQxTP8ig8-QxU 3. Engineering Mechanics: kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS 4. Mechanics of Solids: kzbin.info/aero/PLIhUrsYr8yHzft7ygw5THZo4aDcsxEadP 5. Theory of Machines: kzbin.info/aero/PLIhUrsYr8yHx0aFXSQvT7nm6ivJSMKnAU 6. Machine Drawing: kzbin.info/aero/PLIhUrsYr8yHzwT06rv7u3tqdfmmKOCz1w 7. Engineering Services Examination_Engineering Drawing_Prelims: kzbin.info/aero/PLIhUrsYr8yHwFTNav_k3EEIvztQEQHilU 8. Physics for Class 11: kzbin.info/aero/PLknJ2c9H1euEwtFJLUGZvkjG35OoVvemM 9. Manas Speaks Series: kzbin.info/aero/PLIhUrsYr8yHz9g5V7Lw_BA5UXbAbgVyf0 10. Physics Channel Link: kzbin.info/door/_aqx41HWeOebfL6FqBYU6Q

[@shakthimithra3243]

Really awesome please teach us by solid edge V19 application

[@414_kumarshinde8]

Fabulous sir

[@mistakeboyofficial5779]

Very very helpful air

[@muddasirahmed435]

Sir can we take angle from opposite side?as the protractor have 180° it shows angle from both the sides,from right side and also from left side. Example:I have to take 30° degrees then there are 30° on left side and as well as on right side,then which 30° I have to choose? Hope u understand my question

[@shabajbagwan6652]

Awesome explaination

[@ManasPatnaikofficial]

Thanks Shabaj........

[@pazhanimuniyasamy7695]

Very helpful sir i am useful

[@naveenparnapalli483]

Tq so much sir... It helps me a lot.....

[@vaishnavijasutkar8480]

Sir , why you have taken 30 degree toward left side , why not in right side to HP

[@munnaramachandran9759]

Add perspective view & isometric projection of simple solids.

[@ManasPatnaikofficial]

Sure ....i will

[@avdhootjadhav6705]

If the pyramid is in front view and it is said that it should be nearer to observer then what we should do?

[@TanujKumar-fp8gp]

A hexagonal pyramid of base side 30 mm and axis 60 mm has an edge of its base on the ground, Its axis is inclined at 30° to the ground and paral lel to the V.P Drawits projections, o1

[@viswaspartan309]

The trick is very much useful..

[@ManasPatnaikofficial]

+Viswa Spartan Enjoy.....

[@vinodhi576]

If the axis is inclined to hp,,then we can take 30° from either of the sides right ?...

[@kondapallisivasaimanikanta7737]

Sir Tell me how to draw " projections of cylinder base 40mm diameter and axis is 50mm long , resting on Hp and VP with their bases.".

[@bhavikprajapati155]

Wonderful sir

[@trendz034]

I like it sir😘 but sound quality thodi kharab h 😔will you please improve it for next videos 🙏🙏🙏

[@vinayjustin8138]

In previous videos u didn't said ...when axis is inclined to ground (90-teta) y??

[@deepu_srinivas673]

Sir we are understanding but how can identify the project to draw the given question

[@teja9198]

Thank you sir

[@ManasPatnaikofficial]

Engineering Drawing | Engineering Graphics |: kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS

[@jishink3107]

Sir how will understand the base side is parallel or perpendicular to x-y plane? Sir plz give replay

[@DubsmashAdda]

i have full confusion about this problem sir..about inclination..in the question they said 30° inclined to v.p..you said assume if axis inclination to vp..the front view will be first step in v.p..and tv will be in hp..then why have u drawn first step in hp sir..please correct this problem sir..pls help me sirrrrrrr

[@ManasPatnaikofficial]

The solution is absolutely fine absolutely correct you got to watch the video once again it has been clearly mentioned that the axis is inclined to HP

[@DubsmashAdda]

@@ManasPatnaikofficial okay grounded means hp ah sir..

[@ManasPatnaikofficial]

Yes

[@DubsmashAdda]

@@ManasPatnaikofficial thank you sir

[@shashankgn3202]

tq sir I learn something to u tomorrow I have drawings exam 😃

[@ManasPatnaikofficial]

Hi Shashank…Thanks for appreciating my work…and all the best for your examI am sure this channel is helping you learn…You can support my channel by donating and do watch this video: kzbin.info/www/bejne/jZfchnierc2dkLd8ave a nice day.

[@sunitharamavath1900]

From on words I wanted to follow ur videos because I was failed in graphic because don't know the basics properly can u suggest me sir

[@vashistavenkatesh1804]

I've a question Why'd you take the angle of inclination anti clockwise Is it alrite to take it clockwise also

[@shreeshylesh265]

Yes

[@sriramkumar4449]

Sir why we giving nomenclature for any object in anti clock wise direction

[@ManasPatnaikofficial]

Its your choice....dont worry

[@viditapatil]

Can we tilt the object either side in second stage?? Please reply

[@anujareddy1660]

When the axis is inclined to hp Can we take axis line another way i.e, perpendicular to the axis which you have taken

[@yarravamsi3674]

Sir why can't we make edge "b e" with hp 60 degrees in clockwise please explain it sir??

[@dineshbattu6325]

How to draw when edge of base inclined at 45° to vp

[@bhavaniyallavula2575]

Sir can we take other type of hexagon in this problem?could u plz explain which type of hexagon can take if hexagonal pyramid is resting on hp on one of its base corners